- Aptitude - Home
- Aptitude - Overview
- Quantitative Aptitude
Aptitude Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Aptitude. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - The length, expansiveness and tallness of a cuboid are in the proportion 6:5:4 and its entire surface region is 33300 cm2. Its volume is:
Answer : B
Explanation
Let length = 6x cm, breadth = 5x cm and height = 4x cm Whole surface area = 2(lb+ bh + lh) =2 (6x*5x + 5x *4x + 6x *4x) cm2 = (148x2) cm2 ∴148x2= 33300 ⇒x2 = 225 ⇒x = √225 = 15 cm ∴L= 90 cm , B= 75 cm and h= 60 cm ∴Volume = (L*b*h) = (90*75*60) =405000cm3
Q 2 - Rs. 6000 adds up to Rs. 7920 in 4 years at a sure rate of interest. On the off chance that the rate gets to be 1.5 times of itself, the measure of the same rule in 5 years will be:
Answer : B
Explanation
P = Rs. 6000, S.I = Rs. (7920-6000) = Rs. 1920, T= 4 years. R = (100*1920/6000*4) = 8% p.a. New rate = (1.5*8) % p.a. = 12% p.a. Now = Rs. 6000, R= 12% p.a. and T = 5 years. S.I = Rs. (6000*12/100*5) = Rs.3600 Amount = (6000+3600) = Rs. 9600.
Q 3 - By selling a Book for Rs.20, a man loses one eleventh of what it costs him. The cost of the Book is
Answer : A
Explanation
Let us assume cost price is X i.e., X - 20 = ( 1)/11 X =>X=22
Answer : C
Explanation
y = 935421 x 625 = 935421 x (5)4 = 935421 x (10/2)4 = (935421 x (10)4)/(2)4) = 935421 x 10000 / 16 = 9354210000 / 16 = 584638125
Answer : C
Explanation
Using formula (13 + 23 ... + n3) = [(1/2)n(n+1]2 (13 + 23 ... + 203) = [(20 x 21)/2]2 = 2102 = 44100 Using formula (1 + 2 + ... n) = [(1/2)n(n+1] ∴ (13 + 23 ... + 153) - (1 + 2 + ... + 15) = 44100 - (1/2) x 15 x 16 = 44100 - 120 = 43980
Q 6 - on what dates of April, 2001 did Wednesday fall?
Answer : D
Explanation
We might discover the day on first April, 2001. First April , 2001=(2000 year + Period structure 1.1.2001 to 1.4.2001) Odd days in 1600 years =0. Odd days in 400 year =0. Jan Feb March April 31 + 28 + 31 + 1 = 91 days =0 odd day. Aggregate number of odd days= (0+0+0) =0. On first April, 2001 it was Sunday. In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.
Directions: The following bar diagram given below shows the result of B.S.C students of a collage for three years. Study the bar diagram and answer the questions given below:
Answer - D
Explanation
Pass% in 2005 = (1500/1800*100)%= 250/3% = 83.33%
Q 8 - A man observes the elevation of a balloon to be 45° at a point A .He then walks towards the balloon and at a certain place B finds the elevation to be 60°. He further walks in the direction of the balloon and finds it to be directly over him at a height of 450 m. Distance travelled from A to B is
Answer : A
Explanation
450/BD= tan (60) =>BD =450/√3 450/AD= tan (30) =>AD= 450√3 AD =BD +AB =>AB=AD-BD= 450√3-450/√3=(450x3-450)/√3=300√3m
Directions: Study the graph below carefully and answer the following:
Q 9 - Deals in the year 2004 for organization A structures what % of aggregate offers of organization A for every one of the years together?
Answer - A
Explanation
Total sale of Company A in 2004 =1100 Total sale of A during These years = (600+900+300+600+1100+1000+1100)= 5600 Required % = (1100/5600*100) % = 19.64%
Directions: The diagram given below depicts the sourced and uses of funds in a public Sector Enterprise. The total outlay is Rs. 4000 crore:
Q 10 - The aggregate sum which has been utilized for purchasing area, apparatus, setting plants and capital works is roughly.
Answer - B
Explanation
Required Amount = 75.6% of 4000 crores. = (75.6/100*4000) = 3024 crore= Rs. 3000 crore.