Volume Calculation - Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - The entire surface range of a cuboid 24 cm long, 14 cm wide and 7.5 cm high is:

A - 2520 cm2

B - 1260 cm2

C - 1242 cm2

D - 621 cm2

Answer : C

Explanation

Zone of the entire surface = 2(Lb+ bh +Lh)
= 2 (24*14 + 14*15/2 + 24* 15/2) cm2
= 2(336+105+180) cm2= (621*2) cm2
= 1242 cm2

Q 2 - A rectangular water store contains 42000 liters of water. On the off chance that the length of store is 6 m and its broadness is 3.5m, then the profundity of the supply is:

A - 2 m

B - 5 m

C - 6 m

D - 8 m

Answer : A

Explanation

Volume of reservoir = 42000 ltr. = 42 cubic mtr.
Let the depth be x mtr. Then,
6*7/2*x =42 ⇒ x = 2 m
∴ Depth =2 m

Q 3 - A rectangular tank measuring (5m*4.5 m*2.1 m) is dove in the focal point of field measuring 13.5m*2.5 m. The earth burrow is spread equitably over the remaining part of the field. What amount is the level of the field raised?

A - 4 m

B - 4.1 m

C - 4.2 m

D - 4.3 m

Answer : C

Explanation

Volume of the earth dugout = (5*9/2*21/10) m3= 189/4 m3
Area of the remaining field = [(27/2*5/2) - (5*9/2)] m2
= (135/4-45/2) m2= 45/4m2
Let the level of the field be raised h meter. Then,
45/4*h = 189/4 ⇒h= 189/45 m =21/5 m =4.2 m

Q 4 - A rectangular square 6 cm*12 cm *15 cm is sliced into careful no. of equivalent solid shapes. The slightest conceivable number of blocks will be:

A - 6

B - 11

C - 33

D - 40

Answer : D

Explanation

Each side of required cube = HCF of 6cm, 12cm, 15cm = 3cm
Volume of given block = (6*12*15) cm3= 1080 cm3
Volume of each cube = (3*3*3) cm3=27cm3
∴ required number of cubes = 1080/27= 40

Q 5 - The region of the card board expected to make a crate size 25 cm* 15cm *8 cm will be:

A - 390 cm2

B - 1390 cm2

C - 2780 cm 2

D - 1000 cm2

Answer : B

Explanation

Area needed = 2(25*15+15*8+25*8) cm2
=2(375+120+200) cm2= 2(695) cm2 = 1390 cm2

Q 6 - Two solid shapes have their volumes in the proportion 1:27. The proportion of their surface territories is:

A - 1:3

B - 1:8

C - 1:9

D - 1:18

Answer : C

Explanation

a3/b3= 1/27= (1/3)3⇒ (a/b) 3= (1/3)3⇒a/b=1/3 ⇒b= 3a
S₁/S₂=6a2/6b2= a2/ (3a) 2= a2/9a2= 1/9 = 1:9

Q 7 - How numerous 3D squares of 10 cm edge can be placed in a cubic box of 1 m edge?

A - 10

B - 100

C - 1000

D - 10000

Answer : C

Explanation

Required no. = (100*100*100)/ (10*10*10) = 1000

Q 8 - The number of coins, 1.5cm in distance across and 0.2 cm thick to be softened to shape a right roundabout chamber of stature 10 cm and width 4.5 cm is:

A - 300

B - 350

C - 450

D - 500

Answer : C

Explanation

For each coin = r =1.5/2cm and h = 0.2 cm
Volume of 1 coin = πr2h = (π*1.5/2*1.5/2* 0.2) cm3
=( π*15/2*15/2*2*1/1000)cm3=  9π/80 cm3
For given cylinder, R= 4.5/2 cm and H= 10 cm
Volume= πR2H= (22/7*4.5/2*4.5/2* 10*1/100) cm3
= (π*45/2*45/2*10*1/100) = 45*9π/8 cm3
Number of coins= (45*9*π/8*80/9π) = 450

Q 9 - A chamber and a cone have the same stature and the same sweep of base. The proportion between the volumes of the barrel and the cone is:

A - 1:3

B - 3:1

C - 1:2

D - 2:1

Answer : B

Explanation

Ratio of their volume= πr2h/1/3 πr2h= 3/1 =3:1

Q 10 - The proportion of aggregate surface territory and the parallel surface zone of a chamber whose sweep is 80 cm and stature 20 cm are:

A - 2:1

B - 3:1

C - 4:1

D - 5:1

Answer : D

Explanation

r =80cm and h= 20cm
Total surface area/ lateral surface area = 2πr (h+r)/ 2πrh = (h+r)/h
= (20+80)/20 =100/20 =5:1


aptitude_volume_calculation.htm

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