Speed & Distance - Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Speed & Distance. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A competitor runs 200 meters race in 24 seconds. His rate is:

A - 20 km/hr

B - 24 km/hr

C - 28.5 km/hr

D - 30 km/hr

Answer : D

Explanation

Speed = 200/24 m/sec = (200/24* 18/5) km/hr = 30 km/hr

Q 2 - A man beginning from his home covers a separation at 15 km/hr and come back to the beginning spot at 10 km/hr. His normal velocity amid entire excursion is:

A - 11 km/hr

B - 12 km/hr

C - 25/2 km/hr

D - 13 km/hr

Answer : B

Explanation

Average speed = 2xy/(x+y) km/hr = 2*15*10/(15+10) km/hr = 12 km/hr

Q 3 - A understudy strolls from his home at 5/2 km/hr and achieves his school late by 6 min. Following day, he builds his pace by 1 km/hr and achieves a 6 min. before educational time. How far is the school from his home?

A - 5/4 km

B - 7/4 km

C - 9/4 km

D - 11/4 km

Answer : B

Explanation

Let the required distance be x km. then,
x/ (5/2) - x/ (7/2) = 12/60 (  ∵difference between two times is 12 min.)
⇒ 2x/5 - 2x/7 = 1/5   ⇒ 14 x-10 x = 7 ⇒ 4x= 7 ⇒ x= 7/4
Required distance = 7/4 km

Q 4 - Two auto begins in the meantime from one point and moves along two streets at right edges to one another. Their rates are 36 km/hr and 48 km/hr individually. After 15 sec, the contrast between them will be?

A - 150 m

B - 250 m

C - 300 m

D - 400 m

Answer : B

Explanation

36 km/hr = (36*5/18)m/sec= 10 m/sec.
Distance covered in 15 sec. A= (10*15) m = 150 m
48 km/hr = (48*5/18) m/sec = 40/3 m/sec.
Distance covered in 15 sec. = B = (40/3 *15) m = 200 m
Distance between A and B = AB= √ (150)2+ (200)2m = √62500 m = 250 m

Q 5 - Sunil spreads a separation by strolling for 6 hours .While giving back his pace, diminishes by 1 km/hr and he takes 9 hr. to cover the same distance. What was his velocity consequently traveled?

A - 2km/hr

B - 3km/hr

C - 5km/hr

D - cannot be resolved

Answer : A

Explanation

Let the speed in return journey be x km/hr. then
6(x+1) = 9x
⇒3x= 6 ⇒ x= 2
Hence, the speed in return journey is 2 km/hr

Q 6 - A constable is 114 m behind a thief. The constable runs 21 m and the thief15 m in a moment. In what the reality of the situation will become obvious eventually constable catch the criminal?

A - 16 min

B - 17 min

C - 18 min

D - 19 min

Answer : D

Explanation

(21-15) m i.e.6m is covered in 1 min.
114m will be covered in (1/6*114) min=19 min.

Q 7 - Renu began cycling along the limits of a square field ABCD from corner point A. after thirty minutes, he came to the corner point C, slantingly inverse to A. In the event that his rate was 8 km/hr, the zone of the field is:

A - 64 sq. km

B - 8 sq. km

C - 4 sq. km

D - cannot be resolved

Answer : B

Explanation

Length of diagonal = (8*1/2 )km = 4 km
Area of the field = (1/2 *4*4) sq. km = 8 sq. km

Q 8 - Two trains begin in the meantime from Aligarh and Delhi and continue towards One another at 16 km/hr and 21 km/hr individually. When they meet, it is found that one train has voyage 60 km more than the other. The separation between the two stations is:

A - 445 kms

B - 444 kms

C - 440 kms

D - 450 kms

Answer : B

Explanation

Suppose they meet after x hours. Then , 21x-16 x= 60 ⇒5x =60
⇒   x= 12
Required distance = (16*12+ 21*12) km = 444 km

Q 9 - The proportion between the rates of going of An and B is 2:3 and in this manner A takes 10 minute more than the time taken by B to achieve a destination. In the event that A had strolled at twofold speed, he would have secured the separation in

A - 30 min

B - 25 min

C - 20 min

D - 15 min

Answer : D

Explanation

Ratio of time taken by A and B = 1/2: 1/3
Suppose B takes x min. Then, A takes (x+10) min.
∴(x+10): x= 1/2: 1/3 = 3:2 ⇒ x+10/x = 3/2 ⇒ 2x+20 = 3x ⇒x = 20
Thus B takes 20 min. and A takes 30 min.
AT double speed A would covers it in 15 min.

Q 10 - A train voyaged separations of 10 km, 20 km and 30 km at rates of 50 km/hr, 60 km/hr and 90 km/hr separately. The normal rate of the train was

A - 60 km/hr

B - 66.67 km/hr

C - 69.23 km/hr

D - 65 km/hr

Answer : C

Explanation

Total distance covered = (10+20+30) km = 60 km
Total time taken = (10/50 + 20/60+ 30/90) hr = (1/5+1/3+1/3) hr = 13/15 hr.
Average speed = (60* 15/13) km/hr = (900/13) km/hr = 69.23 km/hr


aptitude_speed_distance.htm

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