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Volume Calculation - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - The length of the askew of a cuboid 30 cm long, 24 cm wide and 18 cm is:
Answer : C
Explanation
Length of the diagonal =√ (L 2+ b2+ h2)= √[ (30)2 +( 24)2+(18)2] = √ (900+576+324) =√1800= √900*2 = 30√2 cm
Q 2 - Half cubic meter of gold sheet is stretched out by pounding in order to spread a region of 1 hectare. The thickness of the sheet is:
Answer : C
Explanation
Area = 1 hectare= 10000m2, Volume = 0.5 m3 Thickness =Volume/Area = (0.5/10000)m =(0.5*100/10000)cm=0.005cm
Q 3 - The whole of the length, broadness and profundity of a cuboid is 19 cm and its askew is 5√5cm. Its surface region is:
Answer : B
Explanation
(L+b+h) =19 and √ (L2+b2+h2) = 5√5 ⇒ (L+b+h) 2= (19) 2 and (L2+b2+h2) = 125 ⇒ (L2+b2+h2) +2(Lb+bh+Lh) = 361 and (L2+b2+h2) = 125 ⇒125+2(Lb+bh+Lh) =361 ⇒2 (Lb+bh+Lh) = (361-125) =236 ∴ Surface area = 236cm2
Q 4 - A store is 15m long and 6m expansive. The amount of water taken out to bring down the level by 1 m is:
Answer : D
Explanation
Let the initial depth be x meters. Then,
Quantity Of water taken out = [(15*6*x)- {15*6*(x-1)}]m3
=[90x-(90x-90)]m3= 90m3= 90 kiloliters.
Q 5 - The volume of a solid shape is 512 cm3. Its aggregate surface zone is:
Answer : C
Explanation
a3=512 =83⇒a= 8 Surface area = 6a2= (6*8*8) cm2= 384cm2
Q 6 - A block of edge 5 cm is cut into 3D squares (cube), each of edge of 1 cm. The proportion of the aggregate surface zone of one of the little 3D shapes to that of the vast 3D square is equivalent to:
Answer : B
Explanation
Required ratio = 6a2: 6b2= a2:b2= (1) 2:(5) 2= 1:25
Q 7 - The tallness of a barrel is 14 cm and its width is 10cm. The volume of the barrel is:
Answer : A
Explanation
Given h= 14cm and r= 5cm Volume = πr2h = (22/7*5*5*14) = 1100cm3
Q 8 - The number of coins, 1.5cm in distance across and 0.2 cm thick to be softened to shape a right roundabout chamber of stature 10 cm and width 4.5 cm is:
Answer : C
Explanation
For each coin = r =1.5/2cm and h = 0.2 cm Volume of 1 coin = πr2h = (π*1.5/2*1.5/2* 0.2) cm3 =( π*15/2*15/2*2*1/1000)cm3= 9π/80 cm3 For given cylinder, R= 4.5/2 cm and H= 10 cm Volume= πR2H= (22/7*4.5/2*4.5/2* 10*1/100) cm3 = (π*45/2*45/2*10*1/100) = 45*9π/8 cm3 Number of coins= (45*9*π/8*80/9π) = 450
Q 9 - The aggregate surface territory of a strong barrel is 231 cm2. On the off chance that its bended surface zone is two ?third of its aggregate surface zone, then its Volume is:
Answer : A
Explanation
(2πrh+2πr2) =231 and 2πrh= 2/3*231= 154 ∴154+ 2πr2 =231 ⇒2*22/7*r2= (231-154) =77 ⇒r2 = (77*7/44)= 49/4 ⇒ r =7/2 cm ∴2*22/7*7/2*h= 154 ⇒ h= 7cm ∴ Volume = πr2h = (22/7 *7/2 * 7/2 * 7) cm3 = 539/2 =269.5 cm3
Q 10 - The bended surface region of a circle is 5544 cm2. Its volume is:
Answer : A
Explanation
4πr2= 5544 ⇒4*22/7* r2 =5544 ⇒ r2= (5544*7/88)=(63*7)= (72*32)⇒ r =(7*3)=21 Volume= 4/3πr3= (4/3*22/7*21*21*21) cm3= 38808cm3