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# Aptitude - Calendar Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Calendar**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

### Answer : A

### Explanation

4Th.june, 2002 = (2001 years+ period from 1.1.2002 to. 4.6.2002. Odd days in 1600 years = 0 Odd days in 400 years = 0 Odd days in 1 customary years = 1 Odd days in 2001 years = (0+0+1)=1 Jan + Feb. +March +April+ May +June (31 + 28 +31+ 30 + 31 +4 = 155 days=22 weeks +1 day = 1 odd days Aggregate no. of odd days = (1+1) = 2 ∴ required day is Tuesday.

Q 2 - What was the week's day on sixteenth July, 1776?

### Answer : B

### Explanation

16 July, 1776 = (1775 years + period from 1.1.1776 to 16.7.1776. Checking of odd days. No. of odd days in 1600 years =0 No. of odd days in 100 years = 5 75 years= 18 jump years+57 conventional years = (18*2+57*1) odd days = 93 odd days = (13 weeks +2 days) = 2 odd days. ∴ 1775 years have= (0+5+2) odd days= 7 days= 0 days Jan + Feb. + March + April + May + June + July 31 +29 + 31 + 30 + 31 + 30 +16 = 198 days 198 days = (28 weeks+2 days) = 2 odd days =Total no. of odd days = (0+2) = 2 Thus, the required day is Tuesday.

Q 3 - Jan.1 2008 is Tuesday. What date of the week lies on Jan 1, 2009?

### Answer : C

### Explanation

The year 2008 is a jump year. So, it has 2 odd days. First day of the year 2008 is Tuesday (Given). In this way, first day of the year 2009 is 2 days past Tuesday. Subsequently, it will be Thursday.

Q 4 - On sixth March, 2005 Monday falls. What was the day of the week on sixth March, 2004?

### Answer : B

### Explanation

The year 2004 is a jump year. In this way, it has 2 odd days. ∴ The day on sixth March, 2005 will be 2 days. past the day on sixth Walk, 2004. Yet, sixth March, 2005 is Monday. ∴ sixth March, 2004 is Saturday.

Q 5 - What was the week's day on seventeenth June, 1988?

### Answer : D

### Explanation

17th June, 1998= (1997 year Period structure 1.1.1998 to 17.6.1998) Odd days in 1600 year=0. Odd days in 300 year = (5*3) =1. 97 year has 24 jump year +73 standard years. = 24*2 + 73*1 = 48 + 73 = 121 odd days = 17 weeks + 2 odd days = 2 odd days = 2 odd days. ∴ 1998 years have (0+1+2) = 3 odd days Jan to June = (31+29+31+30+31) = 152 days Add 17 days of June. = 152 + 17 = 169 days = 24 weeks + 1 days = 1 odd day. ∴ Total number of odd day = 3 + 1 = 4 odd days. Hence 17.06.1998 was Thursday.

Q 6 - What will be the day of the week on fifteenth 2010?

### Answer : A

### Explanation

fifteenth August,2010 =(2009 years+ Period from 1.1.2010 to 15.8.2010) Odd days in 1600 years = 0. Odd days in 400 years = 0. 9 year = (2 jump year +7 conventional years) = (2*2+7*1) = 11 odd days= 4 odd days Jan + feb + March + April + May + June + July + august 31+28+31+30+31+30+31+15 = 227 days =(32 weeks +3 days ) = 3 odd days Aggregate no. of odd days = (0+0+4+3) =7 = 0 odd day Given day is Sunday.

Q 7 - Today is Monday. Following 61 days, it will be?

### Answer : B

### Explanation

Each day of the week is rehashed following 7 days. In this way, after 63 days it will be Monday. ∴ Following 61 days , it will be Saturday.

### Answer : A

### Explanation

The century divisible by 400 is a leap year. ∴ The year 700 is not a jump year.

Q 9 - It was Sunday on Jan 1, 2006. Discover the week's day on Jan 1, 2010.

### Answer : C

### Explanation

On 31st December,2005 it was Saturday. Number of odd days frame the year 2006 to the year 2009=(1+1+2+1)=5 days. ∴ On 31st December 2009 , it was Thursday. In this way, on first jan, 2010 it is Friday.