Speed & Distance - Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Speed & Distance. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - In what time can Somali spread a separation of 400m, in the event that she keeps running at a rate of 20 km/hr?

A - 6/5 min.

B - 3/2 min.

C - 2 min.

D - 3 min.

Answer : A

Explanation

20 km/hr = (20*5/18) m/sec =50/9m/sec.
Time taken to cover 400 m = (400*9/50) sec= 72 sec. = 6/5 min.

Q 2 - The proportion between the paces of two trains is 7:8. On the off chance that the second prepare keeps running in 5 hours 400 km, the pace of the first prepare is :

A - 70 km/hr

B - 200 km/hr

C - 250 km/hr

D - 350 km/hr

Answer : A

Explanation

Let the speed of first train be 7x km/hr.
Then the speed of the second train is 8x km/hr.
But speed of the second train=400/5km/hr=80 km/hr
∴8x=80⇒x=10.
Hence the speed of first train is (7*10) km/hr=70 km/hr.

Q 3 - A plane departed 30 min. later than the planned time and with a specific end goal to achieve the destination 1500 km away in time, it needed to build the pace by 250 km/hrs from the standard rate. Its standard rate is:

A - 720 km/hr

B - 730 km/hr

C - 740 km/hr

D - 750 km/hr

Answer : D

Explanation

Let the usual speed be x km/hr
1500/x - 1500/(x+250) =1/2 ⇒ 1/x - 1/(x+250) = 1/3000
⇒ (x+250)- x /x(x+250) = 1/3000  ⇒x(x+250)= 75000
⇒ x2+250 x-75000=0
⇒ x2+ 1000x- 750 x- 75000= 0
⇒x(x+1000)-750(x+1000) = 0
⇒(x+1000)(x-750)=0 ⇒x = 750
∴usual speed = 750 km/hr

Q 4 - A and B begin all the while from a sure point in North and South bearings on engine cycles. The velocity of A is 80 km/hr and that Of B is 65 km/hr. What is the separation in the middle of A and B following 12 minutes?

A - 14.5 km

B - 29 km

C - 36.2 km

D - 39 km

Answer : B

Explanation

Required distance = sum of distance covered by A and B
= {(80*12/60) + (65*12/60)} = (16+13) = 29 km

Q 5 - A strolls at a uniform rate of 4 km an hours and 4 hours after his begin, B cycles after him at the uniform rate of 10 km an hours. How a long way from the Beginning stage will B get A?

A - 16.7 kms

B - 18.6 kms

C - 21.5 kms

D - 26.7 kms

Answer : D

Explanation

Suppose B catches A after x hours. Then,
Distance travelled by A in (x+4) hr. =distance travelled by B in x hours
4(x+4) =10x⇒6x=16⇒3x=8⇒x=8/3hrs.
Distance travelled by B in 8/3 hrs= (8/3*10)km=80/3km=26.7km.

Q 6 - A man strolling at 3 km/hr crosses a square field corner to corner in 2 minutes. The zone of the field is:

A - 25 ares

B - 30 ares

C - 50 ares

D - 60 ares

Answer : C

Explanation

Speed =(3*5/18)m/sec. = 5/6 m/sec
Distance covered in 2 min. = (5/6* 2* 60) m = 100 m
Length of the diagonal of the square field = 100 m
Area = 1/2 * (diagonal) 2= (1/2 *100 *100 )m2= 5000 m2
= 5000/100 ares = 50 ares {1 are= 100 m2}

Q 7 - A auto ventures a separation of 840 km at a uniform pace. On the off chance that the velocity of the auto is 10 km/hr more, it takes 2 hours less to cover the same separation. The first speed of the auto was

A - 45 km/hr

B - 50 km/hr

C - 60 km/hr

D - 75 km/hr

Answer : C

Explanation

Let the original  speed be x km/hr then,
840/x-840/(x+10) = 2
⇒ 840(x+10)-840 x = 2x(x+10)
⇒2x2+20 x-8400 = 0
 ⇒x2+10x- 4200= 0
⇒(x+70) (x-60) = 0 ⇒x = 60
∴ Original speed = 60 km/hr

Q 8 - If a train keeps running at 40 km/hr, it achieves its destination late by 11 minutes. In any case, in the event that it keeps running at 50 km/hr, it is late by 5 minute just. The right time for the train to cover its trip, is:

A - 13 min

B - 15 min

C - 19 min

D - 21 min

Answer : C

Explanation

Let the required time be x minutes.
Distance covered in (x+11) min at 40 km/hr
Distance covered in (x+5) min at 50km/hr
∴(x+11)/60*(x+5)/60*50⇒4(x+11) =5(x+5) ⇒x= (44-25) =19.
Hence, the required time is 19 minutes.

Q 9 - A auto covers four progressive 3 km extends at 10 km/hr, 20 km/hr, 30 km/hr and 60 km/hr separately. Its normal rate over this separation is:

A - 10 km/hr

B - 20 km/hr

C - 25 km/hr

D - 30 km/hr

Answer : B

Explanation

Total distance = (3*4) km = 12 kms
Total time taken = (3/10+3/20+3/30+ 3/60) = (36+18+12+6)/120 hrs.
= 72/120 hrs = 3/5 hrs.
Average speed = 12/ (3/5) km/hr = (12*5)/3 = 20 km/hr

Q 10 - If the velocity of a railroad train is expanded by 5 km/hr from its ordinary pace, then it would have taken 2 hours less for a journey of 300 km. What is its ordinary velocity?

A - 30 km/hr

B - 25 km/hr

C - 20 km/hr

D - 45 km/hr

Answer : B

Explanation

Let the normal speed be x km/hr. Then
300/x - 300/(x+5) = 2 ⇒1/x - 1/(x+5) = 1/150
⇒(x+5)-x/ x(x+5) = 1/150 ⇒ x2+5x - 750 = 0
⇒x2+30x- 25x -750 = 0 ⇒x (x+30)-25(x+30) =0
⇒(x+30) (x-25) = 0 ⇒ x= 25
∴ Normal speed = 25 km/hr

aptitude_speed_distance.htm
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