Volume Calculation - Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - The entire surface range of a cuboid 24 cm long, 14 cm wide and 7.5 cm high is:

A - 2520 cm2

B - 1260 cm2

C - 1242 cm2

D - 621 cm2

Answer : C

Explanation

Zone of the entire surface = 2(Lb+ bh +Lh)
= 2 (24*14 + 14*15/2 + 24* 15/2) cm2
= 2(336+105+180) cm2= (621*2) cm2
= 1242 cm2

Q 2 - A rectangular water store contains 42000 liters of water. On the off chance that the length of store is 6 m and its broadness is 3.5m, then the profundity of the supply is:

A - 2 m

B - 5 m

C - 6 m

D - 8 m

Answer : A

Explanation

Volume of reservoir = 42000 ltr. = 42 cubic mtr.
Let the depth be x mtr. Then,
6*7/2*x =42 ⇒ x = 2 m
∴ Depth =2 m

Q 3 - A horticultural field is as a rectangle of length 20m and Width 14m. A pit 6m long, 3m wide and 2.5 m profound is delved in a corner of the field and the earth taken out of the pit is spread consistently over the remaining range of the field. The level of the field has been raised by:

A - 15.16 cm

B - 16.17 cm

C - 17.18 cm

D - 18.19 cm

Answer : C

Explanation

Volume of earth dug out = (6*3*5/2) m3=45 m3
Area of the remaining field =[(20*14)-(6*3)]m2= (280-18)m2=262m2
Let the level of the field raised be h cm. Then,
262*h/100= 45 ⇒ h= (45*100)/262 cm =17.18 cm

Q 4 - A rectangular tank is 5 m high, 3 m long and 2 m wide. What number of liter of water can be hold?

A - 30000

B - 15000

C - 25000

D - 35000

Answer : A

Explanation

Volume = (500*300*200) cu. Cm =500*300*200/1000 liters= 30000 ltr.

Q 5 - The aggregate surface zone of a solid shape of side 27 cm is:

A - 2916 cm2

B - 729 cm2

C - 4374 cm2

D - 19683 cm2

Answer : C

Explanation

Surface area =6a2= (6*27*27) cm2= 4374cm2

Q 6 - The size of a wooden square is (15 cm *12 cm* 20 cm) . What number of such pieces will be required to build a strong wooden solid shape of least size?

A - 45

B - 48

C - 60

D - 75

Answer : C

Explanation

Side of smallest cube = LCM (15cm, 12cm, 20cm) =60cm
Volume of such a cube =(60*60*60) cm3
Volume of 1 given block = (15*12*20) cm3
Required no. of blocks= (60*60*60/15*12*20) =60

Q 7 - If the span of a barrel is diminished by half and the stature is expanded by half to frame another chamber, then the volume will be diminished by:

A - 1:4

B - 4:1

C - 2:5

D - none of these

Answer : A

Explanation

Initial volume = πr2h
New radius = r/2, new volume = [π*(r/2)2*4] = 1/4 πr2h
Required ratio = 1/4 πr2h: πr2h = 1/4:1 = 1:4

Q 8 - The number of coins, 1.5cm in distance across and 0.2 cm thick to be softened to shape a right roundabout chamber of stature 10 cm and width 4.5 cm is:

A - 300

B - 350

C - 450

D - 500

Answer : C

Explanation

For each coin = r =1.5/2cm and h = 0.2 cm
Volume of 1 coin = πr2h = (π*1.5/2*1.5/2* 0.2) cm3
=( π*15/2*15/2*2*1/1000)cm3=  9π/80 cm3
For given cylinder, R= 4.5/2 cm and H= 10 cm
Volume= πR2H= (22/7*4.5/2*4.5/2* 10*1/100) cm3
= (π*45/2*45/2*10*1/100) = 45*9π/8 cm3
Number of coins= (45*9*π/8*80/9π) = 450

Q 9 - The total of the range of base and the tallness of a barrel is 37 m. On the off chance that the aggregate surface region of the chamber is 1628m2, then its volume is:

A - 5240 m3

B - 4620 m3

C - 3180 m3

D - none of these

Answer : B

Explanation

Given: (r+h) = 37m
Total surface area = 2πr (h+r)
∴2πr* 37= 1628 ⇒22/7* r= 22 ⇒ r = 7m
h =(37-7)= 30 m
Volume = πr2h= (22/7* 7* 7* 30) m3= 4620 m3

Q 10 - The proportion of aggregate surface territory and the parallel surface zone of a chamber whose sweep is 80 cm and stature 20 cm are:

A - 2:1

B - 3:1

C - 4:1

D - 5:1

Answer : D

Explanation

r =80cm and h= 20cm
Total surface area/ lateral surface area = 2πr (h+r)/ 2πrh = (h+r)/h
= (20+80)/20 =100/20 =5:1


aptitude_volume_calculation.htm

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