- Aptitude - Home
- Aptitude - Overview
- Quantitative Aptitude
Speed & Distance - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Speed & Distance. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - A train goes at 82.6km/hr. What number of meters will it go in 15 minutes?
Answer : D
Explanation
82.6 km/hr = (82.6*5/18)m/sec = 413/18 m/sec Distance covered in 15 min = (413/18*15 *60) m =20650 m
Q 2 - A auto covers a separation of 715 km at a steady speed. On the off chance that the pace of the auto would have been 10 km/hr all the more, then it would have taken 2 hours less to cover the same separation. What is the first speed of the auto?
Answer : C
Explanation
Let the constant speed be x km/hr. Then, 715/x-715/(x+10) =2⇒1/x-1/(x+10) =2/715 ⇒(x+10)-x/x(x+10) =2/715⇒x(x+10) =3575 ⇒x2+10x-3575=0⇒x2+65x-55x-3575=0 ⇒x(x+65)-55(x+65)=0 ⇒(x+65)(x-55)=0 ⇒x=55. ∴Original speed of the car is 55km/hr.
Q 3 - Two train approach one another at 30 km/hr and 27 km/hr from two spot 342 km separated. After how long will they meet?
Answer : B
Explanation
Suppose the two trains meet after x hours. Then, 30x+27 x= 342 ⇒ 57 x = 342 ⇒ x = 342/57 = 6. So the two trains will meet after 6 hours.
Q 4 - Bombay express left Delhi for Bombay at 14.30 hours, going at a rate of 60 kmph and Rajdhani express left Delhi for Bombay around the same time at 16.30 hours, going at a pace of 80 kmph. How far from Delhi will the two trains meet?
Answer : C
Explanation
Let the train meet at a distance of x km from Delhi. Then, x/60 - x/80 = 2 ⇒ 4x-3x = 480 ⇒x = 480 ∴ required distance = 480 km
Q 5 - The velocities of three autos in the proportion 2:3:4. The proportion of the times taken by these autos to venture to every part of the same separation is:
Answer : D
Explanation
Ratio of time taken = 1/2: 1/3: 1/4 = 6:4:3
Q 6 - Two trains begin from stations A and B and travel towards one another at 50 km/hr and 60 km/hr separately. At the season of their meeting, the second prepare has voyage 120 km more than the first. The separation in the middle of A and B is:
Answer : C
Explanation
Let the two train meet after x hours . Then, 60x-50x-=120⇒ 10x =120⇒x=12hrs. Distance AB = (distance covered by slower train) + (distance covered by fast train) = [(150*12)+(60*12)]km=(600+720)km=1320km.
Q 7 - A bullock truck needs to cover a separation of 80 km in 10 hours. On the off chance that it covers half of the excursion in 3/5 th of the time, what ought to be its velocity to cover the remaining separation in the time left?
Answer : C
Explanation
Distance left = (1/2 *80) km = 40 km
Time left = {(1-3/5)*10} hrs = (2/5*10)= 4hrs.
Speed required = 40/4 km/hr = 10 km/hr
Q 8 - If a train keeps running at 40 km/hr, it achieves its destination late by 11 minutes. In any case, in the event that it keeps running at 50 km/hr, it is late by 5 minute just. The right time for the train to cover its trip, is:
Answer : C
Explanation
Let the required time be x minutes. Distance covered in (x+11) min at 40 km/hr Distance covered in (x+5) min at 50km/hr ∴(x+11)/60*(x+5)/60*50⇒4(x+11) =5(x+5) ⇒x= (44-25) =19. Hence, the required time is 19 minutes.
Q 9 - A auto covers four progressive 3 km extends at 10 km/hr, 20 km/hr, 30 km/hr and 60 km/hr separately. Its normal rate over this separation is:
Answer : B
Explanation
Total distance = (3*4) km = 12 kms Total time taken = (3/10+3/20+3/30+ 3/60) = (36+18+12+6)/120 hrs. = 72/120 hrs = 3/5 hrs. Average speed = 12/ (3/5) km/hr = (12*5)/3 = 20 km/hr
Q 10 - A agriculturist voyaged a separation of 61 km in 9 hours. He voyaged halfway by walking at 4 km/hr and incompletely on bike at 9 km/hr. The separation went by walking is:
Answer : C
Explanation
Let the distance travelled on foot be x km Then, distance covered on bicycle = (61-x) km ∴x/4 + 61-x/9 =9 ⇒ 9x+4(61-x)= 324 ⇒ 5x = (324-244)= 80 ⇒x = 16 Distance covered on foot = 16 km