# Aptitude - Arithmetic Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Basic Arithmetic. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - What is the 12th term of A.P. 14, 9, -1, -6 ... ?

A - -36

B - -41

C - -46

D - 41

### Explanation

```Here a = 14, d = 9 - 14 = -5, n = 12
Using formula Tn = a + (n - 1)d
T12 = 14 + (12 - 1) x -5
= -41 ```

Q 2 - What digit should be placed in of H in 78423928H9 so as make it divisible by 9?

A - 3

B - 4

C - 7

D - 2

### Explanation

```
For the number 78423928H9 to be divisible by 9, the sum of all  its digits should be divisible by 9.
So                        (7+8+4+2+3+9+2+8+2+9)/9 = (52+H)/9
= Number divisible by 9
So H should b replaced by 2  ```

Q 3 - The difference between local and the face value of 8 in the numeral is 568012?

A - 7008

B - 0

C - 7992

D - 8008

### Explanation

```
8000 - 8
= 7992      ```

Q 4 - Two numbers are less than the third number by 50% and 54% respectively. By how much percent is the second number less than the first number?

A - 13

B - 10

C - 12

D - 8

### Explanation

```
Let the third number be 100.
∴First Number = 50 and Second Number = 46
Decrease = 50 - 46 = 4
∴Required Percentage = (4/50)x100 = 8% ```

Q 5 - How many multiples of 3 are available between 15 and 105 including both?

A - 30

B - 31

C - 32

D - 33

### Explanation

```
Here numbers are 15, 18, ..., 105 which is an A.P.
Here a = 15,  d = 3,
Using formula Tn = a + (n - 1)d
T11 = 15 + (n - 1) x 3 = 105
=> 12 + 3n = 105
=> n = 93 / 3 = 31 ```

Q 6 - if a, a-2 and 3a are in an A.P. what is a?

A - -3

B - -2

C - 2

D - 3

### Explanation

```
As a, a-2 and 3a are in an A.P.
∴ (a-2) - a = 3a - (a-2)
=> -2 = 2a - 2
=> a = -2 ```

Q 7 - Sum of three numbers in G.P. is 28 and there product is 512. What are the numbers?

A - 2, 6, 18

B - 2, 8, 16

C - 4, 8 , 16

D - 6, 9 , 13

### Explanation

```
let the numbers are a/r, a, ar
Then a/r x a x ar = 512
=> a3 = 83
gt; a = 8
Now a/r + a + ar = 28
=> 8/r + 8 + 8r = 28
=> 8/r + 8r = 20
=> 2/r + 2r = 5
=> 2r2 + -5r + 2 = 0
=> 2r2 + -4r -r + 2 = 0
=> 2r(r-2) - (r-2)=0
=> (r-2)(2r-1) = 0
=> r = 2 or r = 1/2
∴ numbers are 4, 8, 16. ```

Q 8 - One has to pay Rs 975 in yearly installments where each installment is less than earlier one by Rs 5. If first installment is of 100 in how many years, the entire amount will be paid?

A - 10

B - 12

C - 15

D - 25

### Explanation

```
Here a = 100, d = -5 , Sn = 975
Using formula Sn = (n/2)[2a + (n-1)d]
Sn = (n/2)[200 + (n-1)(-5)] = 975
=> n(205 - 5n) = 1950
=> 5n2 - 205n + 1950 = 0
=> n2 - 41n + 390 = 0
=> n2 - 26n - 15n + 390 = 0
=> n(n-26) - 15(n-26)= 0
=> (n-26)(n-15)
=> n = 15 ```

Q 9 - What is the 18th term of A.P. 3, 5, 7, 9 ...?

A - 50

B - 52

C - 35

D - 37

### Explanation

```
Here a = 3, d = 5 - 3 = 2, n = 18
Using formula Tn = a + (n - 1)d
T18 = 3 + (18 - 1) x 2
= 37 ```

Q 10 - If 12 + 22 ... + 202 = 2870. What is 22 + 42 +... + 402?

A - 770

B - 1155

C - 1540

D - 3852

### Explanation

```
(22 + 42 ... + 402)  = (1 x 22 + 22 x 22 + 32 x 22 +... +  202 x 22)
= 22(12 + 22 + .... + 202)
= 4 x  385
= 1540 ```
aptitude_arithmetic.htm