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Volume Calculation - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - The length of the longest shaft that can be kept in a room 5 m long, 4 m wide and 3 m high, is:
Answer : A
Explanation
Required length = √[(5) 2+(4) 2+(3) 2]=√(25+16)+(9)=√50m =√25*2 m =5√2m
Q 2 - A cuboidal water tank contains 216 liters of water. Its profundity is 1/3 of its length and broadness is 1/2of 1/3 of the distinction between Length and profundity. The length of the tank is:
Answer : C
Explanation
Volume of tank = 216 ltr. =216 dm3 Let the length of the tank be x dm. Then, Depth =x/3 dm and breadth= 1/6 of (x-x/3) dm = (1/6*2x/3) dm= x/9 dm ∴ x*x/9*x/3= 216 ⇒x3= 216*27= 63*33 ⇒x= (6*3)= 18dm Hence, length of the tank =18 dm
Q 3 - A horticultural field is as a rectangle of length 20m and Width 14m. A pit 6m long, 3m wide and 2.5 m profound is delved in a corner of the field and the earth taken out of the pit is spread consistently over the remaining range of the field. The level of the field has been raised by:
Answer : C
Explanation
Volume of earth dug out = (6*3*5/2) m3=45 m3 Area of the remaining field =[(20*14)-(6*3)]m2= (280-18)m2=262m2 Let the level of the field raised be h cm. Then, 262*h/100= 45 ⇒ h= (45*100)/262 cm =17.18 cm
Q 4 - A reservoir of limit 8000 liters measures remotely 3.3m by 2.6m by 1.1m and its dividers are 5cm thick. The thickness of the base is:
Answer : B
Explanation
Volume of the cistern = 8000ltr. =8000dm3 External length = 33 dm, external breadth =26 dm and external depth = 11 dm Internal length = (33-5/10*2) dm = 32 dm Internal breadth = (26-5/10*2) dm = 25 dm Internal depth = (11-x) dm ∴ 32*25*(11-x) = 8000 ⇒ (11-x) =8000/ (32*25) =10 ⇒ x = (11-10) =1dm
Q 5 - The aggregate surface zone of a solid shape of side 27 cm is:
Answer : C
Explanation
Surface area =6a2= (6*27*27) cm2= 4374cm2
Q 6 - Two solid shapes have their volumes in the proportion 1:27. The proportion of their surface territories is:
Answer : C
Explanation
a3/b3= 1/27= (1/3)3⇒ (a/b) 3= (1/3)3⇒a/b=1/3 ⇒b= 3a S₁/S₂=6a2/6b2= a2/ (3a) 2= a2/9a2= 1/9 = 1:9
Q 7 - A rectangular box measure s inside 1.6 m long, 1m expansive and 60 cm profound. The no. of cubical obstructs each of edge 20 cm that can be pressed inside the crate, is:
Answer : D
Explanation
Required no. = (160*100*60)/ (20*20*20) = 120
Q 8 - If the tallness of a barrel is expanded by 15% and the span of the base is diminished by 10%, then by what percent will its bended surface region change?
Answer : B
Explanation
Let the original radius =r and height = h Then curved surface area = 2πrh New height = 115% of h = (115/100*h) = 23h/20 New radius = 90% of r = (90/100*r) = 9r/10 New curved surface area = (2π*9r/10*23h/20) = 207πrh/100 Increase = (207πrh/100-2 πrh) = 7 πrh/100 Increase %= (7 πrh/100*1/2 πrh*100) %= 3.5%
Q 9 - A empty greenery enclosure roller 63cm wide with a circumference of 440 cm is made of iron 4 cm thick. The volume of the iron utilized is:
Answer : B
Explanation
2πr= 440 ⇒2*22/7*r= 440 ⇒r= (440*7/44) = 70 cm Outer radius = 70cm, inner radius = (70-4) = 66cm Volume of iron = π [(70)2-(66)2*63cm3= (22/7*136*4*63) = 58752 cm3
Q 10 - In the event that the sweep of a circle is multiplied, its surface region will increment by:
Answer : C
Explanation
Let, original radius=r. Then surface area= 4πr2 New radius= 2r. New surface area = 4π (2r) 2= 16πr2 Increase % in surface areas = (12πr2/4 πr2*100) %= 300%