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Progression - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : D
Explanation
Here a = 14, d = (9 - 14) = -5. ∴ T₁₂ = a + (12 -1) d = a + 11d = 14 + 11 * (-5) = -41.
Q 2 - Which term of the arrangement 72+63 + 54+ ....is zero?
Answer : B
Explanation
Given series is an A.P. in which a=72 and d = (63-72)= -9 Let the nth term be 0. Then a+ (n-1) d =0 ⇒ 72+ (n-1)*(-9) = 0 ⇒ 72-9n +9 =0 ⇒ 9n =81 ⇒ n = 9 ∴ 9th term is the given series is 0.
Q 3 - What number of products of arrive between the whole numbers 15 and 105, both comprehensive?
Answer : B
Explanation
Requisite no. are 15, 18, 21, 24, 105. Here a = 15 and d = (18-15) = 3 Let their number be n. Then, a + (n-1) d =105 ⇒ 15+ (n-1)*3 = 105 ⇒ a+ (n-1) d = 105 ⇒ 15+ (n-1)*3 = 105 ⇒ (n-1)*3 = 90 ⇒ n-1 =30 ⇒ n = 31
Answer : D
Explanation
Give series = 2 (1+2+3+4+?..+99) + 100 = 2 * 99/2 * (1+99) + 100=2* 4950 +100 = 9900 + 100 = 10000
Answer : C
Explanation
Sum = (1+3 +5+7+...to 20 terms
Here a = 1, d = (3-1) =2 and n = 20.
∴ Sṇ = n/2 {2a + (n-1) d} =20/2 *{2*1+ (20-1)*2} =10*40=400.
Answer : B
Explanation
Let Tn = 1280. Then ar (ⁿ⁻ⁱ) = 1280 ⇒ Here a= 5 and r =2 ∴ 5*2(ⁿ⁻ⁱ) =1280 ⇒256 = 2(ⁿ⁻ⁱ) =2⁸ ⇒ n-1 =8 ⇒ n= 9
Q 7 - In the event that a ≠b, Then which of the accompanying proclamations is valid?
Answer : C
Explanation
For any two unequal numbers a and b, we have (A.M).> (g.m) ∴ (a+b)/2 > √ab
Q 8 - A man orchestrates to pay off an obligation of Rs 3600 by 40 yearly portions which are in A.P. At the point when 30 of the portions are paid, he bites the dust abandoning 33% of the obligation unpaid. The estimation of the eighth portion is:
Answer : C
Explanation
Total debt = Rs 3600 to be paid in 40 installments. Debt paid = Rs (3600 * 2/3) = Rs 2400, paid in 30 Installments. Let the installments. Be a, a+d, a+2d... S₃₀ = 2400 ⇒ 30/2* [2a +(30-1) d] = 2400⇒ 2a+29d = 160.......(i) S ₄₀ = 3600 ⇒ 40/2 *[2a + (40 -1) d] = 3600 ⇒ 2a + 39d = 180......... (ii) On solving (i) and (ii) , we get d = 2 and a = 51. T₈= (a+7d) = (51 + 7 *2) = 65 ∴ 8th installments= Rs 65.
Q 9 - The number of inhabitants in microbes, society copies ever 2 minutes. How long will it take for the populace to develop from 1000 to 512000 microbes?
Answer : D
Explanation
Let the growth be 1000, 2000, 4000 ...512000. This is a G.P. in which a = 1000, r = 2 and tn = 512000 Tn = ar&n-1 ⇒ 1000*2 &n-1 = 512000⇒ 2 &n-1 = 512= 2⁹ ⇒ (n-1) = 9. ∴ Time taken = (2*9) min = 18 min.