Speed & Distance - Online Quiz



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Following quiz provides Multiple Choice Questions (MCQs) related to Speed & Distance. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A competitor runs 200 meters race in 24 seconds. His rate is:

A - 20 km/hr

B - 24 km/hr

C - 28.5 km/hr

D - 30 km/hr

Answer : D

Explanation

Speed = 200/24 m/sec = (200/24* 18/5) km/hr = 30 km/hr

Q 2 - The proportion between the paces of two trains is 7:8. On the off chance that the second prepare keeps running in 5 hours 400 km, the pace of the first prepare is :

A - 70 km/hr

B - 200 km/hr

C - 250 km/hr

D - 350 km/hr

Answer : A

Explanation

Let the speed of first train be 7x km/hr.
Then the speed of the second train is 8x km/hr.
But speed of the second train=400/5km/hr=80 km/hr
∴8x=80⇒x=10.
Hence the speed of first train is (7*10) km/hr=70 km/hr.

Q 3 - A auto going with 5/7 of its typical rate covers 42 km in 1 hr. 40 min. 48sec.What is the typical pace of the auto?

A - 125/7 km/hr

B - 25 km/hr

C - 30 km/hr

D - 35 km/hr

Answer : D

Explanation

Let the usual speed be x km/hr.
42/(5x/7)= 126/75 ⇒  42*7/5x = 42/25 ⇒5x = (25*7) ⇒x = (5*7) = 35

Q 4 - A and B begin all the while from a sure point in North and South bearings on engine cycles. The velocity of A is 80 km/hr and that Of B is 65 km/hr. What is the separation in the middle of A and B following 12 minutes?

A - 14.5 km

B - 29 km

C - 36.2 km

D - 39 km

Answer : B

Explanation

Required distance = sum of distance covered by A and B
= {(80*12/60) + (65*12/60)} = (16+13) = 29 km

Q 5 - A star is 8.1* 10ⁱ3km far from the earth. Assume light goes at the pace of 3.0* 10⁵ km for every second. To what extent will it take light from star to achieve the earth?

A - 7.5 * 103 hrs

B - 7.5 * 10⁴ hrs

C - 2.7 * 10ⁱ⁰ sec

D - 2.7 * 10ⁱⁱ sec

Answer : B

Explanation

(3*10⁵) km is covered in 1 sec.
(8.1 * 10ⁱ3) km is covered in (1/3 *10⁵* 8.1*10ⁱ3) sec = (2.7 *10⁸*1/60*1/60) hrs = (2.7*10⁶)/36 hrs= (2.7 *100*10⁴)/36 hrs = (7.5 *10⁴) hrs.

Q 6 - A quick prepare takes 3 hours not exactly the moderate train for a voyage of 600 km. On the off chance that the velocity of the moderate train is 10 km/hr not exactly the quick prepare, the pace of the moderate train is:

A - 30 km/hr

B - 35 km/hr

C - 40 km/hr

D - 45 km/hr

Answer : C

Explanation

Let the speed of the train be x km/hr and (x+10) km/hr. Then,
600/x-600/(x+10) =3⇒1/x-1/(x+10) =1/200
⇒(x+10)-x/x(x+10) =1/200⇒x2+10x-2000=0
⇒(x+50) (x-40) =0⇒x=40.
∴speed of slow train=40km/hr.

Q 7 - The separation between two stations A and B is 220 km. A train leaves a towards B at 80 km/hr. After thirty minutes, another train leaves B towards An at 100 km/hr. The separation of the point where the two trains meet, from A is:

A - 120 km

B - 130 km

C - 140 km

D - 150 km

Answer : A

Explanation

Let the required distance be x km. then,
x/80 - (220-x)/100 = 1/2
⇒ 5x-4 (220-x) = 200 ⇒9x = 1800 ⇒x = 120
Hence the required distance is 120 km.

Q 8 - X and y are two stations 500 km separated. A train begins from X and moves towards Y at 20 km/hr. Another train begins from Y in the meantime and moves towards X at 30 km/hr .How a long way from X will they cross one another?

A - 300 kms

B - 200 kms

C - 120 kms

D - 40 kms

Answer : B

Explanation

Suppose they meet x km from X. then,
X/20 = (500-x)/30 = 30 x = 10000- 20 x ⇒50x = 10000 ⇒x = 200
So, they meet 200 km from X.

Q 9 - The proportion between the rates of going of An and B is 2:3 and in this manner A takes 10 minute more than the time taken by B to achieve a destination. In the event that A had strolled at twofold speed, he would have secured the separation in

A - 30 min

B - 25 min

C - 20 min

D - 15 min

Answer : D

Explanation

Ratio of time taken by A and B = 1/2: 1/3
Suppose B takes x min. Then, A takes (x+10) min.
∴(x+10): x= 1/2: 1/3 = 3:2 ⇒ x+10/x = 3/2 ⇒ 2x+20 = 3x ⇒x = 20
Thus B takes 20 min. and A takes 30 min.
AT double speed A would covers it in 15 min.

Q 10 - A certain separation is secured by cyclist at a sure speed. On the off chance that a jogger covers a large portion of the separation in twofold the time, the proportion of the rate of the jogger to that of the cyclist is:

A - 1:2

B - 2:1

C - 1:4

D - 4:1

Answer : C

Explanation

Let distance = d meters and time taken by cyclist = t sec.
Speed of the cyclist = d/t m/sec.
Again, distance = d/2 meters, time taken by jogger = 2t sec.
Speed of the jogger = (d/2)/2t m/sec. = d/4t m/sec.
Ratio of speeds of jogger and cyclist = d/4t: d/t =   1/4:1 = 1:4


aptitude_speed_distance.htm

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