Aptitude - Time & Work Online Quiz


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Following quiz provides Multiple Choice Questions (MCQs) related to Simple Interest. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - Kamal can do a work in 15 days. Bimal is half more proficient than kamala. The no. of days, Bimal will take to do likewise bit of work, is

A - 10

B - 21/2

C - 12

D - 14

Answer : A

Explanation

Kamal 1 day work=1/5.
Bimal 1 days work=150% of 1/15=150/100*1/15 =1/10.
∴Bimal can finish the work in 10 days.

Q 2 - A and B can do a bit of work in 12 days. B and C can do it in 15 days and C and A can do it in 20 days. An alone can take every necessary step in:

A - 42/3 days

B - 24 days

C - 30 days

D - 40 days

Answer : C

Explanation

(A+B)'s 1 day work = 1/12 ; (B+C) 's 1 day work  = 1/15 ;  (C+A) 's 1 day work = 1/20
2(A+B+C) 's 1 day work = (1/12+ 1/15+ 1/20) = (5+4+3)/60 = 12/60 = 1/5
∴ (A+B+C) 1 day work = 1/10
⇒A 's 1 day work = (1/10- 1/15) = 1/30
⇒A alone can do this work in 30 days.

Q 3 - A and B together can finish a work in 3 days. They begin together. In any case, following 2 days, B left the work. In the event that the work is finished following 2 more days, B alone could take every necessary step in

A - 5 days

B - 6 days

C - 9 days

D - 10 days

Answer : B

Explanation

(A+B)'s 2 day work = (1/3*2)= 2/3 A's 2 days work = (1- 2/3) = 1/3 B's 2 days work = (2/3- 1/3) = 1/3 B's 1 day work = 1/6 ∴ B alone can finish the work in 6 days.

Q 4 - A can do a bit of work in 14 days which B can alone do in 21 days. They start together however 3 days before the fruition of the work, A leaves off. The aggregate no. of days for the work to be finished is

A - 33/5 days

B - 17/2 days

C - 51/5 days

D - 27/2 days

Answer : C

Explanation

B's 3 days work = (3*1/21)= 1/7 ; Remaining work = (1-1/7) = 6/7
   (A+B)'s 1 day?s work = (1/14+ 1/21) = 5/42
5/42 work is finished by (A+B) in 1 day.
6/7 work is finished by (A+B) in (42/5 * 6/7) days = 36/5 days
 Total no. of days = (3+36/5) = 51/5 days.

Q 5 - A certain no. of men finishes a bit of work in 60 days. On the off chance that there were 8 men more work could be done in 10 days less. What number of men arrived initially?

A - 30

B - 40

C - 32

D - 36

Answer : B

Explanation

Let there be x men originally.
X man finish the work in 60 days and (x+8) finish it in 50 days.
X man finish the job in 60 days.
⇒ 1 man can finish it in 50 (x+8) days.
∴ 60 x = 50(X+80 ⇒10 x= 400 ⇒x = 40
Hence, there were 40 men originally.

Q 6 - 9 youngsters can finish a bit of work in 360 days. 18 men can finish the same work of piece in 72 days and 12 ladies can finish it in 162 days. In how long can 4 men, 12 ladies and 10 kids together finish the bit of work?

A - 68 days

B - 81 days

C - 96 days

D - 124 days

Answer : B

Explanation

9 children 1 day work = 1/360 ⇒1 child 1 day work = 1/3240
18 man 1 day work = 1/72 ⇒1 man 1 day work = 1/1296
12 women 1 day work = 1/162 ⇒1 women 1 day work = 1/1944
(4men +12 women +10 children) 1 day work = (4/1296+ 12/1944+10/3240)
= (1/324+1/162+1/324) = 4/324 = 1/81
Hence they can finish the work in 81 days.

Q 7 - If 1 men or 2 ladies or 3 kid can do a bit of work in 44 days , then the same bit of work will be finished by 1 men , 1 ladies and 1 kid in

A - 21 days

B - 24 days

C - 26 days

D - 33 days

Answer : B

Explanation

1 man 's 1 day work = 1/44 , 2 women?s  1 day  work =  1/44
∴ 1 women 1 day work = 1/88
3 boys 1 day's work = 1/44 ⇒1 boys 1 day work = 1/132
(1 man + 1 women + 1 boy)'s 1 day work =  (1/44+ 1/88+1/132 )= (6+3+2)/264
= 11/264 = 1/24
∴ 1 man+ 1 women + 1 boy's can finish this work in 24 days.

Q 8 - If 12 man and 16 young men can do a bit of work in 5 days ; 13 man and 24 young men can do it in 4 days , then the proportion of the everyday work done by a men to that of a kid is:

A - 2:1

B - 3:1

C - 3:2

D - 5:4

Answer : A

Explanation

Let 1 men 1 day work be x and 1 boy 1 day work be y.
Then 12x + 16 y = 1/5 ... (.1) 13x +24 y = 1/4 ... (2)
Multiplying (1) by 3 and (2) by 2 and subtracting, we get
10 x= (3/5- 1/2) = 1/10 ⇒x = 1/100
Putting x = 1/100 in (1), we get 16 y = (1/5- 12/100) = 8/100 ⇒y = 1/200
Required ratio = 1/100: 1/200 = 2:1

Q 9 - A can develop 2/fifth of the area in 6 days and B can develop 1/third of the area in 10 days. Cooperating A and B can develop 4/fifth of the area in

A - 4 days

B - 5 days

C - 8 days

D - 10 days

Answer : C

Explanation

2/5th of the land is cultivated by A in 6 days.
Whole land is cultivated by A in (6*5/2) days = 15 days
1/3 rd of the land is cultivated by B in 10 days.
Whole land is cultivated by B in (10*3) = 30 days
(A+B)'s 1 days work = (1/15+ 1/30) = 3/30 = 1/10
Whole land is cultivated by both in 10 days.
4/5th land is cultivated by both in (10*4/5) = 8 days

Q 10 - 10 ladies can finish a work in 7 days and 10 youngsters take 14 days to finish the work. How long will 5 ladies and 10 kids take to finish the work?

A - 3

B - 5

C - 7

D - none of these

Answer : C

Explanation

10 woman 1 day work =1/7⇒1 woman 1 day work =1/70.
10 children 1 day work =1/14⇒1 child 1 day work=1/140.
(5 woman +10children) 1 days work= (5*1/70+10*1/140) = (1/14+1/14) =2/14=1/7.
∴5 woman and 10 children will finish the work in 7 days.


aptitude_time_work.htm

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