Area Calculation - Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Area Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - The proportion of the length and expansiveness of a plot is 3:2. On the off chance that the expansiveness is 40m not exactly the length of its slanting is:

A - 480 m

B - 320 m

C - 400 m

D - 450 m

Answer : C

Explanation

Let the length be 3x meter. Then, breadth = 2x meters
Then, 3x-2x= 40 ⇒ x=40
∴length = (3*40) = 120m and b= (2*40) =80m
∴ Perimeter = 2(120+80) = 400m

Q 2 - The region of a rectangle is 12sq. mtr. Also, its length is 3 times that of its expansiveness. What is the edge of the rectangle?

A - 14 m

B - 18 m

C - 24 m

D - none of these

Answer : D

Explanation

Let the breadth be x mtr. then its length = 3x
∴ 3x*x= 12 ⇒ x2= 4 ⇒x=2
∴ L= 6m, b=2m ⇒perimeter = 2(6+2) m = 16m

Q 3 - If every side of a square is expanded by half, the proportion of the territory of the subsequent square to the range of the given square is:

A - 5:4

B - 9:4

C - 4:5

D - 4:9

Answer : B

Explanation

Let the original side be x mtr. Then, area =x2 sq. mtr.
New side = (150% of x) m = (150/100* x) m = (3x/2) m
New area = (3x/2*3x/2) m2= 9x2/4 m2
Required ratio of areas = 9x2/4: x2= 9:4

Q 4 - The covering of a room twice the length it is board at the rate of 50 p for every square mtr. costs rs. 12.25 And the expense of painting its dividers the rate of 9 p for every square mtr. is rs. 6.30. The tallness of the room is:

A - 10/3 m

B - 13/3 m

C - 7 m

D - none of these

Answer : A

Explanation

Let breadth = x mtr. Then, length = 2x mtr.
Area of the floor = 1225/50 m2= 49/2 m2
∴ X*2x= 49/2 ⇒x2 =49/4 ⇒x=7/2
∴ L = 7m, b= 7/2 m
Area of 4 walls = 630/9 m2 = 70 m2
2(7+ 7/2)* h= 70 ⇒ 2*21/2*h =70
⇒h =70/21 m = 10/3m

Q 5 - The length of a rectangle is twice than its broadness. On the off chance that the length of this rectangle is expanded by 5cm and broadness is diminished by 5cm, the territory of a rectangle is expanded by 75m2. The length of the rectangle is:

A - 20 cm

B - 30 cm

C - 40 cm

D - 50 cm

Answer : C

Explanation

Let breadth be x cm. Then, length =2x cm
(2x-5) (x+5)-x*2x =75 ⇒5x= 100 ⇒x= 20
∴Length = (2*20) cm =40 cm

Q 6 - Each side of an equilateral triangle measures 2√3cm.The length of its altitude is:

A - √3/2cm

B - √3/4cm

C - 3 cm

D - 0.5 cm

Answer : C

Explanation

Each side=  2√3
1/2 * base *altitude= √3/4* (2√3)2 = √3/4 *12 = 3√3
⇒ 1/2 *2 √3* altitude= 3√3⇒altitude= 3cm

Q 7 - The areas of two similar triangles are 12 cm2 and 48 cm2 .If the height of the smaller one is 2.1 cm, then the corresponding height of the bigger one is:

A - 0.525 cm

B - 4.2 cm

C - 4.41 cm

D - 8.4 cm

Answer : B

Explanation

The areas of two similar triangles are in the ratio of the square of the corresponding sides.
∴12/48= (2.1)2/h2 ⇒h2=4* (2.1)2 ⇒h= (2* 2.1) = 4.2 cm

Q 8 - A typist uses a paper 30cm*15 cm. He leaves an edge of 2.5cm at the top and the base and 1.25 cm on either side. What rate of paper range around accessible for writing?

A - 65%

B - 70%

C - 80%

D - 61.1%

Answer : D

Explanation

Total area = (30*15) cm2
Area used = [(30-1.25*2)* (15-2.5*2)]
= (27.5*10) cm2 = 275cm2
Percentage of area used = (275/450*100) % = 61.1%

Q 9 - If the side of a square is expanded by 25%, then its region is expanded by:

A - 25%

B - 40.5%

C - 55%

D - 56.25%

Answer : D

Explanation

Let original side= a. Then , area =a2
New side= (125% of a) = (125/100*a) = 5a/4
New area = (5a/4* 5a/4) = (25/16) a2
Area increased = [(25/16)a2-a2] =9a2/16
Increased % = (9a2/16* 1/a2*100) %= 225/4= 56.25%

Q 10 - A round greenery enclosure has an outline of 440 m. There is a 7m wide fringe inside the patio nursery along its outskirts. The territory of the fringe is:

A - 2918m2

B - 2921 m2

C - 2924 m2

D - 2926 m2

Answer : D

Explanation

2πR =440 ⇒ 2*22/7*R= 440 ⇒R= (440* 7/44)=70 m
Outer radius = 70m, inner radius = (70-7) =63 m
Required area = π [(70)2-(63)2] m2= 22/7 *(70+63) (70-63) m2
= (22*133) m2, = 2926m2
aptitude_area_calculation.htm
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