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H.C.F & L.C.M. - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to H.C.F & L.C.M.. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - Find L.C.M and H.C.F of 0.63, 1.05 and 2.1.
Answer : D
Explanation
Making the same number of decimal places, the given numbers are 0.63, 1.05 and 2.10. without decimal places, these numbers are 63, 105, and 210 Now, H.C.F of 63, 105 and 210 is 21 so H.C.F of 0.63, 1.05 and 2.1 is 0.21 L.C.M of 63, 105 and 210 is 630 so L.C.M of 0.63, 1.05 and 2.1 is 6.30
Q 2 - Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are?
Answer : B
Explanation
Let the required numbers be z, 2z, and 3z. Then, their H.C.F = z So, z = 12. Therefore The number are 12, 24 and 36.
Q 3 - The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above conditions is?
Answer : A
Explanation
Let the numbers be 33a and 33b. then 33a + 33b = 528 a + b = 16. Now, co-primes with product 16 are (1,15) (3,13) (5,11) and (7,9) So, the required numbers are (33 x 1, 33 x 15) (33 x 3, 33 x 13) (33 x 5, 33 x 11) (33 x 7, 33 x 9) the number of such pairs is 4.
Q 4 - The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of the numbers is 275, then the other is?
Answer : B
Explanation
Other number = 11 x 7700⁄275 = 308
Q 5 - Find the greatest number that will divide 43, 91, and 183 so as to leave the same remainder in each case.
Answer : C
Explanation
Required number = H.C.F of (91 - 43), (183 - 12) and (183 - 43) = H.C.F of 48, 92, and 140 = 4
Q 6 - Find the greatest number which can divide 103 and 199 leaving the same remainder 7 in each case.
Answer : D
Explanation
Required number = H.C.F. of [(103-7) and (199-7)] = H.C.F. of (96 and 192) = H.C.F. of (25*3 and 26*3) = H.C.F. of (25*3 and 25*3*2) = 25*3=96
Q 7 - If the sum of two numbers is 175 and the H.C.F. and L.C.M. of these numbers are 35 and 140 respectively, then the sum of the reciprocals of the numbers is equal to:
Answer : A
Explanation
Let the numbers be X and Y. Then, X+Y = 175 and XY = 35x140 = 4900. The required sum = 1/X+1/Y=(X+Y)/XY=175/4900 = 1/28
Q 8 - If the sum of the H.C.F and L.C.F of two numbers is 680 and their L.C.M is 84 times the H.C.F. If one of the numbers is 56, the other number is:
Answer : D
Explanation
h+L = 680 and L = 84 h ∴ h+84 h = 680 ⇒ 85h ⇒680 ⇒h= 8 ∴ L= (84*8) = 672 Now, h*L =56*x ⇒ 8* 672= 56*x⇒ x = (8*672)/56 = 96 ∴ The other number is 96.
Q 9 - H.C.F and L.C.F of two numbers x and y are 3 and 105 respectively. If x+y=36 then figure out 1/x + 1/y.
Answer : D
Explanation
We have X *y =3 *105 ⇒ xy = 315 ∴ x+y/xy =36/315 = 4/35 ⇒ 1/y+1/x = 4/35 ⇒ 1/x+1/y = 4/35.
Q 10 - If the capacity of two pots is 120 liters and 56 liters. Find the container capacity which can exactly measure the contents of the two pots, is :
Answer : C
Explanation
Required capacity = H.C.F of 120 L and 56 L.= 8 L = 8000cc