Aptitude - Percentages Online Quiz



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Following quiz provides Multiple Choice Questions (MCQs) related to Percentages. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - 40% of 1640 + ? = 35% of 980 + 150% of 850 ?

A - 962

B - 992

C - 300

D - 452

Answer : A

Explanation

Let the unknown value is p, then
p = (35100 x 980  + 150100 x 850) - (40100 x 1640 )
p = 343 + 619 = 962

Q 2 - If 120 is 20% of a number, then 120% of that number will be?

A - 120

B - 620

C - 720

D - 20

Answer : C

Explanation

let z be the number.
Then, 20% of z = 120 i.e (20100 x z) = 120
Therefore, z = 600
120% of z = (120100 x 600) = 720

Q 3 - In a competitive examination in Zone A, 6% candidates got selected from the total appeared candidates. Zone B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each Zone?

A - 8000

B - 9000

C - 7600

D - 9800

Answer : A

Explanation

Let p be the number of candidates appeared from each zone.
Then, 7% of p - 6% of p = 80
p = 80 x 100 = 8000

Q 4 - Two tailors Rajiv and Raman are paid a total of Rs. 550 per week by their employer. If Rajiv is paid 120% of the sum paid to Raman, then how much is Raman paid per week?

A - 250

B - 342

C - 359

D - 290

Answer : A

Explanation

Let p be the sum paid to Raman per week.
Then, p + 120% of p = 550
Therefore, p = 250 after solving the above equation.
Raman is paid Rs. 250 per week.

Q 5 - In an examination, there are 3 papers and a candidate has to get 35% of the total to pass. In one paper, he gets 62 out of 150 and in the second 35 out of 150. How much must he get, out of 180 in the third paper to just qualify for a pass?

A - 62

B - 71

C - 57

D - 78

Answer : B

Explanation

Let z be the marks required.
→ 62 + 35 + x = 35% of 480
Therefore, z = 71 

Q 6 - The price of an article has been reduced by 40%. In order to restore the original price,the new price must be:

A - 200/3%

B - 200/6

C - 200/9

D - 200/8

Answer : A

Explanation

Let the original price = Rs. 100
Reduced price = Rs. 60
Increase on Rs. 60 = Rs. 40
Increase on Rs. 100 = 40/60*100%=2/3*100%=200/3%

Q 7 - In an election the losing candidate gets 20% of the votes polled is defeated by 12000 votes. The number of votes polled by winning candidate is

A - 15000

B - 15500

C - 16000

D - 16500

Answer : C

Explanation

Let the votes polled by the winning candidate be x, then
(x-12000) =20%of (x+(x-12000))
x=16000

Q 8 - 150% of 14+75% of 75 = ?

A - 2503.5

B - 2650.5

C - 2525

D - 2558.60

Answer : C

Explanation

Let his income be x, then
x-5% of x - 20% of 95% of x = 1919     0r 
x-x/20-(20*95*x)/(100*100)=1919
x=Rs.2525

Q 9 - ?% of 64 = 8

A - 10.5

B - 11.5

C - 12.5

D - 13.5

Answer : C

Explanation

Let x% of 64 = 8.  Then, (x/100*64)=8
∴ x= 8* 100/64= 25/2=12.5.

Q 10 - In a library, 40% of the books are in English, 40% of the remaining books are in Hindi, remianing books are in Oriya. If there are 4800 books in Hindi, then what is the toatl number of books in the library?

A - 12000

B - 24000

C - 28000

D - 20000

Answer : D

Explanation

Let the total number of books in the library be x.
∴ Number of books in English = 40% of x = 40/100 * x = 2x/5
Remaining books =x  2x/5 = 3x/5
Number of books in Hindi = 40% of 3x/5
= (40/100) * 3x/5
= 2/5 * 3x/5 
= 6x/25
As per question,
6x/25 = 4800
∴ x = 20000


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