Aptitude - Arithmetic Online Quiz



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Following quiz provides Multiple Choice Questions (MCQs) related to Basic Arithmetic. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - If nth term of the series 72, 63, 54, ... is 0. What is n?

A - 8

B - 9

C - 10

D - 11

Answer : B

Explanation

     
Here a = 72,  d = 63 - 72 = -9,      
Using formula Tn = a + (n - 1)d      
Tn = 72 + (n - 1) x -9 = 0      
=> 81 - 9n = 0     
=> n = 9    

Q 2 - How many 3 digits numbers are there which are divisible by 6?

A - 102

B - 150

C - 151

D - 156

Answer : B

Explanation

  
Here series is 102, 108, 114, ... 996.  
Here a = 102,  d = 108 - 102 = 6     
Using formula Tn = a + (n - 1)d     
Tn = 102 + (n - 1) x 6 = 996     
=> 102 + 6n - 6 = 996    
=> 6n = 900  
=> n = 150  

Q 3 - The value of (3n+3n-1)/(3n+1-3n) is?

A - 5/2

B - 3/2

C - 2/3

D - 1/3

Answer : C

Explanation

  
 (3n+3n-1)/(3n+1-3n)  = (1+3-1)/ (3-1)  
 = 2/3  

Q 4 - The difference between 58% and 39% of a number is 247. What is 62% of that number?

A - 1300

B - 806

C - 754

D - 1170

Answer : B

Explanation

  
 Let the number be y.  
 According to question,       (58 - 39)% of y = 247  
 Or, y x (19/100) = 247  
 Or, y = 1300  
 ∴62% of 1300 = (62/100) x 1300 = 806 

Q 5 - The average of four consecutive even numbers is one- fourth of the sum of these numbers. What is the difference between the first and the last number?

A - 4

B - 6

C - 2

D - 1

Answer : B

Explanation

  
 Let the four consecutive even numbers are x, x + 2, x + 4 and x + 6.  
 ∴ Required difference = x + 6 - x = 6 

Q 6 - What is the sum of all natural numbers starting from 75 up to 97?

A - 1598

B - 1798

C - 1958

D - 1978

Answer : D

Explanation

 Here numbers are 75, 76, ..., 97 which is an A.P. Here a = 75,  d = 1, l = 97    
 Using formula Tn = a + (n - 1)d 
 Tn = 75 + (n - 1) x 1 = 97 
 => 74 + n = 97 
 => n = 97 - 74 = 23 
 Now Using formula Sn = (n/2)(a + l)  
 ∴ Required sum = (23/2)(75+97)  
 = 23 x 86  = 1978 

Q 7 - What is the sum of (1 + 1/2 + 1/4 + ...)?

A - 2

B - 4

C - 8

D - 10

Answer : A

Explanation

  
 This is an infinite G.P. with a = 1 and r = 1/2.  
 Sum of infinite G.P. = a/(1-r)  = 1/(1-1/2)  = 1/(1/2)  = 2 

Q 8 - One has to pay 3600 in 40 installments which are in A.P. After 30th installment being paid, amount left will be one third. What will be the 8th installment?

A - 35

B - 50

C - 65

D - 75

Answer : C

Explanation

   
 Installments = 40, Total debt = 3600  Installments = 30, 
 Total debt = (2/3) x 3600 = 2400  
 Let the installments be a, a + d, a + 2d, ...  
 Using formula Sn = (n/2)[2a+(n-1)d]   
 S30 = (30/2)[2a+(30-1)d] = 3600  
 => 2a + 29d = 160 ... (i)  
 S40 = (40/2)[2a+(40-1)d] = 2400  
 => 2a + 39d = 180 ... (ii)  
 Subtracting (i) from (ii)  
 => 10d = 20  
 => d = 2  
 Using (i)  2a = 160 - 29d = 160 - 58 = 102  
 => a = 51  
 Using formula Tn = a + (n-1)d  
 ∴ T8 = 51 + 7 x 2 = 51 + 14  = 65 

Q 9 - Which term of 2, 7, 12, 17... is 92?

A - 16th

B - 17th

C - 18th

D - 19th

Answer : D

Explanation

  
 Here a = 2,  d = 7 - 2 = 5,  
 Let there be n term.  
 Using formula Tn = a + (n - 1)d  
 Tn = 2 + (n - 1) x 5 = 92  
 => 5n - 3 = 92  
 => n = 19 

Q 10 - If an A.P. have 4th term as 16 and 12th term as 80. What will be its 17th term?

A - 118

B - 107

C - 106

D - 105

Answer : A

Explanation

  
 Let's have first term as a, common difference is d then  
 a + 3d = 16 ... (i)  
 a + 11d = 80 ... (ii)  
 Subtracting (i) from (ii)  
 => 8d = 64  
 => d = 8  
 Using (i)  
 => a = 14 - 3d  = -10 
 Using formula Tn = a + (n - 1)d    
 T17 = -10 + (17 - 1) x 8
 = 118  

aptitude_arithmetic.htm

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