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Chain Rules - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Chain Rules. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - If 4/5th of a cistern is filled in 1 minute, how much more time will be required to fill the rest of it?
Answer : B
Explanation
Let the required time be x seconds. Part filled = 4/5, Remaining part = (1- 4/5 ) = 1/5. Less part to be filled , less is the time taken (direct) 4/5 :1/5 :: 60 : x ⇒ 4/5 * x = (1/5 * 60 ) = 12 ⇒ x= (12 * 5/4 ) = 15. Required time = 15 seconds.
Q 2 - 3 men or 5 women can finish a piece of work in 12 days. How long will 6 men and 5 women take to finish the work?
Answer : A
Explanation
3 men = 5 women ⇒ 6 men =10 women ⇒ (6 men +5 women )= 15 women. Let the required number of days be x. More women , less days (Indirect) 15 : 5 :: 12 : x ⇒ 15x = (5* 12 ) ⇒ x= (5*12)/15 = 4 days
Q 3 - 8 men can complete a piece of work in 12 days ; 4 women can complete it in 48 days and 10 children can complete the same piece of work in 24 days . In how many days can 10 men , 4 women and 10 children complete the same piece of work?
Answer : D
Explanation
1 man can complete the work in ( 12 * 8) = 96 days. 1 women can complete the work in ( 48 * 4) = 192 days. 1 child can complete the work in ( 24 * 10) = 240 days. 1 men 1 days work = 1/96, 1 women1 days work = 1/192. 1 child 1 days work = 1/240. ( 10 men + 4 women + 10 children) 1 days work = ( 10/ 96 + 4/192 + 10/240) = (5/48 + 1 /48 + 1/24) = 8/48 = 1/6. ∴ They will do the work in 6 days.
Q 4 - A man and a boy working together can complete a work in 24 days . If for the last 6 days man alone the work , then it is completed in 26 days. How long will the boy take to complete the work alone?
Answer : A
Explanation
Let 1 men 1 days work be 1/x and 1 boy 1 days work be 1/y Then, 1/x + 1/y = 1/24 20/x + 20 / y + 6 /x )1 ⇒ 20 (1/x + 1/y) + 6/x = 1 ⇒ (20 * 24) + 6/x = 1 ⇒ 6/x = (1- 20/24) = 4 / 24 = 1/6 ⇒ 1/x = 1/ 36 ⇒ 1/y = ( 1/24 - 1/ 36 ) = 1/72. ∴ The boy along will do it in 72 days.
Q 5 - If 9 men working hours 15/2 hours a day can finish a work in 20 days , then how many days will be taken by 12 men , working 6 hours a day to finish the work . It is given that 2 men of latter type work as much as 3 men of former type?
Answer : C
Explanation
2 men of latter type = 3 men of former tyes. 12 men of latter type = (3/2 *12) = 18 men of former tyes. Let the required number of days be x. More men , less days (Indirect) Men 18 : 9 :: 20 : x Working hrs 6 : 15 /2 ∴ 18 *6 *x = 9 * 15/2 * 20 ⇒ x= 9 * 150/18 * 6 = 25/2 = 25/2 days.
Q 6 - A contractor undertakes to build a wall in 50 days. He employs 50 people for the same . However, after 25 days , he finds that only 40 % of the work is complete , How many more men need to be employed to complete the work in time?
Answer : B
Explanation
Work done = 40/100 = 2/5 , Remaining work = ( 1 - 2/5 ) = 3/5. 2/5 work is done in 25 days by 50 people. 3/5 work will be done in 25 days by (50 * 5/ 2 * 3/5) people = 75 people. Required number of people = ( 75 ? 50 ) = 25.
Q 7 - Running at the same constant rate , 6 identical machines can produce 2700 bottle per minute . At this rate , how many bottles could 10 such machines produce in 4 minutes?
Answer : B
Explanation
Let the required number of bottles be x . More machines, more bottles ( Direct) More time, more bottles ( Direct) Machines 6 : 10 :: 2700 : x Time 1:4 (6 * 1 * x) = 10 * 4 * 2700 ) ⇒ 10 * 4 * 2700 / 6 = 1800 bottles.
Q 8 - In a hospital, there is a consumption of 1350 litres of milk for 70 patients for 30 days. How many patients will consume 1710 litres of milk in 28 days?
Answer : C
Explanation
Let the required number of patients be x . More milk, more patients (Direct) Less days , more patients (Indirect) Litres 1350:1710 ::70 : x Days 28 : 30 ∴ ( 1350 * 28 * x ) = ( 1710 * 30 * 70) ⇒ x= 1710 * 30 * 70/ ( 1350 * 28 ) = 95 patients.
Q 9 - A contractor employed 30 men to do a piece of work in 38 days. After 25 days he employed 5 men more and the work was finished one day earlier. How many days , he would have been behind , if he had not employed additional men?
Answer : A
Explanation
After 25 days , 35 men finish the remaining work in (38 - 25 - 1) = 12 days. 35 men can finish the remaining work in 12 days. 30 men can finish it in (12 * 35) /30 days = 14 days , i.e. 1 day behind.
Q 10 - A contractor undertakes to do a piece of work in 40 days . He engages 100 men at the beginning and 100 more after 35 days and complete the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished?
Answer : A
Explanation
[(100 *35 ) + (200 *5)] men can finish the work in 1 day. 4500 men can finish it in 1 day ∴ men can finish it in 4500/100 days = 45 days. This is 5 days behind schedule.