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Aptitude - Simple Interest Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Simple Interest. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - A man had Rs 1600, some portion of which he loaned at 8% for each annum and the rest at 9% for each annum simple interest. On the off chance that the aggregate yearly premium be Rs 1340, the cash loaned at 8% is:
Answer : C
Explanation
Let the money lent at 8% P.a. be Rs. x. (x*8/100*1) + (16000-x)*9/100*1 = 1340 => 8x/100 + (144000-9x/100) =1340 => 8x+144000 -9x = 134000 x = 10000 Hence, the money lent at 8% = RS.10000.
Q 2 - A sure whole is contributed on basic interest, if it trebles in 10 years, what is the rate of interest?
Answer : B
Explanation
Let the sum be Rs. x then, S.I = Rs. (3x-x) = rs. 2x ∴ x*R/100*10= 2x = R = 20% p.a.
Q 3 - Mr. A loans 40% of the whole at 15% p.a., half of rest aggregate at 10% p.a. also, the rest at 18% p.a. Simple interest. What might be the rate of interest per annum figured in general total?
Answer : D
Explanation
Let the whole sum be Rs 100. Sum at 15% p.a. =Rs 40, Rest=Rs 60. Sum at 10% p.a. =Rs 30, sum at 18% p.a. =Rs 30. S.I. on Rs 100 for 1 years = (40*15/100*1) + (30*10/100*1) + (30*18/100*1) = Rs (6+3+ 5.4) =Rs 14.4. Required rate = 14.4%p.a.
Q 4 - An aggregate of Rs 5000 was loaned mostly at 6% and incompletely at 9% basic interest. On the off chance that the aggregate yearly premium be Rs 390, the proportion in which the cash was loaned at given rates is:
Answer : C
Explanation
Let the money invested at the two rates be rs. x and Rs. (5000-x) Then, (x*6/100*1) + (5000-x) *9/100*1 = 390 => 3x/50 + 9(5000-x)/100 = 390 => 6x+45000-9x = 39000 => 3x= 6000 => x= 2000. Required ratio = 2000:3000= 2:3
Q 5 - With a given of rate of basic interest, the proportion of standard and measure of a sure timeframe is 4:5 , following 3 years , with the same rate of interest , the proportion of the rule and sum gets to be 5:7 , the rate of interest per annum is :
Answer : B
Explanation
After t years, let P =Rs. 4x and amount = Rs. 5x.
P + S.I for t years = Rs. 5x
P: {p+S.I for (t+3) years} = 5:7= 1: 7/5 = 4x: (7/5*4x) = 4x: 28x/5
∴ P+S.I. For (t+3) years = Rs. 28x/5
On subtracting (i) from (ii), we get:
S.I for 3 years = Rs. (28x/5 -5x) = Rs. 3x/5
S.I on Rs. 4x for 3 years = 3x/5
∴ Rate = {(100*3x/5)/ (4x*3)} % p.a. = 5% p.a.
Q 6 - Vishwas borrowed a total amount of Rs 30,000 part of it at 12 % per annum and remaining at 10% per annum. If at the end of two years he paid in all Rs 36,480 to settle the loan amount, what was the amount borrowed at 12 % per annum?
Answer : D
Explanation
Let the sum borrowed at 12% per annum be Rs x. So, sum borrowed at 10% per annum = Rs (30000 - x) Simple Interest = Rs 36480 ? Rs 30000 = Rs 6480 According to the question, x*2*12/100 + (30000 - x)*2*10/100 = 6480 or, 24x + 600000 - 20x = 648000 or, 4x = 48000 or, x = 12000
Q 7 - The rate of simple interest on an amount of money is 6% per annum for the first two years, 9% per annum for the next five years, 13% per annum for the period beyond 7 years. If the total interest on a sum at the end of ten years is Rs 7,680, what is the sum?
Answer : B
Explanation
According to the question, Rs 7680 = P*6*2/100 + P*9*5/100 + P*13*3/100 Or, 12P + 45P + 39P = Rs 7680*100 Or, P = Rs 768000/96 = Rs 8000
Q 8 - Peter invested an amount of Rs. 12000 at rate of interest of 10% p.a. simple interest and another amount at the rate of 20% p.a. simple interest. The total interest earned at the end of one year on the total amount invested became 14 p.c.p.a. Find the total amount invested?
Answer : A
Explanation
Let the second number be z. then,
(12000 x 10 x 1⁄100 + z x 20 x 1⁄100) = ((12000 + z) x 14 x 1⁄100) = 12000 + 20z = 168000 + 14z
= 6z = 48000
z = 8000
Therefore Total investment = Rs. (12000 + 8000) = 20000
Q 9 - Straightforward enthusiasm on a sure aggregate is 16/25 of the entirety. Discover the rate percent and time if both are equivalent?
Answer : A
Explanation
Let the standard be Rs. x. At that point, S.I = Rs. (16x/25) Let rate = R% p.a. also, time = R years. Then, S.I = (p*r*t)/100 = (100*p/P*8) => 16x/25 = (x*R*R/100) => R2= 64 => R= 8. Thus, rate = 8% P.a. what's more, time = 8Years.