# Aptitude - Calendar Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Calendar**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - On What dates of March 2005 did Friday fall?

A - 5^{th}, 12^{th}, 17^{th} and 24^{th}

B - 4^{th}, 11^{th}, 18^{th} and 25^{th}

### Answer : B

### Explanation

To begin with we discover the day on 1.3.2005. 1.3.2005= (2004 year+ period from 1.1.2005 to 1.3.2005 Odd days in 1600 years = 0 Odd days in 400 years = 0 4 years = (1 jump year+ 3 normal years) = (1*2+3*1) odd days = 5 odd days. Jan + Feb + March 31 + 28 + 1 = 60 days = (8 weeks +4 days)=4 odd days. ∴ Total number of odd days = (0+0+5+4) =9=2 odd days. ∴ 1.3.2005 was Tuesday. So, Friday lies on 4.3.2005. Thus, Friday lies on 4th, 11th, 18th and 25th of March, 2005.

Q 2 - Jan.1, 2007 was Monday. What day of the week lies on Jan 1, 2008?

### Answer : B

### Explanation

The year 2007 is a common year. So, it has 1 odd day. First day of the year 2007 was Monday. First day of the year 2008 will be 1 day past Monday. Subsequently, it will be Tuesday.

Q 3 - Jan.1 2008 is Tuesday. What date of the week lies on Jan 1, 2009?

### Answer : C

### Explanation

The year 2008 is a jump year. So, it has 2 odd days. First day of the year 2008 is Tuesday (Given). In this way, first day of the year 2009 is 2 days past Tuesday. Subsequently, it will be Thursday.

Q 4 - The calendar for the year 2007 will be the same for the year:

### Answer : D

### Explanation

Count the number of odd days from the year 2007 onwards, to get the sum equal to 0 odd days.

years | 2007 | 2008 | 2009 | 2010 | 2011 | 2012 | 2013 | 2014 | 2015 | 2016 | 2017 |
---|---|---|---|---|---|---|---|---|---|---|---|

Odd Days | 1 | 2 | 1 | 1 | 1 | 2 | 1 | 1 | 1 | 2 | 1 |

Q 5 - on what dates of April, 2001 did Wednesday fall?

### Answer : D

### Explanation

We might discover the day on first April, 2001. First April , 2001=(2000 year + Period structure 1.1.2001 to 1.4.2001) Odd days in 1600 years =0. Odd days in 400 year =0. Jan Feb March April 31 + 28 + 31 + 1 = 91 days =0 odd day. Aggregate number of odd days= (0+0+0) =0. On first April, 2001 it was Sunday. In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.

Q 6 - What will be the day of the week on fifteenth 2010?

### Answer : A

### Explanation

fifteenth August,2010 =(2009 years+ Period from 1.1.2010 to 15.8.2010) Odd days in 1600 years = 0. Odd days in 400 years = 0. 9 year = (2 jump year +7 conventional years) = (2*2+7*1) = 11 odd days= 4 odd days Jan + feb + March + April + May + June + July + august 31+28+31+30+31+30+31+15 = 227 days =(32 weeks +3 days ) = 3 odd days Aggregate no. of odd days = (0+0+4+3) =7 = 0 odd day Given day is Sunday.

### Answer : C

### Explanation

100 years contain 5 odd days. ∴ Last day of first century is Friday. 200 years contain (5*2) = 3 odd days. ∴ Last day of second century is Wednesday. 300 year contain (5*3) =15=1 odd day. ∴ Last day of third century is Monday. 400 year contain 0 odd days. ∴ Last day of fourth century is Sunday. The cycle is repeated. ∴ Last day of a century can't be Tuesday or Thursday or Saturday.

### Answer : B

### Explanation

x weeks x days=(7x+x) days=8x days.

Q 9 - It was Sunday on Jan 1, 2006. Discover the week's day on Jan 1, 2010.

### Answer : C

### Explanation

On 31st December,2005 it was Saturday. Number of odd days frame the year 2006 to the year 2009=(1+1+2+1)=5 days. ∴ On 31st December 2009 , it was Thursday. In this way, on first jan, 2010 it is Friday.