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Aptitude - Ratios Online Quiz

Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Ratios. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - In a class, the number of boys is more than the number of girls by 16% of the total strength. The ratio of boys to girls is

Answer : C

Explanation

Let the number of boys and girls be x and y respectively.
Then (x-y) = 16% of (x+y)
(x-y)=  4/25(x+y)
25x-25y = 4x+4y
=>21x = 29y
x/y = 29/21
=>x:y = 29:21

Q 2 - If 19 inches correspond to 48.26 cm, how many numbers of Centimeters are there in 39 inches?

Answer : B

Explanation

Let 39 inches corresponds to x cm.
Given that 19 inches corresponds to 48.26 cm
=>19/48.26=39/x
=>x=39/19*48.26=99.06

Q 3 - If A:B =5:7 and B:C = 6:11, then A:B:C =?

A - 55:77:66

B - 30:42:77

C - 35:49:42

D - None of the above.

Answer : B

Explanation

A:B = 5:7 = 30:42
B:C = 6:11 = 42:77
Thus A: B: C = 30:42:77

Q 4 - If x/5=y/8,then (x+5):(y+8)=?

Answer : D

Explanation

Let x/5=y/8 = k ,then x = 5k and y = 8k
&therw4; x+5/y+8 = 5k+5 / 8k +8  = 5(k+1)/ 8(k+1) = 5/8
=> (x+5) : (y+8 ) = 5:8

Q 5 - The proportion of young men and young ladies in a school is 3:2 . at the point when 6 more young ladies join , this proportion gets to be 6:5 . What are number of young men there in the school?

Answer : D

Explanation

Let the quantity of young men and young ladies be 3x and 2x individually.
At that point ,3x/(2x+6)=6/5 ?15x=12x+36?3x=36?x=12.
Number of boys=(3*12)=36.

Q 6 - The proportion of winning of An and B is 8:9 , if the gaining of An is expanded by half and procuring of B is diminished by 25%, the new proportion of their acquiring is 16:9 , what are An acquiring?

A - 22000

B - 28500

C - 37000

D - cannot be resolved

Answer : D

Explanation

New earnings of A and B=Rs (150% of 8x), Rs (75%of 9x)
 =Rs (150/100*8x), Rs (75/100*9x) = Rs 12x,Rs 27x/4
 Ratio of new earnings = 12x: 27x/4 = 48:27 = 16:9.
Thus, we cannot find A's earnings.

Q 7 - Two numbers are separately 20% and half all the more than a third Number. These two numbers are in the proportion:

Answer : B

Explanation

Let the 3^rd number be X. Then,
1^st  number =     120% of X= (120/100*X)= 6x/5
2^nd  number= 150 % of X= (150/100 *X) =3x/2
∴ Ration of these no. = 6x/5 :3x/2 =12:15 =4:5

Q 8 - Which of the accompanying is the most reduced proportion?

Answer : C

Explanation

7/13 =0.538, 17/25 =0.68, 7/15= 0.466, 15/23 =0.652
Clearly, 7/15 is the smallest.

Q 9 - Income of A ,B and C are in the proportion 7:9:12 and their consumption are in the proportion 8:9:15 . On the off chance that A sparing is 1/4 of his wage, then the proportion of sparing of A,B and C is:

Answer : A

Explanation

Let the incomes of A, B and C be 7x, 9x and 12 x and their expenditures be Rs 8y,Rs 9y and Rs 15y respectively. Then their savings are Rs(7x -8y), Rs(9x-9y) and Rs (12x-15y).
∴7x-8y=1/4*7x
=>28x-32y=7x
=>21x=32y.
Ratio of saving=(7x-8y):(9x-9y):(12x-15y)
 =  (7*32/21y-8y):(9*32/21y-9y):(12*32/21y-15y)
 = (32y-24y/3):(96y-63y/7):(128y-105y/7)
 = 8y/3:33y/7:23y/7=56:99:69.

Q 10 - A and B are two compounds of gold and copper arranged by blending metals in the extent 7:2 and 7:11 separately. In the event that the equivalent amounts of the combination are dissolved to frame a third amalgam C, the extent of gold and copper In C will be:

Answer : C

Explanation

Gold in C=(7/9+7/18)=21/18=7/6.
Copper in C=(2/9+11/18)=15/18=5/6.
∴Gold:Copper=7/6:5/6=7:5.

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