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Following quiz provides Multiple Choice Questions (MCQs) related to **Cube and Cuboid**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - A big cube is having 32 cm in each portion. Tiny cubes of 8 cm portion each is cut from that. Then how many tiny cubes will be formed that are surrounded by at least one cube?

Here x = 32/8 = 4 cm. so x - 2 = 4 - 2 = 2. Finally: 2 × 2 × 2 = 8. Hence answer is option A.

Tiny cubes having only two faces varnished = (x - 2) × number of edges = (6 - 2) × 12 = 4 × 12 = 48. Hence option D is the answer.

Q 3 - A big cube whose all the corners are named as A, B, C, D, E, F, G and H. Its each portion is of 50 cm length. The cube is segmented into tiny cubes and length of the portion of each tiny cube is 5 cm. Then how many such cubes are possible?

To find the number of tiny cubes first we have to find x. Here x = (50/5) = 10. So number of tiny cubes = 10 × 10 × 10 = 1000. Hence option D is the answer.

Q 4 - What will be length of the portion of tiny cubes, if each portion of the original big cube is 14 cm and the cube is segmented into 343 tiny ones?

Here number of tiny cubes = 343. Cube root of 343 = 7. So x = 7 cm.

2 = (14/portion of tiny cube) or portion of tiny cube = 14/7 = 2 cm.

Q 5 - What will be length of the portion of tiny cubes, if each portion of the original big cube is 4 cm and the cube is segmented into 125 tiny ones?

Number of tiny cubes = 125. Cube root of 125 = 5. So x = 5 cm. 5 = (4/portion of tiny cube) or portion of tiny cube = 4/5 = 0.8 cm.

Q 6 - A big cube whose all the corners are named as H, I, J, K, L, M, N and O. Its each portion is of 50 cm in length. The cube is segmented into tiny cubes and length of the portion of each tiny cube is 10 cm. How many such cubes are possible?

To find the number of tiny cubes, first we have to find x. So x = (50/10) = 5. So number of tiny cubes = 5 × 5 × 5 = 125. Hence option A is the correct answer.

Q 7 - What will be length of the portion of tiny cubes, if the original big cube having each portion of 40 cm is segmented into 125 tiny ones?

Total number of tiny cubes = 125. Cube root of 125 = 5. So x = 5 cm.

5 = (40/ portion of tiny cube) or portion of tiny cube = 40/5 = 8 cm.

Q 8 - What will be length of the portion of tiny cubes, if the original big cube having each portion of 45 cm is segmented into 729 tiny ones?

Total number of tiny cubes = 729. Cube root of 729 = 9. So x = 9 cm.

9 = (45/portion of tiny cube) or portion of tiny cube = 45/9 = 5 cm.

Q 9 - A big cube is segmented into tiny cubes and each portion of the tiny cubes are of equal length. The total number. of tiny cubes formed is 512. Each portion of the tiny cubes is 4 cm. Find out the length of each portion of the original bigger cube.

Total number of cubes = 512. Cube root of 512 is 8. So x = 8. By formula, portion of big cube = 8 × 4 = 32. Hence option A is correct.

Q 10 - A cube is segmented into 512 equal tiny cubes. Before dividing the cube, each face of it is varnished in different colours. How many tiny cubes will be formed having more than one colour?

Here x = Cube root of 512 = 8. More than one colour means two or more colours. So total number of cubes whose two faces are varnished is = (x - 2) × number of edges = (8 - 2) × 12 = 72. Total number of cubes whose three faces are varnished are the number of corners = 8. So total number of required cubes = 72 + 8 = 80. Hence option D is the answer.

reasoning_cube_and_cuboid.htm

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