Area Calculation - Online Quiz



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Following quiz provides Multiple Choice Questions (MCQs) related to Area Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A way of uniform width keeps running round within a rectangular Field 38m long and 32m wide. On the off chance that the way involves 600m2, then The width of the way is:

A - 3 m

B - 5 m

C - 8.75 m

D - 10 m

Answer : B

Explanation

area of the field = (32*38)m2=  1216m2
Let the width of the path be x mtr.
Area without path= (38-2x) (32-2x) m2
= 1216+4x2-140x
Area of the path= 1216- (1216+4x2-140x) = 140x-4x2
∴ 140x-4x2=600
⇒4x2-140x+600=0
⇒x2-35x+150=0 ⇒ (x-30) (x-5) =0 ⇒x=5m

Q 2 - The length of a rectangular plot is thrice its expansiveness. On the off chance that the zone of the rectangular plot is 6075 sq. meter, what is its length?

A - 45 m

B - 75 m

C - 130 m

D - none of these

Answer : D

Explanation

Let the breadth be x meters. Then, its length= 3x mtr.
∴3x*x =6075 ⇒ x2 =2025 ⇒x= √2025= 45
∴ Length = (3*45) m= 135 m

Q 3 - A corridor 20m long and 15m expansive is encompassed by a verandah of Uniform width of 2.5 m. The expense of ground surfaces the verandah at Rs.17.50 per sq. mtr. is:

A - 2500

B - 3000

C - 3500

D - 4000

Answer : C

Explanation

Area of verandah = [(25*20)-(20*15)]m2= 200 m2
  Cost of flooring = (200*35/2) = 3500 rs.

Q 4 - The range of a rectangle is 144m long is the same as that of a square of side 84m. The width of the rectangle is:

A - 7 m

B - 14 m

C - 49 m

D - cannot be resolved

Answer : C

Explanation

Let the width be x meters. Then,
1448* x= 84*84 ⇒ x= 84*84/144 =49m
∴ Width of the rectangle is 49 m.

Q 5 - If the diagonal of a square is doubled, then the area of a new square becomes?

A - Fourfold

B - threefold

C - two fold

D - none of these

Answer : A

Explanation

Let the length of original diagonal be d cm. Then, its area=1/2d2 cm2
New diagonal= (2d) cm. new area = 1/2*(2d) 2=2d2=4*(1/2d2)
=4*old area.

Q 6 - The ratio of the area of a square of side a and that of an equilateral triangle of side a, is

A - 2:1

B - 2:√3

C - 4:3

D - 4:√3

Answer : D

Explanation

Required ratio  = a2/(√3/4) a2  = 4/√3=  4:√3

Q 7 - The perimeter of an isosceles triangle is 14cm. Their lateral side andthe bases are in the ratio 5:4. The area of the triangle is:

A - 1/2 √21cm2

B - 3/2 √21cm2

C - √21cm2

D - 2√21cm2

Answer : D

Explanation

Let lateral side = 5x cm and base = 4x cm
∴5x+5x +4x= 14 ⇒ 14x= 14 ⇒x= 1
∴ Sides are 5 cm, 5 cm and 4 cm.
S=1/2 (5+5+4) = 7, (s-a) = 2, (s-b) = 2 and (s-c) =3
∴ Area = √{s(s-a) (s-b) (s-c)}= √7*2*2*3= √84= √4*21= 2√21 cm2

Q 8 - The ranges of a square and a rectangle are equivalent. On the off chance that their borders are separately P₁and P₂, Which of the accompanying Statement is valid:

A - P₁ < P₂

B - P₁ ≤ P₂

C - P₁ > P₂

D - P₁ ≥ P₂

Answer : A

Explanation

If the areas of a square and a rectangle are equal, then the Perimeter of the square is less. So, P₁

Q 9 - The diagonals of a rhombus are 45 cm and 30 cm. Its territory is:

A - 675 cm2

B - 1350 cm2

C - 2010 cm2

D - 2700 cm2

Answer : A

Explanation

Area of the rhombus = 1/2 d₁* d₂= (1/2 *45*40)cm2 =675 cm2

Q 10 - A round greenery enclosure has an outline of 440 m. There is a 7m wide fringe inside the patio nursery along its outskirts. The territory of the fringe is:

A - 2918m2

B - 2921 m2

C - 2924 m2

D - 2926 m2

Answer : D

Explanation

2πR =440 ⇒ 2*22/7*R= 440 ⇒R= (440* 7/44)=70 m
Outer radius = 70m, inner radius = (70-7) =63 m
Required area = π [(70)2-(63)2] m2= 22/7 *(70+63) (70-63) m2
= (22*133) m2, = 2926m2


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