Aptitude - Questions & Answers

Progression - Online Quiz

Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - The twelfth term of the A.P. 14, 9, 4, - 1, - 6....is:

Answer : D

Explanation

 Here a = 14, d = (9 - 14) = -5.
∴ T₁₂ = a + (12 -1) d = a + 11d = 14 + 11 * (-5) = -41.

Q 2 - What number of numbers arrive somewhere around 10 and 200 which are precisely separable by 7?

Answer : D

Explanation

Requisite numbers are 14, 21, 28, 35 .., 196.
This is an A.P. in which a = 14 and d = 7
a +(n-1) d = 196 ⇒  14+(n-1)*7 =196
= (n-1)*7 = 182 ⇒ (n-1) = 26 ⇒ n = 27.

Q 3 - The main term of a number-crunching movement is 6 and its normal distinction is 5. The eleventh term is:

Answer : D

Explanation

Here a =6 and d = 5
T₁₁    = a + (11-1) d = a +10 d = (6+10*5) =56.

Q 4 - (1+2+3+4....+99+100+99+98+.....+3+2=1) =?

Answer : D

Explanation

Give series = 2 (1+2+3+4+?..+99) + 100
= 2 * 99/2 * (1+99) + 100=2* 4950 +100 = 9900 + 100 = 10000

Q 5 - The total of initial 20 odd regular numbers is:

Answer : C

Explanation

Sum = (1+3 +5+7+...to 20 terms
Here a = 1, d = (3-1) =2 and n = 20.
∴ Sṇ = n/2 {2a + (n-1) d} =20/2 *{2*1+ (20-1)*2} =10*40=400.

Q 6 - The third term of a geometrical progression is 4. The result of initial 5 terms is:

Answer : C

Explanation

Let the first term be a and common ratio r. Then ar = 4
Product of 5 first term = a* ar*ar²*ar³ *ar⁴ *= a*r⁴ = (ar²)⁵ = 4⁵

Q 7 - The whole (1+1/2+1/4+1/8+1/16+..... =?

Answer : A

Explanation

This is an infinite G.P in which a =1 and r = 1/2
Sum of infinite G.P. = a/ (1-r) = 1/ (1-1/2) =2

Q 8 - A whelp comprises of individuals whose ages are in A.P., the normal contrast being 3 months .If the most youthful of the club in not more than years old and the sum of the age of the considerable number of recollects is 250 years, then the no. of recall in the club is :

Answer : C

Explanation

Let the ages be 7 years, 29/4 years, 15/2 years and so on.
The ages are in A.P. in which a=7, d= 1/4 and Sn= 250
Sn = n/2[2a+ (n-1) d] ⇒ n/2 [2*7+ (n-1)*1/4] =250
⇒ n [14+ (n-1)/4] = 250
⇒ n [14+ (n-1)/4 ]=500 ⇒ n[56+(n-1) = 2000
⇒ n (n+55) = 2000 ⇒ n² +55n-2000 = 0
⇒ n²+80n -25n -2000 = 0 ⇒ n (n+80)-25 (n+80) = 0
⇒ (n+80) (n-25) = 0 ⇒ n= 25(∵ n ≠-80)
∴ Number of members in the club= 25

Q 9 - In the event that (1² + 2² + 3²+ ......... + x²) = x(x+1) (2x+1)/6, then (1² + 3²+ 5² + ...... + 19²) =?

Answer : A

Explanation

(1²+ 3²+5²+..........+19²) = (1²+2²+3²+4²+5²+........+18²+19²) - (2²+4²+6²+.........+18²)
 = {19*(19+1) (38+1)/6} - (1*2²+2²*2²+2²*3²+2²*4²+???. +2²*9²)
= 2470 -2²*{1²+2²+3²+... +9²} = 2470 - (4*9*10*19)/6= (2470-1140) =   1330

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