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Aptitude - Time & Work Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Simple Interest. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - Kamal can do a work in 15 days. Bimal is half more proficient than kamala. The no. of days, Bimal will take to do likewise bit of work, is
Answer : A
Explanation
Kamal 1 day work=1/5. Bimal 1 days work=150% of 1/15=150/100*1/15 =1/10. ∴Bimal can finish the work in 10 days.
Q 2 - A can do a work in 4 days, B can do it in 5 days and C can do it in 10 days. A, B and C together can take the necessary steps in
Answer : B
Explanation
A 1 days work=1/4, B 1 days work=1/5 and C 1 days work=1/10. (A+B+C) 1 days work= (1/4+1/5+1/10) = (5+4+2)/2=11/20. ∴A, B, C together can do it in 20/11 days,i.e.20/11days.
Q 3 - A can do 1/3 of a work in 5 days and B can do 2/5 of the work in 10 days. In how long both A and B together can take the necessary steps?
Answer : C
Explanation
1/3 work is done by A in 5 days. Whole work will be done by A in 15 days. 2/5 work is done by B in 10 days. Whole work will be done by B in (10*5/2) day?s i.e 25 days (A+B) 's 1 days work = (1/15+1/25) = 8/75 ∴A and B can do the work in 75/8 days
Q 4 - A and B can complete a bit of work in 30 days. They began at it for 20 days and after that B left. The remaining work was finished by An alone in 20 more days. An alone can complete the work in
Answer : D
Explanation
Work done by (A+B) in 20 days = (1/30*20) = 2/3 ; remaining work = (1- 2/3 )= 1/3 1/3 work is done by B in 20 days. Whole work is done by A in (20*3) = 60 days
Q 5 - A certain no. of men finishes a bit of work in 60 days. On the off chance that there were 8 men more work could be done in 10 days less. What number of men arrived initially?
Answer : B
Explanation
Let there be x men originally. X man finish the work in 60 days and (x+8) finish it in 50 days. X man finish the job in 60 days. ⇒ 1 man can finish it in 50 (x+8) days. ∴ 60 x = 50(X+80 ⇒10 x= 400 ⇒x = 40 Hence, there were 40 men originally.
Q 6 - 8 men can delve a pit in 20 days. On the off chance that a man works half double as a kid then 4 men and 9 kids can delve a comparable pit in:
Answer : D
Explanation
1 man = 3/2 boys , 8 men = (8*3/2) boys = 12 boys (4men + 9 boys) = (4*3/2 +9) boys = 15 boys Now, 12 boys dig it in 20 days. 1 boy digs it in (20*12) days. 15 boys will dig it in (20*12)/15 days = 16 days
Q 7 - If 5 men or 9 ladies can complete a bit of work in 19 days, 3 men and 6 ladies will do likewise work in
Answer : D
Explanation
5 men 1 day work = 1/19 ⇒ 1 man's 1 day work = 1/95 9 women 1 day work = 1/19 ⇒1 women 1 day work = 1/171 (3 men + 6 women) 1 day work = (3/95 + 6/171) = (27+30)/855 = 57/ 855 = 1/15 ∴ 3 men and 6 women can finish the work in 15 days.
Q 8 - If 12 man and 16 young men can do a bit of work in 5 days ; 13 man and 24 young men can do it in 4 days , then the proportion of the everyday work done by a men to that of a kid is:
Answer : A
Explanation
Let 1 men 1 day work be x and 1 boy 1 day work be y. Then 12x + 16 y = 1/5 ... (.1) 13x +24 y = 1/4 ... (2) Multiplying (1) by 3 and (2) by 2 and subtracting, we get 10 x= (3/5- 1/2) = 1/10 ⇒x = 1/100 Putting x = 1/100 in (1), we get 16 y = (1/5- 12/100) = 8/100 ⇒y = 1/200 Required ratio = 1/100: 1/200 = 2:1
Q 9 - A can do 1/4th some portion of the work in 10 days, B can do 40% of the work in 40 days and C can do 1/3 rd of the work in 13 days. Who will finish the work first?
Answer : C
Explanation
1/4th of the work is done by A in 10 days. Whole work will be done by A in (10*4/1) = 40 days 40/100 of the work is done by B in 40 days. Whole work will be done by B in (40*5/2) = 100 days 1/3 of the work is done by C in 13 days. Whole work will be done by C in (13*3/1) = 39 days Hence, C will complete the work first.
Q 10 - A works twice as quick as B. On the off chance that the two can together complete a bit of work in 12 days, then B alone can do it in
Answer : C
Explanation
Let B 1 day work =x. Then , A 1 days work=2x X+2x=1/12⇒3x=1/12⇒x=1/36. B 1 day work=1/36. Hence B alone can finish the work in 36 days.