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Aptitude - Boats & Streams Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Boats & Streams. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - A man can push 6 km/hr in still water. It takes him twice as long to line up as to column down the river. Find the rate of the stream.
Answer : C
Explanation
Let men's rate upstream be x km/hr`At that point, men's rate downstream = 1/2 (2x+x) km/hr = 3x/2 km/hr`And there 4; 3x/2 =6 x= (2*6)/3 =4.`And there 4: 4 km/hr, rate downstream = (2*4) km/hr = 8 km/hr`Rate of stream = 1/2 (8-4) km/hr = 2 km/hr
Q 2 - A man can push 30km upstream and 44km downstream in 10 hours. Additionally, he can push 40km upstream and 55km downstream in 13 hours. Discover the rate of flow and the current of the man in still water.
Answer : C
Explanation
Let speed upstream be x km/hr and the velocity downstream be y km/hr`At that point, 30/x+44/y=10 ... (i) and 40/x+55/y=13 ... (ii)`Increasing (ii) by 4, (i) by 5 and subtracting, we get: 10/x=2=>x=5.`Putting x=5in (i) we get 4y=44=> y=11.`∴ Speed upstream =5km/hr, speed downstream=11km/hr.`Velocity of the current =1/2(11-5) km/hr=3km/hr.`Velocity of man in still water =1/2(11+5) km/hr=8km.
Q 3 - A boat is paddled downstream at 15.5km/hr and upstream at 8.5km/hr. The rate of the stream is:
Answer : A
Explanation
Speed downstream =15.5km/hr, Speed upstream =8.5km/hr.`Speed of the stream=1/2(15.5-8.5) km/hr=3.5 km/hr
Q 4 - A watercraft covers a separation of 30km in 5/2 hrs running downstream. While returning, it covers the same separation 15/4hrs .What is the velocity of the watercraft in still water?
Answer : D
Explanation
Speed downstream = (30*2/5) km/hr=12km/hr.`Speed upstream= (30*4/15) km/hr=8 km/hr.`Speed of boat in still water=1/2(12+8) km/hr=10 km/hr.
Q 5 - A boat can push 1 km with stream in 10 minutes and 1 km against stream in 20 minutes. What is the rate of the vessel in still Water?
Answer : D
Explanation
Distance moved downstream in 10 min=1km.`Distance moved downstream in 60 min= (1/10*60) km=6 km.`Distance moved upstream in 20 min =1 km.`Distance moved upstream in 60 min = (1/20*60) km = 3 km.`Speed downstream =6 km/hr, Speed upstream =3 km/hr`Speed of the boat in still water =1/2(6+3) km/hr =4.5 km/hr.
Q 6 - Aman can push at 5 km/hr in still Water. It the stream is running at 1km/hr, it takes him 75 min. to line to a spot and back. How far is the spot?
Answer : B
Explanation
Speed downstream = (5+1) km/hr=6 km/hr`Speed upstream = (5-1) km/hr=4 km/hr.`Let the required distance be x km. Then,`x/6+ x/4=75/60 = 5/4 => (2x+3x) =15 => 5x = 15 => x=3.`Required distance =3km.
Q 7 - A vessel goes 6 km in an hour in still water. It requires thrice as much investment in covering the same separation against the current. Velocity of the current is:
Answer : C
Explanation
Speed in still water =6 km/hr.`Speed against the current =6/3 km/hr =2 km/hr`Let the speed of the current be x km/hr`6-x = 2 => x = 4 km/hr.
Q 8 - Aman can push 15/2 kms an hour in still water and he finds that it takes him twice as long to down the stream. The rate of the stream is:
Answer : B
Explanation
Let the rate of stream be x km/hr. Then,`Speed downstream = (15/2 +x) km/hr, Speed upstream = (15/2 - x) km/hr`(15/2 +x) = 2 (15/2 -x) => 3x =15/2 => x = 15/2*3 = 5/2 = 2.5`∴ Rate of stream=2.5 km/hr
Q 9 - A boatman goes 2km against the current of stream in 1 hours and goes 1 km along the current in 10 min. To what extent will he takes to go 5km in stationary water?
Answer : C
Explanation
Speed upstream =2km/hr, Speed downstream = 6 km/hr.`Speed in stationary water = 1/2 (6 + 2) km/hr = 4 km/hr.`Time taken to cover 5 km in stationary water = (1/4 *5) = 1 hr 15 min.
Q 10 - A boat sets aside half time in moving a sure separation downstream then upstream. What is the proportion between rate in still Water and rate of current and flow?
Answer : B
Explanation
Let the speed of boat in still water be u km/hr and speed of the current be v km/hr.`Rate downstream = (u+v) km/hr, Rate upstream= (u-v) km/hr.`Let the distance covered in each case be x km. Then,`2x/(u+v) = x/ (u-v) => 2 (u-v) = (u+v) => u =3v =>u/v=3/1`Required ratio = 3:1.