Progression - Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - What number of term arrives in the A.P. 7, 11, 15..... 139?

A - 33

B - 34

C - 32

D - 31

Answer : B

Explanation

Here a = 7 and d = (11-7) = 4
Let there be n terms in the given A.P. then,
Tn = 139 ⇒a+ (n-1) d =139
⇒ 7+ (n-1)*4 = 139 ⇒ (n-1) *4 = 132 ⇒ (n-1) = 33
⇒ n = 34

Q 2 - What number of 3-digit numbers is distinguishable by 6?

A - 102

B - 150

C - 151

D - 966

Answer : B

Explanation

Requisite numbers are 102, 108, 114, 120,..., 996.
This is an A.P. in which a = 102 and d = (108-102) = 6
a + (n-1) d = 996    ⇒   102+ (n-1)*6 = 996   ⇒ (n-1)*6 =894    ⇒ (n-1) = 149    ⇒ n = 150

Q 3 - What number of products of arrive between the whole numbers 15 and 105, both comprehensive?

A - 30

B - 31

C - 32

D - 33

Answer : B

Explanation

Requisite no. are 15, 18, 21, 24, 105.
Here a = 15 and d = (18-15) = 3
Let their number be n. Then,
a + (n-1) d =105 ⇒ 15+ (n-1)*3 = 105
⇒ a+ (n-1) d = 105 ⇒ 15+ (n-1)*3 = 105
⇒ (n-1)*3 = 90   ⇒ n-1 =30 ⇒ n = 31

Q 4 - The total of the all odd number somewhere around 100 and 200 is:

A - 3750

B - 6200

C - 6500

D - 7500

Answer : D

Explanation

 Requisite sum = 101 +103 + 105+...+199.
This is an A.P. in which a = 101, d =2 and L= 199.
A + (n-1) d =199 ⇒ 101 + (n-1) *2 = 199
⇒ (n-1) * 2 = 98 ⇒ (n-1) = 49 ⇒ n = 50.
∴ Sum = n/2 * (a+L) = 50/2 * (101 +199) = (50*150) =7500.

Q 5 - The total of initial 20 odd regular numbers is:

A - 210

B - 300

C - 400

D - 420

Answer : C

Explanation

Sum = (1+3 +5+7+...to 20 terms
Here a = 1, d = (3-1) =2 and n = 20.
∴ Sṇ = n/2 {2a + (n-1) d} =20/2 *{2*1+ (20-1)*2} =10*40=400.

Q 6 - In the event that the fourth and ninth term of a G.P. is 54 and 13122 separately, there its second term is:

A - 6

B - 12

C - 18

D - 9

Answer : A

Explanation

Let its 1st term be a and common ratio r. Then,
ar3 = 54 and ar⁸ = 13122
∴ ar⁸/ ar3 = 13122/54 ⇒ r⁵ =243 = 3⁵ =r = 3
∴ a* 33 = 54 ⇒ a*27 = 54 = > a =2
2nd term = ar = (2*3) =6

Q 7 - In the event that a ≠b, Then which of the accompanying proclamations is valid?

A - a+b/2= √ab

B - a+b/2

C - a+b/2> √ab

D - All of these

Answer : C

Explanation

For any two unequal numbers a and b, we have (A.M).> (g.m)
∴   (a+b)/2 > √ab

Q 8 - A man heaps logs of wood so that the top layer contains one log and every lower layer has one more than the layer above. In the event that there are 15 layers, the aggregate number of logs will be:

A - 105

B - 120

C - 210

D - 225

Answer : B

Explanation

Total number of logs = 1+2+3+...+15.
This is an A.P. in which a =1, d =1 and n= 15.
Sn = n/2(a+1) = 15/2 (1+15) =120

Q 9 - If (12+22+32+??+102) =385, then the value of (22+ 42 + 62 +......+ 202) is

A - 770

B - 1155

C - 1540

D - (385)2

Answer : C

Explanation

(22+42+62+...+202) = (1*22+22*22+32*22+...+102*22)
= 22(12+22+32+??..+102) = (4*385) = 1540.
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