- Aptitude - Home
- Aptitude - Overview
- Quantitative Aptitude
Aptitude - Co-ordinate Geometry Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Co-ordinate Geometry. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - On which pivot does the point (6, 0) lies?
Answer : A
Explanation
The point lies on (6, 0) lies on x-axis.
Q 2 - The separation of the point A (7, 4) and B (0, a) is:
Answer : D
Explanation
AB2 = (7-3)2+ (4-1)2 = (42+32) = (16+9) =25 ⇒ AB= √25 = 5 unit.
Q 3 - P is a point on x-hub at a separation of 3 units from y-pivot on its right side. The co-ordinates of P are:
Answer : A
Explanation
Clearly, the co-ordinates of P are P (3, 0).
Q 4 - The focuses A (- 3, 0), B (1, - 3) and C (4, 1) are the vertices of
Answer : B
Explanation
AB2= (1+3) 2+ (-3-0) 2= 16+9= 25 BC2= (4-1) 2+ (1+3) 2=9+16= 25 AC2= (4+3) 2+ (1-0) 2= 49+1= 50 Clearly, AB= BC and AB2+BC2= AC2 ∴ ∆ABC is ab isosceles right angle triangle.
Q 5 - In the event that the focuses A(1,- 1) , B(5,2) and C(ℏ,5) are collinear , then ℏ=?
Answer : C
Explanation
Here x₁=1, x₂= 5, Xᴈ = ℏ, y₁ =-1, y₂= 2 and Yᴈ = 5 ∆ = 1/2 [x₁(y₂-Yᴈ) +x₂(Yᴈ-y₁) +Xᴈ (y₁-y₂)] 1. (2-5) +5(5+1) +ℏ (-1-2) = 0 -3+30-3ℏ=0 3ℏ =27 ℏ =0
Q 6 - Two vertices of a ∆ ABC are B (- 3, 1) and C (0, - 2) and its centroid is at the inception. The Third vertex A is:
Answer : A
Explanation
Let the vertex A be (a, b). Then, 1/3 (-3+0+a) =0 and 1/3 (1-2+b) =0 = -3 +a =0 and -1 +b=0 ⇒ a=3 and b= 1 ∴ Vertex A is A (3, 1)
Q 7 - x-pivot partitions the join of A (2, 3) and B (5, 6) in the proportion
Answer : A
Explanation
Let the required ratio be ℏ:1. Then, its co- ordinates are (5ℏ+2/ ℏ+1, 6ℏ-3/ℏ+1) But, it lies on x-axis. So, its ordinate is 0. ∴ 6ℏ-3/ℏ+1 =0 ⇒ 6ℏ-3 =0 ⇒ ℏ=1/2 Required ratio is 1/2:1 i.e., 1:2
Q 8 - A line goes through the focuses A (- 2, 3) and B (- 6, 5). The slop of line AB is
Answer : A
Explanation
Slop = (y₁ ?y₂)/( x₁-x₂) = (5-3)/(-6+2) = 2/-4 =-1/2
Q 9 - On the off chance that the slant of a line joining the focuses A(x,- 3) and B(2,5) is 135⁰ then x=?
Answer : D
Explanation
Slop of AB = (5+3)/(2-x) =8/2-x ∴ 8/2-x = tan135⁰ = tan (180⁰- 45⁰) = -tan 45⁰ =-1 8/2-x = -1 ⇒8 = x-2 ⇒ x= 10
Q 10 - The lines x+2y-9 =0 and 3x+6y+8 =0 are commonly.
Answer : A
Explanation
x+2y-9 =0 ⇒ 2y = -x+9 ⇒ y= -x/2+9/2 3x+6y+8 =0 ⇒ 6y= -3x-8 ⇒ y=-x/2 -4/3 ∴ m₁: m₂ = -1/2 Hence, the given lines are parallel.