Aptitude - Questions & Answers

Progression - Online Quiz

Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - 105 th term of the A.P. 4, 9/2, 5, 11/2, 6 ....is

Answer : A

Explanation

 Here a = 4, d = (9/2-4) = 1/2
T₁0₅ = a+(105-1)*d=4+104*1/2=4+52=56.

Q 2 - In the event that the fourth term of a number juggling movement is 14 and its twelfth term is 70, then its first term is:

Answer : B

Explanation

  Let the first term of the A.P. be a and common difference be d. then,
a+ 3d = 14 ...(i)    a+11d = 70 ...(ii)
On subtracting (i) from (ii), we get 8d =56    d = 7
Putting d = 7 in (i), we get a+3*7=14 ⇒ a= (14-21) = -7   ∴ First term = -7

Q 3 - What number between 200 and 600 are distinct by 4, 5, 6?

Answer : B

Explanation

LCM of 4, 5, 6 = 2*2*5*3 = 60
So, each one must be divisible by 60.
Requisite numbers are 240, 300, 360, 420, 480 and 540.
Their no. is 6.

Q 4 - The total of the all odd number somewhere around 100 and 200 is:

Answer : D

Explanation

 Requisite sum = 101 +103 + 105+...+199.
This is an A.P. in which a = 101, d =2 and L= 199.
A + (n-1) d =199 ⇒ 101 + (n-1) *2 = 199
⇒ (n-1) * 2 = 98 ⇒ (n-1) = 49 ⇒ n = 50.
∴ Sum = n/2 * (a+L) = 50/2 * (101 +199) = (50*150) =7500.

Q 5 - What number of odd number pages arrives in a book of 1089 pages?

Answer : C

Explanation

The pages are 1, 3, 5, 7...,1089.
This is an A.P. in which a= 1, d = (3-1) = 2 and L = 1089.
Let the number of these term be n. then,
(a+ (n-1) d = 1089 ⇒ 1 + (n - 1)* 2 = 1089 ⇒ (n-1 ) * 2 = 1088
n-1 =544⇒ n = 545.
∴ Required number of pages=545.

Q 6 - Which term of the G.P. 5,10,20,40 ...is 1280?

Answer : B

Explanation

Let T_n = 1280. Then ar (ⁿ⁻ⁱ) = 1280 ⇒ Here a= 5 and r =2
∴ 5*2(ⁿ⁻ⁱ) =1280 ⇒256 = 2(ⁿ⁻ⁱ) =2⁸ ⇒ n-1 =8 ⇒ n= 9

Q 7 - Three numbers are in G.P. Their whole is 28 and item is 512. The numbers are:

Answer : C

Explanation

Let the number be a/r, a, ar.
Then, a/r* a*ar = 512 ⇒ a³ =8³ ⇒ a =8
8/r+8+8r =28 ⇒ 8/r +8r =20 ⇒ 2/r+2r =5
⇒ 2r²-5r+2 =0 ⇒ 2r²-4r-r+2 =0
⇒ 2r (r-2)- (r-2)=0   ⇒ (r-2)(2r-1) =0
⇒r = 2 or r = 1/2
Numbers are 4,8, 16.

Q 8 - A few buys National Savings Certificates each year whose worth surpasses the earlier years buy by Rs 400. Following 8 years, she finds that she has obtained declarations whose aggregate face worth is Rs 48000. What is the face estimation of the Certificates acquired by her in the first years?

Answer : D

Explanation

Let the required value be Rs a.
Also d= 400, n = 8 and Sn = 48000.
Sn   = n/2 [2a + (n -1) d] ⇒ 8/2 *[2a + 7 *400] = 48000
⇒ 2a + 2800 = 12000⇒ 2a=9200⇒ a = 4600

Q 9 - (14² +15² +......+30²) =?

Answer : D

Explanation

We know that (1²+2²+3²+... +a²) = {n(n+1)(2n+1)}/6
Given Exp. = (1²+2²+...+13²+14²+??+30²)-(1²+2²+...+13²)
= (30*31*61)/6 - (13*14*27)/6 = (9455- 819) = 8636

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