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# Aptitude - Calendar Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Calendar**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - On What dates of March 2005 did Friday fall?

A - 5^{th}, 12^{th}, 17^{th} and 24^{th}

B - 4^{th}, 11^{th}, 18^{th} and 25^{th}

### Answer : B

### Explanation

To begin with we discover the day on 1.3.2005. 1.3.2005= (2004 year+ period from 1.1.2005 to 1.3.2005 Odd days in 1600 years = 0 Odd days in 400 years = 0 4 years = (1 jump year+ 3 normal years) = (1*2+3*1) odd days = 5 odd days. Jan + Feb + March 31 + 28 + 1 = 60 days = (8 weeks +4 days)=4 odd days. ∴ Total number of odd days = (0+0+5+4) =9=2 odd days. ∴ 1.3.2005 was Tuesday. So, Friday lies on 4.3.2005. Thus, Friday lies on 4th, 11th, 18th and 25th of March, 2005.

Q 2 - Jan.1, 2007 was Monday. What day of the week lies on Jan 1, 2008?

### Answer : B

### Explanation

The year 2007 is a common year. So, it has 1 odd day. First day of the year 2007 was Monday. First day of the year 2008 will be 1 day past Monday. Subsequently, it will be Tuesday.

Q 3 - On eighth Dec, 2007 Saturday falls. What was the day of the week would it say it was on eighth dec, 2006?

### Answer : D

### Explanation

The year 2006 is a common year. Along these lines, it has 1 odd day. In this way, the day on eighth Dec, 2007 will be 1 day past the day. On eighth Dec, 2006. Yet, eighth Dec,2007 is Saturday. ∴ eighth Dec, 2007 is Friday.

Q 4 - On sixth March, 2005 Monday falls. What was the day of the week on sixth March, 2004?

### Answer : B

### Explanation

The year 2004 is a jump year. In this way, it has 2 odd days. ∴ The day on sixth March, 2005 will be 2 days. past the day on sixth Walk, 2004. Yet, sixth March, 2005 is Monday. ∴ sixth March, 2004 is Saturday.

Q 5 - What was the week's day on seventeenth June, 1988?

### Answer : D

### Explanation

17th June, 1998= (1997 year Period structure 1.1.1998 to 17.6.1998) Odd days in 1600 year=0. Odd days in 300 year = (5*3) =1. 97 year has 24 jump year +73 standard years. = 24*2 + 73*1 = 48 + 73 = 121 odd days = 17 weeks + 2 odd days = 2 odd days = 2 odd days. ∴ 1998 years have (0+1+2) = 3 odd days Jan to June = (31+29+31+30+31) = 152 days Add 17 days of June. = 152 + 17 = 169 days = 24 weeks + 1 days = 1 odd day. ∴ Total number of odd day = 3 + 1 = 4 odd days. Hence 17.06.1998 was Thursday.

### Answer : D

### Explanation

28.May,2006 =(2005 years +Period structure 1.1.2006 to 28.5.2006) Odd days in 1600 years=0. Odd days in 400 years = 0. 5 years = (4 common years+ 1 jump years)=(4*1+1*2)odd days = 6 odd days. Jan + Feb. + March + April + May 31 + 28 + 31 + 30 + 28 =148 days. 148 days = (21 weeks+1 day) = 1 odd day Aggregate no. of odd days = (0+0+6+1) = 7= 0 odd day. Given day is Sunday.

Q 7 - Today is Monday. Following 61 days, it will be?

### Answer : B

### Explanation

Each day of the week is rehashed following 7 days. In this way, after 63 days it will be Monday. ∴ Following 61 days , it will be Saturday.

### Answer : B

### Explanation

x weeks x days=(7x+x) days=8x days.

Q 9 - It was Sunday on Jan 1, 2006. Discover the week's day on Jan 1, 2010.

### Answer : C

### Explanation

On 31st December,2005 it was Saturday. Number of odd days frame the year 2006 to the year 2009=(1+1+2+1)=5 days. ∴ On 31st December 2009 , it was Thursday. In this way, on first jan, 2010 it is Friday.