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Following quiz provides Multiple Choice Questions (MCQs) related to **Ratios**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - Rs.11256 is divided among X,Yand Z so that X may receive 1/3 as much as Y and Z together receive Y receives 1/5 of what X and Z together receive. The share of X is more than that of Y by:

**Explanation**

X = 1/3(Y+Z) => Y+Z = 3X =>X+Y+Z = 11256 => 4X = 11256 => X = 2814 Again, Y = 1/5(X+Z) => X+Z = 5Y => 6Y = 11256 =>Y = 1876 Then X's share is more than that of Y by Rs. (2814-1876) =938

Q 2 - Rs. 960 was divided among three sons Qavi, Shafi and Rafi. If each of them had received Rs 45 less, their shares would have been in the ratio of 3:5:7. What was the amount received by Qavi?

**Explanation**

Total =Rs.960 If each of them receives Rs.45 less then 960-(45*3) =825 Ratio being 3:5:7 =>3x+5x+7x=825 =>x=55 Qavi's amount = (3x) +45=(3*55)+45=Rs.210

**Explanation**

A/D = (A/B* B/C * C/D ) = (2/3 * 4/5 * 6/7 ) = 16/35 Thus A:D =16:35

Q 4 - If 5x^{2}-13xy+6y^{2} =0, then x:y = ?

**Explanation**

5x^{2}- 13xy +6y^{2}= 0 => 5x^{2}-10xy-3xy+6y^{2}=0 => 5x(x-2y) - 3y(x-2y)=0 => (x-2y) (5x-3y)=0 => x-2y=0 or 5x-3y =0 or 5x=3y => (x:y)= (2:1) or (x:y)= (3:5)

Q 5 - On the off chance that a:b =c:d =e: f =1:2 , then (3a+5c+7e) : (3b +5d +7f ) = ?

**Explanation**

a/b=c/d=e/f=1/2?a= b/2,c=d/2 and e=f/2. ∴ (3a+5c+7e)/(3b+5d+7f) = (3b/2+5d/2+7f/2)/(3b+5d+7f) = 1/2(3b+5d+7f)/3b+5d+7f) = 1/2. => (3a+5c+7e):(3b+5d+7f)= 1:2.

Q 6 - In a class, the no. of young women is 20% more than that of the young fellows. The class' quality is 66. If 4 more young women are admitted to the class, what will be the no's extent of young fellows to that of the young women?

**Explanation**

Let the number of boys be x. Then the no. of girls = 120% of x = (120/100 *X)= 6X/5 . X+6x/5 =66 => 5x+6x=330 => 11x= 330 => x= 3 Now, the no. of boys= 30 , no. of girls =[6/5*30 +4]=40 Now the ratio of boys and girls = 30/40 = 3/4 =3:4

Q 7 - The proportion of two numbers is 3:4 and their entirety is 420.The more noteworthy of the Two numbers is:

**Explanation**

Let the numbers be 3x and 4x , Then 3x+4x= 420 => 7x= 420 => x=60. So, the numbers are 180 and 240. Hence, the correct answer is 240 .

Q 8 - The proportion of first and worthless train passages between two stations is 3:1 and that of the no. of traveler going between two these by first and inferior 1:50 . in the event that on a specific day rs.1325 be gathered from the travelers going between these stations, then the sum gathered from useless travelers is:

**Explanation**

Ratio of the amounts collected form 1^{st}and 2^{nd}class fares =(3*1:1*50)=3:50. Amount collected from 2^{nd}class passengers=Rs (1325*50/53) = Rs 1250.

Q 9 - Income of A ,B and C are in the proportion 7:9:12 and their consumption are in the proportion 8:9:15 . On the off chance that A sparing is 1/4 of his wage, then the proportion of sparing of A,B and C is:

**Explanation**

Let the incomes of A, B and C be 7x, 9x and 12 x and their expenditures be Rs 8y,Rs 9y and Rs 15y respectively. Then their savings are Rs(7x -8y), Rs(9x-9y) and Rs (12x-15y). ∴7x-8y=1/4*7x =>28x-32y=7x =>21x=32y. Ratio of saving=(7x-8y):(9x-9y):(12x-15y) = (7*32/21y-8y):(9*32/21y-9y):(12*32/21y-15y) = (32y-24y/3):(96y-63y/7):(128y-105y/7) = 8y/3:33y/7:23y/7=56:99:69.

Q 10 - Two vessels A and B contain drain and water blended in the proportion 5:3 and 2:3. At the point when these blends are blended to frame another blend containing half drain and half water, they must be taken in the proportion

**Explanation**

Let the required ratio be x:1, Milk in x liters of A=(x*5/8) liters=5x/8 liters,Water=3x/8 liters. Milk in 1 litre of B=(1*2/5) litre=2/5 litre, Water =3/5 liters. ∴ (5x/8+2/5) / (3x/8+3/5) = 1/1 =>(5x/8+2/5)=(3x/8+3/5) => 2x/8=1/5 =>x=4/5. Required ratio= 4/5:1=4:5.

aptitude_ratios.htm

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