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Volume Calculation - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - The entire surface range of a cuboid 24 cm long, 14 cm wide and 7.5 cm high is:
Answer : C
Explanation
Zone of the entire surface = 2(Lb+ bh +Lh) = 2 (24*14 + 14*15/2 + 24* 15/2) cm2 = 2(336+105+180) cm2= (621*2) cm2 = 1242 cm2
Q 2 - A rectangular water tank is open at the top. Its ability is 24m3. Its length and broadness are 4m and 3m separately. Overlooking the thickness of the material utilized for building the tank, the aggregate expense of painting the internal and external surfaces of the tank at Rs 10 for every m2, is:
Answer : D
Explanation
Let the depth of the tank be x meters. Then, 4*3*x = 24 ⇒x =2m
Area of the surface to be painted = 2* [{2*(L+b)*h} + (L*b)}]
= 2*[2*(4+3)*2+ (4*3)] m2= 80m2
Cost of painting = (80*10) = 800 Rs.
Q 3 - What a portion of a trench 48m long, 16.5 m expansive and 4m profound can be filled by the earth got by burrowing a round and hollow passage of distance across 4m what's more, length 56 m?
Answer : B
Explanation
Volume of the earth dug out as a tunnel = πr2h= (22/7*2*2*56) m3= 704 m3 Volume of the ditch = (48*33/2*4) m3=3168 m3 Required part = 704/3168 = 2/9
Q 4 - A rectangular tank is 5 m high, 3 m long and 2 m wide. What number of liter of water can be hold?
Answer : A
Explanation
Volume = (500*300*200) cu. Cm =500*300*200/1000 liters= 30000 ltr.
Q 5 - The aggregate surface range of a 3D shape is 600 cm2. The length of its corner to corner is:
Answer : B
Explanation
6a2=600 ⇒a2=100⇒a =10 Diagonal = √3a =10 √3
Q 6 - Two solid shapes have their volumes in the proportion 1:27. The proportion of their surface territories is:
Answer : C
Explanation
a3/b3= 1/27= (1/3)3⇒ (a/b) 3= (1/3)3⇒a/b=1/3 ⇒b= 3a S₁/S₂=6a2/6b2= a2/ (3a) 2= a2/9a2= 1/9 = 1:9
Q 7 - Capacity of a round and hollow vessel is 25.872ltr. On the off chance that the stature of the chamber is three times the range of its base, what is the region of the base?
Answer : B
Explanation
Volume =(25.872*1000)cm3= 25872cm3 Let the radius be r cm. Then, height = 3r cm ∴22/7*r2*3r= 25872 ⇒r3= (25872*7)/66 = (392*7) = (7*7*7*8) ⇒r = (7*2) cm= 14 cm Area of the base = πr2= (22/7*14*14) cm2= 616 cm2
Q 8 - A well must be hole that is to be 22.5 m profound and of breadth 7m. The expense of putting the internal bended surface at rs. 30 for each sq. meter are:
Answer : B
Explanation
Here r= 7/2 m and h= 45/2 m Curved surface area = 2πrh=(2*22/7*7/2*45/2)m2 = 495m2 Required cost = (495*30) = 14850 rs.
Q 9 - The bended surface zone of a round column is 528m2 and its volume is 2772 m3. The tallness of the column is:
Answer : C
Explanation
2πrh= 528 and πr2h= 2772 Πr2h/2πrh= 2772/528= 21/4⇒r = (21/4*2) = 21/2 m ∴2*22/7*21/2*h= 528 ⇒h =528/66= 8m
Q 10 - The volume of a right roundabout chamber, 14 cm in stature, is equivalent to that of a solid shape whose edge is 11 cm. The range of the base of the barrel is:
Answer : B
Explanation
Let the radius of the base of the cylinder be r cm. Then, πr2*14 = (11)3 ⇒22/7*r2*14= 11*11*11 ⇒r2 =121/4 = (11/2)2 ⇒r =11/2 =5.5 cm