# Cube and Cuboid Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Cube and Cuboid**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

### Answer : A

### Explanation

The answer is the number of corners available which is 8. Hence option A is the correct answer.

Q 2 - A big cube whose each corner is named as A, B, C, D, E, F, G and H is having each portion 30 cm. This cube is segmented into tiny cubes of portion 5 cm each. All the faces of the original big cube is varnished with white colour before being cut.

How many cubes will be formed having only one face varnished?

### Answer : D

### Explanation

Here x = 30/5 = 6. So number of tiny cubes can be formed is M = 6 × 6 × 6 = 216.

Cubes having only one face varnished is = (x - 2) × (x - 2) × number of faces = (6 - 2) × (6 - 2) × 6 = 4 × 4 × 6 = 96. Hence option D is the answer.

Q 3 - A big cube whose each corner is named as Q, R, S, T, U, V, W and X is having each portion of 20 cm. This cube is segmented into tiny cubes of portion 5 cm each. All the faces of the original big cube is varnished with blue colour before being cut.

How many cubes will be formed having only one face varnished?

### Answer : C

### Explanation

Here x = 20/5 = 4. So number of tiny cubes that can be formed is M = 4 × 4 × 4= 64.

Cubes having only one face varnished is = (x - 2) × (x - 2) × number of faces = (4 - 2) × (4-2) × 6 = 2 × 2 × 6 = 24. Hence option C is the answer.

Q 4 - Stalin has a cube whose each portion is of 24 cm. If he wants to cut tiny cubes of portion 8 cm each, then how many such cubes will be possible for him?

### Answer : B

### Explanation

Here x = (24/8) = 3

So number of cubes = 3 × 3 × 3 = 27. Hence option B is correct.

Q 5 - Mita has a cube whose each portion is of 6 cm. If she wants to cut tiny cubes of portion 1.5 cm each, then how many such cubes will be possible for her?

### Answer : A

### Explanation

x = (6/1.5) = 4

So number of tiny cubes = 4 × 4 × 4 = 64. Hence option A is correct.

Q 6 - Two adjacent portions of a big cube are varnished in red and other two portion are varnished in yellow and the rest of the two portions are varnished in blue. The cube is segmented into 64 tiny and equal cubes.

How many tiny cubes will be formed having all the three colours?

### Answer : D

### Explanation

The number of corners is 8 hence answer for tiny cubes which have all the three colours are related to 8 corners. Hence option D is the correct answer.

Q 7 - What will be length of the portion of tiny cubes, if the original big cube having each portion of 40 cm is segmented into 125 tiny ones?

### Answer : D

### Explanation

Total number of tiny cubes = 125. Cube root of 125 = 5. So x = 5 cm.

5 = (40/ portion of tiny cube) or portion of tiny cube = 40/5 = 8 cm.

Q 8 - Radhamohan has a cube which has length of 15 cm, breadth of 4 cm, and height of 2 cm and is segmented into tiny cubes. How many such tiny cubes can be formed?

### Answer : B

### Explanation

Number of cubes can be formed = length × breadth × height

= 15 × 4 × 2 = 120.

Q 9 - A big cube is segmented into tiny cubes and each portion of the tiny cubes is of equal length. The total number of tiny cubes formed is 8. Each portion of the tiny cubes is 1 cm. Find out the length of each portion of the original bigger cube.

### Answer : D

### Explanation

Total number of tiny cubes is = 8. Cube root of 8 is 2. So x = 2. By formula portion of big cube = 2 × 1 = 2. Hence option D is correct.

Q 10 - A cube is segmented into 1331 equal tiny cubes. Before dividing the cube, each face of it is varnished in different colours. How many tiny cubes will be formed having more than one colour?

### Answer : C

### Explanation

Here x = Cube root of 1331 = 11. More than one colour means two or more colours. So total number of cubes whose two faces are varnished is = (x - 2) × number of edges = (11 - 2) × 12 = 108. The cubes having three faces varnished are the number of corners = 8. So total number of required cubes = 108 + 8 = 116. Hence option C is the answer.