Aptitude - Arithmetic Online Quiz


Advertisements


Following quiz provides Multiple Choice Questions (MCQs) related to Basic Arithmetic. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - What is y if 2y, y+10, 3y+2 are in an A.P.?

A - 4

B - 5

C - 6

D - 8

Answer : C

Explanation

    
As numbers are in A.P.  
Thus (y + 10) - 2y = (3y + 2) - (y + 10)  
=> 10 - y = 2y - 8  
=> -3y = -18  
=> y = 6  

Q 2 - Find the number which being increased by 1 will be exactly divisible by 13, 15 and 19?

A - 3704

B - 3706

C - 3705

D - 3715

Answer : A

Explanation

  
LCM of 13, 15 and 19 is 3705  
So the desired number is3705-1=3704  

Q 3 - The difference between local and the face value of 8 in the numeral is 568012?

A - 7008

B - 0

C - 7992

D - 8008

Answer : C

Explanation

  
 8000 - 8 
 = 7992      

Q 4 - If 123 is subtracted from the square of a number, the answer so obtained is 976. What is the number?

A - 58

B - 56

C - 54

D - 52

Answer : D

Explanation

  
 Let the number be x.  
 According to question:       
 x2 - 123 = 976  
 or, x = 52 

Q 5 - How many numbers between 100 and 200 are exactly divisible by 6 and 9?

A - 5

B - 6

C - 7

D - 8

Answer : B

Explanation

 
 L.C.M. of 9 and 6 = 18 
 ∴ required numbers are 108, 126, 144, 162, 180, 198 which are 6. 

Q 6 - What is the sum of 1 + 2 + ... + 100 + 99 + ...1?

A - 200

B - 500

C - 1000

D - 10000

Answer : D

Explanation

 
 Given sequence = 2(1 + 2 + ... 99) + 100 
 Using formula Sn = (n/2)(a + l) 
 Required sum = 2 x (99/2)(1+99) +100 
 = 2 x 4950 + 100 
 = 9900 + 100 = 10000 

Q 7 - If a ≠ b then which of the following statement is correct?

A - (a+b)/2 = √ab

B - (a+b)/2 < √ab

C - (a+b)/2 > √ab

D - All of these

Answer : C

Explanation

For any two unequal number a and b, arithmetic mean is always greater than their geometric mean. ∴ c is the correct answer.

Q 8 - One has to pay 3600 in 40 installments which are in A.P. After 30th installment being paid, amount left will be one third. What will be the 8th installment?

A - 35

B - 50

C - 65

D - 75

Answer : C

Explanation

   
 Installments = 40, Total debt = 3600  Installments = 30, 
 Total debt = (2/3) x 3600 = 2400  
 Let the installments be a, a + d, a + 2d, ...  
 Using formula Sn = (n/2)[2a+(n-1)d]   
 S30 = (30/2)[2a+(30-1)d] = 3600  
 => 2a + 29d = 160 ... (i)  
 S40 = (40/2)[2a+(40-1)d] = 2400  
 => 2a + 39d = 180 ... (ii)  
 Subtracting (i) from (ii)  
 => 10d = 20  
 => d = 2  
 Using (i)  2a = 160 - 29d = 160 - 58 = 102  
 => a = 51  
 Using formula Tn = a + (n-1)d  
 ∴ T8 = 51 + 7 x 2 = 51 + 14  = 65 

Q 9 - What is y if 2y, y+10, 3y+5 are in an A.P.?

A - 4

B - 5

C - 6

D - 8

Answer : B

Explanation

    
 As numbers are in A.P.  Thus (y + 10) - 2y = (3y + 5) - (y + 10)  
 => 10 - y = 2y - 5  
 => -3y = -15  
 => y = 5  

Q 10 - If an A.P. have 4th term as 16 and 12th term as 80. What will be its 17th term?

A - 118

B - 107

C - 106

D - 105

Answer : A

Explanation

  
 Let's have first term as a, common difference is d then  
 a + 3d = 16 ... (i)  
 a + 11d = 80 ... (ii)  
 Subtracting (i) from (ii)  
 => 8d = 64  
 => d = 8  
 Using (i)  
 => a = 14 - 3d  = -10 
 Using formula Tn = a + (n - 1)d    
 T17 = -10 + (17 - 1) x 8
 = 118  

aptitude_arithmetic.htm

Advertisements