# Area Calculation - Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Area Calculation**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - A rectangular floor covering has a territory of 120 square meters and an Edge of 46m. The length of it?s asked is:

### Answer : D

### Explanation

L*b=120 and 2(L+b)= 46 ⇒(L+b)=23 (L-b)^{2}= (L+b)^{2}-4Lb = (23)^{2}-4*120 = 529-480 =49 ⇒L-b= 7 On solving L+b= 23, L-b= 7 we get: L= 15, b=8 Diagonal = {√ (15)^{2}+ (8)^{2}} = (√225+64) = √289 =17

Q 2 - The biggest size of the bamboo can be set in a square of zone 100sq. meters is:

### Answer : B

### Explanation

side of the square = √100 m =10 m Largest size of the bamboo= length of the diagonal of the square. = √ (10)^{2}+ (10)^{2}m = √ 200m = 10√ 2m =(10*1.414) m 14.14m

Q 3 - The expense of covering a room 15m long with a rug 75cm wide at 90 p for every meter is Rs. 108. The broadness of the room is:

### Answer : A

### Explanation

Length of the carpet= (10800/90)m =120m Area of the room = Area of the carpet= (120*75/100) m^{2}= 90m^{2}Breadth of the room = area/length = 90/15m =6m

Q 4 - The range of a rectangle is 144m long is the same as that of a square of side 84m. The width of the rectangle is:

### Answer : C

### Explanation

Let the width be x meters. Then, 1448* x= 84*84 ⇒ x= 84*84/144 =49m ∴ Width of the rectangle is 49 m.

Q 5 - The territory of the four dividers of the room is 168m^{2}. The broadness and Length of the room is 8m and 6m. The length of the room is:

### Answer : C

### Explanation

2(L+8)*6= 168 ⇒L+8= 168/12= 14 ⇒L= (14-8) = 6m

Q 6 - The ratio of the area of a square of side a and that of an equilateral triangle of side a, is

### Answer : D

### Explanation

Required ratio = a^{2}/(√3/4) a^{2}= 4/√3= 4:√3

Q 7 - ∆ABC and ∆ DEF are similar triangles such that BC= 4cm, EF= 5cm and area (∆ ABC) = 64cm^{2}. The area of ∆DEF is:

### Answer : B

### Explanation

The areas of two similar triangles are in the ratio of the square of the corresponding sides. Ar (∆ABC)/ ar (∆Def) =BC^{2}/Ef^{2}⇒64/ ar (∆Def) = (4)^{2}/ (5)^{2}= 16/25 ⇒ar (∆DEF) = (25*64/16) = 100 cm^{2}

Q 8 - The edges of a square and a rectangle are equivalent. On the off chance that their zones are individually A m and B m, then which of the accompanying is a genuine proclamation.

### Answer : C

### Explanation

If the perimeter of a square and a rectangle are equal, then area of the square is more. So, A>B is true.

Q 9 - The border of a rhombus is 52cm and the length of its littler Inclining is 10cm. The length of the more extended slanting is:

### Answer : D

### Explanation

Each side = 52/4=13cm Let AC be the smaller diagonal, Then AC= 10cm Let AC and BD intersect at o. Then ∠AOB= 90∘ and AO= 1/2 AC= 5cm In right ∆ AOB, we have AB= 13cm, AO=5cm ∴ OB =√ (ab)^{2}-(OA)^{2}= √ (13)^{2}-(5)^{2}= √169-25 =√144=12cm ∴ BD =2*BO= (2*12) =24 cm

Q 10 - If the sweep of a circle is expanded to three times, then how often will its periphery are expanded?

### Answer : A

### Explanation

Let original radius = R. Then, circumference= 2πR New radius = 3R. New circumference= 2π*(3R) = 6πR Increase = (6πR-2πR) = 4πR = 2(2πR) = 2* original circumference