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Following quiz provides Multiple Choice Questions (MCQs) related to **Chain Rules**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - If 4/5th of a cistern is filled in 1 minute, how much more time will be required to fill the rest of it?

Let the required time be x seconds. Part filled = 4/5, Remaining part = (1- 4/5 ) = 1/5. Less part to be filled , less is the time taken (direct) 4/5 :1/5 :: 60 : x ⇒ 4/5 * x = (1/5 * 60 ) = 12 ⇒ x= (12 * 5/4 ) = 15. Required time = 15 seconds.

Q 2 - The Qutab minar casts a shadow 150m long at the same time when the vikes minar casts a shadow 120m long on the ground . If the height of the Vikes minar is 80m, what is the height of the Qutab Minar?

Let the height of the Qutab Minar be x metres. Longer is the shadow , longer is the object (Direct) 120 : 150 :: 80 : x ⇒ 120 * x = (150 *80)⇒ x= (150 *80)/120=100m. Height of Qutab Miinar = 100m.

Q 3 - If 12 men or 18 women can do a piece of work in 14 days , how long will 8 men and 16 women take to finish the work?

12 men = 18 women ⇒ 1 man = 18/12 women ⇒ 8 men = (18/12 * 8) women = 12 women ⇒ (8 men + 16 women ) = 28 women Let the required number of days be x. More women, less days (Indirect) 28: 18:: 14 : x ⇒ 28x = (18*14 ) ⇒ x= (18 *14) / 28 = 9days

Q 4 - 8 men can finish a piece of work in 40 days . If 2 more men join with them , then the work will be completed in?

Let 10 men finish it in x days. More men, less days (Indirect) 10 : 8 :: 40 : x ⇒ 10x = (8 * 40 ) ⇒ x = (8*40) /10 = 32 days.

Q 5 - If 9 men working hours 15/2 hours a day can finish a work in 20 days , then how many days will be taken by 12 men , working 6 hours a day to finish the work . It is given that 2 men of latter type work as much as 3 men of former type?

2 men of latter type = 3 men of former tyes. 12 men of latter type = (3/2 *12) = 18 men of former tyes. Let the required number of days be x. More men , less days (Indirect) Men 18 : 9 :: 20 : x Working hrs 6 : 15 /2 ∴ 18 *6 *x = 9 * 15/2 * 20 ⇒ x= 9 * 150/18 * 6 = 25/2 = 25/2 days.

Q 6 - Four examiners can examine a certain number of answer papers in 10 days by working for 5 hours a day. For how many hours in a day would 2 examiners have to work in order to examine twice the number of answer papers in 20 days?

Let the number of hours per days be x. More days, less hours per days ( Indirect) Less examiners , more hours per days ( Indirect) More Ans. Books , more hours per days ( direct) Days 20 : 10 Examiners 2 : 4 :: 5 : x Ans. Books 1 : 2 ∴ (20 * 2 * 1 * x) = ( 10 * 4 * 2* 5 ) ⇒ x = 400 / 40 = 10 hrs per days.

Q 7 - If 5 spiders can catch 5 flies in 5 minutes, how many flies can 100 spiders catch in 100 minutes?

Let the required number of flies be x. More spiders , more flies ( Direct) More time, more flies ( Direct) Spiders 5 : 100 :: 5 : x Times 5 : 100 ( 5* 5 * x ) = ( 10 0* 100* 5 ) ⇒ x= 100 * 100* 5 / 5 * 5 = 2000 flies.

Q 8 - In a hospital, there is a consumption of 1350 litres of milk for 70 patients for 30 days. How many patients will consume 1710 litres of milk in 28 days?

Let the required number of patients be x . More milk, more patients (Direct) Less days , more patients (Indirect) Litres 1350:1710 ::70 : x Days 28 : 30 ∴ ( 1350 * 28 * x ) = ( 1710 * 30 * 70) ⇒ x= 1710 * 30 * 70/ ( 1350 * 28 ) = 95 patients.

Q 9 - If 18 pumps can raise 2170 tonnes of water in 10 days , working 7 hours per day , in how many days will 16 pumps rise 1736 tonnes, working 9 hours per day?

Let the required number of days be x. Less pumps, more days (Indirect) Less water, less days (direct) More working hrs, less days (Indirect) Pumps 16:18 Water Qty. 2170 : 1736 :: 10 :x Water hrs 9:7 ∴ (16 * 2170 * 9 *x ) = ( 18 * 1736*7 *10)⇒ x=18 * 1736*7 *10/16*2170 * 9 = 7 days .

Q 10 - A contractor undertakes to do a piece of work in 40 days . He engages 100 men at the beginning and 100 more after 35 days and complete the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished?

[(100 *35 ) + (200 *5)] men can finish the work in 1 day. 4500 men can finish it in 1 day ∴ men can finish it in 4500/100 days = 45 days. This is 5 days behind schedule.

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