Speed & Distance - Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Speed & Distance. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - A train goes at 82.6km/hr. What number of meters will it go in 15 minutes?

A - 20.65 m

B - 206.5 m

C - 2065 m

D - 20650 m

Answer : D

Explanation

82.6 km/hr = (82.6*5/18)m/sec = 413/18 m/sec
Distance covered in 15 min = (413/18*15 *60) m =20650 m

Q 2 - The velocities of A and B are in the proportion 3:4. A takes 20 min. more than B to achieve a destination. In what time does A achieve the destination?

A - 4/3 hrs

B - 2 hrs

C - 5/3 hrs

D - 8/3 hrs

Answer : A

Explanation

Let the time taken by A be x hrs.
Then, time taken by B = (x-20/60) hrs = (x-1/3) hrs
Ratio of speeds = inverse ratio of time taken
∴3:4 =(x- 1/3): x ⇒3x-1/3x = 3/4
⇒12x- 4 = 9x
⇒3x= 4 ⇒x= 4/3 hrs
Required time = 4/3 hrs.

Q 3 - A plane departed 30 min. later than the planned time and with a specific end goal to achieve the destination 1500 km away in time, it needed to build the pace by 250 km/hrs from the standard rate. Its standard rate is:

A - 720 km/hr

B - 730 km/hr

C - 740 km/hr

D - 750 km/hr

Answer : D

Explanation

Let the usual speed be x km/hr
1500/x - 1500/(x+250) =1/2 ⇒ 1/x - 1/(x+250) = 1/3000
⇒ (x+250)- x /x(x+250) = 1/3000  ⇒x(x+250)= 75000
⇒ x2+250 x-75000=0
⇒ x2+ 1000x- 750 x- 75000= 0
⇒x(x+1000)-750(x+1000) = 0
⇒(x+1000)(x-750)=0 ⇒x = 750
∴usual speed = 750 km/hr

Q 4 - Bombay express left Delhi for Bombay at 14.30 hours, going at a rate of 60 kmph and Rajdhani express left Delhi for Bombay around the same time at 16.30 hours, going at a pace of 80 kmph. How far from Delhi will the two trains meet?

A - 120 km

B - 360 km

C - 480 km

D - 500 km

Answer : C

Explanation

Let the train meet at a distance of x km from Delhi. Then,
x/60 - x/80 = 2 ⇒ 4x-3x = 480 ⇒x = 480
∴ required distance = 480 km

Q 5 - A star is 8.1* 10ⁱ3km far from the earth. Assume light goes at the pace of 3.0* 10⁵ km for every second. To what extent will it take light from star to achieve the earth?

A - 7.5 * 103 hrs

B - 7.5 * 10⁴ hrs

C - 2.7 * 10ⁱ⁰ sec

D - 2.7 * 10ⁱⁱ sec

Answer : B

Explanation

(3*10⁵) km is covered in 1 sec.
(8.1 * 10ⁱ3) km is covered in (1/3 *10⁵* 8.1*10ⁱ3) sec = (2.7 *10⁸*1/60*1/60) hrs = (2.7*10⁶)/36 hrs= (2.7 *100*10⁴)/36 hrs = (7.5 *10⁴) hrs.

Q 6 - By what amount of percent must a driver expand his pace so as to lessen the time by 20%, taken to cover a sure separation?

A - 20%

B - 25%

C - 30%

D - none of these

Answer : B

Explanation

Distance= (time*speed) =t*x.
Let the required increase in speed be p%. Then,
(80%of t)*(100+p)/100=x=t*x
⇒80/100*t*(100+p)/100*x=t*x⇒4 (100+p/500=1⇒4p=100⇒p=25.
∴Required increase in speed=25%.

Q 7 - Renu began cycling along the limits of a square field ABCD from corner point A. after thirty minutes, he came to the corner point C, slantingly inverse to A. In the event that his rate was 8 km/hr, the zone of the field is:

A - 64 sq. km

B - 8 sq. km

C - 4 sq. km

D - cannot be resolved

Answer : B

Explanation

Length of diagonal = (8*1/2 )km = 4 km
Area of the field = (1/2 *4*4) sq. km = 8 sq. km

Q 8 - Laxman needs to cover 6 km in 45 minutes. On the off chance that he covers one portion of the separation in 2/3 rd time, what ought to be his rate to cover the remaining separation in the remaining time?

A - 12 km/hr

B - 16 km/hr

C - 8 km/hr

D - 6 km/hr

Answer : A

Explanation

Time left = (1/3*45/60)hr = 1/4 hr, distance left = 3 km
Speed required = 3/ (1/4) km/hr = 12 km/hr

Q 9 - The proportion between the rates of going of An and B is 2:3 and in this manner A takes 10 minute more than the time taken by B to achieve a destination. In the event that A had strolled at twofold speed, he would have secured the separation in

A - 30 min

B - 25 min

C - 20 min

D - 15 min

Answer : D

Explanation

Ratio of time taken by A and B = 1/2: 1/3
Suppose B takes x min. Then, A takes (x+10) min.
∴(x+10): x= 1/2: 1/3 = 3:2 ⇒ x+10/x = 3/2 ⇒ 2x+20 = 3x ⇒x = 20
Thus B takes 20 min. and A takes 30 min.
AT double speed A would covers it in 15 min.

Q 10 - Sweta runs 9 km at a pace of 6 km/hr. At what pace would she have to go amid the following 1.5 hours to have a normal velocity of 9 km/hr for the whole running session?

A - 9 km/hr

B - 10 km/hr

C - 12 km/hr

D - 14 km/hr

Answer : C

Explanation

Time taken to cover 9 km = 9/6 hrs. = 1.5 hrs
Total time taken = (1.5 +1.5) hrs = 3 hrs.
Total distance covered in 3 hrs = (9*3) = 27 km
In 1.5 hrs, distance covered = (27-9) km = 18 km
Required speed = 18/ (3/2) km/hr = (18*2/3) km/hr = 12 km/hr


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