Volume Calculation - Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A rectangular marble stone 28 cm wide and 5 cm thick weighs 112 kg. In the event that 1 cubic cm of marble measures 25 gm, then the length of given stone is:

A - 36 cm

B - 37.5 cm

C - 32 cm

D - 26.5 cm

Answer : C

Explanation

Let the required length be x cm.
Then, its volume = (x*28*5*25/1000) kg = 7x/2 kg
∴ 7x/2= 112 ⇒x= 112*2/7= 32 cm
Required length = 32 cm

Q 2 - In a shower, 5 cm of downpour falls. The volume of water that falls on 2 Hectares of ground are:

A - 100 m3

B - 1000 m3

C - 10000 m3

D - 10 m3

Answer : B

Explanation

Volume = (2*10000*5/100) m3=1000 m3

Q 3 - A plot of area as rectangle has measurements 240 m* 180 m. A drain let 10 m wide is burrowed surrounding it on the outside and the earth uncovered is uniformly spread over the plot, expanding its surface level by 25 cm profundity of the drain let is:

A - 1.223 m

B - 1.225 m

C - 1.227 m

D - 1.229 m

Answer : C

Explanation

Outer length = (240+20)m =260 m
Outer breadth = (180+20) =200 m
Area of the drain let = [(260*200)-(240*180)] m2
= (52000-43200) m2= 8800m2
Let the depth of the drain let be x meter. Then,
8800*x = (240*180)25/100⇒x = (60*180)/8800 = 27/22 m =1.227m

Q 4 - The result of the regions of three neighboring countenances of a rectangular box is equivalent to:

A - The volume of the container

B - twice of the volume of the crate

C - The square of the volume of the container

D - block foundation of the volume of the crate

Answer : C

Explanation

Product of areas of 3 adjacent faces = (Lb*bh*Lh)
=(L2*b2*h2) = (L*b*h) 2= V2

Q 5 - The diagonal of a 3D shape (cube) measures 9√3 cm. Its aggregate surface range is:

A - 243 cm2

B - 486 cm2

C - 324 cm2

D - 648 cm2

Answer : B

Explanation

√3a= 9√3 ⇒a= 9 cm
Total surface area = 6a2= (6*9*9) cm2= 486cm2

Q 6 - Two solid shapes have their volumes in the proportion 1:27. The proportion of their surface territories is:

A - 1:3

B - 1:8

C - 1:9

D - 1:18

Answer : C

Explanation

a3/b3= 1/27= (1/3)3⇒ (a/b) 3= (1/3)3⇒a/b=1/3 ⇒b= 3a
S₁/S₂=6a2/6b2= a2/ (3a) 2= a2/9a2= 1/9 = 1:9

Q 7 - Capacity of a round and hollow vessel is 25.872ltr. On the off chance that the stature of the chamber is three times the range of its base, what is the region of the base?

A - 336 cm2

B - 616 cm2

C - 1232 cm2

D - none of these

Answer : B

Explanation

Volume =(25.872*1000)cm3= 25872cm3
Let the radius be r cm. Then, height = 3r cm
∴22/7*r2*3r= 25872 ⇒r3= (25872*7)/66 = (392*7) = (7*7*7*8)
⇒r = (7*2) cm= 14 cm
Area of the base = πr2= (22/7*14*14) cm2= 616 cm2

Q 8 - A divider with 10 m inside diameter is burrowed 14 m profound. Earth taken out of it is spread all around to a width of 5 m to shape a dike. The tallness of the bank is:

A - 2.46 m

B - 3.56 m

C - 4.66 m

D - 5.76 m

Answer : C

Explanation

Volume of the earth dugout = πr2h = (22/7* 5*5*14) m3= 1100m3
Area of embankment = π (R2- r2) = 22/7*[(10)2-(5)2]
= (22/7*75) m2
Let the height of the embankment be h meters. Then,
22/7*75*h = 1100 ⇒h = (1100*7/22*1/75) m = 14/3 m = 4.66m

Q 9 - A empty greenery enclosure roller 63cm wide with a circumference of 440 cm is made of iron 4 cm thick. The volume of the iron utilized is:

A - 56372 cm3

B - 58752 cm3

C - 54982 cm3

D - 57636 cm3

Answer : B

Explanation

2πr= 440 ⇒2*22/7*r= 440 ⇒r= (440*7/44) = 70 cm
Outer radius = 70cm, inner radius = (70-4) = 66cm
Volume of iron = π [(70)2-(66)2*63cm3= (22/7*136*4*63)
= 58752 cm3

Q 10 - If the sweep of circle is 6cm, then its volume is:

A - (288π) cm3

B - (388π) cm3

C - (684π) cm3

D - (864π) cm3

Answer : A

Explanation

Volume = {4/3π*(6)3} cm3 = (4/3π*6*6*6) cm3= (288π) cm3


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