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This section presents you various set of Mock Tests related to Aptitude. You can download these sample mock tests at your local machine and solve offline at your convenience. Every mock test is supplied with a mock test key to let you verify the final score and grade yourself.

Aptitude Mock Test II

Q 1 - A vendor bought toffees at 8 for one rupee. How many for a rupee must he sell to gain 25%?

Answer : D

Explanation

C.P. of 8 toffees = Re. 1
S.P. of 8 toffees = 125% of Re. 1 = Rs 1.25=5/4
For Rs5/4 toffees sold = 8.
For Re. 1, toffees sold =8x( 5)/( 4)=10.

Q 2 - If the cost price is 80% of the selling price, then what is the profit percent?

Answer : A

Explanation

Let the SP be 100 => CP=80
Profit % =(100-80)/80 x100=25%

Q 3 - If books bought at prices ranging from Rs.150 to Rs.250 are sold at prices ranging from Rs.225 to Rs.325, what is the greatest possible profit that might be made in selling 6 books?

Answer : D

Explanation

Let us consider all the six books are bought at least cost
150 x 6 = 900
Selling at the highest price
325 x 6 = 1950
∴ Profit = selling price ? cost price
=1950 - 900 = 1050

Q 4 - The month to month pay of An and B are in the proportion 2:3 and their month to month costs are in the proportion 6:9. On the off chance that each of them recovery 600 rs for every month, then their month to month wage?

Answer : C

Explanation

Let the incomes of A and B be Rs 2x and Rs 3x respectively and their Expenditures are Rs 5y and Rs 9y respectively. Then,
  2x-5y=600 ...  (i) and  3x-9y=600
=> x- 3y=200 ...  (ii) 
On solving (i) and   (ii) ,  we  get  x =800.
So, their incomes are Rs.1600 and Rs.2400 respectively.

Q 5 - If 32 understudies In a class are females and the proportion of females to guys understudy is 16:9 , then what % of the class is females ?

Answer : D

Explanation

Let the females be16x and males 9x .
Then, 16 x = 32  
=> x=2
 So, there are 32 females and 18 males in the class. 
 Percentage of females = {32/50*100)% = 64 %

Q 6 - In a class, the no. of young women is 20% more than that of the young fellows. The class' quality is 66. If 4 more young women are admitted to the class, what will be the no's extent of young fellows to that of the young women?

Answer : C

Explanation

Let the number of boys be x.
Then the no. of girls = 120% of x = (120/100 *X)= 6X/5 .
X+6x/5 =66 
=> 5x+6x=330
 => 11x= 330  
=> x= 3
 Now, the no. of boys= 30 , no. of girls =[6/5*30 +4]=40
 Now the ratio of boys and girls = 30/40 = 3/4 =3:4

Q 7 - Two no. are in the extent of 3:5 . If each no. is extended by 10, the extent gets the opportunity to be 5:7 , the no. are?

Answer : D

Explanation

Let the numbers be 3x and 5x then,
(3x+10 ) / (5x+10)= 5/7
=> 7 ( 3x+10)= 5 (5x+10)
=> 4x= (70-50) =20
=> x =5
∴ The numbers are (3*5) and (5*5) , 15 and 25

Q 8 - Two no. are in the extent 3/2 :8/3, when each of these are extended by 15 , their extent gets the chance to be 5/3 :5/2 . The greater of the no. is :

Answer : C

Explanation

Ratio of the given numbers = 3/2:8/3 = 9 :16
Let the numbers be 9x and 16 x, Then,
 (9x+15)/ (16 x+15) = (5/3)/ (5/2) =2/3
=>  3(9x+15)= 2 (16x+15)
=>  5x= 15  =x= 3.
 ∴ Larger no.= (16*3)= 48

Q 9 - In an extent which is proportionate to 5:8 , if the harbinger is 40, then the subsequent is :

Answer : B

Explanation

Let the consequent be X. Then,
 5/8 =40/x
=>  5x=8*40
=>  x=64
∴ Consequent is 64.

Q 10 - What must be added to each term of the extent 7:13 so that the extent gets the chance to be 2:3 ?

Answer : D

Explanation

Let the number to be added be X. Then,
7+x/13+x= 2/3  
=> 3(7+X)=2(13+x)
 => X= (26-21)= 5
∴ number to be added = 5.

Q 11 - x is 7 times large as Y. The percent that Y is less then x is

Answer : C

Explanation

x=7Y .Thus, Y is less than x  by 6Y
=> Y is less x by 6Y/7Y*100=600/7%

Q 12 - 15% of 180 = 50% of?

Answer : D

Explanation

Let 15% of 180=50% of x
Then 15/100*180=50/100*x
=>x=54

Q 13 - By how much is 35 % of 81 is greater then 80% of 25.

Answer : C

Explanation

It is 35/100*81  -  80/100*25=8.35

Q 14 - 50% of a number when added to 50, is equal to a number .the number is

Answer : A

Explanation

50 + 50% of x =x
x - 1/2x = 50
x=100

Q 15 - What will be 90 % of a number whose 200% is 300?

Answer : A

Explanation

200% of x = 300,=>x=150
90% of 150=135

Q 16 - 5358 x 51 = y. What is y?

Answer : B

Explanation

  y =5358 x 51  =5358 x (50 + 1)  =5358 x 50 + 5358  =267900 + 5358  =273258

Q 17 - 1024 x 976 = y. What is y?

Answer : C

Explanation

  y =1024 x 976  = (1000 + 24) x (1000 - 24)  Now using formula (a+b)(a-b)=a²-b²  y = (1000)² - (24)²  = 1000000 - 576  = 999424

Q 18 - 587 x 999 = y. What is y?

Answer : A

Explanation

  y = 587 x 999   = 587 x (1000 - 1)  = 587 x 1000 - 587  = 587000 - 587  = 586413

Q 19 - 496157 x 9999 = y. What is y?

Answer : B

Explanation

  y = 496157 x 9999    = 496157 x (10000 - 1)   = 496157 x 10000 - 496157   = 4961570000 - 496157   = 4691100843

Q 20 - 935421 x 625 = y. What is y?

Answer : C

Explanation

  y = 935421 x 625  = 935421 x (5)⁴  = 935421 x (10/2)⁴  = (935421 x (10)⁴)/(2)⁴)  = 935421 x 10000 / 16  = 9354210000 / 16  = 584638125

Q 21 - 12846 x 593 + 12846 x 407 = y. What is y?

Answer : A

Explanation

  y = 12846 x 593 + 12846 x 407  = 12846 x (593 + 407)  = 12846 x 1000  = 12846000

Q 22 - 14927 x 567 - 14927 x 467 = y. What is y?

Answer : B

Explanation

  y = 14927 x 567 - 14927 x 467   = 14927 x (567 - 467)   = 14927 x 100  = 1492700

Q 23 - The L.C.M of two numbers is 12 times their H.C.F and sum of H.C.F and L.C.M is 403. Having one number as 93, find the other one.

Answer : B

Explanation

Let L.C.M =x and H.C.F = y . Then,
X= 12y  and x+y = 403 ⇒12y+y = 403 ⇒13y= 403 ⇒y = 403/13 = 31
∴ x=   (12*31 ) = 372
Let the other number be z. then,
372*31 = 93*z ⇒ z = (372*31)/93  =124
Hence , the other number is 124 .

Q 24 - The sum of two numbers is 45 and difference is 1/9 of their sum. What is their L.C.M:

Answer : A

Explanation

Let the numbers be x and y . Then,
{x+y= 45  , x= (1/9*45)= 5} ⇒x = 25, y =20
L.C.M of 25 and 20 = (5*5*4)= 100

Q 25 - Having H.C.F and L.C.M of two numbers as 21 and 4641 respectively. If one of the numbers is in between 200 and 300, then the two numbers are :

Answer : D

Explanation

Let the numbers be 21 a and 21 b, where a and b are co-primes.
Then ,21 a* 21 b= (21* 4641)⇒ab= 221.
Two co-primes with product 221 are 13 and 17.
∴ Numbers are (21*13, 21*17) , i.e (273,357)

Q 26 - If two numbers are greater than 13 and the H.C.F of two numbers be 13, L.C.M 273, then the sum of the numbers is:

Answer : B

Explanation

Let the number be 13 a and 13 b, where a and b are co-primes.
Then, 13a * 13b=   (13* 273)  ⇒ab= 21
Two co-primes with product 21are 3 and 7.
∴ numbers are (13*3, 13*7) i.e , 39 and 91.
Their sum = (39+91) = 130

Q 27 - Sum of two numbers is 60 and their H.C.F and L.C.M are 12 and 72 respectively. One of the numbers is:

Answer : B

Explanation

Let the numbers be  12 a and 12 b, where a and b are co primes.
Then, 12 a *12 b = 12 *72  ⇒ ab= 6
co-primes with product 6 are a = 2, b= 3
∴ numbers are (12*2, 12*3 ) i.e  24 and 36

Q 28 - If the sum of the H.C.F and L.C.F of two numbers is 680 and their L.C.M is 84 times the H.C.F. If one of the numbers is 56, the other number is:

Answer : D

Explanation

h+L = 680 and L = 84 h
∴ h+84 h = 680 ⇒ 85h ⇒680 ⇒h= 8
∴ L= (84*8) = 672
Now, h*L =56*x  ⇒ 8* 672=  56*x⇒ x  = (8*672)/56  = 96
∴ The other number is  96.

Q 29 - H.C.F and L.C.M of two 3-digit numbers are 29 and 4147 respectively. What is the sum of the numbers?

Answer : C

Explanation

Let the numbers be 29a and 29 b , where a and b  are co-primes.
Then, 29 a * 29 b + 29*147 ⇒ ab + (29*4147)/(29*29)= 143
co-primes with product 143 are 11  and 13.
∴ numbers are (29*11,   29* 13) i.e ,  319, 377
Their sum = (319+377)= 696

Q 30 - The ratio of two numbers is 2:3. Having their L.C.M as 150, numbers are :

Answer : C

Explanation

Let the numbers be  2x and 3x . Then, their L.C.M is 6x.
6x =  150    ⇒ x=  25
So, the numbers are 50 and 75.

Q 31 - If (x - 0.11) / 1.6 = 1.6. What is x?

Answer : C

Explanation

 
 (x - 0.11) / 1.6 = 1.6 
 => x = (1.6 x 1.6) + 0.11 =  2.56 + 0.11 
= 2.67

Q 32 - If 185 x 28 = 5180 then what is 51.8 / 18.5?

Answer : A

Explanation

 
 51.8 / 18.5 = 518/185 = 28/10 = 2.8

Q 33 - Which of the following is same as 54.327 x 357.2 x .0057?

A - 5.4327 x 3.572 x 5.7

B - 5.4327 x 3.572 x .57

C - 54327 x 3572 x .0000057

D - 543.27 x 35.72 x .0057

Answer : A

Explanation

 
 As sum of decimal places in product is 8 and in option A is also 8.

Q 34 - 1/0.04 = ?

Answer : D

Explanation

 
 1/0.04 = 100/4 = 25

Q 35 - 25.732² - 15.732² = ?

Answer : C

Explanation

 
 25.732²  - 15.732² = (25.732 + 15.732)(25.732 - 15.732) = 41.464 x 10 = 414.64

Q 36 - The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?

Answer - B

Explanation

Let the average age of the whole team be z years. 
Therefore 11z - (26 + 29) = 9 (z - 1) = 11z - 9z = 46 
= 2z = 46
= z = 23 

So, average age of team is 23 years.

Q 37 The average weight of 8 persons increases by 2.5kg when a new person comes in place of one of them weighing 65kg . what might be the weight of the new person?

Answer - A

Explanation

Total weight increased = (8 x 2.5) kg = 20kg 
Weight of new person = (65 + 20) kg = 85kg.

Q 38 - The average weight of 45 students in a class is 52kg. Five of them whose average weight is 48 kg leave the class and other 5 students whose average weight is 54kg join the class. What is the new average weight (in kg) of the class?

Answer - A

Explanation

Sum of the weights of the students after replacement. 
= [(52 x 45) - (48 x 5) + (54 x 5)] kg = 2370kg. 

Therefore, new Average = ²³⁷⁰⁄₄₅kg = 53²⁄₃kg

Q 39 - The average age of 8 men is increased by 2 years when two of them whose ages are 21years and 23 years are replaced by two new men. The average age of the two new men is?

Answer - C

Explanation

Total age increased = (8 x 2) years = 16 years. 
Sum of ages of two new men = (21 + 23 + 16) years = 60 years 

Therefore age of two new men = ⁶⁰⁄₂ = 30 years.

Q 40 - A cricketer has a certain average for 10 innings. In the eleventh inning, he scored 108 runs, thereby increasing his average by 6 runs. His new average is?

Answer - B

Explanation

Let average for 10 innings be z. Then, 
= ^{10z + 108}⁄₁₁ = 11z + 66 = 10z + 108 = z = 42. 

New average = (z + 6) = 48 runs.

Q 41 - The range of a square field is 6050m². The length of its corner to corner is

Answer : A

Explanation

Let the diagonal be d meter. Then,
1/2 d²=6050⇒ d²= 12100 ⇒d=√12100= 110 m.

Q 42 - The region of a circle is 24.64m². The circuit of the circle is:

Answer : C

Explanation

πR²=24.64
⇒R²= (24.64*7/22)=(1.12*7)=7.84⇒R=√7.84=2.8
Circumference= 2πR= (2*22/7*2.8) m =17.60 m

Q 43 - If the range of a circle is expanded by 6%, then its region is expansion by:

Answer : C

Explanation

Let initial radius= R. Then, area = πR²
New radius =106% of R= (106/100* R) = 53R/50
New area = π* (53R/50)²
Increase in area = π*{(53R/50)² -R²}=π(53R/50+R)( 53R/50 -R)
= (π*103R/50*3R/50) = (309/2500) πR²
Increased % = (309/2500 *πR²*1/πR²*100) %= 309/25%= 12.36%

Q 44 - The distinction between the radii of the smaller circle and the greater circle is 7cm and the contrast between the territories of the two circles is 1078 cm². Span of the littler circle is:

Answer : B

Explanation

Let the radii of the inner and outer circle be r and R cm.
Then, R-r= 7 and π (R²-r²) = 1078
∴ Π (R²-r²)/ (R-r) = 1078/7
⇒R+r = (1078/7*7/22) =49
On solving (R-r) =7 and (R+r) = 49, we get r= 21 cm

Q 45 - A round greenery enclosure has an outline of 440 m. There is a 7m wide fringe inside the patio nursery along its outskirts. The territory of the fringe is:

Answer : D

Explanation

2πR =440 ⇒ 2*22/7*R= 440 ⇒R= (440* 7/44)=70 m
Outer radius = 70m, inner radius = (70-7) =63 m
Required area = π [(70)²-(63)²] m²= 22/7 *(70+63) (70-63) m²
= (22*133) m², = 2926m²

Q 46 - 1² + 2² ... + x² = [x(x+1)(2x+1)]/6. What is 1² + 3² +... + 20²?

Answer : A

Explanation

  
 (1² + 3² ... + 20²)  = (1² + 2² ... + 20²) - (2² + 4² ... + 19²)  
 Using formula  (1² + 3² ... +  n²) = [n(n+1)(2n+1)]/6  
 [20(20+1)(40+1)]/6 - (1 x 2² +  2² x 2² + 2² x  3² + ... + 2² x  9² + 2² x 10²)  = 2870 - 2²(1² + 2² + ... + 19²)  
 = 2870 -  4(1 x 2 x 39)/6  
 = 2870 - 52  
 = 2818

Q 47 - 14² + 15² ... + 50² = ?

Answer : D

Explanation

  
 Using formula  (1² + 3² ... +  n²) = [n(n+1)(2n+1)]/6  
 14² + 15² ... + 50² = (1² + 2² ... + 50²) - (1² + 2² ... + 13²)  
 = (50 x 51 x 101)/ 6 - (13 x 14 x 27) / 6  
 = 6739225 - 819  
 = 6738406

Q 48 - (1³ + 2³ ... + 20³) = ?

Answer : D

Explanation

  
 Using formula  (1³ + 2³ ... +  n³) = [(1/2)n(n+1]²  
 (1³ + 2³ ... + 20³) = [(20 x 21)/2]² 
 = 210²  
 = 44100

Q 49 - (1³ + 2³ ... + 20³) - (1 + 2 + ... + 20)= ?

Answer : C

Explanation

  
 Using formula  (1³ + 2³ ... +  n³) = [(1/2)n(n+1]²  
 (1³ + 2³ ... + 20³) = [(20 x 21)/2]²  = 210²  = 44100  
 Using formula  (1 + 2 + ... n) = [(1/2)n(n+1]  
 ∴ (1³ + 2³ ... + 15³) - (1 + 2 + ... + 15) = 44100 - (1/2) x 15 x 16 
 = 44100 - 120  
 = 43980

Q 50 - If 1² + 2² ... + 20² = 2870. What is 2² + 4² +... + 40²?

Answer : C

Explanation

   
 (2² + 4² ... + 40²)  = (1 x 2² + 2² x 2² + 3² x 2² +... +  20² x 2²)  
 = 2²(1² + 2² + .... + 20²) 
 = 4 x  385  
 = 1540

Answer Sheet

Question Number	Answer Key
1	D
2	A
3	D
4	C
5	D
6	C
7	D
8	C
9	B
10	D
11	C
12	D
13	C
14	A
15	A
16	B
17	C
18	A
19	B
20	C
21	A
22	B
23	B
24	A
25	D
26	B
27	B
28	D
29	C
30	C
31	C
32	A
33	A
34	D
35	C
36	B
37	A
38	A
39	C
40	B
41	A
42	C
43	C
44	B
45	D
46	A
47	D
48	D
49	C
50	C

aptitude_questions_answers.htm

Question Number	Answer Key
1	D
2	A
3	D
4	C
5	D
6	C
7	D
8	C
9	B
10	D
11	C
12	D
13	C
14	A
15	A
16	B
17	C
18	A
19	B
20	C
21	A
22	B
23	B
24	A
25	D
26	B
27	B
28	D
29	C
30	C
31	C
32	A
33	A
34	D
35	C
36	B
37	A
38	A
39	C
40	B
41	A
42	C
43	C
44	B
45	D
46	A
47	D
48	D
49	C
50	C

Question Number	Answer Key
1	D
2	A
3	D
4	C
5	D
6	C
7	D
8	C
9	B
10	D
11	C
12	D
13	C
14	A
15	A
16	B
17	C
18	A
19	B
20	C
21	A
22	B
23	B
24	A
25	D
26	B
27	B
28	D
29	C
30	C
31	C
32	A
33	A
34	D
35	C
36	B
37	A
38	A
39	C
40	B
41	A
42	C
43	C
44	B
45	D
46	A
47	D
48	D
49	C
50	C

Question Number	Answer Key
1	D
2	A
3	D
4	C
5	D
6	C
7	D
8	C
9	B
10	D
11	C
12	D
13	C
14	A
15	A
16	B
17	C
18	A
19	B
20	C
21	A
22	B
23	B
24	A
25	D
26	B
27	B
28	D
29	C
30	C
31	C
32	A
33	A
34	D
35	C
36	B
37	A
38	A
39	C
40	B
41	A
42	C
43	C
44	B
45	D
46	A
47	D
48	D
49	C
50	C