- Aptitude Test Preparation
- Aptitude - Home
- Aptitude - Overview
- Quantitative Aptitude

- Aptitude Useful Resources
- Aptitude - Questions & Answers

- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who

Following quiz provides Multiple Choice Questions (MCQs) related to **Simple Interest**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - At which aggregate the simple interest at the rate of 15/4 for each annum will be Rs 210 in 7/3 years?

Sum = Rs. (100*s.I/R*T) = Rs. (100*210)/(15/4*7/3) = Rs. (100*210*12/105) =2400 Rs.

Q 2 - On the off chance that the basic simple interest for a long time be equivalent to 30% of the principal, it will be equivalent to the vital after.

Let the principle be Rs.x and the rate be R% p.a. Then, X*R/100*6 = 30/100*x = R= 5 Let the required time be t years. X*5/100*t = x => t =100/5 = 20 years.

Q 3 - The simple interest at x% p.a. for x years will be Rs x on an aggregate of:

Let the sum be Rs. P. then, P = 100*S.I /Rate * time = (100*x/x*x) = Rs. 100/x

Q 4 - An aggregate of Rs 5000 was loaned mostly at 6% and incompletely at 9% basic interest. On the off chance that the aggregate yearly premium be Rs 390, the proportion in which the cash was loaned at given rates is:

Let the money invested at the two rates be rs. x and Rs. (5000-x) Then, (x*6/100*1) + (5000-x) *9/100*1 = 390 => 3x/50 + 9(5000-x)/100 = 390 => 6x+45000-9x = 39000 => 3x= 6000 => x= 2000. Required ratio = 2000:3000= 2:3

Q 5 - With a given of rate of basic interest, the proportion of standard and measure of a sure timeframe is 4:5 , following 3 years , with the same rate of interest , the proportion of the rule and sum gets to be 5:7 , the rate of interest per annum is :

After t years, let P =Rs. 4x and amount = Rs. 5x. P + S.I for t years = Rs. 5x P: {p+S.I for (t+3) years} = 5:7= 1: 7/5 = 4x: (7/5*4x) = 4x: 28x/5 ∴ P+S.I. For (t+3) years = Rs. 28x/5 On subtracting (i) from (ii), we get: S.I for 3 years = Rs. (28x/5 -5x) = Rs. 3x/5 S.I on Rs. 4x for 3 years = 3x/5 ∴ Rate = {(100*3x/5)/ (4x*3)} % p.a. = 5% p.a.

Q 6 - Vishwas borrowed a total amount of Rs 30,000 part of it at 12 % per annum and remaining at 10% per annum. If at the end of two years he paid in all Rs 36,480 to settle the loan amount, what was the amount borrowed at 12 % per annum?

Let the sum borrowed at 12% per annum be Rs x. So, sum borrowed at 10% per annum = Rs (30000 - x) Simple Interest = Rs 36480 ? Rs 30000 = Rs 6480 According to the question, x*2*12/100 + (30000 - x)*2*10/100 = 6480 or, 24x + 600000 - 20x = 648000 or, 4x = 48000 or, x = 12000

Q 7 - A sum of money becomes ^{7}⁄_{6} of itself in 3 years at a certain rate of simple interest. The rate per annum is?

Let sum be z. Then, Amount =^{7z}⁄_{6}S.I. = (^{7z}⁄_{6}- 6) =^{z}⁄_{6}years = 3 years. therefore Rate =^{100 x z}⁄_{z x 6 x 3}=^{50}⁄_{9}= 5^{5}⁄_{9}

Q 8 - The difference between the simple interest received from two different sources on Rs. 1500 for 3 years is Rs. 13.50. The difference between their rate of interest is?

(^{1500 x R1 x 3}⁄_{100}) - (^{1500 x R2 x 3}⁄_{100}) = 13.50 = 4500 (R_{1}- R_{2}) = 1350 = R_{1}- R_{2}=^{1350}⁄_{4500}= 0.3%

Here P = 5600 Rs.R= 20/3% p.a. also, T = 9/12 = 3/4 year S.I = (P*R*T)/100 = (5600*20/3*3/4*1/100) = Rs. 280

aptitude_simple_interest.htm

Advertisements