Area Calculation - Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Area Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A rectangle measures 8cm on length and its slanting measures 10 cm. what is the border of the rectangle?

A - 36 cm

B - 38 cm

C - 28 cm

D - 18 cm

Answer : C

Explanation

second side = √{(10)2-(8)}2=  √(100-64) =√36= 6cm
Perimeter = 2(8+6) = 28cm

Q 2 - The border of the rectangle is 60 m. on the off chance that its length is twice its broadness, and then its region is:

A - 160 m2

B - 180 m2

C - 200 m2

D - 220 m2

Answer : C

Explanation

Let the breadth be x mtr. Then, length = 2x mtr.
2(2x+x) = 60 ⇒ 6x=60 ⇒x= 60
∴ L=20m and b= 10m ⇒area = (20*10) =200 m2

Q 3 - The length of a rectangular plot is expanded by 25%. To keep its region unaltered, the width of the plot ought to be:

A - kept unaltered

B - expanded by 25%

C - expanded by 20%

D - Diminished by 20%

Answer : D

Explanation

Let the length be x meter and breadth be y mtr.
Then, its area = (xy) m2
New length = (125/100*x) m = (5x/4) m. let the new breadth be z meters.
Then, xy = 5x/4*z ⇒z= 4/5 y
Decrease in width = (y-4/5y) = y/5 mtr.
Decrease % in width = (y/5*1/y*100) % = 20%

Q 4 - The range of a rectangle is 144m long is the same as that of a square of side 84m. The width of the rectangle is:

A - 7 m

B - 14 m

C - 49 m

D - cannot be resolved

Answer : C

Explanation

Let the width be x meters. Then,
1448* x= 84*84 ⇒ x= 84*84/144 =49m
∴ Width of the rectangle is 49 m.

Q 5 - The area of the largest circle that can be drawn inside a square of side 14cm is:

A - 84 cm2

B - 154 cm2

C - 204 cm2

D - 176 cm2

Answer : B

Explanation

Radius of the circle =(1/2*14) =7 cm
Area of the circle = (22/7*7*7) cm2= 154 cm2

Q 6 - Each side of an equilateral triangle measures 8 cm. Its area is:

A - 64 cm2

B - 16√3cm2

C - 4√3cm2

D - 21.3 cm2

Answer : B

Explanation

Area =( √3/4*8*8 ) cm2 = 16√3 cm2

Q 7 - The areas of two similar triangles are 12 cm2 and 48 cm2 .If the height of the smaller one is 2.1 cm, then the corresponding height of the bigger one is:

A - 0.525 cm

B - 4.2 cm

C - 4.41 cm

D - 8.4 cm

Answer : B

Explanation

The areas of two similar triangles are in the ratio of the square of the corresponding sides.
∴12/48= (2.1)2/h2 ⇒h2=4* (2.1)2 ⇒h= (2* 2.1) = 4.2 cm

Q 8 - The length of every side of an equilateral triangle is 24 cm. The region of its engraved circle is:

A - 18 πcm2

B - 24 πcm2

C - 36 πcm2

D - 48 πcm2

Answer : D

Explanation

Let the height of the triangle be h then,
1/2 * 24*h = √3/4 *24*24 ⇒h= 12 √3
∴ 3r = 12 √3 ⇒r = 4√3
Area of in circle = π* (4√3)2 = 48πcm2

Q 9 - The slanting of a square is 20 m. The territory of the square is:

A - 40 m2

B - 120 m2

C - 200 m2

D - 400 m2

Answer : C

Explanation

Area =1/2*(diagonal)2=(1/2*20*20)m2=200m2

Q 10 - The distinction between the radii of the smaller circle and the greater circle is 7cm and the contrast between the territories of the two circles is 1078 cm2. Span of the littler circle is:

A - 17.5 cm

B - 21 cm

C - 28 cm

D - none of these

Answer : B

Explanation

Let the radii of the inner and outer circle be r and R cm.
Then, R-r= 7 and π (R2-r2) = 1078
∴ Π (R2-r2)/ (R-r) = 1078/7
⇒R+r = (1078/7*7/22) =49
On solving (R-r) =7 and (R+r) = 49, we get r= 21 cm


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