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Progression - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : A
Explanation
Here a = 4, d = (9/2-4) = 1/2 T₁0₅ = a+(105-1)*d=4+104*1/2=4+52=56.
Q 2 - In the event that the fourth term of a number juggling movement is 14 and its twelfth term is 70, then its first term is:
Answer : B
Explanation
Let the first term of the A.P. be a and common difference be d. then, a+ 3d = 14 ...(i) a+11d = 70 ...(ii) On subtracting (i) from (ii), we get 8d =56 d = 7 Putting d = 7 in (i), we get a+3*7=14 ⇒ a= (14-21) = -7 ∴ First term = -7
Q 3 - On the off chance that the tenth term of the succession, a - b, a-2b, a-3b ...is 20 and its twentieth term is 10, then its xth term is:
Answer : D
Explanation
This is an A.P. in which A = a and d = (a-b) -a = -b T₁₀ = 20 ⇒ a+9d = 20 ⇒ a+9*)-b) =20⇒a-9b=20 ... (i) T₂₀ =10⇒ a+19d = 10 ⇒ a+19*(-b) =10⇒a-19b=10 ... (ii) On subtracting (ii) from (i) we get 10b = 10 ⇒ b=1 Putting b= 1 in (i) we get a-9*1=20 ⇒ a =29. ∴ xth term = a + (x-1) *d=29+ (x-1) * (-b) = 29 + (x-1) * (-1) = (30-x).
Answer : C
Explanation
This is an A.P. in which a = 5, d =1 and L=19. Let the number of its term be n. Then, Tṇ = 19 ⇒ a + (n-1) d =19 ⇒ 5 + (n-1) * 1 = 19 ⇒ (n-1) =14 ⇒ n= 15. ∴ Sṇ = n/2 * (a+L) = 15/2 *(5+19) = 180.
Q 5 - What number of odd number pages arrives in a book of 1089 pages?
Answer : C
Explanation
The pages are 1, 3, 5, 7...,1089. This is an A.P. in which a= 1, d = (3-1) = 2 and L = 1089. Let the number of these term be n. then, (a+ (n-1) d = 1089 ⇒ 1 + (n - 1)* 2 = 1089 ⇒ (n-1 ) * 2 = 1088 n-1 =544⇒ n = 545. ∴ Required number of pages=545.
Q 6 - In a G.P. the primary term is 5 and the regular proportion is 2. The eighth term is:
Answer : C
Explanation
a =5, r = 2 ∴ 8th term = a *r⁷ = (5*2⁷) = 5*128 = 640
Q 7 - Three numbers are in G.P. Their whole is 28 and item is 512. The numbers are:
Answer : C
Explanation
Let the number be a/r, a, ar. Then, a/r* a*ar = 512 ⇒ a3 =83 ⇒ a =8 8/r+8+8r =28 ⇒ 8/r +8r =20 ⇒ 2/r+2r =5 ⇒ 2r2-5r+2 =0 ⇒ 2r2-4r-r+2 =0 ⇒ 2r (r-2)- (r-2)=0 ⇒ (r-2)(2r-1) =0 ⇒r = 2 or r = 1/2 Numbers are 4,8, 16.
Q 8 - A few buys National Savings Certificates each year whose worth surpasses the earlier years buy by Rs 400. Following 8 years, she finds that she has obtained declarations whose aggregate face worth is Rs 48000. What is the face estimation of the Certificates acquired by her in the first years?
Answer : D
Explanation
Let the required value be Rs a. Also d= 400, n = 8 and Sn = 48000. Sn = n/2 [2a + (n -1) d] ⇒ 8/2 *[2a + 7 *400] = 48000 ⇒ 2a + 2800 = 12000⇒ 2a=9200⇒ a = 4600
Q 9 - The number of inhabitants in microbes, society copies ever 2 minutes. How long will it take for the populace to develop from 1000 to 512000 microbes?
Answer : D
Explanation
Let the growth be 1000, 2000, 4000 ...512000. This is a G.P. in which a = 1000, r = 2 and tn = 512000 Tn = ar&n-1 ⇒ 1000*2 &n-1 = 512000⇒ 2 &n-1 = 512= 2⁹ ⇒ (n-1) = 9. ∴ Time taken = (2*9) min = 18 min.