# Aptitude - Calendar Online Quiz

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Following quiz provides Multiple Choice Questions (MCQs) related to **Calendar**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

### Answer : A

### Explanation

4Th.june, 2002 = (2001 years+ period from 1.1.2002 to. 4.6.2002. Odd days in 1600 years = 0 Odd days in 400 years = 0 Odd days in 1 customary years = 1 Odd days in 2001 years = (0+0+1)=1 Jan + Feb. +March +April+ May +June (31 + 28 +31+ 30 + 31 +4 = 155 days=22 weeks +1 day = 1 odd days Aggregate no. of odd days = (1+1) = 2 ∴ required day is Tuesday.

Q 2 - Jan.1, 2007 was Monday. What day of the week lies on Jan 1, 2008?

### Answer : B

### Explanation

The year 2007 is a common year. So, it has 1 odd day. First day of the year 2007 was Monday. First day of the year 2008 will be 1 day past Monday. Subsequently, it will be Tuesday.

Q 3 - Jan.1 2008 is Tuesday. What date of the week lies on Jan 1, 2009?

### Answer : C

### Explanation

The year 2008 is a jump year. So, it has 2 odd days. First day of the year 2008 is Tuesday (Given). In this way, first day of the year 2009 is 2 days past Tuesday. Subsequently, it will be Thursday.

Q 4 - On sixth March, 2005 Monday falls. What was the day of the week on sixth March, 2004?

### Answer : B

### Explanation

The year 2004 is a jump year. In this way, it has 2 odd days. ∴ The day on sixth March, 2005 will be 2 days. past the day on sixth Walk, 2004. Yet, sixth March, 2005 is Monday. ∴ sixth March, 2004 is Saturday.

Q 5 - What was the week's day on seventeenth June, 1988?

### Answer : D

### Explanation

17th June, 1998= (1997 year Period structure 1.1.1998 to 17.6.1998) Odd days in 1600 year=0. Odd days in 300 year = (5*3) =1. 97 year has 24 jump year +73 standard years. = 24*2 + 73*1 = 48 + 73 = 121 odd days = 17 weeks + 2 odd days = 2 odd days = 2 odd days. ∴ 1998 years have (0+1+2) = 3 odd days Jan to June = (31+29+31+30+31) = 152 days Add 17 days of June. = 152 + 17 = 169 days = 24 weeks + 1 days = 1 odd day. ∴ Total number of odd day = 3 + 1 = 4 odd days. Hence 17.06.1998 was Thursday.

### Answer : D

### Explanation

28.May,2006 =(2005 years +Period structure 1.1.2006 to 28.5.2006) Odd days in 1600 years=0. Odd days in 400 years = 0. 5 years = (4 common years+ 1 jump years)=(4*1+1*2)odd days = 6 odd days. Jan + Feb. + March + April + May 31 + 28 + 31 + 30 + 28 =148 days. 148 days = (21 weeks+1 day) = 1 odd day Aggregate no. of odd days = (0+0+6+1) = 7= 0 odd day. Given day is Sunday.

### Answer : C

### Explanation

100 years contain 5 odd days. ∴ Last day of first century is Friday. 200 years contain (5*2) = 3 odd days. ∴ Last day of second century is Wednesday. 300 year contain (5*3) =15=1 odd day. ∴ Last day of third century is Monday. 400 year contain 0 odd days. ∴ Last day of fourth century is Sunday. The cycle is repeated. ∴ Last day of a century can't be Tuesday or Thursday or Saturday.

### Answer : B

### Explanation

x weeks x days=(7x+x) days=8x days.

Q 9 - On eighth Feb, 2005 it was Tuesday. What was the week's day on eighth Feb, 2004?

### Answer : C

### Explanation

The year 2004 is a jump year. It has 2 odd days. ∴ The day on eighth Feb,2004 is 2 days before the day. On eighth Feb, 2005. Henceforth This day is Sunday.

aptitude_calendar.htm

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