# Aptitude - Simple Interest Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Simple Interest**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - At which aggregate the simple interest at the rate of 15/4 for each annum will be Rs 210 in 7/3 years?

### Answer : B

### Explanation

Sum = Rs. (100*s.I/R*T) = Rs. (100*210)/(15/4*7/3) = Rs. (100*210*12/105) =2400 Rs.

Q 2 - On the off chance that the basic simple interest for a long time be equivalent to 30% of the principal, it will be equivalent to the vital after.

### Answer : B

### Explanation

Let the principle be Rs.x and the rate be R% p.a. Then, X*R/100*6 = 30/100*x = R= 5 Let the required time be t years. X*5/100*t = x => t =100/5 = 20 years.

Q 3 - The distinction between the basic interests got from two unique sources on Rs 1500 for a long time is Rs 13.50. The contrast between their rates of interest is:

### Answer : C

### Explanation

Let the rates of interest be x% p.a. Then, (1500*x/100*3) ? (1500*y/100*3) =27/2 45(x-y) =27/2 => (x-y) = (27/2* 1/45)=3/10=0.3 Required difference = 0.3%

Q 4 - A man loses Rs 55.50 yearly when the yearly rate of interest tumbles from 11.5% to 10%. His capital is:

### Answer : A

### Explanation

Let the capital be Rs. x. then, (x*23/2*1/100*1) ?(x*10*1/100*1) = 55.50 => 23x/200 ?x/10 =111/2 => 23x-20x =11100 => 3x= 11100 => x = 3700 Hence, the capital is Rs. 3700.

Q 5 - A man disperses Rs. 25300 among his three children A, B, C. In a manner that the measure of there at 10% simple interest for a long time, 3 years and 4 years will be equivalent an offer is:

### Answer : C

### Explanation

Let the parts of A, B, C be x, Y, z respectively. Then (x+ x*2*10/100)= (Y+ y*3*10/100) = (z+ z*4*10/100) => 6x/5 =13y/10 = 7z/5 =ℏ = 5ℏ/6, y = 10ℏ/13, z= 5ℏ/7 => x: y: z = 5ℏ /6:10ℏ/13 :5ℏ/7 = 1/6:2/13: 1/7 = 91: 84: 78 A's part = Rs. (25300*91/253) = Rs. 9100.

Q 6 - In what time will the simple interest be 2/5 of the principal at 8 percent per annum?

### Answer : C

### Explanation

If Principal = Rs x, then I = 2x/5. Rate = 8 % Time = I*100/P*R = (2x/5)*100/x*8 = 5 years

Q 7 - The simple interest on a sum of money is 4/9 of the principal and the number of years is equal to the rate percent per annum. The rate per annum is

### Answer : B

### Explanation

We know, I = PTR/100 According to question, I = 4P/9 and r = t 4P/9 = P*r*r/100 Or, r2 = 400/9 Or, r = 20/3

Q 8 - Peter invested an amount of Rs. 12000 at rate of interest of 10% p.a. simple interest and another amount at the rate of 20% p.a. simple interest. The total interest earned at the end of one year on the total amount invested became 14 p.c.p.a. Find the total amount invested?

### Answer : A

### Explanation

Let the second number be z. then,

(^{12000 x 10 x 1}⁄_{100}+^{z x 20 x 1}⁄_{100}) = (^{(12000 + z) x 14 x 1}⁄_{100}) = 12000 + 20z = 168000 + 14z

= 6z = 48000

z = 8000

Therefore Total investment = Rs. (12000 + 8000) = 20000

Q 9 - Divide Rs. 2379 into 3 parts so that their amounts after 2,3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The first part is?

### Answer : A

### Explanation

Let the parts be a,b and [2379 - (a + b)] a + (a x 2^{5}⁄_{100}) = b + (b x 3^{5}⁄_{100}) = c + (c x 4^{5}⁄_{100}) =^{11a}⁄_{10}=^{23b}⁄_{20}=^{6c}⁄_{5}= k a =^{10k}⁄_{11}

b =^{20k}⁄_{23}

c =^{5k}⁄_{6}But, a + b + c = 2379^{10k}⁄_{11}+^{20k}⁄_{23}+^{5k}⁄_{6}= 2379 1380k + 1320k + 1265k = 2379 x 11 x 23 x 6 k =^{2379 x 11 x 23 x 6}⁄_{3965}=^{3 x 11 x 23 x 6}⁄_{5}a = 828