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Aptitude - Arithmetic Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Basic Arithmetic. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : B
Explanation
Here a = 14, d = 9 - 14 = -5, n = 12 Using formula Tn = a + (n - 1)d T12 = 14 + (12 - 1) x -5 = -41
Answer : A
Explanation
29/9 = 3 and 98/9 = 10 => 10 - 3 =7.
Answer : B
Explanation
1 to 9 ------ 9 digits 10 to 50 ------ 82 digits
Q 4 - The product of two successive positive integers is 462. Which is the smaller integer?
Answer : C
Explanation
Suppose the two consecutive integers be y and y + 1 respectively. According to question, (y) x (y + 1) = 462 Or, y2 + y - 462 = 0 Or, y2 + 22y - 21y - 462 = 0 Or, y(y + 22) - 21(y + 22) = 0 Or, (y + 22) (y - 21) = 0 Or, y = 21
Q 5 - How many multiples of 3 are available between 15 and 105 including both?
Answer : B
Explanation
Here numbers are 15, 18, ..., 105 which is an A.P. Here a = 15, d = 3, Using formula Tn = a + (n - 1)d T11 = 15 + (n - 1) x 3 = 105 => 12 + 3n = 105 => n = 93 / 3 = 31
Answer : D
Explanation
Here numbers are 45, 46, ..., 115 which is an A.P. Here a = 45, d = 1, l = 115 Using formula Tn = a + (n - 1)d Tn = 45 + (n - 1) x 1 = 115 => 44 + n = 116 => n = 116 - 44 = 71 Now Using formula Sn = (n/2)(a + l) ∴ Required sum = (71/2)(45+115) = 71 x 80 = 5680
Answer : B
Explanation
Here numbers are in G.P. Here a = 5, r = 2, l = 1280. Using formula Tn = arn- 1 Tn = 5 x 2(n-1) = 1280 =2(n-1) = 256 =2(n-1) = 28 => n - 1 = 8 => n = 9
Q 8 - 12 + 22 ... + x2 = [x(x+1)(2x+1)]/6. What is 12 + 32 +... + 192?
Answer : A
Explanation
(12 + 32 ... + 192) = (12 + 22 ... + 192) - (22 + 42 ... + 182) Using formula (12 + 32 ... + n2) = [n(n+1)(2n+1)]/6 [19(19+1)(38+1)]/6 - (1 x 22 + 22 x 22 + 22 x 32 + ... + 22 x 92) = 2470 - 22(12 + 22 + ... + 92) = 2470 - (4 x 9 x 10 x 19)/6 = 2470 - 1140 = 1330
Q 9 - If an A.P. have 4th term as 16 and 12th term as 80. What will be its common difference?
Answer : C
Explanation
Let's have first term as a, common difference is d then a + 3d = 15 ... (i) a + 11d = 80 ... (ii) Subtracting (i) from (ii) => 8d = 64 => d = 8
Answer : C
Explanation
(22 + 42 ... + 402) = (1 x 22 + 22 x 22 + 32 x 22 +... + 202 x 22) = 22(12 + 22 + .... + 202) = 4 x 385 = 1540
aptitude_arithmetic.htm
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