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Speed & Distance - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Speed & Distance. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - A train is moving with a pace of 180 km/hr. Its rate is:
Answer : D
Explanation
180 km/hr = (180*5/18) m/sec = 50 m/sec.
Q 2 - A is twice as quick as B and B is thrice as quick as C. The excursion secured by C in 42 min. will be secured by A in
Answer : A
Explanation
Let c speed be x meters/min. Then, B speed=3x meters /min and A speed =6x meters/ min. Ratio of speed of A and C =ratio of times taken by C and A 6x:x=42:ymin⇒6x/x=42/y⇒y=42/6min=7 min.
Q 3 - By strolling at 3/4 of his standard speed, a man achieves his office 20 min. later than Normal. His standard time is:
Answer : B
Explanation
At a speed of 3/4 of the usual speed , time taken = 4/3 of usual time ∴ (4/3 of usual time) - (usual time) = 20 min. Let the usual time be x min. then, (4x/3 - x) = 20 ⇒x = 60 min. ∴usual time is 60 min.
Q 4 - Two auto begins in the meantime from one point and moves along two streets at right edges to one another. Their rates are 36 km/hr and 48 km/hr individually. After 15 sec, the contrast between them will be?
Answer : B
Explanation
36 km/hr = (36*5/18)m/sec= 10 m/sec. Distance covered in 15 sec. A= (10*15) m = 150 m 48 km/hr = (48*5/18) m/sec = 40/3 m/sec. Distance covered in 15 sec. = B = (40/3 *15) m = 200 m Distance between A and B = AB= √ (150)2+ (200)2m = √62500 m = 250 m
Q 5 - Sunil spreads a separation by strolling for 6 hours .While giving back his pace, diminishes by 1 km/hr and he takes 9 hr. to cover the same distance. What was his velocity consequently traveled?
Answer : A
Explanation
Let the speed in return journey be x km/hr. then 6(x+1) = 9x ⇒3x= 6 ⇒ x= 2 Hence, the speed in return journey is 2 km/hr
Q 6 - A thief takes an auto at 1.30 pm and drives it at 45 km/hr. the burglary is found at 2 p.m and the proprietor sets off in another auto at 50 km/hr. HE will surpass the criminal at:
Answer : B
Explanation
Distance covered by thief in 1/2 hour =20 km. Clearly, 20 km is compensated by the owner at a relative speed of 10km/hr in 2 hours. So, he overtakes the thief at 4p.m.
Q 7 - A man performs 2/15 of the aggregate adventure by rail, 9/20 by transport and the remaining 10 km on cycle. His aggregate voyage is:
Answer : D
Explanation
Let the total journey be x km. then , 2x/15+ 9x/20 +10 = X ⇒ 8x+27 x+600 = 60 x ⇒ 25x = 600 ⇒x = 24 ∴ Total journey = 24 km
Q 8 - X and y are two stations 500 km separated. A train begins from X and moves towards Y at 20 km/hr. Another train begins from Y in the meantime and moves towards X at 30 km/hr .How a long way from X will they cross one another?
Answer : B
Explanation
Suppose they meet x km from X. then, X/20 = (500-x)/30 = 30 x = 10000- 20 x ⇒50x = 10000 ⇒x = 200 So, they meet 200 km from X.
Q 9 - A man on visit ventures initial 160 km at 64 km/hr and the following 160 km at 80 km/hr. The normal rate for the entire excursion is:
Answer : B
Explanation
Average speed = 2xy/(x+y) km/hr = (2*64*80)/ (64+80) km/hr = (2*64*80)/144 km/hr = 640/9 km/hr = 71.11 km/hr
Q 10 - A certain separation is secured by cyclist at a sure speed. On the off chance that a jogger covers a large portion of the separation in twofold the time, the proportion of the rate of the jogger to that of the cyclist is:
Answer : C
Explanation
Let distance = d meters and time taken by cyclist = t sec. Speed of the cyclist = d/t m/sec. Again, distance = d/2 meters, time taken by jogger = 2t sec. Speed of the jogger = (d/2)/2t m/sec. = d/4t m/sec. Ratio of speeds of jogger and cyclist = d/4t: d/t = 1/4:1 = 1:4