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Speed & Distance - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Speed & Distance. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - In what time can Somali spread a separation of 400m, in the event that she keeps running at a rate of 20 km/hr?
Answer : A
Explanation
20 km/hr = (20*5/18) m/sec =50/9m/sec. Time taken to cover 400 m = (400*9/50) sec= 72 sec. = 6/5 min.
Q 2 - A is twice as quick as B and B is thrice as quick as C. The excursion secured by C in 42 min. will be secured by A in
Answer : A
Explanation
Let c speed be x meters/min. Then, B speed=3x meters /min and A speed =6x meters/ min. Ratio of speed of A and C =ratio of times taken by C and A 6x:x=42:ymin⇒6x/x=42/y⇒y=42/6min=7 min.
Q 3 - Two train approach one another at 30 km/hr and 27 km/hr from two spot 342 km separated. After how long will they meet?
Answer : B
Explanation
Suppose the two trains meet after x hours. Then, 30x+27 x= 342 ⇒ 57 x = 342 ⇒ x = 342/57 = 6. So the two trains will meet after 6 hours.
Q 4 - A train secured a separation at a uniform velocity. On the off chance that the train had been 6 km/hr speedier, it would have taken 4 hours not exactly the booked time, and if the train were slower by 6 km/hr, the train would have taken 6 hours more than the planned time. The length of the trip is?
Answer : B
Explanation
Let the required distance be x km and uniform speed by y km/hr x/y - x/(y+6) = 4 ...(a) x/(y-6) - x/y = 6 ...(b) ⇒xy+6x-xy = 4y (y+6) and xy - xy +6x = 6y (y-6) ⇒4y2+24 y - 6x = 0 and 6y2- 36y - 6x = 0 ⇒2y2- 60 y = 0 ⇒ 2y (y-30) = 0 ⇒y = 30 ∴x/30 - x/36 = 4 ⇒6x- 5x = 720 ⇒x = 720 km
Q 5 - Sunil spreads a separation by strolling for 6 hours .While giving back his pace, diminishes by 1 km/hr and he takes 9 hr. to cover the same distance. What was his velocity consequently traveled?
Answer : A
Explanation
Let the speed in return journey be x km/hr. then 6(x+1) = 9x ⇒3x= 6 ⇒ x= 2 Hence, the speed in return journey is 2 km/hr
Q 6 - A man strolling at 3 km/hr crosses a square field corner to corner in 2 minutes. The zone of the field is:
Answer : C
Explanation
Speed =(3*5/18)m/sec. = 5/6 m/sec
Distance covered in 2 min. = (5/6* 2* 60) m = 100 m
Length of the diagonal of the square field = 100 m
Area = 1/2 * (diagonal) 2= (1/2 *100 *100 )m2= 5000 m2
= 5000/100 ares = 50 ares {1 are= 100 m2}
Q 7 - The separation between two stations A and B is 220 km. A train leaves a towards B at 80 km/hr. After thirty minutes, another train leaves B towards An at 100 km/hr. The separation of the point where the two trains meet, from A is:
Answer : A
Explanation
Let the required distance be x km. then, x/80 - (220-x)/100 = 1/2 ⇒ 5x-4 (220-x) = 200 ⇒9x = 1800 ⇒x = 120 Hence the required distance is 120 km.
Q 8 - X and y are two stations 500 km separated. A train begins from X and moves towards Y at 20 km/hr. Another train begins from Y in the meantime and moves towards X at 30 km/hr .How a long way from X will they cross one another?
Answer : B
Explanation
Suppose they meet x km from X. then, X/20 = (500-x)/30 = 30 x = 10000- 20 x ⇒50x = 10000 ⇒x = 200 So, they meet 200 km from X.
Q 9 - Excluding stoppages, the velocity of a transport is 54 km/hr and including stoppages, it is 45 km/hr. For how long does the transport stop every hour?
Answer : B
Explanation
Due to stoppage, it covers 9 km less per hour. Time taken to cover 9 km = (9/54*60) min. = 10 min.
Q 10 - A train without stoppages goes at the rate of 50 km/hr and with stoppages it goes at 45 km/hr. How long does the train stop on a normal for every hour?
Answer : B
Explanation
Due to stoppage it covers 5 km less per hour. Time taken to cover 5 km= (5/50*60) min. = 6 min. Hence, the train stops on an average 6 min/hr.