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Aptitude - Ratios Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Ratios. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - The ratio of money with Raju and Babu is 9:19 and that with Babu and Shyam is 9:19.if Raju has Rs.567,Babu has

Answer : A

Explanation

Raju:Babu = 9:19 = 81:171
Babu:Shyam = 9:19 = 171:361
=> Raju:Shaym = 81:361
=> 81:361 = 567:x
=>x = 2527

Q 2 - If 19 inches correspond to 48.26 cm, how many numbers of Centimeters are there in 39 inches?

Answer : B

Explanation

Let 39 inches corresponds to x cm.
Given that 19 inches corresponds to 48.26 cm
=>19/48.26=39/x
=>x=39/19*48.26=99.06

Q 3 - If A:B = 2:3 , B:C = 4:5 and C:D = 6:7 , Then A:D =?

Answer : C

Explanation

A/D = (A/B* B/C * C/D ) = (2/3 * 4/5 * 6/7 ) = 16/35 
Thus A:D =16:35

Q 4 - If 2A=3B=4C,then A:B:C=?

Answer : C

Explanation

let 2A = 3B =4C = k.
At that point , A= k/2 , B = k/3 , C = k/4 
∴ A:B:C = k/2 : k/3: K/4 = 6:4:3

Q 5 - In a school, the proportion of young men and young ladies is 4:5 . at the point when 100 young lady leaves the school , the proportion gets to be 6:7 . What are number of young men are there in the school?

Answer : B

Explanation

Let the number of boys and girls be 4x and 5x respectively.
      Then,4x/5x-100=6/7?28x=30x-600 =>2x=600 => x=300.
Number of  boys=(4*300)=1200.

Q 6 - Two no. are in the extent of 3:5 . If each no. is extended by 10, the extent gets the opportunity to be 5:7 , the no. are?

Answer : D

Explanation

Let the numbers be 3x and 5x then,
(3x+10 ) / (5x+10)= 5/7
=> 7 ( 3x+10)= 5 (5x+10)
=> 4x= (70-50) =20
=> x =5
∴ The numbers are (3*5) and (5*5) , 15 and 25

Q 7 - What ought to be added to each of the four numbers 6, 14, 18, 38 to make them corresponding?

Answer : B

Explanation

Let the number to be added be x. Then,
6+X/14+x=  18+x/38+x
=>  (6+x) (38+x)= (14+ x) (18 +x)
=>  228 +44x+x<sup>2</sup> = 252+32x+x<sup>2</sup>
= 12x=24 
=>  x=2 .
∴ the required number is 2.

Q 8 - Rs. 680 is separated among A, B, C such that A gets 2/3 of what B gets and B gets 1/4 of what C gets. At that point their shares are separately:-

Answer : B

Explanation

Suppose C gets Rs. x. then B gets Rs. x/4 and gets Rs. (2/3*x/4)= x/6.
∴x/6+x/4+x=680
=>2x+3x+12x=8160
=> 17x= 8160
=> x=480
∴ A gets rs. 80, B gets rs. 120 and C gets rs. 480

Q 9 - The pay of A,B and C together add up to rs. 333. If they burn through 80% , 85%, 75% of their livelihoods , their sparing are as 7:6:9 . The pay of B is:

Answer : D

Explanation

Let their savings   be Rs 7x, Rs 6x and Rs 9x respectively.
  A+B+C=333 ?(i)
20/100 A=7x 
=>A=35x,15/100B=6x
=>B=40x,25/100C=9x
=>C=36x.
          ∴ 35x+40x+36x=333 
=> 111x =333  
=> x=3
           ∴B salary = (40*3)= 120.

Q 10 - Rs 1300 are separated among A,B,C and D in a manner that: A share / B share = B share / C share =C share/ D share = 2/3, What is A share?

Answer : C

Explanation

A:B=2:3,B:C=2:3=3/2*2:3/2*3:9/2.
C:D=2:3=2*9/4:3*9/4=9/2:27/4.
∴ A:B:C:D=2:3:9/2:27/4=8:12:18:27.
A share =Rs(1300*8/65)=Rs160.

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