Cube and Cuboid Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Cube and Cuboid. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A big cube is having 33 cm portion and the tiny cubes cut out of it is having 11 cm in each portion. Then how many tiny cubes will be formed such that each face of these cubes is surrounded by other cubes?

A - 10

B - 22

C - 3

D - 1

Answer : D

Explanation

Here x = 33/11 = 3. Such cubes can be found by following method. X 2 = 3 - 2 = 1 and 1 × 1 × 1 = 1. So, number of cubes will be formed such that each face of these cubes is surrounded by other cubes is only one.

Q 2 - How many cubes will be formed having all the four faces varnished?

A - 5

B - 8

C - 10

D - 0

Answer : D

Explanation

It is impossible to get four varnished faces out of a big cube. Hence answer is zero.

Q 3 - A big cube whose all the corners are named as A, B, C, D, E, F, G and H. Its each portion is of 50 cm length. The cube is segmented into tiny cubes and length of the portion of each tiny cube is 5 cm. Then how many such cubes are possible?

A - 1025

B - 185

C - 125

D - 1000

Answer : D

Explanation

To find the number of tiny cubes first we have to find x. Here x = (50/5) = 10. So number of tiny cubes = 10 × 10 × 10 = 1000. Hence option D is the answer.

Q 4 - Aishwarya has a cube which has length of 8 cm, breadth of 7 cm and height of 6 cm and is segmented into tiny cubes. How many such tiny cubes can be formed?

A - 360

B - 322

C - 370

D - 336

Answer : D

Explanation

Number of cubes can be formed = length × breadth × height

= 8 × 7 × 6 = 336.

Q 5 - A big cube is segmented into tiny cubes and each portion of the tiny cubes are of equal length. The total number of tiny cubes formed are 27. Each portion of the tiny cube is 3 cm. Then find out the length of each portion of the original bigger cube.

A - 12

B - 9

C - 8

D - 10

Answer : B

Explanation

Number of cube = 27. Cube root of 27 is 3. So x= 3. By formula, portion of big cube = 3 × 3 = 9. Hence option B is correct.

Q 6 - Two adjacent portions of a big cube are varnished in red and other two portion are varnished in yellow and the rest of the two portions are varnished in blue. The cube is segmented into 64 tiny and equal cubes.

How many tiny cubes will be formed having all the three colours?

A - 7

B - 9

C - 10

D - 8

Answer : D

Explanation

The number of corners is 8 hence answer for tiny cubes which have all the three colours are related to 8 corners. Hence option D is the correct answer.

Q 7 - What will be length of the portion of tiny cubes, if the original big cube having each portion of 40 cm is segmented into 125 tiny ones?

A - 5

B - 9

C - 4

D - 8

Answer : D

Explanation

Total number of tiny cubes = 125. Cube root of 125 = 5. So x = 5 cm.

5 = (40/ portion of tiny cube) or portion of tiny cube = 40/5 = 8 cm.

Q 8 - How many cubes will be formed having only two faces varnished?

A - 75

B - 65

C - 48

D - 72

Answer : D

Explanation

Tiny cubes having only two faces varnished = (x - 2) × number of edges = (8 - 2) × 12 = 6 × 12 = 72. Hence option D is the option.

Q 9 - A big cube is segmented into tiny cubes and each portion of the tiny cubes are of equal length. The total number. of tiny cubes formed is 512. Each portion of the tiny cubes is 4 cm. Find out the length of each portion of the original bigger cube.

A - 32

B - 39

C - 8

D - 10

Answer : A

Explanation

Total number of cubes = 512. Cube root of 512 is 8. So x = 8. By formula, portion of big cube = 8 × 4 = 32. Hence option A is correct.

Q 10 - A cube is segmented into 1331 equal tiny cubes. Before dividing the cube, each face of it is varnished in different colours. How many tiny cubes will be formed having more than one colour?

A - 164

B - 132

C - 116

D - 531

Answer : C

Explanation

Here x = Cube root of 1331 = 11. More than one colour means two or more colours. So total number of cubes whose two faces are varnished is = (x - 2) × number of edges = (11 - 2) × 12 = 108. The cubes having three faces varnished are the number of corners = 8. So total number of required cubes = 108 + 8 = 116. Hence option C is the answer.

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