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# Aptitude - Arithmetic Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Basic Arithmetic**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - If an A.P. have 4^{th} term as 14 and 12^{th} term as 70. What will be its 17^{th} term?

### Answer : D

### Explanation

Let's have first term as a, common difference is d then a + 3d = 14 ... (i) a + 11d = 70 ... (ii) Subtracting (i) from (ii) => 8d = 56 => d = 7 Using (i) => a = 14 - 3d = -7 Using formula T_{n}= a + (n - 1)d T_{17}= -7 + (17 - 1) x 7 = 105

### Answer : B

### Explanation

Here series is 102, 108, 114, ... 996. Here a = 102, d = 108 - 102 = 6 Using formula T_{n}= a + (n - 1)d T_{n}= 102 + (n - 1) x 6 = 996 => 102 + 6n - 6 = 996 => 6n = 900 => n = 150

### Answer : A

### Explanation

For 3Y-2X to be minimum the condition is that Y must be substituted with least value and X must be with large value => 3(3)-2(3) =3.

Q 4 - Two numbers are less than the third number by 50% and 54% respectively. By how much percent is the second number less than the first number?

### Answer : D

### Explanation

Let the third number be 100. ∴First Number = 50 and Second Number = 46 Decrease = 50 - 46 = 4 ∴Required Percentage = (4/50)x100 = 8%

### Answer : D

### Explanation

Here numbers are 2, 5, 8, ... which is an A.P. Here a = 2, d = 3, So next number will be 8 + 3 = 11.

Q 6 - How many odd numbered pages are present in a book of 1089 pages?

### Answer : D

### Explanation

Here pages are 1, 3, ..., 1089 which is an A.P. Here a = 1, d = 2, l = 1089 Using formula T_{n}= a + (n - 1)d T_{n}= 1 + (n - 1) x 2 = 1089 => 2n -1 = 1089 => n = 1090 / 2 = 545

### Answer : B

### Explanation

Here numbers are in G.P. Here a = 5, r = 2, l = 1280. Using formula T_{n}= ar^{n- 1}T_{n}= 5 x 2^{(n-1)}= 1280 =2^{(n-1)}= 256 =2^{(n-1)}= 2^{8}=> n - 1 = 8 => n = 9

Q 8 - A piles of logs is arranged in such a way that top layer contains one log and each lower layer has one log more than the layer above. if there are 15 layers in total than how many logs are arranged in that pile?

### Answer : B

### Explanation

Total logs = 1 + 2 + 3 ... + 15 Here a = 1, d = 1 , l = 15 Using formula S_{n}= (n/2)[a+l] S_{n}= (15/2)[1+15] = 15 x 8 = 120

### Answer : A

### Explanation

Here a = 7, d = 11 - 7 = 4, Let there be n term. Using formula T_{n}= a + (n - 1)d T_{n}= 7 + (n - 1) x 4 = 151 => 4n + 3 = 151 => n = 37

Q 10 - If 1^{2} + 2^{2} ... + 20^{2} = 2870. What is 2^{2} + 4^{2} +... + 40^{2}?

### Answer : C

### Explanation

(2^{2}+ 4^{2}... + 40^{2}) = (1 x 2^{2}+ 2^{2}x 2^{2}+ 3^{2}x 2^{2}+... + 20^{2}x 2^{2}) = 2^{2}(1^{2}+ 2^{2}+ .... + 20^{2}) = 4 x 385 = 1540