Aptitude - Arithmetic Online Quiz



Following quiz provides Multiple Choice Questions (MCQs) related to Basic Arithmetic. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - Which term of 2,7, 12,17... is 87?

A - 16th

B - 17th

C - 18th

D - 15th

Answer : C

Explanation

  
Here a = 2,  d = 7 - 2 = 5,  
Let there be n term.  
Using formula Tn = a + (n - 1)d  
Tn = 2 + (n - 1) x 5 = 87  
=> 5n - 3 = 87  
=> n = 18 

Q 2 - The divisor is five times the quotient and five times the remainder. If the remainder is 29, the dividend is?

A - 4224

B - 4234

C - 4232

D - 4222

Answer : B

Explanation

  
Divisor = (5 x 29) = 145 = 5 x Quotient = Divisor 
=> Quotient = 145/5 = 29 
Dividend = (Divisor x Quotient) + Remainder 
Dividend = (145* 29) + 29 = 4234.  

Q 3 - The sum of first 99 natural numbers is?

A - 9801

B - 9800

C - 4851

D - 4950

Answer : D

Explanation

  
 Sum of n natural numbers is  Sn=n(n+1)/2  =99(99+1)/2  
 =4950  

Q 4 - Two numbers are less than the third number by 50% and 54% respectively. By how much percent is the second number less than the first number?

A - 13

B - 10

C - 12

D - 8

Answer : D

Explanation

 
 Let the third number be 100. 
 ∴First Number = 50 and Second Number = 46 
 Decrease = 50 - 46 = 4 
 ∴Required Percentage = (4/50)x100 = 8% 

Q 5 - How many 3-digits numbers are there which are completely divisible by 6?

A - 102

B - 150

C - 151

D - 156

Answer : B

Explanation

 
 Here numbers are 102, 108, ..., 996 which is an A.P. 
 Here a = 102,  d = 108 - 102 = 6,    
 Using formula Tn = a + (n - 1)d    
 Tn = 102 + (n - 1) x 6 = 996    
 => 96 - 6n = 996   
 => n = 900 / 6 
 = 150 

Q 6 - What is the sum of all odd numbers between 100 and 200?

A - 3750

B - 6200

C - 6500

D - 7500

Answer : D

Explanation

  
 Required sum = 101 + 103 + ... + 199 which is an A.P. where a = 101, d = 2, l = 199.  
 Using formula Tn = a + (n - 1)d  
 Tn = 101 + (n-1)2 = 199  
 => 2n = 199 - 99 = 100  
 => n = 50  
 Now Using formula Sn = (n/2)(a + l)  
 ∴ Required sum = (50/2)(101+199)  = 50 x 150  = 7500 

Q 7 - If first term of a G.P. is 5, common ratio is 2 what is the 8th term?

A - 160

B - 256

C - 640

D - 1280

Answer : C

Explanation

  
 Here a = 5,  r = 2, n = 8. 
 Using formula Tn = arn- 1 
 Tn = 5 x 2(8-1)  
 =5 x 27  
 =5 x 128  =640 

Q 8 - If a clock buzzes 1 time at 1 o'clock , 2 times at 2 o'clock and so on then how many times it buzzes in a day?

A - 100

B - 150

C - 156

D - 166

Answer : C

Explanation

  
 Total buzzes = 2(1 + 2 + 3 ... + 12)   
 Here a = 1, d = 1 , l = 12   
 Using formula Sn = (n/2)[a+l]   
 Sn = (12/2)[1+12]  = 6 x 13  = 78 
 Thus total number of buzzes = 2 x 78 = 156. 

Q 9 - How many terms are present in A.P. 7, 11, 15, ..., 151?

A - 37

B - 32

C - 33

D - 34

Answer : A

Explanation

   
 Here a = 7,  d = 11 - 7 = 4,   
 Let there be n term.   
 Using formula Tn = a + (n - 1)d   
 Tn = 7 + (n - 1) x 4 = 151  
 => 4n + 3 = 151  
 => n = 37  

Q 10 - 12 + 22 ... + x2 = [x(x+1)(2x+1)]/6. What is 12 + 32 +... + 202?

A - 2818

B - 2100

C - 2485

D - 2500

Answer : A

Explanation

  
 (12 + 32 ... + 202)  = (12 + 22 ... + 202) - (22 + 42 ... + 192)  
 Using formula  (12 + 32 ... +  n2) = [n(n+1)(2n+1)]/6  
 [20(20+1)(40+1)]/6 - (1 x 22 +  22 x 22 + 22 x  32 + ... + 22 x  92 + 22 x 102)  = 2870 - 22(12 + 22 + ... + 192)  
 = 2870 -  4(1 x 2 x 39)/6  
 = 2870 - 52  
 = 2818 
aptitude_arithmetic.htm
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