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Aptitude - Pipes & Cisterns Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Pipes & Cisterns. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - Two funnels can fill a tank in 20 minutes and 30 minutes separately. On the off chance that both the channels are opened at the same time, then the tank will be filled in:
Answer : B
Explanation
Part filled by both pipes in 1 min. =(1/20+ 1/30)= 5/60 = 1/12 Time taken to fill the tank = 12 minutes
Q 2 - A tank can be filled by a tap in 20 minutes and by another tap in an hour. Both the taps are kept open for 10 minutes and after that the first tap is shutoff. After this, the tank will be totally filled in:
Answer : D
Explanation
Part of the tank filled by both in 10 min. = 10*(1/20+1/60)= 40/60 = 2/3 Remaining part = (1-2/3) = 1/3 1/60 part is now filled in 1 min. 1/3 part is now filled in (60*1/3) min. = 20 min.
Q 3 - A funnel can discharge a tank in 40 minutes. A second pipe with distance across twice as much as that of the first is likewise joined with the tank to purge it. The two together can exhaust the tank in:
Answer : B
Explanation
A pipe with double diameter will take half time. So, the second pipe can empty the full tank in 20 min. Part emptied by both in 1 min. (1/40+ 1/20) = 3/40 Time taken to empty the full tank = 40/3 min.
Q 4 - Two pipes A and B can fill a tank in 15 minutes and 20 minutes separately. Both the channels are opened together. Be that as it may, following 4 minutes, pipe is turned off. What is the aggregate time required to fill the tank?
Answer : D
Explanation
Part filled by both in 4 min. = 4*(1/15+1/20)= (4*7/60)= 7/15 Part unfilled = (1-7/15) = 8/15 1/20 part is filled by B in 1 min. 8/15 part is filled by B in (20*8/15) min. = 32/3 min = 10 min 40 sec. Total time taken = (4 min+10 min 40 sec.) = 14 min 40 sec.
Q 5 - A reservoir has three channels A, B and C. A and B can fill it in 3 hrs and 4 hrs. individually while C can exhaust the totally filled reservoir in 1 hours. On the off chance that the funnels are opened all together at 3 pm, 4 pm and 5 pm individually, at what the truth will surface eventually reservoir void?
Answer : B
Explanation
Let the cistern be emptied in x hrs after 3 pm Work done by A in x hrs, by B in(x-1) hrs and by C in (x-2) hrs= 0 ⇒x/3 +x-1/4 ? (x-2) =0 ⇒ 4x+3(x-1)-12(x-2) = 0 ⇒5x=21 ⇒x= 4 hrs 12 min. Required time is 7.12 pm.
Q 6 - A tap can fill a tank in 6 hours. After a large portion of the tank is filled, three more comparable taps are opened. What is the aggregate time taken to fill the tank totally?
Answer : B
Explanation
Time taken by the tap to make the tank half full= 3 hrs. Remaining part = 1/2 Part filled by 4 taps in 1 hour= (4*1/6) = 2/3 2/3 part is filled in 1 hour. 1/2 part is filled in (3/2*1/2) hr = 3/4 hr = 45 min. Required time = 3hrs 45 min.
Q 7 - If two funnels work at the same time, the repository will be filled in 12 hours. One channel fills the store 10 hours quicker than the request. How long does the speedier funnel take to fill the store?
Answer : C
Explanation
Suppose that one pipe takes x hours to fill the reservoir. Than the other pipes takes (x-10) hours. ∴ 1/x+ 1/(x-10) = 1/12 ⇒12(x-10+x)= x(x-10) ⇒x2-34x +120=0 ⇒(x-30) (X-4) =0 ⇒x= 30 or x= 4 So, the faster pipe takes 30 hrs to fill the reservoir.
Q 8 - A channel can fill a reservoir in 12 minutes and another funnel can fill it in 15 minutes, however a third pipe can discharge it in 6 minutes. The initial two funnels are kept open for 5 minute to start with and after that the third pipe is additionally opened. In what time is the storage exhausted?
Answer : D
Explanation
Part filled in 5 min= 5*(1/12+1/15)= (5*9/60)= 3/4 Part emptied in 1 min. when all the pipes are opened= 1/6 ? (1/12+1/15) = (1/6- 3/20) = 1/60 1/60 part is emptied in 1 min. 3/4 part will be emptied in (60*3/4) min = 45 min.
Q 9 - A pump can fill a tank with water in 2 hours. Because of a leak in the tank, it takes 7/3 hours to fill the tank. The leak can empty the filled tank in?
Answer : D
Explanation
Part of the tank filled by the pump in 1 hour = 1/2 Part of the tank filled by the pump in 1 hour because of the leak = 3/7 ∴ Part of the tank emptied by the leak in 1 hour = 1/2 - 3/7 = 1/14 ∴ Leak will empty the tank in 14 hours.
Q 10 - Taps A, B and C are connected to a water tank and the rate of flow of water is 42 ltr/hr, 56 ltr/hr and 48 ltr/hr respectively. A and ill fill the tank while tap C empties the tank. If the three taps are opened simultaneously, the tank gets filled up completely in 16 hours. What is the capacity of the tank?
Answer : A
Explanation
Net amount of water filled in 1 hr when all the pipes are opened simultaneously = 42 + 56 ? 48 = 50 ltr Tank gets completely filled in 16 hrs. ∴ Capacity of tank = 16*50 = 800 liters.