Calendar Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Calendar. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - Today is Saturday, what will be the day after 90 days?

Answer : B

Explanation

Every day of the week is repeated after 7 days. Hence, it will be Saturday again after 84 days because 12 × 7 = 84. After 6 days, the day will be Friday. Hence, option B is correct.

Q 2 - How many days are there in between 11^th January and 23^rd April including both the days?

Answer : A

Explanation

Here both dates are included so in January total 21 days. Here we assume that the year is not a leap year so February has 28 days, March has 31 days and April has 23 days. So total 103 days. Hence, option A is correct.

Q 3 - If 12^th June falls on Thursday then on which day 24^th August will fall?

Answer : C

Explanation

The number of days between these two dates is 73. Every day of the week is repeated after 7 days. Hence, it will be Thursday after 70 days because 10 × 7 = 70. After 3 days, it will be Sunday. Hence option C is correct.

Q 4 - Find the day of the week on 12^th March 1982.

Answer : A

Explanation

12^th March 1982 has 1981 years, 2 months and 12 days. Now 1600 years have no odd days and 300 years have 1 odd day. The rest 81 years contain 20 leap years and 61 ordinary years so total number of days in 81 years is

(20 × 366 + 61 × 365) days

= 29585 days = 29585/7 = 4226 weeks and 3 days. It means 81 years contain 3 odd days.

2 months and 12 days = 71 days which is equal to 10 weeks + 1 odd day so 1 + 3 + 1 = 5. 5 odd days means that day is Friday. Hence option A is correct.

Q 5 - Find the day of the week on 15^th August 1999.

Answer : B

Explanation

15^th August 1999 have 1998 years, 7 months and 15 days. First 1600 years have no odd days. The next 300 years have one odd day. The rest 98 years have 24 leap years and 74 ordinary years. So total number of days in 98 years can be calculated as follows:

(24 × 366 + 74 × 365)

= 8784 + 27010 = 35794

Total number of odd days in 98 years = 35794/7 = 5113 weeks and 3 odd days

The remaining 7 months and 15 days have 227 days

Number of odd days = 227 / 7 = 32 weeks and 3 days

Total number of odd days = 3 + 3 + 1 =7

So 15^th August 1999 was on Sunday.

Q 6 - How many days are there in between 2^nd January and 24^th February including both the days?

Answer : B

Explanation

Here both dates are included so in January total 30 days, and February 24 days. So there are 54 days in between the given dates. Hence, option B is correct.

Q 7 - Find the day of the week on 29^th August 1972.

Answer : D

Explanation

By calculating the number of odd days from years, months, and days we can say that 29^th August 1972 was on Tuesday.

Q 8 - Today is St. Josephs annual function which is Monday, St. Xaviers annual function will be after 22 days. On what day it will be celebrated?

Answer : B

Explanation

Every day of the week is repeated after 7 days. Hence, it will be Monday after 21 days because 3 × 7 = 21. After one day the day will be on Tuesday on which St. Xaviers annual function will be observed.

Q 9 - How many days are there in between the dates 1^st April and 21^st April?

Answer : C

Explanation

Here both the given dates are not inclusive. So there are 19 days between the given dates.

Q 10 - On Thursday, volleyball tournament took place. Next it will be played after 21 days. On which day it will be played?

Answer : D

Explanation

Every day of the week is repeated after 7 days. Hence, it will be Thursday after 21 days because 3 × 7 = 21.

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