# Aptitude - Calendar Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Calendar**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - On What dates of March 2005 did Friday fall?

A - 5^{th}, 12^{th}, 17^{th} and 24^{th}

B - 4^{th}, 11^{th}, 18^{th} and 25^{th}

### Answer : B

### Explanation

To begin with we discover the day on 1.3.2005. 1.3.2005= (2004 year+ period from 1.1.2005 to 1.3.2005 Odd days in 1600 years = 0 Odd days in 400 years = 0 4 years = (1 jump year+ 3 normal years) = (1*2+3*1) odd days = 5 odd days. Jan + Feb + March 31 + 28 + 1 = 60 days = (8 weeks +4 days)=4 odd days. ∴ Total number of odd days = (0+0+5+4) =9=2 odd days. ∴ 1.3.2005 was Tuesday. So, Friday lies on 4.3.2005. Thus, Friday lies on 4th, 11th, 18th and 25th of March, 2005.

Q 2 - What was the week's day on sixteenth July, 1776?

### Answer : B

### Explanation

16 July, 1776 = (1775 years + period from 1.1.1776 to 16.7.1776. Checking of odd days. No. of odd days in 1600 years =0 No. of odd days in 100 years = 5 75 years= 18 jump years+57 conventional years = (18*2+57*1) odd days = 93 odd days = (13 weeks +2 days) = 2 odd days. ∴ 1775 years have= (0+5+2) odd days= 7 days= 0 days Jan + Feb. + March + April + May + June + July 31 +29 + 31 + 30 + 31 + 30 +16 = 198 days 198 days = (28 weeks+2 days) = 2 odd days =Total no. of odd days = (0+2) = 2 Thus, the required day is Tuesday.

Q 3 - On eighth Dec, 2007 Saturday falls. What was the day of the week would it say it was on eighth dec, 2006?

### Answer : D

### Explanation

The year 2006 is a common year. Along these lines, it has 1 odd day. In this way, the day on eighth Dec, 2007 will be 1 day past the day. On eighth Dec, 2006. Yet, eighth Dec,2007 is Saturday. ∴ eighth Dec, 2007 is Friday.

Q 4 - The calendar for the year 2007 will be the same for the year:

### Answer : D

### Explanation

Count the number of odd days from the year 2007 onwards, to get the sum equal to 0 odd days.

years | 2007 | 2008 | 2009 | 2010 | 2011 | 2012 | 2013 | 2014 | 2015 | 2016 | 2017 |
---|---|---|---|---|---|---|---|---|---|---|---|

Odd Days | 1 | 2 | 1 | 1 | 1 | 2 | 1 | 1 | 1 | 2 | 1 |

Q 5 - What was the week's day on seventeenth June, 1988?

### Answer : D

### Explanation

17th June, 1998= (1997 year Period structure 1.1.1998 to 17.6.1998) Odd days in 1600 year=0. Odd days in 300 year = (5*3) =1. 97 year has 24 jump year +73 standard years. = 24*2 + 73*1 = 48 + 73 = 121 odd days = 17 weeks + 2 odd days = 2 odd days = 2 odd days. ∴ 1998 years have (0+1+2) = 3 odd days Jan to June = (31+29+31+30+31) = 152 days Add 17 days of June. = 152 + 17 = 169 days = 24 weeks + 1 days = 1 odd day. ∴ Total number of odd day = 3 + 1 = 4 odd days. Hence 17.06.1998 was Thursday.

### Answer : D

### Explanation

28.May,2006 =(2005 years +Period structure 1.1.2006 to 28.5.2006) Odd days in 1600 years=0. Odd days in 400 years = 0. 5 years = (4 common years+ 1 jump years)=(4*1+1*2)odd days = 6 odd days. Jan + Feb. + March + April + May 31 + 28 + 31 + 30 + 28 =148 days. 148 days = (21 weeks+1 day) = 1 odd day Aggregate no. of odd days = (0+0+6+1) = 7= 0 odd day. Given day is Sunday.

### Answer : C

### Explanation

100 years contain 5 odd days. ∴ Last day of first century is Friday. 200 years contain (5*2) = 3 odd days. ∴ Last day of second century is Wednesday. 300 year contain (5*3) =15=1 odd day. ∴ Last day of third century is Monday. 400 year contain 0 odd days. ∴ Last day of fourth century is Sunday. The cycle is repeated. ∴ Last day of a century can't be Tuesday or Thursday or Saturday.

### Answer : A

### Explanation

The century divisible by 400 is a leap year. ∴ The year 700 is not a jump year.

Q 9 - It was Sunday on Jan 1, 2006. Discover the week's day on Jan 1, 2010.

### Answer : C

### Explanation

On 31st December,2005 it was Saturday. Number of odd days frame the year 2006 to the year 2009=(1+1+2+1)=5 days. ∴ On 31st December 2009 , it was Thursday. In this way, on first jan, 2010 it is Friday.