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# Aptitude - Simple Interest Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Simple Interest**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - A man puts cash in three unique plans for a long time, 10 years and 12years at 10%, 12% and 15% simple premium, separately. At the completion of every plan he gets the same interest. The proportion of his speculations is:

### Answer : D

### Explanation

Let the required ratio be x: 1: y. Then, S.I on Rs. x for 6 years at 10 % p.a. = S.I on Re 1 for 10 years at 12%p.a. X*10/100*6 = 1*12/100*10 => x= 120/60= 2 S.I. on Rs.1 for 10 years at 12% p.a. = S.I. on Rs. y for 12 years at 15% p.a. ∴ (1*12/100*10) = (y* 15/100*12) => y = 120/180= 2/3 Required ratio = 2:1:2/3 = 6:3:2

Q 2 - The total of cash that will give Re 1 as basic premium for each at the rate of 5% for every annum is:

### Answer : C

### Explanation

Annual interest = Rs. 365, Rate = 5% p.a. Sum = (100*S.I/R*T) = Rs. (100*365/5*1) = Rs. 7300.

Q 3 - The simple interest at x% p.a. for x years will be Rs x on an aggregate of:

### Answer : C

### Explanation

Let the sum be Rs. P. then, P = 100*S.I /Rate * time = (100*x/x*x) = Rs. 100/x

Q 4 - An aggregate of Rs 5000 was loaned mostly at 6% and incompletely at 9% basic interest. On the off chance that the aggregate yearly premium be Rs 390, the proportion in which the cash was loaned at given rates is:

### Answer : C

### Explanation

Let the money invested at the two rates be rs. x and Rs. (5000-x) Then, (x*6/100*1) + (5000-x) *9/100*1 = 390 => 3x/50 + 9(5000-x)/100 = 390 => 6x+45000-9x = 39000 => 3x= 6000 => x= 2000. Required ratio = 2000:3000= 2:3

Q 5 - Anand took some advance at 12% P.a. simple interest and paid back Rs. 17584 toward the end of 3 years 4 months. What amount of cash did he acquire?

### Answer : C

### Explanation

Let the money borrowed be Rs. x. Then, x+x* 12/100* 10/3 = 17584 => (x+2x/5) = 17584 => 7x/5 = 17584 => x= (17584*5/7) = 12560. Hence, the money borrowed is Rs. 12560.

Q 6 - A sum of Rs 1500 is lent out in two parts in such a way that the simple interest on one part at 10% per annum for 5 years is equal to that on another pert at 12.5% per annum for 4 years. The sum lent out at 12.5% is:

### Answer : C

### Explanation

Let the sum lent out at 12.5% be x Sum lent out at 10% = 1500 - x Now, (1500-x)*10*5/100 = x * 12.5*4/100 Or, 50(1500-x) = 50x Or, 2x = 1500 Or, x = 750

Q 7 - A sum of money amounts to RS. 9800 after 5 years and to 12005 after a further period of 8 years at the same rate of simple interest. The rate of interest per annum is?

### Answer : A

### Explanation

S.I. for 3 year = Rs. (12005 - 9800) = 2205 S.I. for 5 years = Rs. (^{2205 x 5}⁄_{3}) = 3675 Therefore Principal = (9800 - 3675) = 6125 Hence, Rate = (^{100 x 3675}⁄_{6125 x 5}) = 12%

Q 8 - A money lender finds that due to fall in the annual rate of interest from 8% to 7^{3}⁄_{4}%, his yearly income diminishes by Rs. 61.50. His capital is?

### Answer : A

### Explanation

Let the capital be Rs z then,^{z x 8 x 1}⁄_{100}- z x^{31 x}⁄_{4}^{1}⁄_{100}= 61.50 32z - 31z = 6150 x 4 z = 24600

### Answer : A

### Explanation

Here P = 5600 Rs.R= 20/3% p.a. also, T = 9/12 = 3/4 year S.I = (P*R*T)/100 = (5600*20/3*3/4*1/100) = Rs. 280