# Aptitude - Averages Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Averages. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz. Q 1 - 18 is the mean of 5 numbers. What should be the exclude number if the average became 16 after excluding number?

A - 18

B - 25

C - 34

D - 26

### Explanation

```5 number have the total sum = (18*5)= 90
4 number have the total sum = (16*4)= 64
So, the exclude number is = (90-64)= 26.```

Q 2 - 44 is the average of 100 numbers. If we add 4 new numbers in 100 numbers then average will be 50 then what should be the average value of new 4 numbers?

A - 100

B - 200

C - 400

D - 500

### Explanation

```The value of 100 number=  (44*100) = 4400
The value of 104 number = ( 50*104)=   5200
∴ value of 4 new number = 5200- 4400 = 800
Then the  average value of the 4 numbers = 800/4 = 200```

Q 3 - 38°C is the average temperature of 4 day Monday , Tuesday , Wednesday and Thursday while 40°C is the average temperature of Tuesday, Wednesday , Thursday and Friday. On Monday 30° C temperature recorded. Find out the temperature on Friday?

A - 34°

B - 27°

C - 45°

D - 38°

### Explanation

``` M+T+W+Th = (38*4)= 152 ...(i)
T+W+Th+F = (40*4) =160 ...(ii)
After subtracting  (ii)-(i)  we find that f-M =8 ⇒ F-30 =8 ⇒ F =38.
∴ 38° C is the temperature on Friday.```

Q 4 - What should be the average speed of the train if first 12 min. travelled by train at a speed of 30km/hr and after that speed increased and with the speed of 45km/hr travelled for next 8 min?

A - 36 km/hr

B - 26 km/hr

C - 22 km/hr

D - 23 km/hr

### Explanation

```Total covered distance by train = (30*12/60+45* 8/60) = 12 km
Total time taken by train  to cover the distance = 12+8 = 20min = 1/3 hours.
Required  average speed = 12*3/1 = 36 km/hr.```

Q 5 - In 11 innings a certain average has been made by a player. In the next innings he made 90 runs and his average have downfall with 5 runs. What will be the average of that player after 12 innings?

A - 145

B - 150

C - 155

D - 123

### Explanation

```If x is the average of run in 11 innings. Then,
11x+90 =(x-5)*12 ⇒ x= 150
Average run rate after 12th innings = (11x+90 )/12 =(11*150+90)/12= 145```

Q 6 - Rs. 450 is average of 5 shirts and Rs.750 is the average of 4 trousers and 12 pair of shoes average is also Rs.750. Find out the average expenditure per product?

A - Rs 678.21

B - Rs 250

C - Rs 240

D - Rs 230

### Explanation

```sum of the all items = (450*5 +750*4+750*12) = Rs. 14250
Average expenditure  per product = Rs. 14250/21 = Rs. 678.21```

Q 7 - A company produces on an average 4000 items per month for the first 3 months. How many items it must produce on an average per month over the next 9 months, to average 4375 items per month over the whole?

A - 4500

B - 4600

C - 4680

D - 4710

Explanation

```Required average = (4375 x 12) - (4000 x 3)⁄9 = 52500 - 12000⁄9 = 40500⁄9 = 4500.
```

Q 8 - If the arithmetic mean of seventy-five numbers is calculated, it is 35. If each number is increased by 5, then mean of new number is?

A - 70

B - 90

C - 30

D - 40

Explanation

```A.M. of 75 numbers = 35.
Sum of 75 numbers = (75 x 35) = 2625.
Total increase = (75 x 5) = 375.
Increased sum = (2625 + 375) = 3000.
Increased average = 3000⁄75 = 40.
```

Q 9 The average weight of 8 persons increases by 2.5kg when a new person comes in place of one of them weighing 65kg . what might be the weight of the new person?

A - 85

B - 75

C - 75.5

D - 80

Explanation

```Total weight increased = (8 x 2.5) kg = 20kg
Weight of new person = (65 + 20) kg = 85kg.
```

Q 10 - The average weight of 3 men A, B, C is 84 kg. Another man D joins the group and the average now becomes 80kg. If another man E, whose weight is 3 kg more than that of D, replaces A, then the average weight of B, C, D, E becomes 79kg. The weight of A is?

A - 70

B - 75

C - 72

D - 70

Explanation

```Let A, B, C, D and E represent their respective weights. Then,
A + B + C = (84 x 3) = 252 kg,

A + B + C + D = (80 x 4) = 320 kg.
D = (320 - 252)kg = 68 kg,
E = (68 + 3)kg = 71 kg.

B + C + D + E =  (79 x 4) = 316 kg
Now, (A + B + C + D) - (B + C + D + E) = (320 - 316)kg = 4 kg

A - E = 4
A = ( 4 + E ) = 75 kg.
```
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