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Aptitude - Co-ordinate Geometry Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Co-ordinate Geometry. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - In which quadrant does the point (2, 5) lies?

Answer : A

Explanation

The Point (2, 5) lies in 1st quadrant

Q 2 - The separation of the point p (8, - 6) from the beginning is:

Answer : C

Explanation

Op = √ (8-0)²+ (-6-0)² = √64+ 36    = √100 =10 unit

Q 3 - In the event that the separation of the point p(x, y) from A (a, 0) is a+x, then y²=?

Answer : B

Explanation

(x-a) ²+(y-o) ²= a+x
⇒ (x-a) ²+y²= (a+x) ²⇒y²=(x+a) ²-(x-a) ²= 4ax ⇒ y²=4ax

Q 4 - The vertices of a quadrilateral ABCD are A(0,0) ,B(4,4) ,C(4,8) and D(0,4).Then ABCD is a

Answer : D

Explanation


AB²= (4-0) ²+ (4-0) ²= 32
 BC²= (4-4) ²+ (8-4) ²= 0+16= 16
 CD²= (0-4) ²+ (4-8) ²= (16+16) = 32
 AB= CD= √32 = 4√2, BC= AD =√16 = 4
 AC²= (4-0) ²+ (8-0) ²= (16+64) = 80
 BD²= (0-4) ²+ (4-4) ²= 16+0= 16
 ∴ Diag = AC≠Diag BD.
 ∴ ABCD is a parallelogram.

Q 5 - In the event that the focuses A(1,- 1) , B(5,2) and C(ℏ,5) are collinear , then ℏ=?

Answer : C

Explanation

Here x₁=1, x₂= 5, Xᴈ = ℏ, y₁ =-1, y₂= 2 and Yᴈ = 5
 ∆ = 1/2 [x₁(y₂-Yᴈ) +x₂(Yᴈ-y₁) +Xᴈ (y₁-y₂)]
  1. (2-5) +5(5+1) +ℏ (-1-2) = 0
  -3+30-3ℏ=0   3ℏ =27  ℏ =0

Q 6 - A point C partitions the join Of A (1, 3) and B (2, 7) in the proportion 3:4. The co-ordinates of C are:

Answer : C

Explanation

Co-ordinates of C are [(5*2+4*1/3+4), (3*7+4*3/ 3+4) i.e. (10/7, 33/7)

Q 7 - The slop of a flat line is

Answer : A

Explanation

The slop of a horizontal line is m= tan ℴ =0

Q 8 - On the off chance that for a line m= tan ℴ>0, then

Answer : C

Explanation

m tan ℴ>0 ⇒ℴ is acute.

Q 9 - On the off chance that the slant of a line joining the focuses A(x,- 3) and B(2,5) is 135⁰ then x=?

Answer : D

Explanation

Slop of AB = (5+3)/(2-x) =8/2-x
 ∴ 8/2-x = tan135⁰ = tan (180⁰- 45⁰) = -tan 45⁰ =-1 
8/2-x = -1 ⇒8 = x-2 ⇒ x= 10

Q 10 - The lines 3x-4y+6 =0 and 4x+3y-10 =0 are mutually.

Answer : D

Explanation

3x-4y+6 = 0 ⇒ 4y = 3x+6 ⇒ y =3x/4 +3/2
 4x+3y -10 =0 ⇒ 3y= -4x+10 ⇒ y = -4x/3 + 10/3
 ∴ m₁ = 3/4 and m₂ = -4/3. So, m₁m₂= -1

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