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Aptitude - Co-ordinate Geometry Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Co-ordinate Geometry. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : A
Explanation
The Point (2, 5) lies in 1st quadrant
Q 2 - The separation of the point A (- 5, 0) from the beginning is:
Answer : A
Explanation
OA = √ (0+5)2+ (0+0)2 = √ 25 = 5 unit.
Q 3 - P is a point on x-hub at a separation of 3 units from y-pivot on its right side. The co-ordinates of P are:
Answer : A
Explanation
Clearly, the co-ordinates of P are P (3, 0).
Q 4 - The vertices of a quadrilateral ABCD are A(0,0) ,B(4,4) ,C(4,8) and D(0,4).Then ABCD is a
Answer : D
Explanation
AB2= (4-0) 2+ (4-0) 2= 32 BC2= (4-4) 2+ (8-4) 2= 0+16= 16 CD2= (0-4) 2+ (4-8) 2= (16+16) = 32 AB= CD= √32 = 4√2, BC= AD =√16 = 4 AC2= (4-0) 2+ (8-0) 2= (16+64) = 80 BD2= (0-4) 2+ (4-4) 2= 16+0= 16 ∴ Diag = AC≠Diag BD. ∴ ABCD is a parallelogram.
Q 5 - The end purposes of the distance across of a circle are A (4,- 1) and B(- 2,- 5). The co-ordinates of its middle are:
Answer : A
Explanation
Co-ordinates of the center are [4+ (-2)/2, -1+ (-5)/2], i.e. (1,-3)
Q 6 - Two vertices of a ∆ ABC are B (- 3, 1) and C (0, - 2) and its centroid is at the inception. The Third vertex A is:
Answer : A
Explanation
Let the vertex A be (a, b). Then, 1/3 (-3+0+a) =0 and 1/3 (1-2+b) =0 = -3 +a =0 and -1 +b=0 ⇒ a=3 and b= 1 ∴ Vertex A is A (3, 1)
Answer : C
Explanation
The slop of a vertical line is not defined.
Q 8 - On the off chance that for a line m= tan ℴ>0, then
Answer : C
Explanation
m tan ℴ>0 ⇒ℴ is acute.
Q 9 - The slop of a line going through the focuses A (3, - 1) and B (3, 2) is:
Answer : C
Explanation
Slop = (y₁ ?y₂)/( x₁-x₂) = (2+1)/ (3-3) = 3/0, which is not defined
Q 10 - The lines 3x-4y+6 =0 and 4x+3y-10 =0 are mutually.
Answer : D
Explanation
3x-4y+6 = 0 ⇒ 4y = 3x+6 ⇒ y =3x/4 +3/2 4x+3y -10 =0 ⇒ 3y= -4x+10 ⇒ y = -4x/3 + 10/3 ∴ m₁ = 3/4 and m₂ = -4/3. So, m₁m₂= -1