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Progression - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : B
Explanation
Here a = 7 and d = (11-7) = 4 Let there be n terms in the given A.P. then, Tn = 139 ⇒a+ (n-1) d =139 ⇒ 7+ (n-1)*4 = 139 ⇒ (n-1) *4 = 132 ⇒ (n-1) = 33 ⇒ n = 34
Answer : B
Explanation
Requisite numbers are 102, 108, 114, 120,..., 996. This is an A.P. in which a = 102 and d = (108-102) = 6 a + (n-1) d = 996 ⇒ 102+ (n-1)*6 = 996 ⇒ (n-1)*6 =894 ⇒ (n-1) = 149 ⇒ n = 150
Q 3 - What number of products of arrive between the whole numbers 15 and 105, both comprehensive?
Answer : B
Explanation
Requisite no. are 15, 18, 21, 24, 105. Here a = 15 and d = (18-15) = 3 Let their number be n. Then, a + (n-1) d =105 ⇒ 15+ (n-1)*3 = 105 ⇒ a+ (n-1) d = 105 ⇒ 15+ (n-1)*3 = 105 ⇒ (n-1)*3 = 90 ⇒ n-1 =30 ⇒ n = 31
Q 4 - The total of the all odd number somewhere around 100 and 200 is:
Answer : D
Explanation
Requisite sum = 101 +103 + 105+...+199. This is an A.P. in which a = 101, d =2 and L= 199. A + (n-1) d =199 ⇒ 101 + (n-1) *2 = 199 ⇒ (n-1) * 2 = 98 ⇒ (n-1) = 49 ⇒ n = 50. ∴ Sum = n/2 * (a+L) = 50/2 * (101 +199) = (50*150) =7500.
Answer : C
Explanation
Sum = (1+3 +5+7+...to 20 terms
Here a = 1, d = (3-1) =2 and n = 20.
∴ Sṇ = n/2 {2a + (n-1) d} =20/2 *{2*1+ (20-1)*2} =10*40=400.
Q 6 - In the event that the fourth and ninth term of a G.P. is 54 and 13122 separately, there its second term is:
Answer : A
Explanation
Let its 1st term be a and common ratio r. Then, ar3 = 54 and ar⁸ = 13122 ∴ ar⁸/ ar3 = 13122/54 ⇒ r⁵ =243 = 3⁵ =r = 3 ∴ a* 33 = 54 ⇒ a*27 = 54 = > a =2 2nd term = ar = (2*3) =6
Q 7 - In the event that a ≠b, Then which of the accompanying proclamations is valid?
Answer : C
Explanation
For any two unequal numbers a and b, we have (A.M).> (g.m) ∴ (a+b)/2 > √ab
Q 8 - A man heaps logs of wood so that the top layer contains one log and every lower layer has one more than the layer above. In the event that there are 15 layers, the aggregate number of logs will be:
Answer : B
Explanation
Total number of logs = 1+2+3+...+15. This is an A.P. in which a =1, d =1 and n= 15. Sn = n/2(a+1) = 15/2 (1+15) =120
Q 9 - If (12+22+32+??+102) =385, then the value of (22+ 42 + 62 +......+ 202) is
Answer : C
Explanation
(22+42+62+...+202) = (1*22+22*22+32*22+...+102*22) = 22(12+22+32+??..+102) = (4*385) = 1540.