# Aptitude - Simple Interest Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Simple Interest**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - Rs 6000 get to be Rs 7200 in 4 years at a sure rate of interest. On the off chance that the rate gets to be 1.5 times of itself, the measure of the same central in 5 years will be:

### Answer : B

### Explanation

S.I on Rs 6000 for 4 years= (7200-6000) = 1200 Rs. ∴ Rate = (100*1200/6000*4) % p.a. = 5% p.a New rate = (5*3/2) % = 15/2% P.a. Required amount = [6000+ (6000*5/100*15/2)] = Rs. (6000+2250) = Rs. 8250.

Q 2 - On the off chance that the basic simple interest for a long time be equivalent to 30% of the principal, it will be equivalent to the vital after.

### Answer : B

### Explanation

Let the principle be Rs.x and the rate be R% p.a. Then, X*R/100*6 = 30/100*x = R= 5 Let the required time be t years. X*5/100*t = x => t =100/5 = 20 years.

Q 3 - Simple interest on a sure whole at a sure yearly rate of interest is 25/16 of the entirety. In the event that the number speaking to rate percent and time in years is equivalent, then rate percent per annum is:

### Answer : D

### Explanation

Let the sum be Rs. x, Rate = R% P.a., time = 25/2 years. S.I = Rs. 25x/16 R = 100*25x/16 *1/x* 1/R => R^{2}=2500/16 = R= 25/2 Hence, Rate = 25/2%

Q 4 - An acquires Rs 8000 at 12% p.a simple interest and B gets Rs 9100 at 10%p.a. simple interest . In how long will their measures of obligations be equivalent?

### Answer : C

### Explanation

Let the required time be x years. Then, 8000+8000*12/100*x= 9100+9100*10/100*x => 50x =1100 => x= 22 years

Q 5 - A sum of money doubles itself in 20 years. What is the rate of interest?

### Answer : B

### Explanation

Here, I = P. Given T = 20 years. R = ? We know, I = PTR/100 Or, R = I*100/PT = P*100/P*20 = 5%

Q 6 - A person invests a certain sum at a certain rate of simple interest for 5 years. Had he invested it at 2% higher, he would have earned Rs 250 more. Find the sum he invested.

### Answer : A

### Explanation

Rs 250 is the additional interest in 5 years that he would have earned if he had invested it at 2% higher rate of interest. Hence we can consider, I = Rs 250, R = 2% and t = 5 years. P = I*100/Rt = (250*100)/2*5 = Rs 2500

Q 7 - Simple interest on a certain amounts is ^{9}⁄_{16} of the principal. If the numbers representing the rate of interest in percent and time in years be equal, then time, for which the principal is lent out, is?

### Answer : C

### Explanation

Let sum be z. Then,S.I =^{9z}⁄_{16}Let rate = R% and Time = R years therefore^{z x R x R}⁄_{100}R^{2}^{900}⁄_{16}R =^{30}⁄_{4}= 7^{1}⁄_{2}years.

Q 8 - An amount of Rs. 1,00,000 is invested in two types of shares. The first yields an interest of 9% p.a. and the second, 11% p.a. If the total interest at the end of one year is 9^{3}⁄_{4}, then the amount invested in each share was?

### Answer : A

### Explanation

Let the sum invested at 9% be Rs. z and that invested at 11% be Rs. ( 100000 - z ). Then,^{z x 9 x 1}⁄_{100}+^{(100000 - z) x 11 x 1}⁄_{100}= 100000 x^{39}⁄_{4}x^{1}⁄_{100}=^{9z + 1100000 - 11z}⁄_{100}

^{39000}⁄_{4}= 9750 2z = (1100000 - 975000) = 125000 x = 62500 sum invested at 9% = Rs. 62500 sum invested at 11% = Rs. (100000 - 62500) = 37500

Q 9 - Divide Rs. 2379 into 3 parts so that their amounts after 2,3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The first part is?

### Answer : A

### Explanation

Let the parts be a,b and [2379 - (a + b)] a + (a x 2^{5}⁄_{100}) = b + (b x 3^{5}⁄_{100}) = c + (c x 4^{5}⁄_{100}) =^{11a}⁄_{10}=^{23b}⁄_{20}=^{6c}⁄_{5}= k a =^{10k}⁄_{11}

b =^{20k}⁄_{23}

c =^{5k}⁄_{6}But, a + b + c = 2379^{10k}⁄_{11}+^{20k}⁄_{23}+^{5k}⁄_{6}= 2379 1380k + 1320k + 1265k = 2379 x 11 x 23 x 6 k =^{2379 x 11 x 23 x 6}⁄_{3965}=^{3 x 11 x 23 x 6}⁄_{5}a = 828