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Aptitude - Calendar Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Calendar. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : A
Explanation
4Th.june, 2002 = (2001 years+ period from 1.1.2002 to. 4.6.2002. Odd days in 1600 years = 0 Odd days in 400 years = 0 Odd days in 1 customary years = 1 Odd days in 2001 years = (0+0+1)=1 Jan + Feb. +March +April+ May +June (31 + 28 +31+ 30 + 31 +4 = 155 days=22 weeks +1 day = 1 odd days Aggregate no. of odd days = (1+1) = 2 ∴ required day is Tuesday.
Q 2 - What was the week's day on sixteenth July, 1776?
Answer : B
Explanation
16 July, 1776 = (1775 years + period from 1.1.1776 to 16.7.1776. Checking of odd days. No. of odd days in 1600 years =0 No. of odd days in 100 years = 5 75 years= 18 jump years+57 conventional years = (18*2+57*1) odd days = 93 odd days = (13 weeks +2 days) = 2 odd days. ∴ 1775 years have= (0+5+2) odd days= 7 days= 0 days Jan + Feb. + March + April + May + June + July 31 +29 + 31 + 30 + 31 + 30 +16 = 198 days 198 days = (28 weeks+2 days) = 2 odd days =Total no. of odd days = (0+2) = 2 Thus, the required day is Tuesday.
Q 3 - Jan.1 2008 is Tuesday. What date of the week lies on Jan 1, 2009?
Answer : C
Explanation
The year 2008 is a jump year. So, it has 2 odd days. First day of the year 2008 is Tuesday (Given). In this way, first day of the year 2009 is 2 days past Tuesday. Subsequently, it will be Thursday.
Q 4 - The calendar for the year 2007 will be the same for the year:
Answer : D
Explanation
Count the number of odd days from the year 2007 onwards, to get the sum equal to 0 odd days.Sum =14 odd days=0 odd day. ∴ Calendar for the year 2018 will be the same as for the year 2007.
years 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd Days 1 2 1 1 1 2 1 1 1 2 1
Q 5 - on what dates of April, 2001 did Wednesday fall?
Answer : D
Explanation
We might discover the day on first April, 2001. First April , 2001=(2000 year + Period structure 1.1.2001 to 1.4.2001) Odd days in 1600 years =0. Odd days in 400 year =0. Jan Feb March April 31 + 28 + 31 + 1 = 91 days =0 odd day. Aggregate number of odd days= (0+0+0) =0. On first April, 2001 it was Sunday. In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.
Q 6 - What will be the day of the week on fifteenth 2010?
Answer : A
Explanation
fifteenth August,2010 =(2009 years+ Period from 1.1.2010 to 15.8.2010) Odd days in 1600 years = 0. Odd days in 400 years = 0. 9 year = (2 jump year +7 conventional years) = (2*2+7*1) = 11 odd days= 4 odd days Jan + feb + March + April + May + June + July + august 31+28+31+30+31+30+31+15 = 227 days =(32 weeks +3 days ) = 3 odd days Aggregate no. of odd days = (0+0+4+3) =7 = 0 odd day Given day is Sunday.
Q 7 - Today is Monday. Following 61 days, it will be?
Answer : B
Explanation
Each day of the week is rehashed following 7 days. In this way, after 63 days it will be Monday. ∴ Following 61 days , it will be Saturday.
Answer : A
Explanation
The century divisible by 400 is a leap year. ∴ The year 700 is not a jump year.
Q 9 - On eighth Feb, 2005 it was Tuesday. What was the week's day on eighth Feb, 2004?
Answer : C
Explanation
The year 2004 is a jump year. It has 2 odd days. ∴ The day on eighth Feb,2004 is 2 days before the day. On eighth Feb, 2005. Henceforth This day is Sunday.