# Speed & Distance - Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Speed & Distance**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

Q 1 - A train goes at 82.6km/hr. What number of meters will it go in 15 minutes?

### Answer : D

### Explanation

82.6 km/hr = (82.6*5/18)m/sec = 413/18 m/sec Distance covered in 15 min = (413/18*15 *60) m =20650 m

Q 2 - The velocities of A and B are in the proportion 3:4. A takes 20 min. more than B to achieve a destination. In what time does A achieve the destination?

### Answer : A

### Explanation

Let the time taken by A be x hrs. Then, time taken by B = (x-20/60) hrs = (x-1/3) hrs Ratio of speeds = inverse ratio of time taken ∴3:4 =(x- 1/3): x ⇒3x-1/3x = 3/4 ⇒12x- 4 = 9x ⇒3x= 4 ⇒x= 4/3 hrs Required time = 4/3 hrs.

Q 3 - A plane departed 30 min. later than the planned time and with a specific end goal to achieve the destination 1500 km away in time, it needed to build the pace by 250 km/hrs from the standard rate. Its standard rate is:

### Answer : D

### Explanation

Let the usual speed be x km/hr 1500/x - 1500/(x+250) =1/2 ⇒ 1/x - 1/(x+250) = 1/3000 ⇒ (x+250)- x /x(x+250) = 1/3000 ⇒x(x+250)= 75000 ⇒ x^{2}+250 x-75000=0 ⇒ x^{2}+ 1000x- 750 x- 75000= 0 ⇒x(x+1000)-750(x+1000) = 0 ⇒(x+1000)(x-750)=0 ⇒x = 750 ∴usual speed = 750 km/hr

Q 4 - Bombay express left Delhi for Bombay at 14.30 hours, going at a rate of 60 kmph and Rajdhani express left Delhi for Bombay around the same time at 16.30 hours, going at a pace of 80 kmph. How far from Delhi will the two trains meet?

### Answer : C

### Explanation

Let the train meet at a distance of x km from Delhi. Then, x/60 - x/80 = 2 ⇒ 4x-3x = 480 ⇒x = 480 ∴ required distance = 480 km

Q 5 - A star is 8.1* 10ⁱ^{3}km far from the earth. Assume light goes at the pace of 3.0* 10⁵ km for every second. To what extent will it take light from star to achieve the earth?

### Answer : B

### Explanation

(3*10⁵) km is covered in 1 sec. (8.1 * 10ⁱ^{3}) km is covered in (1/3 *10⁵* 8.1*10ⁱ^{3}) sec = (2.7 *10⁸*1/60*1/60) hrs = (2.7*10⁶)/36 hrs= (2.7 *100*10⁴)/36 hrs = (7.5 *10⁴) hrs.

Q 6 - By what amount of percent must a driver expand his pace so as to lessen the time by 20%, taken to cover a sure separation?

### Answer : B

### Explanation

Distance= (time*speed) =t*x. Let the required increase in speed be p%. Then, (80%of t)*(100+p)/100=x=t*x ⇒80/100*t*(100+p)/100*x=t*x⇒4 (100+p/500=1⇒4p=100⇒p=25. ∴Required increase in speed=25%.

Q 7 - Renu began cycling along the limits of a square field ABCD from corner point A. after thirty minutes, he came to the corner point C, slantingly inverse to A. In the event that his rate was 8 km/hr, the zone of the field is:

### Answer : B

### Explanation

Length of diagonal = (8*1/2 )km = 4 km Area of the field = (1/2 *4*4) sq. km = 8 sq. km

Q 8 - Laxman needs to cover 6 km in 45 minutes. On the off chance that he covers one portion of the separation in 2/3 rd time, what ought to be his rate to cover the remaining separation in the remaining time?

### Answer : A

### Explanation

Time left = (1/3*45/60)hr = 1/4 hr, distance left = 3 km Speed required = 3/ (1/4) km/hr = 12 km/hr

Q 9 - The proportion between the rates of going of An and B is 2:3 and in this manner A takes 10 minute more than the time taken by B to achieve a destination. In the event that A had strolled at twofold speed, he would have secured the separation in

### Answer : D

### Explanation

Ratio of time taken by A and B = 1/2: 1/3 Suppose B takes x min. Then, A takes (x+10) min. ∴(x+10): x= 1/2: 1/3 = 3:2 ⇒ x+10/x = 3/2 ⇒ 2x+20 = 3x ⇒x = 20 Thus B takes 20 min. and A takes 30 min. AT double speed A would covers it in 15 min.

Q 10 - Sweta runs 9 km at a pace of 6 km/hr. At what pace would she have to go amid the following 1.5 hours to have a normal velocity of 9 km/hr for the whole running session?

### Answer : C

### Explanation

Time taken to cover 9 km = 9/6 hrs. = 1.5 hrs Total time taken = (1.5 +1.5) hrs = 3 hrs. Total distance covered in 3 hrs = (9*3) = 27 km In 1.5 hrs, distance covered = (27-9) km = 18 km Required speed = 18/ (3/2) km/hr = (18*2/3) km/hr = 12 km/hr