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Speed & Distance - Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Speed & Distance. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - A train goes at 82.6km/hr. What number of meters will it go in 15 minutes?

Answer : D

Explanation

82.6 km/hr = (82.6*5/18)m/sec = 413/18 m/sec
Distance covered in 15 min = (413/18*15 *60) m =20650 m

Q 2 - A is twice as quick as B and B is thrice as quick as C. The excursion secured by C in 42 min. will be secured by A in

Answer : A

Explanation

Let c speed be x meters/min.
Then, B speed=3x meters /min and A speed =6x meters/ min.
Ratio of speed of A and C =ratio of times taken by C and A
6x:x=42:ymin⇒6x/x=42/y⇒y=42/6min=7 min.

Q 3 - A auto going with 5/7 of its typical rate covers 42 km in 1 hr. 40 min. 48sec.What is the typical pace of the auto?

Answer : D

Explanation

Let the usual speed be x km/hr.
42/(5x/7)= 126/75 ⇒  42*7/5x = 42/25 ⇒5x = (25*7) ⇒x = (5*7) = 35

Q 4 - Bombay express left Delhi for Bombay at 14.30 hours, going at a rate of 60 kmph and Rajdhani express left Delhi for Bombay around the same time at 16.30 hours, going at a pace of 80 kmph. How far from Delhi will the two trains meet?

Answer : C

Explanation

Let the train meet at a distance of x km from Delhi. Then,
x/60 - x/80 = 2 ⇒ 4x-3x = 480 ⇒x = 480
∴ required distance = 480 km

Q 5 - The velocities of three autos in the proportion 2:3:4. The proportion of the times taken by these autos to venture to every part of the same separation is:

Answer : D

Explanation

Ratio of time taken = 1/2: 1/3: 1/4 = 6:4:3

Q 6 - A man strolling at 3 km/hr crosses a square field corner to corner in 2 minutes. The zone of the field is:

Answer : C

Explanation

Speed =(3*5/18)m/sec. = 5/6 m/sec
Distance covered in 2 min. = (5/6* 2* 60) m = 100 m
Length of the diagonal of the square field = 100 m
Area = 1/2 * (diagonal) ²= (1/2 *100 *100 )m²= 5000 m²
= 5000/100 ares = 50 ares {1 are= 100 m²}

Q 7 - Renu began cycling along the limits of a square field ABCD from corner point A. after thirty minutes, he came to the corner point C, slantingly inverse to A. In the event that his rate was 8 km/hr, the zone of the field is:

A - 64 sq. km

B - 8 sq. km

C - 4 sq. km

D - cannot be resolved

Answer : B

Explanation

Length of diagonal = (8*1/2 )km = 4 km
Area of the field = (1/2 *4*4) sq. km = 8 sq. km

Q 8 - If a train keeps running at 40 km/hr, it achieves its destination late by 11 minutes. In any case, in the event that it keeps running at 50 km/hr, it is late by 5 minute just. The right time for the train to cover its trip, is:

Answer : C

Explanation

Let the required time be x minutes.
Distance covered in (x+11) min at 40 km/hr
Distance covered in (x+5) min at 50km/hr
∴(x+11)/60*(x+5)/60*50⇒4(x+11) =5(x+5) ⇒x= (44-25) =19.
Hence, the required time is 19 minutes.

Q 9 - The proportion between the rates of going of An and B is 2:3 and in this manner A takes 10 minute more than the time taken by B to achieve a destination. In the event that A had strolled at twofold speed, he would have secured the separation in

Answer : D

Explanation

Ratio of time taken by A and B = 1/2: 1/3
Suppose B takes x min. Then, A takes (x+10) min.
∴(x+10): x= 1/2: 1/3 = 3:2 ⇒ x+10/x = 3/2 ⇒ 2x+20 = 3x ⇒x = 20
Thus B takes 20 min. and A takes 30 min.
AT double speed A would covers it in 15 min.

Q 10 - A agriculturist voyaged a separation of 61 km in 9 hours. He voyaged halfway by walking at 4 km/hr and incompletely on bike at 9 km/hr. The separation went by walking is:

Answer : C

Explanation

Let the distance travelled on foot be x km
Then, distance covered on bicycle = (61-x) km
∴x/4 + 61-x/9 =9 ⇒ 9x+4(61-x)= 324 ⇒ 5x = (324-244)=  80 ⇒x = 16
Distance covered on foot = 16 km

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