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Aptitude - Averages Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Averages. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : A
Explanation
Average = (3+6+9+12+15+18+21+24+27)/ 9= 135/9 = 15
Q 2 - 23 is the average of 3 friends if we add 1 more person then the value of average will be same or no change. Find out the age of the new person?
Answer : D
Explanation
3 friends have the sum of the ages = (3*23)= 69 ...(i) 4 friend have the sum of the ages = (4*23)=92 ...(ii) Difference between the (i) and (ii) is the age of the new person. We find that the age of the new person is (92-69)= 23 years.
Q 3 - A committee have 8 person. If 35 year and 45 year aged lady replaced by two men in that case the average of age become more 2 year in the comparison of old one. Find out the average age of two men?
Answer : D
Explanation
Age increase = (2*8) = 16 years. Total age of two lady who replaced = (35+45)= 80 Total age of two man = (80+16) =96 Average age of those men = 96/2 = 48. Hence, is 48 the required average age.
Q 4 - A hostel have 35 students if 42 student became in the hostel then expenditure on per student increase and became Rs. 42 per head while Rs. 1 reduce in the average expenditure. Find out the expenditure per day at the present time?
Answer : D
Explanation
If x is the original expenditure , then x/35- (x+42)/42 = 1 =. 6x -5(x+42)= 210 ⇒ x= 420 ∴ original expenditure = Rs. 420
Q 5 - 15 is the average weight of 19 students if a new student add then the average weight of the class is 14.8 kg. Find out the weight of the new join student?
Answer : B
Explanation
19 students have total sum of the weight = (15*19) =285 kg. 20 students have total sum of the weight = (14.8*20)= 296 kg. Weight of the new student = 296- 285 = 11 kg.
Q 6 - Find out the number of papers in exams if 63 is the average marks in exams.65 marks will be the average if 20 marks obtained by him in geography and 22 marks in History.
Answer : A
Explanation
let there be n papers. Sum of marks of all papers = 63n 65-63n = (20+2) ⇒ 2n = 22 ⇒ n =11 Hence, its proves that the 11 papers held in exams.
Q 7 - The average score of a cricketer for ten matches is 38.9 runs. If the average for the first six matches is 42, then find the average for the last four matches?
Answer - B
Explanation
Required average = (38.9 x 10) - (42 x 6)⁄4 = 137⁄4 = 34.25.
Q 8 - Of the four numbers, the first is twice the second, the second is one-third of the third and the third is 5 times the fourth. The average of the numbers is 24.75. The largest of these numbers is?
Answer - A
Explanation
Let the fourth number be z. then, third number = 5z, second number = 5z⁄3 and first number = 10z⁄3 z + 5z + 5z⁄3 + 10z⁄3 = (24.75 x 4) or 11z = 99 or z = 9 So, the numbers are 9, 45, 15, and 30. Therefore Largest number = 45.
Q 9 - The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?
Answer - B
Explanation
Let the average age of the whole team be z years. Therefore 11z - (26 + 29) = 9 (z - 1) = 11z - 9z = 46 = 2z = 46 = z = 23 So, average age of team is 23 years.
Q 10 - The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is?
Answer - A
Explanation
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years. Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years Therefore Husbands present age = (90 - 50) years = 40 years