Aptitude - Arithmetic Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Basic Arithmetic. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - What is the 105th term of A.P. 4, 4.5, 5, 5.5 ... ?

A - 56

B - 55.5

C - 56.5

D - 55

Answer : A

Explanation

Here a = 4, d = 4.5 - 4 = 0.5, n = 105 
Using formula Tn = a + (n - 1)d 
T105 = 4 + (105 - 1) x 0.5 
= 56 

Q 2 - What digit should be placed in of H in 78423928H9 so as make it divisible by 9?

A - 3

B - 4

C - 7

D - 2

Answer : D

Explanation

  
For the number 78423928H9 to be divisible by 9, the sum of all  its digits should be divisible by 9.  
So                        (7+8+4+2+3+9+2+8+2+9)/9 = (52+H)/9 
= Number divisible by 9  
So H should b replaced by 2  

Q 3 - 5#2 is a three digit number with # as a missing number. If the number is divisible by 6, the missing number is?

A - 2

B - 7

C - 6

D - 3

Answer : A

Explanation

If the number is divisible by 6, the sum of the number must be divisible by 6.

Q 4 - The difference between a number and 2/5th of the number is 30. The number is

A - 50

B - 75

C - 57

D - 60

Answer : A

Explanation

  
 Let the number be y.  
 According to question:       
 y - 2y/5 = 30  
 or, 3y/5 = 30  
 or, y = 50  

Q 5 - How many numbers between 100 and 200 are exactly divisible by 6 and 9?

A - 5

B - 6

C - 7

D - 8

Answer : B

Explanation

 
 L.C.M. of 9 and 6 = 18 
 ∴ required numbers are 108, 126, 144, 162, 180, 198 which are 6. 

Q 6 - How many odd numbered pages are present in a book of 1089 pages?

A - 542

B - 543

C - 544

D - 545

Answer : D

Explanation

 
 Here pages are 1, 3, ..., 1089 which is an A.P. Here a = 1,  d = 2, l = 1089    
 Using formula Tn = a + (n - 1)d 
 Tn = 1 + (n - 1) x 2 = 1089 
 => 2n -1 = 1089 
 => n = 1090 / 2 = 545 

Q 7 - Which term of 5, 10, 20, 40,.... is 1280?

A - 8th

B - 9th

C - 10th

D - 11th

Answer : B

Explanation

  
 Here numbers are in G.P.  Here a = 5,  r = 2, l = 1280. 
 Using formula Tn = arn- 1 
 Tn = 5 x 2(n-1) = 1280  
 =2(n-1) = 256  
 =2(n-1) 
 = 28  
 => n - 1 = 8  => n = 9 

Q 8 - Suman purchases N.S.C. every year whose value exceed s previous year's N.S.C by 400 Rs. In 8 years, she has bought N.S.Cs of 48000 Rs. What was the value of N.S.C. she bought in first year?

A - 4300

B - 4400

C - 4500

D - 4600

Answer : D

Explanation

   
 Let the required amount is a. 
 Also, d = 400, n = 8, S8 = 48000  
 Using formula S8 = (n/2)[2a + (n-1)d  
 => (8/2)[2a + (8-1)400] = 48000  
 => 4(2a + 7 x 400) = 48000  
 => 2a + 3800 = 12000  
 => a = 9200 / 2 = 4600 

Q 9 - (13 + 23 ... + 153) - (1 + 2 + ... + 15)= ?

A - 12280

B - 13280

C - 14280

D - 14400

Answer : C

Explanation

  
 Using formula  (13 + 23 ... +  n3) = [(1/2)n(n+1]2  
 (13 + 23 ... + 153) = [(15 x 16)/2]2  
 = 1202  = 14400  
 Using formula  (1 + 2 + ... n) = [(1/2)n(n+1]  
 ∴ (13 + 23 ... + 153) - (1 + 2 + ... + 15) 
 = 14400 - (1/2) x 15 x 16 = 14400 - 120  
 = 14280 

Q 10 - (13 + 23 ... + 203) - (1 + 2 + ... + 20)= ?

A - 43950

B - 43970

C - 43980

D - 43960

Answer : C

Explanation

  
 Using formula  (13 + 23 ... +  n3) = [(1/2)n(n+1]2  
 (13 + 23 ... + 203) = [(20 x 21)/2]2  = 2102  = 44100  
 Using formula  (1 + 2 + ... n) = [(1/2)n(n+1]  
 ∴ (13 + 23 ... + 153) - (1 + 2 + ... + 15) = 44100 - (1/2) x 15 x 16 
 = 44100 - 120  
 = 43980 

aptitude_arithmetic.htm

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