# Aptitude - Averages Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Averages**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - If 40 is the average of the four number A, B,C and D . on the other hand 40 is also the average of four numbers A,B,E and F. Find out the following term which must be correct?

### Answer : B

### Explanation

(A+B+C+D)= (40*4) =160 , (A+B+E+F) = (40*4) =160 ∴ A+B+C+D = A+B+E+F ⇒ C+D= E+F

Q 2 - 28 is the average of 3 numbers. Find out the value of third number if the given condition is such that the second number have the double value in the comparison of first number and third number have 4 times value of first number?

### Answer : A

### Explanation

If x is the value of third number. Then the value of second number is x/2 , if x/2 is the value of second number then the value of first number will be 1/2 . x/2 = x/4. Total sum of three number = (3*28) =84 ∴ x+x/2+x/4 = 84 ⇒ 7x/4 = 84 ⇒ x= (84*4)/7 = 48 So, its proves that the value of the third number is 48.

Q 3 - 38.6°C is the average temperature of 4 first day of the week while 40.3°C is the average of last 4 days in a week. Find out the temperature on Thursday if 39.1°C is average of whole week?

### Answer : C

### Explanation

M+T+W+Th = (38.6*4)= 154.4 ...(i) T+W+Th+F = (40.3*4) =161.2 ...(ii) M+T+W+Th+F+S+Su =(39.1*7) =273.7 ...(iii) (i)+(ii) –(iii) we find that , (154.4+161.2- 272.7) =41.9°C ∴ 41.9 °C was the temperature on Thursday.

Q 4 - 84 kg is the average weight of 3 people A, B and C. 80 kg is the average if D joins the group. A new man E replaces who have 3kg more weight than D. At that time 79 kg is the average weight of B, C, D and E. What should be the weight of A?

### Answer : A

### Explanation

A+B+C= (3*84)= 252 kg. A+B+C+D= (4*80)= 320 kg weight of D =( 320- 252) =68 kg. weight of E = (68+3)= 71 kg. sum of the weight of B+C+D+E= (79*4)= 316 kg , sum of the weight of B+C+D = (316-71)=245kg. Total weight of A = (320- 245 )= 75 kg.

Q 5 - In 11 innings a certain average has been made by a player. In the next innings he made 90 runs and his average have downfall with 5 runs. What will be the average of that player after 12 innings?

### Answer : A

### Explanation

If x is the average of run in 11 innings. Then, 11x+90 =(x-5)*12 ⇒ x= 150 Average run rate after 12th innings = (11x+90 )/12 =(11*150+90)/12= 145

Q 6 - Drinks were done by 6 persons. Out of them 5 person paid 32 Rs. each, Rs. 80 more paid by the 6th person in the comparison of average expenditure of all. Find out the total amount paid by 6 persons?

### Answer : A

### Explanation

if x is the average expenditure of 6 person. (32*5)+(x+80)= 6x = 5x = (160+80) = 5x= 240 ⇒ x = 48 Total expenditure = 48*6 =288 Rs.

Q 7 - The average score of a cricketer for ten matches is 38.9 runs. If the average for the first six matches is 42, then find the average for the last four matches?

**Answer - B**

**Explanation**

Required average =^{(38.9 x 10) - (42 x 6)}⁄_{4}=^{137}⁄_{4}= 34.25.

Q 8 - Of the three numbers, the first is twice the second and the second is twice of the third. The average of the reciprocal of the numbers is ^{7}_{72}?

**Answer - B**

**Explanation**

Let the third number be z. Then, second number = 2z. First number = 4z. Therefore^{1}⁄_{z}+^{1}⁄_{2z}+^{1}⁄_{4z}=^{7}⁄_{72}x 3^{7}⁄_{4z}=^{7}⁄_{24}or 4z = 24 or z = 6 So, the number are 24, 12 and 6.

Q 9 - The average weight of a class of 24 students is 35 kg. If the weight of the teacher be included, the average rises by 400g. The weight of the teacher is:?

**Answer - B**

**Explanation**

Weight of the teacher = (35.4 x 25 - 35 x 24)kg = 45 kg

Q 10 - A crickter whose bowling average is 12.4 runs per wicket takes 5 wickets for 26 runs and thereby decreases his average by 0.4. The number of wickets taken by him till the last match was:?

**Answer - B**

**Explanation**

Let the number of wickets taken till the last match be z. Then,^{12.4z + 26}⁄_{z + 5}= 12 = 12.4z + 26 = 12z + 60 = 0.4z = 34 z =^{34}⁄_{0.4}z =^{340}⁄_{4}= 85