Progression - Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - What number of term arrives in the A.P. 7, 11, 15..... 139?

A - 33

B - 34

C - 32

D - 31

Answer : B

Explanation

Here a = 7 and d = (11-7) = 4
Let there be n terms in the given A.P. then,
Tn = 139 ⇒a+ (n-1) d =139
⇒ 7+ (n-1)*4 = 139 ⇒ (n-1) *4 = 132 ⇒ (n-1) = 33
⇒ n = 34

Q 2 - In the event that the fourth term of a number juggling movement is 14 and its twelfth term is 70, then its first term is:

A - - 10

B - -7

C - 7

D - 10

Answer : B

Explanation

  Let the first term of the A.P. be a and common difference be d. then,
a+ 3d = 14 ...(i)    a+11d = 70 ...(ii)
On subtracting (i) from (ii), we get 8d =56    d = 7
Putting d = 7 in (i), we get a+3*7=14 ⇒ a= (14-21) = -7   ∴ First term = -7

Q 3 - Aggregate number of whole numbers somewhere around 100 and 200 which are distinct by both 9 and 6 is:

A - 5

B - 6

C - 7

D - 8

Answer : B

Explanation

LCM of 9 and 6 = 18
So, each one must be multiple of 18.
Requisite no. is 108,126, 144, 162, 180, 198.
Their no. is 6.

Q 4 - (1+2+3+4....+99+100+99+98+.....+3+2=1) =?

A - 200

B - 500

C - 1000

D - 10000

Answer : D

Explanation

Give series = 2 (1+2+3+4+?..+99) + 100
= 2 * 99/2 * (1+99) + 100=2* 4950 +100 = 9900 + 100 = 10000

Q 5 - What number of odd number pages arrives in a book of 1089 pages?

A - 542

B - 544

C - 545

D - 546

Answer : C

Explanation

The pages are 1, 3, 5, 7...,1089.
This is an A.P. in which a= 1, d = (3-1) = 2 and L = 1089.
Let the number of these term be n. then,
(a+ (n-1) d = 1089 ⇒ 1 + (n - 1)* 2 = 1089 ⇒ (n-1 ) * 2 = 1088
n-1 =544⇒ n = 545.
∴ Required number of pages=545.

Q 6 - In a G.P. the primary term is 5 and the regular proportion is 2. The eighth term is:

A - 160

B - 256

C - 640

D - 1280

Answer : C

Explanation

a =5, r = 2
∴ 8th term = a *r⁷ = (5*2⁷) =    5*128 = 640

Q 7 - The second term of a geometrical progression is 2/3 and its fifth term is 16/81. Its seventh term is:

A - 15/524

B - 1/32

C - 32/729

D - 64/729

Answer : D

Explanation

Let the G.P. be a, ar, ar2...
Then T2 =2/3 and T₅ = 16/81 ⇒ ar = 2/3 ...(i) And ar⁴= 16/81 ...(ii)
∴ar⁴/ar =16/81*3/2 = 8/27 ⇒ r3 = 8/27 ⇒ r= 2/3
Putting r =2/3 in (i), we get =a= 1.
T7 = ar⁶ = 1* (2/3)⁶ = 2⁶/3⁶ = 64/729

Q 8 - A few buys National Savings Certificates each year whose worth surpasses the earlier years buy by Rs 400. Following 8 years, she finds that she has obtained declarations whose aggregate face worth is Rs 48000. What is the face estimation of the Certificates acquired by her in the first years?

A - Rs 4300

B - Rs 4400

C - Rs 4500

D - Rs 4600

Answer : D

Explanation

Let the required value be Rs a.
Also d= 400, n = 8 and Sn = 48000.
Sn   = n/2 [2a + (n -1) d] ⇒ 8/2 *[2a + 7 *400] = 48000
⇒ 2a + 2800 = 12000⇒ 2a=9200⇒ a = 4600

Q 9 - (13 +23 + 33+...... + 153) =?

A - 900

B - 11025

C - 13400

D - 14400

Answer : D

Explanation

We know that (13+23+33+??+n3) = {n (n-1)/2)2
∴ (13+23+33+?..+153) = (15*16/2)2 = (120)2 = 14400.3


aptitude_progression.htm

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