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Aptitude - Simple Interest Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Simple Interest. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - A man stored Rs 400 for a long time, Rs 550 for 4 year and Rs 1200 for 6 years. He got Rs 1020 as the aggregate simple interest. The rate of interest per annum is:
Answer : B
Explanation
Let the rate of interest be R% p.a. then, (400*R*2)/100 + (550*R*4)/100 + (1200*R*6)/100 = 1020 => 800R+2200R+7200R= 102000 => 10200R = 102000 => R = 10. Hence, the rate of interest is 10%.
Q 2 - At what rate of simple interest a certain aggregate will be multiplied in 15 years?
Answer : C
Explanation
Let the sum be rs. x. then, S.I = Rs.x. Rate = (100*S.I / sum*time) = (100*x/x*15) % p.a = 20/3% p.a.
Q 3 - Simple interest on a sure whole at a sure yearly rate of interest is 25/16 of the entirety. In the event that the number speaking to rate percent and time in years is equivalent, then rate percent per annum is:
Answer : D
Explanation
Let the sum be Rs. x, Rate = R% P.a., time = 25/2 years. S.I = Rs. 25x/16 R = 100*25x/16 *1/x* 1/R => R2=2500/16 = R= 25/2 Hence, Rate = 25/2%
Q 4 - An aggregate of Rs 5000 was loaned mostly at 6% and incompletely at 9% basic interest. On the off chance that the aggregate yearly premium be Rs 390, the proportion in which the cash was loaned at given rates is:
Answer : C
Explanation
Let the money invested at the two rates be rs. x and Rs. (5000-x) Then, (x*6/100*1) + (5000-x) *9/100*1 = 390 => 3x/50 + 9(5000-x)/100 = 390 => 6x+45000-9x = 39000 => 3x= 6000 => x= 2000. Required ratio = 2000:3000= 2:3
Q 5 - Anand took some advance at 12% P.a. simple interest and paid back Rs. 17584 toward the end of 3 years 4 months. What amount of cash did he acquire?
Answer : C
Explanation
Let the money borrowed be Rs. x. Then, x+x* 12/100* 10/3 = 17584 => (x+2x/5) = 17584 => 7x/5 = 17584 => x= (17584*5/7) = 12560. Hence, the money borrowed is Rs. 12560.
Q 6 - A sum of Rs 1500 is lent out in two parts in such a way that the simple interest on one part at 10% per annum for 5 years is equal to that on another pert at 12.5% per annum for 4 years. The sum lent out at 12.5% is:
Answer : C
Explanation
Let the sum lent out at 12.5% be x Sum lent out at 10% = 1500 - x Now, (1500-x)*10*5/100 = x * 12.5*4/100 Or, 50(1500-x) = 50x Or, 2x = 1500 Or, x = 750
Q 7 - The rate of simple interest on an amount of money is 6% per annum for the first two years, 9% per annum for the next five years, 13% per annum for the period beyond 7 years. If the total interest on a sum at the end of ten years is Rs 7,680, what is the sum?
Answer : B
Explanation
According to the question, Rs 7680 = P*6*2/100 + P*9*5/100 + P*13*3/100 Or, 12P + 45P + 39P = Rs 7680*100 Or, P = Rs 768000/96 = Rs 8000
Q 8 - Mr. Thomas invested an amount of Rs. 13,900 divided in two different Schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in scheme B?
Answer : B
Explanation
Let the sum be invested in scheme A be Rs. z and that in scheme B be Rs. (13900 - z) Then, z x 14 x 2⁄100 + (13900 - z) x 11 x 2⁄100 = 3508 28z -22z = 350800 - (13900 x 22) = 6z = 45000 = x = 7500 sum invested in scheme B = Rs (13900 - 7500) = 6400
Q 9 - A sure entirety of cash adds up to rs. 756 in 2 years and to Rs. 873 in 7/2 years. Discover the aggregate and the rate of hobby.
Answer : A
Explanation
Sum in 7/2 years = Rs. 873, sum in 2 years= Rs. 756 S.I for 3/2 year = Rs. (873-756) = Rs. 117 S.I for a long time = Rs. (117*2/3*2) = rs. 156. Standard = (sum in 2 year) - (s.I for 2 year) = Rs. (756-156)= Rs. 600 Presently P = 600 Rs. T= 2 years. What's more, S.I = 156 Rs. ∴ R = (100*S.I)/P*T = (100*156)/ (600*2) = 13% P.a. Henceforth, aggregate = Rs. 600 and Rate = 13% P.a.