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Area Calculation - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Area Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - The proportion of the length and expansiveness of a plot is 3:2. On the off chance that the expansiveness is 40m not exactly the length of its slanting is:
Answer : C
Explanation
Let the length be 3x meter. Then, breadth = 2x meters Then, 3x-2x= 40 ⇒ x=40 ∴length = (3*40) = 120m and b= (2*40) =80m ∴ Perimeter = 2(120+80) = 400m
Q 2 - The askew of a square is 4√2cm. the inclining of other who?s Range is twofold that of the first square is:
Answer : A
Explanation
Area of given square = 1/2 (diagonal) 2= {1/2 (4√2) 2} cm2=16cm2
Area of new square = (2*16) cm2 =32cm2
Let the diagonal of 2nd square be D cm
Then, 1/2*D2=32 ⇒D2=64 ⇒D=8 cm
Q 3 - If the proportion of the ranges of two squares, one having twofold it's corner to corner then the other is:
Answer : D
Explanation
Let the length of the diagonals be 2x and x units. Then, their areas are 1/2 *(2x)2 and (1/2*x2) Required ratio: (1/2*4x2): (1/2x2) = 4:1
Q 4 - Of the two square fields, the range of the one is 1 hectare, while another is more extensive by 1%. The distinction in ranges is:
Answer : B
Explanation
Area of one Sq. field= 10000m2 Side of this field = √10000m =100m Side of another square = 101 m Difference of area = [(101) 2-(100) 2] m2 =(101+100)(101-100)m2 = (201*1)m2= 201m2
Q 5 - The area of the largest circle that can be drawn insight rectangle with sides 8m by 7m is:
Answer : B
Explanation
Radius of the circle= 7/2 m Area of the circle = (22/7 *7/2 *7/2) m2 =77/2m2
Q 6 - The area of an equilateral triangle is 4√3cm2. Each of its side measures.
Answer : D
Explanation
Let each side be a cm. then, √3/4 a2= 4√3 ⇒a2 =16 ⇒a= 4cm
Q 7 - The area of a right angled triangle is 20cm2 and one of the sides containing the right angle is 4cm. The altitude on the hypotenuse is:
Answer : D
Explanation
Let the altitude be x cm. Then, 1/2 *4*x = 20 ⇒ x= 10 cm BC= Hypotenuse = √ (10)2+ (4)2 =√116 =√4*29= 2√29 Let AD⏊ BC. Then, 1/2 * BC* AD = area of ∆ ABC ⇒1/2*2 √29* AD= 20 ∴ AD = 20/√29 cm
Q 8 - The territory of a circle engraved in an equilateral triangle is 462 cm2. The edge of this triangle is:
Answer : C
Explanation
Πr2 = 462 ⇒ 22/7* r2 = 462 ⇒ r2 = (462*7/22) = 147 ⇒ r = √ 7*7*3 = 7 √3 cm Height = 3r = (3* 7 √ 3) cm = 21√ 3 cm a2 - (a/2) 2 = (21√ 3) 2 ⇒ (a2- a2/4) = 1323 3a2 = (1323*4) ⇒ a2= (441* 4) ⇒ a = (21*2) = 42 Perimeter of the triangle = 3a = (3*42) = 126 cm.
Q 9 - If the side of a rhombus is 20cm and its shorter corner to corner is three-fourth of its more extended askew, then the range of the rhombus is:
Answer : C
Explanation
Let the longer diagonal be x cm , then shorter diagonal = (3/4)x cm ∴ AC= x cm and BD=(3/4 )x cm AO =1/2*AC =x/2 cm, BO= 1/2 BD= (3/8) X cm and AB= 20 cm In right ∆ AOB, we have AO2 +BO2 = AB2 (x/2) 2+ (3x/8) 2= (20) 2⇒x2/4+9x2/64=400 ⇒16x2+9x2=25600 ⇒25x2= 25600 ⇒x2=1024 ⇒ x=√1024= 32 cm ∴ AO =32/2=16cm, BO= (3/8*32) cm=12cm ∴ AC=2*AO= 32 cm, BD= 2*BO= 24cm Area of the rhombus = (1/2*32*24) cm2 =384 cm2
Q 10 - The range of a square field is 6050m2. The length of its corner to corner is
Answer : A
Explanation
Let the diagonal be d meter. Then, 1/2 d2=6050⇒ d2= 12100 ⇒d=√12100= 110 m.