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Aptitude - Percentages Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Percentages. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : A
Explanation
(0.01⁄0.1 x 100 )% = (1 x 10)% = 10%
Q 2 - If Rs. 2800 is 2⁄7 percent of the value of a car, the worth of car in Rs. is ?
Answer : D
Explanation
Let z be the worth of car.
Then, 2⁄7 of p = 2800
p = (2800x100x7⁄2) = Rs. 980000
Q 3 - Three candidates contested and election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?
Answer : B
Explanation
Total votes polled: 1136 + 7636 + 11628 = 20400 Therefore, percentage = (11628⁄20400 x 100)% = 57%
Q 4 - In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:
Answer : D
Explanation
Number of valid votes = 80⁄100 x 7500 = 6000 Valid votes polled by other candidate = (45⁄100 x 6000) = 2700
Q 5 - In a recent survey, 40% houses contained two or more people. Of those house containing only one person, 25% were having only a male. What is the percentage of all houses, which contain exactly one female and no males?
Answer : D
Explanation
Let Z be the number of houses. Therefore, number of houses having one family = (100 - 25)% of (100 - 40)% of Z = (75⁄100 x 60⁄100 x Z) Z = 45%
Q 6 - The population of a state is counted after every three years. It is found that the population each time is increased by 20% as compared to the previous count. If the population in the year 1998 was 42 lakhs, what will be the population in the year 2007 in lakhs?
Answer : B
Explanation
Since population is counted after every three years, there will be three countings between 1998 and 2007. ∴ Population in 2007 = 42(1 + 20/100)3 = 42(6/5)3 = 42 (216/125) = 72.576 lakhs
Answer : C
Explanation
It is 35/100*81 - 80/100*25=8.35
Q 8 - The estimation of a machine deteriorates at the rate of 10% for every annum. On the off chance that its present worth is Rs. 8100. What was the machine's estimation 2 years prior?
Answer : A
Explanation
Value of the machine 2 years ago
= {81000/(1-10/100)2 }=(81000*10/9*10/9)=Rs.100000
Answer : D
Explanation
Let's have 40% of x = 240. => 40/100 x = 240 => x = 240 * 10/4= 600
Q 10 - The production of company A increased by 25% from 1994 to 1995 and its production further increased by 60% from 1995 to 1996. What is the total percent increase in production from 1994 to 1996?
Answer : D
Explanation
Production in 1996 = 160/100 * 125/100 * Production on 1994
= 20000/10000 * Production on 1994
= 2 * Production on 1994
∴ Required % Increase = {(Production on 1996 - Production on 1994)/ Production on 1994}*100%
Consider, Production on 1994 = x. Then, Production on 1996 = 2x.
= (2x x)/x * 100%= 100%