Aptitude - Arithmetic Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Basic Arithmetic. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - What is the 16th term of A.P. 3, 5, 7, 9 ...?

A - 48

B - 50

C - 33

D - 35

Answer : C

Explanation

   
Here a = 3, d = 5 - 3 = 2, n = 16   
Using formula Tn = a + (n - 1)d   
T16 = 3 + (16 - 1) x 2 = 33  

Q 2 - How many 3 digits numbers are there which are divisible by 6?

A - 102

B - 150

C - 151

D - 156

Answer : B

Explanation

  
Here series is 102, 108, 114, ... 996.  
Here a = 102,  d = 108 - 102 = 6     
Using formula Tn = a + (n - 1)d     
Tn = 102 + (n - 1) x 6 = 996     
=> 102 + 6n - 6 = 996    
=> 6n = 900  
=> n = 150  

Q 3 - The difference between local and the face value of 8 in the numeral is 568012?

A - 7008

B - 0

C - 7992

D - 8008

Answer : C

Explanation

  
 8000 - 8 
 = 7992      

Q 4 - In a three digit number the digit in the unit's place is twice the digit in the ten's place and 1.5 times the digit in the hundred's place. If the sum of all the three digits of the number is 13, what is the number?

A - 364

B - 436

C - 238

D - 634

Answer : B

Explanation

 
 Let the ten's digit be y. 
 ∴Unit's digit = 2y And Hundred's digits = 2y/1.5 
 According to the question,       
 y + 2y + 2y/1.5 = 13 or, 
 (1.5y + 3y + 2y) /1.5 = 13 or, 
 6.5y = 13 x 1.5 or, 
 y = (13 x 1.5)/6.5 or, 
 y = 3 
 ∴Unit's digit = 6 and hundred's digit = 6/1.5 = 4 
 ∴Number = 436 

Q 5 - What is next in 2, 5, 8,...?

A - 7

B - 9

C - 10

D - 11

Answer : D

Explanation

 
 Here numbers are 2, 5, 8, ... which is an A.P. Here a = 2,  d = 3,    
 So next number will be 8 + 3 = 11. 

Q 6 - What is the sum of first 20 odd numbers?

A - 210

B - 300

C - 400

D - 420

Answer : C

Explanation

 
 Here numbers are 1, 3, ..., upto 20 terms which is an A.P. Here a = 1,  d = 2, n = 20. 
 Now Using formula Sn = (n/2)[2a + (n-1)d]  
 ∴ Required sum = (20/2)[2+(20-1)x2]  = 10 x 40  = 400 

Q 7 - Sum of how many terms of series 3, 9, 27 will be 363?

A - 5

B - 6

C - 7

D - 8

Answer : A

Explanation

   
 Here a = 3, r = 3 , Sn = 363  
 Using formula Sn = a(rn - 1) / (r-1)  
 Sn = 3 x (3n - 1) / (3 - 1) = 363  
 => 3n - 1 = (363 x 2) / 3  
 => 3n = 243 
 = 35  
 => n = 5 

Q 8 - If population of a bacteria doubles every 2 minutes. In how much minutes, it will grow from 1000 to 512000?

A - 10

B - 12

C - 14

D - 18

Answer : D

Explanation

   
 Let the required growth be 1000, 2000, 4000,...512000.  
 Here, a = 1000, r = 2, Tn = 512000  
 Using formula Tn = arn-1 
 => 1000 x 2n-1 = 512000  
 => 2n-1 = 512 = 29  
 => n - 1 = 9  => n = 10 
 ∴ time taken will be 2 x 9 = 18 minutes. 

Q 9 - If an A.P. have 4th term as 16 and 12th term as 80. What will be its common difference?

A - -10

B - -7

C - 8

D - 10

Answer : C

Explanation

  
 Let's have first term as a, common difference is d then  
 a + 3d = 15 ... (i)  
 a + 11d = 80 ... (ii)  
 Subtracting (i) from (ii)  
 => 8d = 64  
 => d = 8  

Q 10 - (13 + 23 ... + 203) = ?

A - 44400

B - 34100

C - 24100

D - 44100

Answer : D

Explanation

  
 Using formula  (13 + 23 ... +  n3) = [(1/2)n(n+1]2  
 (13 + 23 ... + 203) = [(20 x 21)/2]2 
 = 2102  
 = 44100 

aptitude_arithmetic.htm

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