Area Calculation - Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Area Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A rectangular floor covering has a territory of 120 square meters and an Edge of 46m. The length of it?s asked is:

A - 11 m

B - 13 m

C - 15 m

D - 17 m

Answer : D

Explanation

L*b=120 and 2(L+b)= 46 ⇒(L+b)=23
(L-b) 2= (L+b) 2-4Lb = (23)2-4*120
= 529-480 =49 ⇒L-b= 7
On solving L+b= 23, L-b= 7 we get: L= 15, b=8
Diagonal = {√ (15)2+ (8)2} = (√225+64) = √289 =17

Q 2 - The biggest size of the bamboo can be set in a square of zone 100sq. meters is:

A - 10 m

B - 14.14 m

C - 20 m

D - 25 m

Answer : B

Explanation

side of the square = √100 m =10 m
Largest size of the bamboo= length of the diagonal of the square.
= √ (10) 2+ (10) 2m = √ 200m   = 10√ 2m
=(10*1.414) m 14.14m

Q 3 - The expense of covering a room 15m long with a rug 75cm wide at 90 p for every meter is Rs. 108. The broadness of the room is:

A - 6 m

B - 8 m

C - 9 m

D - 12 m

Answer : A

Explanation

Length of the carpet= (10800/90)m =120m
Area of the room = Area of the carpet= (120*75/100) m2= 90m2
Breadth of the room = area/length = 90/15m =6m

Q 4 - The range of a rectangle is 144m long is the same as that of a square of side 84m. The width of the rectangle is:

A - 7 m

B - 14 m

C - 49 m

D - cannot be resolved

Answer : C

Explanation

Let the width be x meters. Then,
1448* x= 84*84 ⇒ x= 84*84/144 =49m
∴ Width of the rectangle is 49 m.

Q 5 - The territory of the four dividers of the room is 168m2. The broadness and Length of the room is 8m and 6m. The length of the room is:

A - 14 m

B - 12 m

C - 6 m

D - 3.5 m

Answer : C

Explanation

2(L+8)*6= 168 ⇒L+8= 168/12= 14 ⇒L= (14-8) = 6m

Q 6 - The ratio of the area of a square of side a and that of an equilateral triangle of side a, is

A - 2:1

B - 2:√3

C - 4:3

D - 4:√3

Answer : D

Explanation

Required ratio  = a2/(√3/4) a2  = 4/√3=  4:√3

Q 7 - ∆ABC and ∆ DEF are similar triangles such that BC= 4cm, EF= 5cm and area (∆ ABC) = 64cm2. The area of ∆DEF is:

A - 80 cm2

B - 100 cm2

C - 256/5 cm2

D - None of these

Answer : B

Explanation

The areas of two similar triangles are in the ratio of the square of  the corresponding sides.
Ar (∆ABC)/ ar (∆Def) =BC2/Ef2 ⇒64/ ar (∆Def) = (4)2/ (5)2 = 16/25
⇒ar (∆DEF) = (25*64/16) = 100 cm2

Q 8 - The edges of a square and a rectangle are equivalent. On the off chance that their zones are individually A m and B m, then which of the accompanying is a genuine proclamation.

A - A < B

B - A≤B

C - A > B

D - A≥B

Answer : C

Explanation

If the perimeter of a square  and a rectangle are equal, then area of the square is more. So, A>B is true.

Q 9 - The border of a rhombus is 52cm and the length of its littler Inclining is 10cm. The length of the more extended slanting is:

A - 10.4 cm

B - 12 cm

C - 18 cm

D - 24 cm

Answer : D

Explanation

Each side = 52/4=13cm
Let AC be the smaller diagonal, Then AC= 10cm
Let AC and BD intersect at o. Then ∠AOB= 90∘ and AO= 1/2 AC= 5cm
In right ∆ AOB, we have AB= 13cm, AO=5cm
∴ OB =√ (ab) 2-(OA) 2= √ (13)2-(5)2= √169-25
=√144=12cm
∴ BD =2*BO= (2*12) =24 cm

Q 10 - If the sweep of a circle is expanded to three times, then how often will its periphery are expanded?

A - 2 times

B - 3 times

C - 1/3 times

D - 9 times

Answer : A

Explanation

Let original radius = R. Then, circumference= 2πR
New radius = 3R. New circumference= 2π*(3R) = 6πR
Increase = (6πR-2πR) = 4πR = 2(2πR) = 2* original circumference


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