Aptitude - Questions & Answers

Progression - Online Quiz

Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - What number of term arrives in the A.P. 7, 11, 15..... 139?

Answer : B

Explanation

Here a = 7 and d = (11-7) = 4
Let there be n terms in the given A.P. then,
Tn = 139 ⇒a+ (n-1) d =139
⇒ 7+ (n-1)*4 = 139 ⇒ (n-1) *4 = 132 ⇒ (n-1) = 33
⇒ n = 34

Q 2 - Which term of the arrangement 72+63 + 54+ ....is zero?

Answer : B

Explanation

Given series is an A.P. in which a=72 and d = (63-72)= -9
Let the nth term be 0. Then a+ (n-1) d =0 ⇒ 72+ (n-1)*(-9) = 0 ⇒ 72-9n +9 =0
⇒ 9n =81 ⇒ n = 9
∴ 9th term is the given series is 0.

Q 3 - What number between 200 and 600 are distinct by 4, 5, 6?

Answer : B

Explanation

LCM of 4, 5, 6 = 2*2*5*3 = 60
So, each one must be divisible by 60.
Requisite numbers are 240, 300, 360, 420, 480 and 540.
Their no. is 6.

Q 4 - The total 5+6+7+8+.....+19=?

Answer : C

Explanation

This is an A.P. in which a = 5, d =1 and L=19.
Let the number of its term be n. Then,
Tṇ = 19 ⇒ a + (n-1) d =19
⇒ 5 + (n-1) * 1 = 19 ⇒ (n-1) =14 ⇒ n= 15.
∴ Sṇ = n/2 * (a+L) = 15/2 *(5+19) = 180.

Q 5 - What number of odd number pages arrives in a book of 1089 pages?

Answer : C

Explanation

The pages are 1, 3, 5, 7...,1089.
This is an A.P. in which a= 1, d = (3-1) = 2 and L = 1089.
Let the number of these term be n. then,
(a+ (n-1) d = 1089 ⇒ 1 + (n - 1)* 2 = 1089 ⇒ (n-1 ) * 2 = 1088
n-1 =544⇒ n = 545.
∴ Required number of pages=545.

Q 6 - The third term of a geometrical progression is 4. The result of initial 5 terms is:

Answer : C

Explanation

Let the first term be a and common ratio r. Then ar = 4
Product of 5 first term = a* ar*ar²*ar³ *ar⁴ *= a*r⁴ = (ar²)⁵ = 4⁵

Q 7 - Three numbers are in G.P. Their whole is 28 and item is 512. The numbers are:

Answer : C

Explanation

Let the number be a/r, a, ar.
Then, a/r* a*ar = 512 ⇒ a³ =8³ ⇒ a =8
8/r+8+8r =28 ⇒ 8/r +8r =20 ⇒ 2/r+2r =5
⇒ 2r²-5r+2 =0 ⇒ 2r²-4r-r+2 =0
⇒ 2r (r-2)- (r-2)=0   ⇒ (r-2)(2r-1) =0
⇒r = 2 or r = 1/2
Numbers are 4,8, 16.

Q 8 - A whelp comprises of individuals whose ages are in A.P., the normal contrast being 3 months .If the most youthful of the club in not more than years old and the sum of the age of the considerable number of recollects is 250 years, then the no. of recall in the club is :

Answer : C

Explanation

Let the ages be 7 years, 29/4 years, 15/2 years and so on.
The ages are in A.P. in which a=7, d= 1/4 and Sn= 250
Sn = n/2[2a+ (n-1) d] ⇒ n/2 [2*7+ (n-1)*1/4] =250
⇒ n [14+ (n-1)/4] = 250
⇒ n [14+ (n-1)/4 ]=500 ⇒ n[56+(n-1) = 2000
⇒ n (n+55) = 2000 ⇒ n² +55n-2000 = 0
⇒ n²+80n -25n -2000 = 0 ⇒ n (n+80)-25 (n+80) = 0
⇒ (n+80) (n-25) = 0 ⇒ n= 25(∵ n ≠-80)
∴ Number of members in the club= 25

Q 9 - The estimation of (1³+2³+3³+? ? ..+15³) - (1+2+3+...+15) =?

Answer : C

Explanation

(1³+2³+3³+...+15³) - (1+2+3+...+15)
= (15*16/2)² -1/2 *15*16 = (120)² -120 =(14400- 120) = 14280.

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