Speed & Distance - Online Quiz



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Following quiz provides Multiple Choice Questions (MCQs) related to Speed & Distance. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A train goes at 82.6km/hr. What number of meters will it go in 15 minutes?

A - 20.65 m

B - 206.5 m

C - 2065 m

D - 20650 m

Answer : D

Explanation

82.6 km/hr = (82.6*5/18)m/sec = 413/18 m/sec
Distance covered in 15 min = (413/18*15 *60) m =20650 m

Q 2 - The velocities of A and B are in the proportion 3:4. A takes 20 min. more than B to achieve a destination. In what time does A achieve the destination?

A - 4/3 hrs

B - 2 hrs

C - 5/3 hrs

D - 8/3 hrs

Answer : A

Explanation

Let the time taken by A be x hrs.
Then, time taken by B = (x-20/60) hrs = (x-1/3) hrs
Ratio of speeds = inverse ratio of time taken
∴3:4 =(x- 1/3): x ⇒3x-1/3x = 3/4
⇒12x- 4 = 9x
⇒3x= 4 ⇒x= 4/3 hrs
Required time = 4/3 hrs.

Q 3 - A plane departed 30 min. later than the planned time and with a specific end goal to achieve the destination 1500 km away in time, it needed to build the pace by 250 km/hrs from the standard rate. Its standard rate is:

A - 720 km/hr

B - 730 km/hr

C - 740 km/hr

D - 750 km/hr

Answer : D

Explanation

Let the usual speed be x km/hr
1500/x - 1500/(x+250) =1/2 ⇒ 1/x - 1/(x+250) = 1/3000
⇒ (x+250)- x /x(x+250) = 1/3000  ⇒x(x+250)= 75000
⇒ x2+250 x-75000=0
⇒ x2+ 1000x- 750 x- 75000= 0
⇒x(x+1000)-750(x+1000) = 0
⇒(x+1000)(x-750)=0 ⇒x = 750
∴usual speed = 750 km/hr

Q 4 - A and B begin all the while from a sure point in North and South bearings on engine cycles. The velocity of A is 80 km/hr and that Of B is 65 km/hr. What is the separation in the middle of A and B following 12 minutes?

A - 14.5 km

B - 29 km

C - 36.2 km

D - 39 km

Answer : B

Explanation

Required distance = sum of distance covered by A and B
= {(80*12/60) + (65*12/60)} = (16+13) = 29 km

Q 5 - A strolls at a uniform rate of 4 km an hours and 4 hours after his begin, B cycles after him at the uniform rate of 10 km an hours. How a long way from the Beginning stage will B get A?

A - 16.7 kms

B - 18.6 kms

C - 21.5 kms

D - 26.7 kms

Answer : D

Explanation

Suppose B catches A after x hours. Then,
Distance travelled by A in (x+4) hr. =distance travelled by B in x hours
4(x+4) =10x⇒6x=16⇒3x=8⇒x=8/3hrs.
Distance travelled by B in 8/3 hrs= (8/3*10)km=80/3km=26.7km.

Q 6 - A quick prepare takes 3 hours not exactly the moderate train for a voyage of 600 km. On the off chance that the velocity of the moderate train is 10 km/hr not exactly the quick prepare, the pace of the moderate train is:

A - 30 km/hr

B - 35 km/hr

C - 40 km/hr

D - 45 km/hr

Answer : C

Explanation

Let the speed of the train be x km/hr and (x+10) km/hr. Then,
600/x-600/(x+10) =3⇒1/x-1/(x+10) =1/200
⇒(x+10)-x/x(x+10) =1/200⇒x2+10x-2000=0
⇒(x+50) (x-40) =0⇒x=40.
∴speed of slow train=40km/hr.

Q 7 - A bullock truck needs to cover a separation of 80 km in 10 hours. On the off chance that it covers half of the excursion in 3/5 th of the time, what ought to be its velocity to cover the remaining separation in the time left?

A - 8 km/hr

B - 6.4 km/hr

C - 10 km/hr

D - 20 km/hr

Answer : C

Explanation

Distance left = (1/2 *80) km = 40 km
Time left = {(1-3/5)*10} hrs = (2/5*10)= 4hrs.
Speed required = 40/4 km/hr = 10 km/hr

Q 8 - X and y are two stations 500 km separated. A train begins from X and moves towards Y at 20 km/hr. Another train begins from Y in the meantime and moves towards X at 30 km/hr .How a long way from X will they cross one another?

A - 300 kms

B - 200 kms

C - 120 kms

D - 40 kms

Answer : B

Explanation

Suppose they meet x km from X. then,
X/20 = (500-x)/30 = 30 x = 10000- 20 x ⇒50x = 10000 ⇒x = 200
So, they meet 200 km from X.

Q 9 - A man on visit ventures initial 160 km at 64 km/hr and the following 160 km at 80 km/hr. The normal rate for the entire excursion is:

A - 35.55 km/hr

B - 71.11 km/hr

C - 36 km/hr

D - 72 km/hr

Answer : B

Explanation

Average speed = 2xy/(x+y) km/hr = (2*64*80)/ (64+80) km/hr
=   (2*64*80)/144 km/hr = 640/9 km/hr = 71.11 km/hr

Q 10 - If the velocity of a railroad train is expanded by 5 km/hr from its ordinary pace, then it would have taken 2 hours less for a journey of 300 km. What is its ordinary velocity?

A - 30 km/hr

B - 25 km/hr

C - 20 km/hr

D - 45 km/hr

Answer : B

Explanation

Let the normal speed be x km/hr. Then
300/x - 300/(x+5) = 2 ⇒1/x - 1/(x+5) = 1/150
⇒(x+5)-x/ x(x+5) = 1/150 ⇒ x2+5x - 750 = 0
⇒x2+30x- 25x -750 = 0 ⇒x (x+30)-25(x+30) =0
⇒(x+30) (x-25) = 0 ⇒ x= 25
∴ Normal speed = 25 km/hr


aptitude_speed_distance.htm

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