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Volume Calculation - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - The region of the base of a rectangular tank is 6500 cm2 and the volume of the water contained in it in 2.6 cubic meter. The profundity of the water in the tank is:
Answer : D
Explanation
L*b= 6500cm2 , L*b*d=2.6m3=(2.6*100*100*100) cm3 ∴ d = (2.6*100*100*100)/6500 cm = (2.6*100*100*100)/6500*100 = 4m ∴ Depth = 4m
Q 2 - Half cubic meter of gold sheet is stretched out by pounding in order to spread a region of 1 hectare. The thickness of the sheet is:
Answer : C
Explanation
Area = 1 hectare= 10000m2, Volume = 0.5 m3 Thickness =Volume/Area = (0.5/10000)m =(0.5*100/10000)cm=0.005cm
Q 3 - A rectangular tank measuring (5m*4.5 m*2.1 m) is dove in the focal point of field measuring 13.5m*2.5 m. The earth burrow is spread equitably over the remaining part of the field. What amount is the level of the field raised?
Answer : C
Explanation
Volume of the earth dugout = (5*9/2*21/10) m3= 189/4 m3 Area of the remaining field = [(27/2*5/2) - (5*9/2)] m2 = (135/4-45/2) m2= 45/4m2 Let the level of the field be raised h meter. Then, 45/4*h = 189/4 ⇒h= 189/45 m =21/5 m =4.2 m
Q 4 - A room is 10 m long, 8m wide and 3.3 m high. What number of men can be obliged in this room if every man requires 3m3 of space?
Answer : B
Explanation
Volume of the room = (10*8*3.3) m3= 264m3 Volume required by 1man = 3m3 Required number of men = 264/3 = 88
Q 5 - If every side of a solid shape is multiplied, then its volume:
Answer : D
Explanation
Let the edge of the original cube be x. Then its volume = x3 New edge = 2x, new volume (2x) 3=8x3 So, it?s become 8 times.
Q 6 - The volume of a cuboid is twice that of a solid shape. On the off chance that the measurement of the cuboid is (9cm *8 cm* 6cm), the aggregate surface region of the block is:
Answer : B
Explanation
2*volume of cube= volume of cuboid= (9*8*6) cm3 Volume of cube = (1/2 *9*8*6) cm3= 216cm3 ∴ a3= 216 = (6) 3 ⇒a =6 cm Total surface area = 6a2 = (6*6*6) cm2= 216cm2
Q 7 - The tallness of the barrel is 14 cm and its bended surface range is 264 cm2. The volume of the barrel is:
Answer : B
Explanation
Given h= 14cm and 2πrh= 264 ∴ 2*22/7*r *14= 264 ⇒88r= 264 ⇒r =3 Volume = πr2h = (22/7*3*3*14) cm3= 396 cm3
Q 8 - A funnel of 2 inch measurement fills the water tank in 60 minutes. In the event that the measurement of the funnel is 4inch, in what the reality of the situation will become obvious eventually pipe fills the same tank?
Answer : C
Explanation
r = 1 inch, volume = πr2h= π*1*1*h= πh r =2 inch volume = π (2)2*h= 4πh 4 time water pass at the same time. ∴Rates are 1:4 so, time taken =4:1 ∴ 2nd pipe will take = (1/4*60) = 15 min
Q 9 - A empty greenery enclosure roller 63cm wide with a circumference of 440 cm is made of iron 4 cm thick. The volume of the iron utilized is:
Answer : B
Explanation
2πr= 440 ⇒2*22/7*r= 440 ⇒r= (440*7/44) = 70 cm Outer radius = 70cm, inner radius = (70-4) = 66cm Volume of iron = π [(70)2-(66)2*63cm3= (22/7*136*4*63) = 58752 cm3
Q 10 - The volume of the circle is 2145(11/21) cm3. Its sweep is:
Answer : B
Explanation
4/3πr3=45056/21 ⇒4/3*22/7* r3 = 45056/21 ⇒r3= (45056/21 *21/88) = 512 = (8) 3 ⇒r =8 ∴Radius of the sphere =8cm