Aptitude - Ratios Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Ratios. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - The ratio between Hyder's and Siddiq's age at present is 3:5.Hyder is 8 years younger then Siddiq. The ratio of Hyder's age to Siddiq's age after 8 years will be:

A - 4:9

B - 5:6

C - 5:7

D - 3:5

Answer : C

Explanation

Let their ages be 3x and 5x years.
5x-3x=8 or x=4.
Hyder's age = 3x =12 and Siddiq's age = 5x =20.
After 8 years Hyder's age = 12+8 = 20
After 8 years Siddiq's age = 20+8 =28
Ratio of their ages 20:28 = 5:7

Q 2 - If 18: x=x: 18, then x is equal to:

A - 18

B - 324

C - 9

D - 4.24

Answer : A

Explanation

18: x=x: 18
=>18/x=x/18=>x=18

Q 3 - If a:b =2:3 and b:c =4:5 , then c:a =?

A - 15:8

B - 6:5

C - 8:5

D - 8:15

Answer : A

Explanation

A/C = (a/b *b/c) = (2/3*4/5 ) = 8/15 
C/A =15/8 , 
so C:A = 15:8

Q 4 - if 0.4 :1.4 ::1.4:x , then x= ?

A - 49

B - 4.9

C - 0.49

D - 0.4

Answer : B

Explanation

0.4*X =1.4 *1.4
=> X=1.4*1.4/0.4 
=14*14/10*4 
=49/10= 4.9

Q 5 - In a school, the proportion of young men and young ladies is 4:5 . at the point when 100 young lady leaves the school , the proportion gets to be 6:7 . What are number of young men are there in the school?

A - 1300

B - 1200

C - 1500

D - 1600

Answer : B

Explanation

Let the number of boys and girls be 4x and 5x respectively.
      Then,4x/5x-100=6/7?28x=30x-600 =>2x=600 => x=300.
Number of  boys=(4*300)=1200.

Q 6 - The month to month pay of An and B are in the proportion 2:3 and their month to month costs are in the proportion 6:9. On the off chance that each of them recovery 600 rs for every month, then their month to month wage?

A - 1500, 2250

B - 1200, 1800

C - 1600, 2400

D - 1400, 2100

Answer : C

Explanation

Let the incomes of A and B be Rs 2x and Rs 3x respectively and their Expenditures are Rs 5y and Rs 9y respectively. Then,
  2x-5y=600 ...  (i) and  3x-9y=600
=> x- 3y=200 ...  (ii) 
On solving (i) and   (ii) ,  we  get  x =800.
So, their incomes are Rs.1600 and Rs.2400 respectively.

Q 7 - At the point when 20% of a no. is added to another no., the no. increment by half. What is the proportion between the first and the second no?

A - 3:2

B - 2:3

C - 5:2

D - cannot be resolved

Answer : C

Explanation

Let the numbers be x and y. Then,
Y+ 20x/100 = (150/100)y
=> x/5 ={ (3/2)y-y}= y/2
=> 2x-5y
=> x/y=5/2 
=> x:y =5:2

Q 8 - Three numbers A , B and C are in the proportion 1:2 :3. Their normal is 600. In the event that An is expanded by 10% and B is diminished by 20 %, then to get the normal expanded by 5%, C will be expanded by:

A - 90

B - 100

C - 150

D - 180

Answer : D

Explanation

Let A= x, B= 2x and C=3x, then,
      (X+2x+3x)/3 =600 
=> 6x =1800 
=>x= 300
  ∴  the numbers are 300, 600, 900.
  New average= 105% of 600 =(105/100*600)= 630.
    Let 110% of 300+ 80% of 600 +y=630*3
     => (110/100*300) +(80/100*600)+y =1890
=> (330+480)+y= 1890 
=> y=1890-810 =1080
     Increase in C= (1080-900) =180.

Q 9 - Some cash is isolated among A, B and C in a manner that 5 times An offer ,3 times of B's offer and 2 times C offer are all equivalent . The proportion between the offer of A, B, c is:

A - 5:3:2

B - 2:2:5

C - 15:10:6

D - 6:10:15

Answer : D

Explanation

Let 5A= 3B= 2C=k. Then,
A = k/5, B = k/3 and C = k/2
∴ A:B:C =k/5 :k/3:k/2 =6:10:15.

Q 10 - Rs 3068 are circulated among A,B and C such that on diminishing Their shares by Rs 10,Rs 14 and Rs 20 individually, the parity cash would be isolated among then in the proportion 5:6:7. at that point ,B offer is:

A - 864

B - 1022

C - 2014

D - 1064

Answer : B

Explanation

Money in the ration 5:6:7 is Rs (3068 -44) =Rs 3024.
∴B share =Rs{(3024*6/18)+14}=Rs(1008+14) =1022
aptitude_ratios.htm
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