- Aptitude - Home
- Aptitude - Overview
- Quantitative Aptitude
Aptitude - Averages Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Averages. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - Find the average of the numbers which are as follows : 15, 5, 0, 12, 8
Answer : C
Explanation
Average required = (15+5+0+12+8)/5 = 40/5 = 8
Q 2 - There are three numbers but the conditions of the number are first number having double value in the comparison of second number. On the other hand first number should be half value in the comparison of third number 56 is the averages of three numbers then find out the difference between first and the third number?
Answer : D
Explanation
If 2x is the first number , then the value of the second and third number will be x and 4x.∴ 2x+x+4x = 56*3 ⇒ 7x = 168 ⇒ x= 24 here we find the value of x which is the second number . With the help of them we can find the value of first number and the second number. First number = 2x = 48 and third number = 4x =96 ∴ Required difference = 96-48 = 48
Q 3 - Find out the total employee's quantity if the given condition such that Rs. 8500 is the average salary of workers. 10000 Rs. is the average monthly salary of 7 technicians and remaining worker has Rs. 7800 average salary of the month.
Answer : B
Explanation
If x employees working in firm . then (7* 10000)+7800(x-7 )= 8500 = 70000 +7800x-546 00 =8500x ⇒ 700x = 15400 ⇒ x = 22 We find that 22 employees are working in the firm.
Q 4 - The students who leave the school find out the average of their marks if 50 is the average of their marks if 50 is the average of 28 students. Condition is given that 55 is the average marks of 20 students.
Answer : A
Explanation
28 students have total marks = ( 28*50)= 1400 20 students have total marks = (55* 20) =1100 Total of 8 those students who leaves the school = 1400- 1100 = 300 Required average = 300/8 = 37.5
Q 5 - What should be the weight of the new men if a 56 kg person replaced by new person then 2.5 kg weight increase in the average of 8 person weight?
Answer : D
Explanation
total weight increment = (2.5* 8)= 20 kg. New men weight = (56+20) = 76 kg
Q 6 - M is the average of 5 consecutive natural numbers. What should be the improvement in average if next 3 numbers included?
Answer : B
Explanation
let the 5 consecutive natural numbers be n, n+1,n+2, n+3, n+4. Then n+(n+1)+(n+2)+(n+3)+(n+4) /5 = 5n+10= 5m ⇒ 5(n+2)= 5m ⇒ (n+2) =m ⇒ n=(m-2) New numbers are m-2, m-1, m, m+1,m+2,m +3, m+4, m+5 New average = ( 8m+12)/8 = m+1.5 , which is 1.5 more than m.
Q 7 - The average age of 35 students in class is 16 years. The average age of 21 students is 14. What is the average age of remaining 14 students?
Answer - B
Explanation
Sum of the ages of 14 students = (16 x 35) - (14 x 21) = 560 - 294 = 266 Therefore Required average = 266⁄14 = 19years.
Q 8 - Of the four numbers, the first is twice the second, the second is one-third of the third and the third is 5 times the fourth. The average of the numbers is 24.75. The largest of these numbers is?
Answer - A
Explanation
Let the fourth number be z. then, third number = 5z, second number = 5z⁄3 and first number = 10z⁄3 z + 5z + 5z⁄3 + 10z⁄3 = (24.75 x 4) or 11z = 99 or z = 9 So, the numbers are 9, 45, 15, and 30. Therefore Largest number = 45.
Q 9 - A cricketer has a certain average for 10 innings. In the eleventh inning, he scored 108 runs, thereby increasing his average by 6 runs. His new average is?
Answer - B
Explanation
Let average for 10 innings be z. Then, = 10z + 108⁄11 = 11z + 66 = 10z + 108 = z = 42. New average = (z + 6) = 48 runs.
Q 10 - In an examination, a pupil's average marks were 63 per paper. If he had obtained 20 more marks for his Geography paper and 2 more marks for his history paper, his average per paper would have been 65. How many papers were there in the examination?
Answer - C
Explanation
Let the number of papers be z. Then, 63z + 20 + 2 = 65z 2z = 22 or z = 11