# Aptitude - Profit & Loss Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Profit & Loss**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - Amit sold an umbrella for Rs. 680, losing 15%. The expense cost of the umbrella is:

### Answer : B

### Explanation

Let the C.P. be Rs x =Then, S.P. = 85% of Rs x. ∴ 85/100 * x =680 ⇒ x = (680*20/17) =800. ∴ C.P. =Rs 800.

Q 2 - Raghavan purchased a bike at 13/15 of its checked value and sold it at 12% more than the checked cost. His addition % is:

### Answer : A

### Explanation

Let M.P be Rs. x. Then, C.P = Rs. 13x/15 S.P = (112% of x) = (112/100*x) =Rs. 28X/25 Gain = Rs. (28x/25-13x/15) = (84x-65x)/75 = Rs. 19x/75 Gain % = (19x/75 *15/13x*100) % = 380/13%

Q 3 - On offering an article for Rs. 19.5, a man increases 30%. So as to increase 40%, what will be increment in its offering cost?

### Answer : C

### Explanation

S.P = Rs. 19.50 , Gain =30% ∴ C.P = (100/130*19.50) = 15 Now, C.P = Rs. 15, gain = 40% New S.P= (140/100*15) =21 Increase = Rs. (21-19.50) = Rs. 1.50

Q 4 - A shipper has 1000kg of sugar, a portion of which he offers at 8% benefit what's more, and the rest at 18% benefit. He increases 14% in general. The amount sold at 18% benefit is:

### Answer : B

### Explanation

Let the sugar sold at *5 gain be x kg. Then, sugar sold at 18% gain = (1000-x) kg Let the C.P Of sugar be Rs. Y per Kg. Total C.P = Rs.(1000y) (108/100*xy)+ 118/100 (1000-x)y = 114/100 *1000y ⇒108xy + 118000y -118xy = 114000y ⇒ 10x =4000 ⇒ x= 400 Quantity sold at 18% gain= (1000-400) = 600 kg

Q 5 - A salesman is allowed 11/2% discount on the total sales made by him plus a bonus of 1/2% on sales over Re 10000. If his total earnings were Re 1990, his total sales was:

### Answer : D

### Explanation

Let the salesman?s total sales = Re (10000 + x) According to the question, 10000 * 11/2% + x*6% = 1990 Or, 5000*11% + 6x% = 1990 Or 5000*11/100 + 6x/100 = 1990 Or, 550 + 6x/100 = 1990 Or, 55000 + 6x = 199000 Or, 6x = 199000 ? 55000 Or, 6x = 144000 Or, x = 144000/6 = 24000 ∴The required sales = Re (1000 + 24000) = Re 34000

Q 6 - By selling an article for Rs.8.5 a dealer makes a profit of 20% by how much should he increase his selling price so as to make a profit of 30%?

### Answer : A

### Explanation

Assume cost = 100 ; Assume cost = 100 Profit =20 = 120 ; Profit= 30 = 130 =? 120 = 24 130 =? 130x24/( 120)=28 Increase in Selling price = 28-24=4

Q 7 - The aggregate expense cost of two watches is R. 840. One is sold at a benefit of 16% and the other at lost 12%. There is no misfortune or addition in the entire exchange. The expense cost of the watch on which the businessperson additions, is:

### Answer : A

### Explanation

Let their C.P be rs. x and Rs. (840-x) resp. Then, (116/100*x) + 88/100*(840-x) ⇒ 29x/25+ (22 (840-x)/25) = 840 ⇒ (29x-22x) + 18480 =21000 ⇒ 7x =2520 ∴ Required C.P = Rs. 360

Q 8 - Rs. 355 were separated among A, B,C in a manner that A had Rs. 20 more than B and C had Rs.15 all the more than A . What amount was C offer?

### Answer : C

**Explanation**

Suppose B gets Rs. X. Then, A gets Rs. (x+20) and C gets Rs. (x+35) ∴ x+20+x+x+35= 355 => 3x=300 =>x=100 ∴ C share= (100+35) =135.

Q 9 - A broker denotes his merchandise at such a cost, to the point that he can deduct 15% for money but makes 20% benefit. The stamped cost of a thing which cost him Rs 90 is:

### Answer : C

### Explanation

C.P = RS. 90, Gain =20% ∴ S.P = (120/100*90) = Rs.108 Let the M.P be Rs. x then, 85% of x = 108. ∴ 85/100*x =108 ⇒x=(108*100/85) = 2160/17.∴ M.P = 2160/17

Q 10 - A rebate arrangement of P% and Q% on a receipt is the same as a Single rebate of:

### Answer : D

### Explanation

Let M.P be rs. 100. Then, S.P = (100-p)% of (100-q)% of Rs. 100 = { (100-p)/100 * (100-q)/100*100} = rs. [100-p) (100-q)]/100 Single discount = {100- (100-p) (100-q)/100}% = [10000- (10000-100q-100p+pq)/100]% = 100q+100p-pq/100 = {(p+q)-pq/100}%