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Aptitude - Number System Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Number System. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : C
Explanation
Unit digit in 735 = (74)8 x 73
= 1 x 3 = 3
Unit digit in 348 = (34)12
= 1
Therefore, unit digit in 735 - 348 = 3 - 1 = 2
Answer : A
Explanation
Divisibility by 11: If the difference between the sum of digits at odd places and the sum of its digits at even places is either 0 or a number divisible by 11.
(9 + 5 + 4) - (1 + 5 + 1) = 11 i.e. exactly divisible by 11.
(7 + 6) - (2 + 3) is not divisible by 11.
(6 + 3) - (4 + 3) is not divisible by 11.
(7 + 3 + 4) - (6 + 9 +1) is not divisible by 11.
Q 3 - On dividing a number by 5, we get remainder as 3. What will be the remainder when the square of this number is divided by 5?
Answer : D
Explanation
Let number be p
Dividing p by 5, we get k as quotient and remainder as 3
p = 5k + 3 ->
p2 = (5k + 3)2 p = (25k2 + 30k + 9)
p = 5 (5k2 + 6k + 1) + 4
Therefore, we get 4 as remainder on dividing p2 by 5.
Q 4 - It is being given that (232) + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
Answer : C
Explanation
Let 232 = p
-> (232 + 1) = p + 1
Let (p + 1) be completely divisible by natural number Z. Then->
(296 + 1) = [(232)3 + 1]
As (p3 + 1) = (p + 1)(p2 - p + 1), which is completely divisible by Z, since (p + 1) is completely divisible by Z.
Answer : A
Explanation
a = 6, d = 9, l = 123
Let number of terms be n
123 = a + (n - 1)d
123 = 6 + (n - 1)9
123 = 9n - 9
n = 14
Sn = n⁄2 (a + l)
= 14⁄2 (6 + 123)
= 7 x 129
= 903
Answer : B
Explanation
Multiply unit digits of each number. Unit digit in 549 x 56 x 28p x 684 = 8 Unit digit in 9 x 6 x p x 4 = 8 Unit digit in 216 x p = 8 Thus p must be 3.
Answer : C
Explanation
Using formula for sum of natural numbers (1 + 2 + 3 +... + n) = (1/2)n(n+1) (45 + 46 + 47 + ... + 114 + 115) = (1 + 2 + 3 +... + 115) - (1 + 2 + 3 + ... + 44) = (1/2) x 115 x 116 - (1/2) x 44 x 45 = 115 x 58 - 22 x 45 = 6670 - 990 = 5680
Answer : C
Explanation
y = 1499 x 1499 = (1500-1) x (1500 -1) = (1500-1)2 Using formulae (a-b)2 = a2 + b2 - 2ab ∴ y = (1500)2 + (1)2 - 2 x 1500 x 1 = 2250000 + 1 - 3000 = 2247001
Answer : D
Explanation
91. As it is divisible by 7.
Q 10 - What is the common factor in (4743 + 4343) and (4747 + 4347)
Answer : B
Explanation
an + bn is divisible by a + b if n is an odd number. ∴ each number is divisible by (47 + 43).