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Trains - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Trains. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - A train 132m long passes a telegraph post in 6 seconds. The speed of the train is
Answer : C
Explanation
speed =(132/6)m/sec =22 m/sec. =(22*18/5) kmph = (396/5) = 79.2 kmph
Q 2 - How much time will a train 171 m long take to cross a bridge 229 m long , if it is running at a speed of 45 kmph?
Answer : C
Explanation
Speed = (45*5/18)m/sec = 25/2 m/sec. Required time =(171+229)/(25/2) sec. = (400*2/25)sec. =32 sec.
Q 3 - A train 100 m long moving at a speed of 50km/hr crosses a train 120m long coming from opposite side on parallel tracks in 6 sec. The speed of the second train is
Answer : B
Explanation
let the speed of the second train be x kmph.
Their relative speed = (50+x) kmph ={ (50+x)* 5/18) m/sec.
Sum of their lengths = (100+120)m =220 m
220/ [(50+x)*5/18] = 6 ⇒30 (50+x)= 3960
⇒ 30x =(3960-1500) = 2460
X = 82
Speed of the second train = 82 kmph.
Q 4 - Two trains are running in opposite directions at 36kmph and 45kmph cross each other in 20 sec. if one train is 200m long, the length of the other train is
Answer : D
Explanation
let the length of the other train be x meters. Sum of their length =(200+x)m Relative speed =(36+45) kmph =81kmph = (81*5/18)m/sec. = 45/2 m/sec. (200+x)/ (45/2) = 20 ⇒ 400 +2x = 900 ⇒ 2x = 500 ⇒ x = 250 ∴ length of the other train is 250m
Q 5 - A train moving at the rate of 36 km per hour crosses a standing man in 10 sec. It will cross a platform 55m long, in
Answer : D
Explanation
speed of the train = (36*5/18)m/sec. =10m/sec. Let the length of the second train be x meters. Then, x/10 =10 ⇒ x =100m Time taken by the train to cross the platform = (100+55)/10 sec.=31/2 sec.
Q 6 - A train is running at the rate of 40kmph. A man is going in the same direction parallel to the train at 25kmph . If the train crosses the man in 48 sec. , the length of the train is
Answer : D
Explanation
relative speed = (40-25)kmph =15kmph =(15*5/18) m/sec. =25/6 m/sec. Length of the train = (25/6*48)m= 200 m.
Q 7 - A train X speeding with 120kmph cross another train Y, running in the same direction, in 2 min. If the length of the trains X and Y be 100 m and 200m respectively, What is the speed of train Y
Answer : A
Explanation
let the speed of train y be x km/hr. Speed of x relative to y =(120-x) km/hr =[ (120-x)*5/18]m/sec. = (600-5x)/18 m/sec. 300/ (600-5x)/18 =120 ⇒120 (600-5x) =5400 ⇒ 600-5x =45 ⇒ 5x =555 ⇒ x =111 Speed of train y = 111km/hr