# Aptitude - Simple Interest Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Simple Interest**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - An aggregate of cash adds up to Rs 5200 in 5 years and to Rs 5680 in 7 years at basic premium. The rate of interest per annum is:

### Answer : D

### Explanation

S.I for 2 years = Rs. (5680-5200) = Rs. 480 S.I for 1 year = Rs. (480/2) = 240 S.I for 5 year = (240*5) = 1200 Rs. Principle = Rs. (5200-1200) = 4000. Rate = (1200*100/4000*5) %p.a. = 6% p.a.

Q 2 - A man contributes 1/3 of his capital at 7% p.a. 1/4 at 8% p.a. what's more, the rest of 10% p.a. In the event that his yearly wage is Rs 561, the capital is:

### Answer : C

### Explanation

Let capital be rs. x. then, (x/3*7/100*1) +(x/4 * 8/100*1) + {x-(x/3+x/4)}*100*1= 561 => 7x/300 +x/50 +5x/120 = 561 =>14x+12x +25 x = 336600 => 51x = 336600 => x= 6600.

Q 3 - The distinction between the basic interests got from two unique sources on Rs 1500 for a long time is Rs 13.50. The contrast between their rates of interest is:

### Answer : C

### Explanation

Let the rates of interest be x% p.a. Then, (1500*x/100*3) ? (1500*y/100*3) =27/2 45(x-y) =27/2 => (x-y) = (27/2* 1/45)=3/10=0.3 Required difference = 0.3%

Q 4 - An aggregate of Rs 10000 is loaned mostly at 8% and the staying at 10% p.a. On the off chance that the year?s interest on the normal is 9.2% the cash loaned at 10% is:

### Answer : A

### Explanation

Ratio of investments = 0.8: 1.2: = 2:3 Money at 10% = Rs. (10000*3/5) = Rs. 6000>

Q 5 - With a given of rate of basic interest, the proportion of standard and measure of a sure timeframe is 4:5 , following 3 years , with the same rate of interest , the proportion of the rule and sum gets to be 5:7 , the rate of interest per annum is :

### Answer : B

### Explanation

After t years, let P =Rs. 4x and amount = Rs. 5x. P + S.I for t years = Rs. 5x P: {p+S.I for (t+3) years} = 5:7= 1: 7/5 = 4x: (7/5*4x) = 4x: 28x/5 ∴ P+S.I. For (t+3) years = Rs. 28x/5 On subtracting (i) from (ii), we get: S.I for 3 years = Rs. (28x/5 -5x) = Rs. 3x/5 S.I on Rs. 4x for 3 years = 3x/5 ∴ Rate = {(100*3x/5)/ (4x*3)} % p.a. = 5% p.a.

Q 6 - A person invests a certain sum at a certain rate of simple interest for 5 years. Had he invested it at 2% higher, he would have earned Rs 250 more. Find the sum he invested.

### Answer : A

### Explanation

Rs 250 is the additional interest in 5 years that he would have earned if he had invested it at 2% higher rate of interest. Hence we can consider, I = Rs 250, R = 2% and t = 5 years. P = I*100/Rt = (250*100)/2*5 = Rs 2500

Q 7 - The rate of simple interest on an amount of money is 6% per annum for the first two years, 9% per annum for the next five years, 13% per annum for the period beyond 7 years. If the total interest on a sum at the end of ten years is Rs 7,680, what is the sum?

### Answer : B

### Explanation

According to the question, Rs 7680 = P*6*2/100 + P*9*5/100 + P*13*3/100 Or, 12P + 45P + 39P = Rs 7680*100 Or, P = Rs 768000/96 = Rs 8000

Q 8 - An amount of Rs. 1,00,000 is invested in two types of shares. The first yields an interest of 9% p.a. and the second, 11% p.a. If the total interest at the end of one year is 9^{3}⁄_{4}, then the amount invested in each share was?

### Answer : A

### Explanation

Let the sum invested at 9% be Rs. z and that invested at 11% be Rs. ( 100000 - z ). Then,^{z x 9 x 1}⁄_{100}+^{(100000 - z) x 11 x 1}⁄_{100}= 100000 x^{39}⁄_{4}x^{1}⁄_{100}=^{9z + 1100000 - 11z}⁄_{100}

^{39000}⁄_{4}= 9750 2z = (1100000 - 975000) = 125000 x = 62500 sum invested at 9% = Rs. 62500 sum invested at 11% = Rs. (100000 - 62500) = 37500

Q 9 - Find S.I on Rs. 7300 at 12% p.a. for the period from fifth Jan. 2007 to 18 April 2007.

### Answer : B

### Explanation

Note: The day on which the cash is kept is not tallied and the day on which the cash is pulled back, is numbered. Here P = Rs. 7300, R= 12% P.a. T = 26 Jan+ Feb. 28+ 31 March +18 April = 103days. = 103/365 days. S.I = (p*R*T)/100 = (7300*12*103/365*1/100) = 1236/5 =Rs. 247.20