# Volume Calculation - Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Volume Calculation**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - An iron shaft is 9 m long, 40 cm wide and 20 cm high. In the event that 1 cubic meter of iron measures 50 kg. What is the heaviness of the bar?

### Answer : C

### Explanation

Volume of beam = (9*40/100*20/100)m^{3}= 18/25m^{3}Weight of the bean = (18/25*50) kg = 36 kg

Q 2 - A cuboidal water tank contains 216 liters of water. Its profundity is 1/3 of its length and broadness is 1/2of 1/3 of the distinction between Length and profundity. The length of the tank is:

### Answer : C

### Explanation

Volume of tank = 216 ltr. =216 dm^{3}Let the length of the tank be x dm. Then, Depth =x/3 dm and breadth= 1/6 of (x-x/3) dm = (1/6*2x/3) dm= x/9 dm ∴ x*x/9*x/3= 216 ⇒x^{3}= 216*27= 6^{3}*3^{3}⇒x= (6*3)= 18dm Hence, length of the tank =18 dm

Q 3 - A rectangular tank measuring (5m*4.5 m*2.1 m) is dove in the focal point of field measuring 13.5m*2.5 m. The earth burrow is spread equitably over the remaining part of the field. What amount is the level of the field raised?

### Answer : C

### Explanation

Volume of the earth dugout = (5*9/2*21/10) m^{3}= 189/4 m^{3}Area of the remaining field = [(27/2*5/2) - (5*9/2)] m^{2}= (135/4-45/2) m^{2}= 45/4m^{2}Let the level of the field be raised h meter. Then, 45/4*h = 189/4 ⇒h= 189/45 m =21/5 m =4.2 m

Q 4 - A store is 15m long and 6m expansive. The amount of water taken out to bring down the level by 1 m is:

### Answer : D

### Explanation

Let the initial depth be x meters. Then, Quantity Of water taken out = [(15*6*x)- {15*6*(x-1)}]m^{3}=[90x-(90x-90)]m^{3}= 90m^{3}= 90 kiloliters.

Q 5 - The aggregate surface zone of a solid shape of side 27 cm is:

### Answer : C

### Explanation

Surface area =6a^{2}= (6*27*27) cm^{2}= 4374cm^{2}

Q 6 - The volume of a cuboid is twice that of a solid shape. On the off chance that the measurement of the cuboid is (9cm *8 cm* 6cm), the aggregate surface region of the block is:

### Answer : B

### Explanation

2*volume of cube= volume of cuboid= (9*8*6) cm^{3}Volume of cube = (1/2 *9*8*6) cm^{3}= 216cm^{3}∴ a^{3}= 216 = (6)^{3}⇒a =6 cm Total surface area = 6a^{2}= (6*6*6) cm^{2}= 216cm^{2}

Q 7 - The measurement of the base of a tube shaped drum is 35dm and its tallness is 24 dm. It is brimming with lamp oil. What number of tins each of size 25cm *22cm* 35 cm can be loaded with lamp fuel from the drum?

### Answer : D

### Explanation

r= 35/2 dm=(35/2*10)cm= 175 cm , h=24 dm = 240cm Volume of drum = (22/7*175*175*240) cm^{3}=(22*25*175*240) cm^{3}Volume of a tin = (25*22*35) cm^{3}Number of tin = (22*25*175*240)/ (25*22*35) = 1200

Q 8 - Water streams out through a round funnel whose inner measurement is 2cm, at the rate of 6 meters for each second into a barrel shaped tank, the range of whose base is 60 cm. By what amount will the level of water ascend in 30 minutes?

### Answer : B

### Explanation

Length flown in 30 minutes = (6*60*30) m = 10800 m r = 1/100m, h = 10800 m Volume = (π*1/100*1/100*10800) m^{3}Let the height of the water level be h meters. Then, π*60/100*60/100*h = π*1/100*1/100*10800 ⇒ h = (108/100*5/3*5/3) = 3m

Q 9 - A empty greenery enclosure roller 63cm wide with a circumference of 440 cm is made of iron 4 cm thick. The volume of the iron utilized is:

### Answer : B

### Explanation

2πr= 440 ⇒2*22/7*r= 440 ⇒r= (440*7/44) = 70 cm Outer radius = 70cm, inner radius = (70-4) = 66cm Volume of iron = π [(70)^{2}-(66)^{2}*63cm^{3}= (22/7*136*4*63) = 58752 cm^{3}

Q 10 - The volume of a right roundabout chamber, 14 cm in stature, is equivalent to that of a solid shape whose edge is 11 cm. The range of the base of the barrel is:

### Answer : B

### Explanation

Let the radius of the base of the cylinder be r cm. Then, πr^{2}*14 = (11)^{3}⇒22/7*r^{2}*14= 11*11*11 ⇒r^{2}=121/4 = (11/2)^{2}⇒r =11/2 =5.5 cm