- Multiply and Divide Whole Numbers
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- Multiplication as Repeated Addition
- Single Digit Multiplication
- Multiplication by 10, 100, and 1000
- Multiplication Without Carry
- Multiplication With Carry
- Multiplication With Trailing Zeros: Problem Type 1
- Multiplication With Trailing Zeros: Problem Type 2
- Multiplication of 2-digit Numbers With 2-digit Numbers
- Multiplication of a Single Digit Number With Large Numbers
- Multiplication of Large Numbers
- Multiples Problem Type 1
- Multiples Problem Type 2
- Division Facts
- Fact Families for Multiplication and Division
- Multiplication or Division of Whole Numbers (Word problems)
- Multiplication and Addition or Subtraction of Whole numbers (Word problems)
- Unit Rates and Ratios of Whole Numbers (Word problems)
- Division Without Carry
- Division With Carry
- Division Involving Zero
- Whole Number Division: 2-digit by 2-digit, No Remainder
- Whole Number Division: 3-digit by 2-digit, No Remainder
- Division With Trailing Zeros: Problem Type 1
- Division With Trailing Zeros: Problem Type 2
- Quotient and Remainder: Problem type 1
- Quotient and Remainder: Problem type 2
- Quotient and Remainder (Word problems)

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Loretta has 16 candies. She wants to give same number of candies to each of her five friends. How many candies can she give to each of her friends? How many candies will Loretta have remaining?

**Step 1:**

The problem can be written as a division statement 16 ÷ 5. The largest multiple of 5 that is less than 16 is 5 × 3 = 15.

So 3 is the quotient and 16 – 15 = 1 is the remainder.

**Step 2:**

So 16 ÷ 5 = 3 R 1.

So Loretta can give 3 candies each to her five friends and have 1 candy left over with her.

Phil has 31 playing cards. He wants to deal same number of cards to each of four players. How many cards can he deal to each of the four players? How many cards will be remaining with Phil?

**Step 1:**

The problem can be written as a division statement 31 ÷ 4. The largest multiple of 4 that is less than 31 is 4 × 7 = 28.

So 7 is the quotient and 31 – 28 = 3 is the remainder.

**Step 2:**

So 31 ÷ 4 = 7 R 3.

So Phil can deal 7 cards each to the four players and have 3 cards left over with him.

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