# Aptitude - Ratios Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Ratios**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - Divide Rs. 1500 among U,V,W,X so that u and V together get thrice as much as W and X together, V gets four times of what W gets and W gets 1.5 times as much as X. V gets Rs

### Answer : B

**Explanation**

U+V+W+X=1500 ------ (1) Here U+V=3(W+X) From (1) And 4(W+X) =1500 => W+X=375 U+V=1125 Given that V=4W & W=1.5X => 2.5X = 375 => X=150 => V=4*1.5*X=900

Q 2 - The speed of three trains is in the ratio 3:5:7. The ratio between the time taken by these trains to travel the same distance is

### Answer : A

**Explanation**

Speeds are in the ratio 3:5:7 Ratio of time taken will be 1/3:1/5:1/7 => 35/105:21/105:15/105 =35:21:15

### Answer : D

**Explanation**

0.6*A = 0.09 *B A/B =0.09/0.6 = 0.09/0.60 = 9/60 =3/20 ∴A:B = 3:20

### Answer : B

**Explanation**

2A =3B thus A/B=3/2 and 4B=5C thus B/C = 5/4 ∴ A/C=(A/B*B/C) = (3/2*5/4) = 15/8 A:C =15:8.

Q 5 - On separating a total of rs. 832 in the middle of An and B in the proportion 1/3 :1/5 , there offer are :

### Answer : A

**Explanation**

Given ratio =1/3: 1/5 = 5:3 I^{st}part=Rs(832*5/8)=Rs 520; 2^{nd}part = Rs(832*3/8)=Rs 312.

Q 6 - The no's proportion of understudy concentrating on in school A,B and C is 5:6:8 . In the event that the no. of understudy in each of the schools is expanded by 30%, 25% and 25% individually, what will be the new proportion of the understudy in the school A, B and C?

### Answer : B

**Explanation**

New strength = (130% of 5x), (125% of 6x) and (125% of 8x) = (130/100*5x), (125/100*6x),(125/100*8x) New ratio=650x/100:750x/100:1000x/100=65:75:100=13:15:20.

Q 7 - A portion bears the same proportion to 1/27 as 3/7 does to 5/9, the part is :

### Answer : B

**Explanation**

Let the fraction be X. Then, X:1/27 = 3/7 :5/9 => x *5/9= 1/27 *3/7 = 1/63 => x=(1/63*9/5) = 1/35 Required fraction =1/35

Q 8 - Three numbers A , B and C are in the proportion 1:2 :3. Their normal is 600. In the event that An is expanded by 10% and B is diminished by 20 %, then to get the normal expanded by 5%, C will be expanded by:

### Answer : D

**Explanation**

Let A= x, B= 2x and C=3x, then, (X+2x+3x)/3 =600 => 6x =1800 =>x= 300 ∴ the numbers are 300, 600, 900. New average= 105% of 600 =(105/100*600)= 630. Let 110% of 300+ 80% of 600 +y=630*3 => (110/100*300) +(80/100*600)+y =1890 => (330+480)+y= 1890 => y=1890-810 =1080 Increase in C= (1080-900) =180.

Q 9 - Rs. 600 are partitioned among A, B and C such that Rs. 40 more than 2/fifth of An offer , Rs. 20 more than 2/7 of B offer and Rs. 10 all the more then 9/17 of C offer may all be equivalent . What is A's offer?

### Answer : B

**Explanation**

(2/5)A +40 = ( 2/7)B +20 + 9/17 C+10 = k. Then, A =5/2 (k-40), B= 7/2(k-20) and C= 17/9 (k-10) A+B+C =600 =>5/2 (k-40) +7/2(k-20) + 17/9 (k-10) = 600 => 45(k-40) +63(k-20)+34(k-10)= 10800 => 142k- (45*40+63*20+34*10) =10800 => 142k- (10800+3400) = 14200 =>k=100. ∴ A= 5/2(100-40)= (5/2*60) =150

Q 10 - A blend contains drain and water in the proportion 5:1. On including 5 liters of water, the proportion of milk to water gets to be 5:2. The amount of milk in the first blend is:

### Answer : C

**Explanation**

In the given mixture, Let milk = 5x liter and water =x liters. Then, 5x/x+5= 5/2 => 10x= 5x+25 =>5x =25 =>x=5 ∴ milk in original mixture= (5*5) =25 liters