# Aptitude - Ratios Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Ratios**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - X's money is to Y's money as 5:7 and Y's money is to Z's money as 3:4 .If X has Rs.900, Z has

### Answer : D

**Explanation**

X:Y = 5:7 = 15:21, Y:Z = 3:4 = 21:28 X:Y:Z = 15:21:28 X:Z = 15:28 800:Z = 15:28 =>Z = Rs.1680.

Q 2 - The speed of three trains is in the ratio 3:5:7. The ratio between the time taken by these trains to travel the same distance is

### Answer : A

**Explanation**

Speeds are in the ratio 3:5:7 Ratio of time taken will be 1/3:1/5:1/7 => 35/105:21/105:15/105 =35:21:15

### Answer : C

**Explanation**

A/D = (A/B* B/C * C/D ) = (2/3 * 4/5 * 6/7 ) = 16/35 Thus A:D =16:35

### Answer : D

**Explanation**

Let x/5=y/8 = k ,then x = 5k and y = 8k &therw4; x+5/y+8 = 5k+5 / 8k +8 = 5(k+1)/ 8(k+1) = 5/8 => (x+5) : (y+8 ) = 5:8

Q 5 - On the off chance that a:b =c:d =e: f =1:2 , then (3a+5c+7e) : (3b +5d +7f ) = ?

### Answer : A

**Explanation**

a/b=c/d=e/f=1/2?a= b/2,c=d/2 and e=f/2. ∴ (3a+5c+7e)/(3b+5d+7f) = (3b/2+5d/2+7f/2)/(3b+5d+7f) = 1/2(3b+5d+7f)/3b+5d+7f) = 1/2. => (3a+5c+7e):(3b+5d+7f)= 1:2.

Q 6 - In a class, the no. of young women is 20% more than that of the young fellows. The class' quality is 66. If 4 more young women are admitted to the class, what will be the no's extent of young fellows to that of the young women?

### Answer : C

**Explanation**

Let the number of boys be x. Then the no. of girls = 120% of x = (120/100 *X)= 6X/5 . X+6x/5 =66 => 5x+6x=330 => 11x= 330 => x= 3 Now, the no. of boys= 30 , no. of girls =[6/5*30 +4]=40 Now the ratio of boys and girls = 30/40 = 3/4 =3:4

Q 7 - If a container containing twelve mirrors is dropped, which of the accompanying cannot be the proportion of broken mirror to unbroken mirror?

### Answer : C

**Explanation**

For dividing 12 in to two whole numbers, the sum of the terms of the ratio must be a factor of 12. So, they cannot be in the ratio 3:2.

Q 8 - Three numbers A , B and C are in the proportion 1:2 :3. Their normal is 600. In the event that An is expanded by 10% and B is diminished by 20 %, then to get the normal expanded by 5%, C will be expanded by:

### Answer : D

**Explanation**

Let A= x, B= 2x and C=3x, then, (X+2x+3x)/3 =600 => 6x =1800 =>x= 300 ∴ the numbers are 300, 600, 900. New average= 105% of 600 =(105/100*600)= 630. Let 110% of 300+ 80% of 600 +y=630*3 => (110/100*300) +(80/100*600)+y =1890 => (330+480)+y= 1890 => y=1890-810 =1080 Increase in C= (1080-900) =180.

Q 9 - The wage of A and B are in the proportion 3:2 and their uses are in the proportion 5:3. On the off chance that every spares Rs1000, then A pay is :

### Answer : C

**Explanation**

Let the incomes of A and B be Rs 3x and Rs 2x respectively and let their expenditures be Rs 5y and Rs 3y respectively. Then, 3x -5x =1000 ...(i) and 2x-3y=1000 ...(ii) On solving (i) and (ii),we get x=2000. ∴ A income =Rs (3*2000)=Rs 6000.

Q 10 - Vessels An and B contain blends of milk and water in the proportion 4:5 and 5:1 separately .in what proportion ought to amounts of blends be taken From A to B to shape a blend in which drain to water is in the proportion 5:4?

### Answer : D

**Explanation**

Let the required ratio be X:1 Milk in x ltr. of 1st mix= (x*4/9)= 4x/9 ltr. Water in x ltr. of 1st mix= (x-4x/9)= 5x/9 ltr. Milk in 1 ltr. of 2nd. Mix= 5/6 ltr. Water in 1 ltr. of 2nd. Mix= {1-5/6}=1/6 ltr. Milk: water =(4x/9+5/6): (5x/9+1/6) =(8x+15)/18: (10x+3)/18 ∴ (8x+15)/(10x+3) =5/4 => 4(8x+15)= 5(10x+3) = 18x=45 =>x=5/2 Required ratio : 5/2:1 =5:2