Simplification - Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Simplification. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - 2567 / 17 * 3 = ? + 180

A - 51

B - 73

C - 271

D - 273

Answer : D

Explanation

let 2567 / 17 * 3 = x + 180 . Then,
2567 * 1/17 * 3 = x +  180 ⇒ x = (151 * 3 ) - 180 = (453 - 180) = 273

Q 2 - (11/4) / (8/3) / (13/12) = ?

A - 13/16

B - 5/4

C - 169/144

D - None of these

Answer : D

Explanation

given exp. =   (11/4)  / (8/3) / (13/12) = 11/4 *3/8 *12/13 = 99/104

Q 3 - 998996/999 * 999 = ?

A - 990809

B - 998996

C - 998999

D - 999824

Answer : B

Explanation

given exp= (1000-4/ 999)*999 = (999000-4 )= 998996

Q 4 - [8/7-2/3+2/5 /(1- 1/25)]/[1- 1/7 {1/3+2/5 /(1- 2/5 )] = ?

A - 3/4

B - 24/25

C - 1

D - 25/24

Answer : D

Explanation

given exp. = [8/7- 2/3+ (2/50/(24/25)]/[1- 1/7 {1/3+ (2/5)/(3/5)}] = [8/7 -2/3 +(2/5*25/24)]/[1-1/7 {1/3+2/3}]
= [8/7- 2/3+5/12]/[1-1/7*1]= [(96-56+35)/84]/[6/7] =(75/84*7/6) = 25/24

Q 5 - 3/2 /1+1/(1+1/4)= ?

A - 5/4

B - 3/2

C - 5/6

D - 1

Answer : C

Explanation

given exp. = (3/2) / 1+ 1(/5/4)
=  (3/2)/ (1+4/5)
= (3/2) /(9/5)
= ( 3/2 * 5/9)
= 5/6  

Q 6 - 1/ (1*2) + 1/ (2*3) + 1/ (3*4) +??+ 1/ (100* 101 ) = ?

A - 1/100

B - 100/101

C - 101/102

D - 99/10

Answer : B

Explanation

given exp. =  (1-1/2 )+ (1/2 -1/3)+ (1/3 -1/4)+???.+(1/100- 1/101) = (1- 1/100) = 100/101

Q 7 - if a/b = 3/4 and 8a +5b = 22 , then a = ?

A - 2/3

B - 3/2

C - 5/8

D - none of these

Answer : B

Explanation

a/b = 3/4 ⇒ 3b = 4a ⇒ b = 4a / 3.
∴  8a + 5b = 22 =.> 8a+ 5* 4a/3 =22
⇒ 24a+20a =66 ⇒ 44a= 66  ⇒ a = 3/2

Q 8 - if 2a +b = 5 and 3a -4b = 2, then ab = ?

A - 4

B - 5

C - 2

D - 3

Answer : C

Explanation

on solving 2a+b =5 and 3a-4b =2 , we get a =2, b=1
∴ ab = (2*1) = 2

Q 9 - if a +b+c = 11 and ab+ bc + ca = 20 , then what should be the value of (a3+b3+c3-3abc) = ?

A - 121

B - 341

C - 671

D - 781

Answer : C

Explanation

(a3+b3+c3- 3abc) = (a+b+c)
(a2+b2+c2-ab- bc-ca)
=  (a+b+c)[ (a+b+c)2 - 3(ab+bc+ca)]  = [ 11* (11) -3*20]
=  11* (121-60) = 11*61 = 671

Q 10 - If in a examination condition of marks is that for the right answer student gets 3 marks but reduce 2 marks for every wrong answer . if 30 questions attempted and 40 marks gets by the student. Find out the number of question correctly done by the student.

A - 19

B - 20

C - 21

D - 22

Answer : B

Explanation

Let correctly attempted questions be x. Then ,
3x-2 (30-x) = 40 ⇒  5x = 100  ⇒ x = 20.
Hence, 20 question  correctly done by  the  student.
aptitude_simplification.htm
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