
- Aptitude - Home
- Aptitude - Overview
- Quantitative Aptitude
Aptitude - Squares & Cubes Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Squares & Cubes. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Answer : B
Explanation
Let 6/50 = √x/200. Then, √x =6/50*200 = 24 ∴ x= (24*24) = 576
Answer : C
Explanation
Let 250/√x =10, Then √x= 250/10 25 ⇒ x= (25)2=625
Q 3 - given that √3= 1.732, the value of 3 +√6 /(5√3-2√12 -√32+√50)is:
Answer : D
Explanation
Given exp = 3+√6/(5√3-2√4*3-√16*2+ √25*2) = 3+√6/(5√3-4√3-4√2+5√2) = (3+√6)/( √3+√2)*( √3-√2)/( √3-√2) = 3√3-3√2+√18-√12/(3-2) =(3√3-3√2+√9*2 -√4*3 )= (3√3-3√2+3√2-2√3) =√3= 1.732
Answer : A
Explanation
√0.001 + √0.0064 = √0.01+0.08 = √0.09 = 0.3
Answer : C
Explanation
√0.0064 = √64/10000= 8/100 = 0.08 Given expression = √0.01+0.08/ 0.01*0.3 =√ 0.09/0.03 = 0.3/0.003 =0.300/0.003 =300/3 =100
Answer : D
Explanation
√0.0016 = √16/10000 = 4/100 =0.04 ∴ x*0.04 =4 ⇒ x = 4/0.04= 4*100/4 =100
Answer : C
Explanation
√x+1 +√x-1/√x+1=√x-1= 3 ⇒ (√x+1 +√x-1)/(√x+1*√x+1 +√x-1/√x+1=√x-1= 3 ⇒ ((√x+1 +√x-1)2 /(x+1)-(x-1) = [(x+1+x-1)+2√x+1. √X-1]/2 =3 ⇒2(x+√ x2-1)/2 =3 ⇒ x+√x2-1 =3 ⇒ √x2-1=(3-x) ⇒ (x2-1)=(3-x)2 =(9+x2-6x) ⇒ 6x-10=0 ⇒ 6x=10 ⇒ x= 10/6 =5/3
Answer : C
Explanation
1120/ √p= 80 ⇒ √p =1120/80 =14 ⇒ P=(14*14) = 196
Answer : C
Explanation
√8/3 = √8*3/3*3 = √24/√9 =√24/3 =4.899/3 =1.633
Answer : B
Explanation
Let x = √2+√2+√2+√2+...∞. Then x= √2+x ∴ 2+x= x2 ⇒ x2-x-2= 0 ⇒ x2-2x+x-2 =0 ⇒ x(x-2)+(x-2)= 0 ⇒ (x-2)(x+1)=0 ⇒ x= 2 (∵x≠ -1)
aptitude_squares_cubes.htm
Advertisements