Aptitude - Arithmetic Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Basic Arithmetic. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - If an A.P. have 4th term as 14 and 12th term as 70. What will be its 17th term?

A - 108

B - 107

C - 106

D - 105

Answer : D

Explanation

  
Let's have first term as a, common difference is d then  
a + 3d = 14 ... (i)  
a + 11d = 70 ... (ii)  
Subtracting (i) from (ii)  
=> 8d = 56  => d = 7  
Using (i)  
=> a = 14 - 3d  = -7  
Using formula Tn = a + (n - 1)d    
T17 = -7 + (17 - 1) x 7 = 105  

Q 2 - Find the unit digit of 415 x 66?

A - 0

B - 6

C - 8

D - 4

Answer : D

Explanation

  
Unit digit of 415 is 4 and unit digit of  66  is 6.  
So unit digit of 415 x 66  will be 4 x 6 =24 i.e., 4.  

Q 3 - 5#2 is a three digit number with # as a missing number. If the number is divisible by 6, the missing number is?

A - 2

B - 7

C - 6

D - 3

Answer : A

Explanation

If the number is divisible by 6, the sum of the number must be divisible by 6.

Q 4 - The difference between 58% and 39% of a number is 247. What is 62% of that number?

A - 1300

B - 806

C - 754

D - 1170

Answer : B

Explanation

  
 Let the number be y.  
 According to question,       (58 - 39)% of y = 247  
 Or, y x (19/100) = 247  
 Or, y = 1300  
 ∴62% of 1300 = (62/100) x 1300 = 806 

Q 5 - What is next in 2, 5, 8,...?

A - 7

B - 9

C - 10

D - 11

Answer : D

Explanation

 
 Here numbers are 2, 5, 8, ... which is an A.P. Here a = 2,  d = 3,    
 So next number will be 8 + 3 = 11. 

Q 6 - What is the sum of all natural numbers which are multiples of 3 and lies between 100 and 200.

A - 4900

B - 4950

C - 4980

D - 5000

Answer : B

Explanation

 
 Here numbers are 102, 105, ..., 198 which is an A.P. Here a = 102,  d = 23, l = 198. 
 Using formula Tn = a + (n - 1)d 
 Tn = 102 + (n - 1) x 3 = 198 
 => 99 + 3n = 198 
 => n = 99 / 3 = 33 
 Now Using formula Sn = (n/2)(a + l)  
 ∴ Required sum = (33/2)(102+198)  
 = 33 x 150  = 4950 

Q 7 - If a ≠ b then which of the following statement is correct?

A - (a+b)/2 = √ab

B - (a+b)/2 < √ab

C - (a+b)/2 > √ab

D - All of these

Answer : C

Explanation

For any two unequal number a and b, arithmetic mean is always greater than their geometric mean. ∴ c is the correct answer.

Q 8 - Suman purchases N.S.C. every year whose value exceed s previous year's N.S.C by 400 Rs. In 8 years, she has bought N.S.Cs of 48000 Rs. What was the value of N.S.C. she bought in first year?

A - 4300

B - 4400

C - 4500

D - 4600

Answer : D

Explanation

   
 Let the required amount is a. 
 Also, d = 400, n = 8, S8 = 48000  
 Using formula S8 = (n/2)[2a + (n-1)d  
 => (8/2)[2a + (8-1)400] = 48000  
 => 4(2a + 7 x 400) = 48000  
 => 2a + 3800 = 12000  
 => a = 9200 / 2 = 4600 

Q 9 - What is the 115th term of A.P. 4, 4.5, 5, 5.5 ... ?

A - 56

B - 55.5

C - 59

D - 55

Answer : C

Explanation

 Here a = 4, d = 4.5 - 4 = 0.5, n = 115 
 Using formula Tn = a + (n - 1)d 
 T115 = 4 + (115 - 1) x 0.5 
 = 59 

Q 10 - How many 2 digits numbers are there which are divisible by 6?

A - 12

B - 15

C - 16

D - 17

Answer : B

Explanation

  
 Here series is 12, 18, 24, ... 96.  
 Here a = 12,  d = 18 - 12 = 6     
 Using formula Tn = a + (n - 1)d     
 Tn = 12 + (n - 1) x 6 = 96     
 => 12 + 6n - 6 = 96    
 => 6n = 90  
 => n = 15  
aptitude_arithmetic.htm
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