Aptitude Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Aptitude. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A divider 24m long , 8 m high and 60cm thick is comprised of blocks, every measuring 24cm * 12cm *8cm , it being given that 10% of the divider comprises of mortar. What number of blocks will be required?

A - 50000

B - 45000

C - 40000

D - 20000

Answer : B

Explanation

Volume of wall = (24*8*60/100)m3 =576/5m3
Volume of bricks = (90% of 576/5) m3= (90/100*576/5) m3= (144*18/25) m3
Volume if 1 bricks = (24/100*12/100*8/100) m3
Number of bricks = [(144*18/25)*100/24*100/12*100/8) = 45000

Q 2 - An acquires Rs 8000 at 12% p.a simple interest and B gets Rs 9100 at 10%p.a. simple interest . In how long will their measures of obligations be equivalent?

A - 18 years

B - 20 years

C - 22 years

D - 24 years

Answer : C

Explanation

Let the required time be x years. Then,
8000+8000*12/100*x= 9100+9100*10/100*x
=> 50x =1100 => x= 22 years

Q 3 - { 1+1/1+ 1/(1+1/3) } / 11/7 = ?

A - 1

B - 4/3

C - 5/4

D - 8/7

Answer : A

Explanation

given exp.   = { 1+  1/ (1+1/(4/3)} /11/7
= { 1+  1/( 1+3/4)} /11/7
= [ 1+ 1/(7/4)]/11/7
= (1+4/7) /11/7
= 11/7 /11/7
= 1

Q 4 - 12846 x 593 + 12846 x 407 = y. What is y?

A - 12846000

B - 14203706

C - 24038606

D - 24064000

Answer : A

Explanation

  y = 12846 x 593 + 12846 x 407  = 12846 x (593 + 407)  = 12846 x 1000  = 12846000  

Q 5 - The average weight of 45 students in a class is 52kg. Five of them whose average weight is 48 kg leave the class and other 5 students whose average weight is 54kg join the class. What is the new average weight (in kg) of the class?

A - 5223

B - 5212

C - 5213

D - 5214

Answer - A

Explanation

Sum of the weights of the students after replacement. 
= [(52 x 45) - (48 x 5) + (54 x 5)] kg = 2370kg. 

Therefore, new Average = 237045kg = 5323kg

Q 6 - The last day of a century can't be:

A - Monday

B - Wednesday

C - Tuesday

D - Friday

Answer : C

Explanation

100 years contain 5 odd days.
∴ Last day of first century is Friday. 

200 years contain (5*2) = 3 odd days.
∴ Last day of second century is Wednesday.

300 year contain (5*3) =15=1 odd day.
∴ Last day of third century is Monday.

400 year contain 0 odd days.
∴ Last day of fourth century is Sunday.

The cycle is repeated.
∴ Last day of a century can't be Tuesday or Thursday or Saturday.

Directions: The following bar diagram given below shows the result of B.S.C students of a collage for three years. Study the bar diagram and answer the questions given below:

Result of B.S.C students

Q 35 - Which is the following is the aggregate pass percentage during 3 years?

A - 51.66%

B - 82.9%

C - 80.4%

D - 77.6%

Answer - B

Explanation

Required % =  { (1500+1600+1750)/(1800+2000+2050)*100} = (4850/5850*100)%  = 82.9%

Q 8 - At what time between 2 and 3 o' clock will the hands of a clock be together?

A - 120/11 min past 2

B - 10 min past 2

C - 11 min past 2

D - None of these

Answer : A

Explanation

At 2 o' clock, the hour hand is at 2 and minute hand is at 12
i.e. they are 10 min spaces apart.
The minute hand has to gain 10 minute spaces
over the hour hand to be together.

The minute hand gains 55 mins in 60 mins.
∴ It will gain 10 mins in 60/55 * 10 min
= 120/11 minutes.

Hence the hands will coincide at 120/11 minutes past 2.

Q 9 - In 1 minute 3/7 of a basin is filled. Whatever remains of the container can be filled in:

A - 2 min

B - 4/3 min

C - 7/3 min

D - none of these

Answer : B

Explanation

Part filled in 1 min. = 3/7. remaining part = (1- 3/7)= 4/7
Let the required time be x min.
More part, more time taken. (Direct)
3/7: 4/7:: 1: x ⇒ 3x/7 = (4/7*1) ⇒ x= 4/3 min.

Q 10 - If in a examination condition of marks is that for the right answer student gets 3 marks but reduce 2 marks for every wrong answer . if 30 questions attempted and 40 marks gets by the student. Find out the number of question correctly done by the student.

A - 19

B - 20

C - 21

D - 22

Answer : B

Explanation

Let correctly attempted questions be x. Then ,
3x-2 (30-x) = 40 ⇒  5x = 100  ⇒ x = 20.
Hence, 20 question  correctly done by  the  student.

aptitude_questions_answers.htm
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