Volume Calculation - Online Quiz



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Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A divider 24m long , 8 m high and 60cm thick is comprised of blocks, every measuring 24cm * 12cm *8cm , it being given that 10% of the divider comprises of mortar. What number of blocks will be required?

A - 50000

B - 45000

C - 40000

D - 20000

Answer : B

Explanation

Volume of wall = (24*8*60/100)m3 =576/5m3
Volume of bricks = (90% of 576/5) m3= (90/100*576/5) m3= (144*18/25) m3
Volume if 1 bricks = (24/100*12/100*8/100) m3
Number of bricks = [(144*18/25)*100/24*100/12*100/8) = 45000

Q 2 - A rectangular water store contains 42000 liters of water. On the off chance that the length of store is 6 m and its broadness is 3.5m, then the profundity of the supply is:

A - 2 m

B - 5 m

C - 6 m

D - 8 m

Answer : A

Explanation

Volume of reservoir = 42000 ltr. = 42 cubic mtr.
Let the depth be x mtr. Then,
6*7/2*x =42 ⇒ x = 2 m
∴ Depth =2 m

Q 3 - If the territory of three adjoining countenances of a cuboid is x, y, z separately, At that point the volume of the cuboid is:

A - xyz

B - 2xyz

C - √xyz

D - 3√xyz

Answer : C

Explanation

Let the length of cuboid = L, Breadth = b and height = h
Lb=x, bh= y and Lh= z
∴ xyz = L2b2h2⇒Lbh = √xyz ⇒volume =√xyz.

Q 4 - If the zone of the three adjoining appearances of a cuboidal box is 120 cm2, 72 cm2 and 60 cm2 individually, then the volume of the crate is:

A - 720 cm3

B - 864 cm3

C - 7200 cm3

D - 5184 cm3

Answer : A

Explanation

Lb= 120, bh= 72 and Lh = 60
⇒ (Lb*bh*Lh) = 120*72*60⇒ (Lbh) 2= (120*72*60)
⇒ Lbh =√ (12*10*12*6*10*6) = (12*10*6) = 720
∴ Volume = 720 cm3

Q 5 - The region of the card board expected to make a crate size 25 cm* 15cm *8 cm will be:

A - 390 cm2

B - 1390 cm2

C - 2780 cm 2

D - 1000 cm2

Answer : B

Explanation

Area needed = 2(25*15+15*8+25*8) cm2
=2(375+120+200) cm2= 2(695) cm2 = 1390 cm2

Q 6 - A metal 3D square of edge 12cm is liquefied and framed into three littler 3D shape. In the event that the edge of two littler 3D shapes is 6cm and 8 cm. the edge of the third littler solid shape is:

A - 10 cm

B - 14 cm

C - 12 cm

D - 16 cm

Answer : A

Explanation

Let the edge of third smaller cube be a cm. Then,
(6) 3+ (8) 3+a3= (12) 3 ⇒ (216+512) +a3=1728
⇒a3= (1728-728) = 1000= (10) 3⇒a= 10cm
∴ Edge of third smaller cube = 10 cm

Q 7 - A rectangular box measure s inside 1.6 m long, 1m expansive and 60 cm profound. The no. of cubical obstructs each of edge 20 cm that can be pressed inside the crate, is:

A - 30

B - 53

C - 60

D - 120

Answer : D

Explanation

Required no. = (160*100*60)/ (20*20*20) = 120

Q 8 - A divider with 10 m inside diameter is burrowed 14 m profound. Earth taken out of it is spread all around to a width of 5 m to shape a dike. The tallness of the bank is:

A - 2.46 m

B - 3.56 m

C - 4.66 m

D - 5.76 m

Answer : C

Explanation

Volume of the earth dugout = πr2h = (22/7* 5*5*14) m3= 1100m3
Area of embankment = π (R2- r2) = 22/7*[(10)2-(5)2]
= (22/7*75) m2
Let the height of the embankment be h meters. Then,
22/7*75*h = 1100 ⇒h = (1100*7/22*1/75) m = 14/3 m = 4.66m

Q 9 - The total of the range of base and the tallness of a barrel is 37 m. On the off chance that the aggregate surface region of the chamber is 1628m2, then its volume is:

A - 5240 m3

B - 4620 m3

C - 3180 m3

D - none of these

Answer : B

Explanation

Given: (r+h) = 37m
Total surface area = 2πr (h+r)
∴2πr* 37= 1628 ⇒22/7* r= 22 ⇒ r = 7m
h =(37-7)= 30 m
Volume = πr2h= (22/7* 7* 7* 30) m3= 4620 m3

Q 10 - The bended surface region of a circle is 5544 cm2. Its volume is:

A - 38808 cm3

B - 42304 cm3

C - 22176 cm3

D - 33951 cm3

Answer : A

Explanation

4πr2= 5544 ⇒4*22/7* r2 =5544
⇒ r2= (5544*7/88)=(63*7)=  (72*32)⇒ r =(7*3)=21
Volume= 4/3πr3= (4/3*22/7*21*21*21) cm3= 38808cm3


aptitude_volume_calculation.htm

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