Volume Calculation - Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - The length of the longest shaft that can be kept in a room 5 m long, 4 m wide and 3 m high, is:

A - 5√2 m

B - 6√2 m

C - 7√2 m

D - none of these

Answer : A

Explanation

Required length = √[(5) 2+(4) 2+(3) 2]=√(25+16)+(9)=√50m =√25*2 m =5√2m

Q 2 - A stream 2m profound and 45m wide is running at the rate of 3 km/hr. The measure of water that keeps running into the ocean every moment is:

A - 4500 m3

B - 27000 m3

C - 3000 m3

D - 2700 m3

Answer : A

Explanation

Speed per minute = (3*1000)/60 m= 50 m
Volume of water running per minute= (45*2*50) m3=4500 m3

Q 3 - A swimming shower is 24 m long and 15 m wide. At the point when various men jump into the shower, the tallness of water ascends by 1 cm. On the off chance that the normal volume of water uprooted by every men be 0.1 m3, what number of men arrive in the shower?

A - 32

B - 36

C - 42

D - 46

Answer : B

Explanation

Let there be x man in the bath .Then,
x *0.1= (24*15*1/100) ⇒x*1/10=   24*15*1/100⇒x= 36.

Q 4 - Water streams into a tank 200m *150m through a rectangular funnel 1.5m*1.25m at the rate of 20 kmph. In what the reality of the situation will become obvious eventually water rise By 2 meters?

A - 76 min

B - 80 min

C - 90 min

D - 96 min

Answer : D

Explanation

Volume of the water flown in the tank= (200*150*2) m3= 60000m3
Volume flown per hour = (3/2*125/100*20*1000) m3=37500m3
Time taken = 60000/37500 = 8/5 hrs = (8/5*60) min. = 96 min.

Q 5 - The volume of a solid shape is 512 cm3. Its aggregate surface zone is:

A - 64 cm2

B - 256 cm2

C - 384 cm2

D - 512 cm2

Answer : C

Explanation

a3=512 =83⇒a= 8
Surface area = 6a2= (6*8*8) cm2= 384cm2

Q 6 - The volume of a cuboid is twice that of a solid shape. On the off chance that the measurement of the cuboid is (9cm *8 cm* 6cm), the aggregate surface region of the block is:

A - 72 cm2

B - 216 cm2

C - 108 cm2

D - 432 cm2

Answer : B

Explanation

2*volume of cube= volume of cuboid= (9*8*6) cm3
Volume of cube = (1/2 *9*8*6) cm3= 216cm3
∴ a3= 216 = (6) 3 ⇒a =6 cm
Total surface area = 6a2 = (6*6*6) cm2= 216cm2

Q 7 - Capacity of a round and hollow vessel is 25.872ltr. On the off chance that the stature of the chamber is three times the range of its base, what is the region of the base?

A - 336 cm2

B - 616 cm2

C - 1232 cm2

D - none of these

Answer : B

Explanation

Volume =(25.872*1000)cm3= 25872cm3
Let the radius be r cm. Then, height = 3r cm
∴22/7*r2*3r= 25872 ⇒r3= (25872*7)/66 = (392*7) = (7*7*7*8)
⇒r = (7*2) cm= 14 cm
Area of the base = πr2= (22/7*14*14) cm2= 616 cm2

Q 8 - A funnel of 2 inch measurement fills the water tank in 60 minutes. In the event that the measurement of the funnel is 4inch, in what the reality of the situation will become obvious eventually pipe fills the same tank?

A - 30 min.

B - 45 min.

C - 15 min.

D - 10 min.

Answer : C

Explanation

r = 1 inch,  volume = πr2h= π*1*1*h= πh
r =2 inch volume = π (2)2*h= 4πh
4 time water pass at the same time.
∴Rates are 1:4 so, time taken =4:1
∴ 2nd pipe will take = (1/4*60) = 15 min

Q 9 - A empty greenery enclosure roller 63cm wide with a circumference of 440 cm is made of iron 4 cm thick. The volume of the iron utilized is:

A - 56372 cm3

B - 58752 cm3

C - 54982 cm3

D - 57636 cm3

Answer : B

Explanation

2πr= 440 ⇒2*22/7*r= 440 ⇒r= (440*7/44) = 70 cm
Outer radius = 70cm, inner radius = (70-4) = 66cm
Volume of iron = π [(70)2-(66)2*63cm3= (22/7*136*4*63)
= 58752 cm3

Q 10 - If 1 cubic cm of cast iron weight 21 gms. At that point the heaviness of a cast iron funnel of lenght1 m with a drag of 3 cm and in which the thickness of the metal is 1cm, is:

A - 21 kg

B - 24.2 kg

C - 18.6 kg

D - 26.4 kg

Answer : D

Explanation

External radius = 2.5cm, length= 100cm
External volume = [π*(2.5)2*100] cm3
Internal radius = 1.5 cm
Internal volume = [π*(1.5)2*100] cm3
Volume of metal =[π*(2.5)2*100-π*(1.5)2*100] cm3
=π*100*{(2.5)2-(1.5)2} = (22/7*100*4*1) cm3
Weight of metal = (8800/7 -21/1000) kg = 26.4 kg


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