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Progression - Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Progression. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : A
Explanation
Here a = 4, d = (9/2-4) = 1/2 T₁0₅ = a+(105-1)*d=4+104*1/2=4+52=56.
Q 2 - In the event that the fourth term of a number juggling movement is 14 and its twelfth term is 70, then its first term is:
Answer : B
Explanation
Let the first term of the A.P. be a and common difference be d. then, a+ 3d = 14 ...(i) a+11d = 70 ...(ii) On subtracting (i) from (ii), we get 8d =56 d = 7 Putting d = 7 in (i), we get a+3*7=14 ⇒ a= (14-21) = -7 ∴ First term = -7
Answer : B
Explanation
LCM of 4, 5, 6 = 2*2*5*3 = 60 So, each one must be divisible by 60. Requisite numbers are 240, 300, 360, 420, 480 and 540. Their no. is 6.
Answer : D
Explanation
This is an A.P. in which a = 2 and d = (5-2) =3. ∴ Next number= (8+3) =11.
Q 5 - What number of odd number pages arrives in a book of 1089 pages?
Answer : C
Explanation
The pages are 1, 3, 5, 7...,1089. This is an A.P. in which a= 1, d = (3-1) = 2 and L = 1089. Let the number of these term be n. then, (a+ (n-1) d = 1089 ⇒ 1 + (n - 1)* 2 = 1089 ⇒ (n-1 ) * 2 = 1088 n-1 =544⇒ n = 545. ∴ Required number of pages=545.
Q 6 - In the event that the fourth and ninth term of a G.P. is 54 and 13122 separately, there its second term is:
Answer : A
Explanation
Let its 1st term be a and common ratio r. Then, ar3 = 54 and ar⁸ = 13122 ∴ ar⁸/ ar3 = 13122/54 ⇒ r⁵ =243 = 3⁵ =r = 3 ∴ a* 33 = 54 ⇒ a*27 = 54 = > a =2 2nd term = ar = (2*3) =6
Q 7 - In the event that a ≠b, Then which of the accompanying proclamations is valid?
Answer : C
Explanation
For any two unequal numbers a and b, we have (A.M).> (g.m) ∴ (a+b)/2 > √ab
Q 8 - A clock hums 1 time at 1o, clock, 2 times at 2o, clock, 3 times at 3o, clock etc. What will be the aggregate quantities of hums in a day?
Answer : C
Explanation
Total number of buzzes =2 (1+2+3+..........+12). This is an A.P. in which a=1, d=1, n = 12 and L = 12. (1+2+3+ .........+12) = 12/2* (1+12) = 78. ∴ Total number of buzzes = (2 * 78) = 156.
Q 9 - The estimation of (13+23+33+? ? ..+153) - (1+2+3+...+15) =?
Answer : C
Explanation
(13+23+33+...+153) - (1+2+3+...+15) = (15*16/2)2 -1/2 *15*16 = (120)2 -120 =(14400- 120) = 14280.