# Aptitude - Simple Interest Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Simple Interest**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - How crunch simple interest will Rs 2000 win in year and a half at 6% for every annum?

### Answer : B

### Explanation

S.I = Rs. (2000*18/12*6/100) = Rs. 180.

Q 2 - On the off chance that the basic simple interest for a long time be equivalent to 30% of the principal, it will be equivalent to the vital after.

### Answer : B

### Explanation

Let the principle be Rs.x and the rate be R% p.a. Then, X*R/100*6 = 30/100*x = R= 5 Let the required time be t years. X*5/100*t = x => t =100/5 = 20 years.

Q 3 - A farmer acquired Rs 3600 at 15% for every annum. Toward the end of 4 years he cleared his record by paying Rs 4000 and a goat. The expense of the goat is:

### Answer : D

### Explanation

Amount after 4 year = Rs. 3600+Rs. (3600*15/100* 4) = Rs.3600+(3600*15/100*4) = cost of goat = Rs. (5760-4000) = 1760

Q 4 - What yearly installment will release an obligation of Rs 580 due in 5 years at 8% p.a.?

### Answer : C

### Explanation

Let the required annual installment be Rs. x. then, (Amount of Rs. x for 4 year) + (amount of Rs. x for 3 year) + (amount of Rs.x for 2 year) + (amount of Rs.x for 1 year) + Rs. x = 580 => (x+ x*8*4/100) +(x+ x*8*3/100) + (x+ x*8*2/100) + (x+ x*8*1/100) +x= 580 => (x+ 8 x/25) +(x+ 6 x/25) + (x+ 4 x/25) + (x+ 2 x/25) +x = 580 => 33x/25 + 31x/25 + 29x/25+ 27x/25+x = 580 => (33x+31x+29x+27X+25x) = 14500 =>145x = 14500 => x= 100. Required installment = Rs. 100.

Q 5 - Rs.1000 contributed at 5% p.a. S.I. In the event that the interest is added to the rule after at regular intervals, the sum will be gets to be Rs 2000 after.

### Answer : D

### Explanation

S.I for the 10 years = Rs. (1000* 5/100*10) = Rs. 500 Principle after 10 years becomes = Rs. (1000+500) = Rs. 1500 S.I on it = Rs. (2000- 1500) = 500 Time = (100*500/ 5*1500) years = 20/3 years

Q 6 - Vishwas borrowed a total amount of Rs 30,000 part of it at 12 % per annum and remaining at 10% per annum. If at the end of two years he paid in all Rs 36,480 to settle the loan amount, what was the amount borrowed at 12 % per annum?

### Answer : D

### Explanation

Let the sum borrowed at 12% per annum be Rs x. So, sum borrowed at 10% per annum = Rs (30000 - x) Simple Interest = Rs 36480 ? Rs 30000 = Rs 6480 According to the question, x*2*12/100 + (30000 - x)*2*10/100 = 6480 or, 24x + 600000 - 20x = 648000 or, 4x = 48000 or, x = 12000

Q 7 - A sum of money amounts to RS. 9800 after 5 years and to 12005 after a further period of 8 years at the same rate of simple interest. The rate of interest per annum is?

### Answer : A

### Explanation

S.I. for 3 year = Rs. (12005 - 9800) = 2205 S.I. for 5 years = Rs. (^{2205 x 5}⁄_{3}) = 3675 Therefore Principal = (9800 - 3675) = 6125 Hence, Rate = (^{100 x 3675}⁄_{6125 x 5}) = 12%

Q 8 - Peter invested an amount of Rs. 12000 at rate of interest of 10% p.a. simple interest and another amount at the rate of 20% p.a. simple interest. The total interest earned at the end of one year on the total amount invested became 14 p.c.p.a. Find the total amount invested?

### Answer : A

### Explanation

Let the second number be z. then,

(^{12000 x 10 x 1}⁄_{100}+^{z x 20 x 1}⁄_{100}) = (^{(12000 + z) x 14 x 1}⁄_{100}) = 12000 + 20z = 168000 + 14z

= 6z = 48000

z = 8000

Therefore Total investment = Rs. (12000 + 8000) = 20000

Q 9 - Straightforward enthusiasm on a sure aggregate is 16/25 of the entirety. Discover the rate percent and time if both are equivalent?

### Answer : A

### Explanation

Let the standard be Rs. x. At that point, S.I = Rs. (16x/25) Let rate = R% p.a. also, time = R years. Then, S.I = (p*r*t)/100 = (100*p/P*8) => 16x/25 = (x*R*R/100) => R^{2}= 64 => R= 8. Thus, rate = 8% P.a. what's more, time = 8Years.