Volume Calculation - Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A rectangular marble stone 28 cm wide and 5 cm thick weighs 112 kg. In the event that 1 cubic cm of marble measures 25 gm, then the length of given stone is:

A - 36 cm

B - 37.5 cm

C - 32 cm

D - 26.5 cm

Answer : C

Explanation

Let the required length be x cm.
Then, its volume = (x*28*5*25/1000) kg = 7x/2 kg
∴ 7x/2= 112 ⇒x= 112*2/7= 32 cm
Required length = 32 cm

Q 2 - A spread wooden box has the inward measures as 115 cm, 75 cm and 35 cm and the thickness of wood is 2.5 cm. The volume of the wood is:

A - 81000 cu. cm

B - 81775 cu.cm

C - 82125 cu.cm

D - none of these

Answer : C

Explanation

Inner volume= (115*75*35) cm3= 301875 cm3
Outer volume = (115+5)* (75+5)*(35+5) cm3
=(120*80*40) cm3= 384000 cm3
Volume of wood = (384000-301875) cm3= 82125 cm3

Q 3 - The whole of the length, broadness and profundity of a cuboid is 19 cm and its askew is 5√5cm. Its surface region is:

A - 125 cm2

B - 236 cm2

C - 361 cm2

D - none of these

Answer : B

Explanation

(L+b+h) =19 and √ (L2+b2+h2) = 5√5
⇒ (L+b+h) 2= (19) 2 and (L2+b2+h2) = 125
⇒ (L2+b2+h2) +2(Lb+bh+Lh) = 361 and (L2+b2+h2) = 125
⇒125+2(Lb+bh+Lh) =361 ⇒2 (Lb+bh+Lh) = (361-125) =236
∴ Surface area = 236cm2

Q 4 - Water streams into a tank 200m *150m through a rectangular funnel 1.5m*1.25m at the rate of 20 kmph. In what the reality of the situation will become obvious eventually water rise By 2 meters?

A - 76 min

B - 80 min

C - 90 min

D - 96 min

Answer : D

Explanation

Volume of the water flown in the tank= (200*150*2) m3= 60000m3
Volume flown per hour = (3/2*125/100*20*1000) m3=37500m3
Time taken = 60000/37500 = 8/5 hrs = (8/5*60) min. = 96 min.

Q 5 - If every side of a solid shape is multiplied, then its volume:

A - is multiplied

B - get to be 4 times

C - gets to be 6 times

D - Gets to be 8 times

Answer : D

Explanation

Let the edge of the original cube be x. Then its volume = x3
New edge = 2x, new volume (2x) 3=8x3
So, it?s become 8 times.

Q 6 - The aggregate surface zone of 3D square (cube) is 1734 cm2 .Its volume is:

A - 2197 cm3

B - 2744 cm3

C - 4096 cm3

D - 4913 cm3

Answer : D

Explanation

6a2=1734 ⇒a2=289= (17) 2 ⇒a= 17
Volume = a3= (17*17*17) cm3= 4913cm3

Q 7 - How numerous 3D squares of 10 cm edge can be placed in a cubic box of 1 m edge?

A - 10

B - 100

C - 1000

D - 10000

Answer : C

Explanation

Required no. = (100*100*100)/ (10*10*10) = 1000

Q 8 - The bended surface of a tube shaped column is 264 m2 and its volume is 924 m3. The proportion of its width to its stature is:

A - 7:3

B - 3:7

C - 7:6

D - 6:7

Answer : A

Explanation

2πrh =264 and πr2h =924
∴πr2h/2πrh=   924/264= 7/2 ⇒r =7 ⇒d= 2r =14m
2*22/7*7*h =264 ⇒h = 264/44= 6
∴ d/h= 14/6=    7/3 = 7:3

Q 9 - A chamber and a cone have the same stature and the same sweep of base. The proportion between the volumes of the barrel and the cone is:

A - 1:3

B - 3:1

C - 1:2

D - 2:1

Answer : B

Explanation

Ratio of their volume= πr2h/1/3 πr2h= 3/1 =3:1

Q 10 - The volume of a right roundabout chamber, 14 cm in stature, is equivalent to that of a solid shape whose edge is 11 cm. The range of the base of the barrel is:

A - 5.2 cm

B - 5.5 cm

C - 11 cm

D - 22 cm

Answer : B

Explanation

Let the radius of the base of the cylinder be r cm. Then,
πr2*14 = (11)3
⇒22/7*r2*14= 11*11*11   ⇒r2 =121/4 = (11/2)2 ⇒r =11/2 =5.5 cm


aptitude_volume_calculation.htm

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