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Volume Calculation - Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - The length of the askew of a cuboid 30 cm long, 24 cm wide and 18 cm is:

Answer : C

Explanation

Length of the diagonal =√ (L ²+ b²+ h²)=  √[ (30)² +( 24)²+(18)²]
= √ (900+576+324)   =√1800= √900*2
= 30√2 cm

Q 2 - A rectangular water store contains 42000 liters of water. On the off chance that the length of store is 6 m and its broadness is 3.5m, then the profundity of the supply is:

Answer : A

Explanation

Volume of reservoir = 42000 ltr. = 42 cubic mtr.
Let the depth be x mtr. Then,
6*7/2*x =42 ⇒ x = 2 m
∴ Depth =2 m

Q 3 - A tank is 7m long and 4m wide. At what pace ought to water gone through a channel 5 cm expansive and 4cm profound so that in 6 hours and 18 minutes, water level in the tank ascends by 4.5m?

Answer : B

Explanation

Volume of water flown = (7*4*9/2) m³=126 m³
Let the speed of the water be x km/hr.
(x*1000*63/10)*5/100*4/100= 126 ⇒ 63x/5=126
⇒x = (5*126)/63= 10
∴ Speed of water = 10 km/hr

Q 4 - A reservoir of limit 8000 liters measures remotely 3.3m by 2.6m by 1.1m and its dividers are 5cm thick. The thickness of the base is:

Answer : B

Explanation

Volume of the cistern = 8000ltr. =8000dm³
External length = 33 dm, external breadth =26 dm and external depth = 11 dm
Internal length = (33-5/10*2) dm = 32 dm
Internal breadth = (26-5/10*2) dm = 25 dm
Internal depth = (11-x) dm
∴ 32*25*(11-x) = 8000 ⇒ (11-x) =8000/ (32*25) =10
⇒ x = (11-10) =1dm

Q 5 - The aggregate surface zone of a solid shape is 150 cm². Its volume is:

Answer : B

Explanation

6a²=150 ⇒a²= 25 ⇒a =5cm
Volume of the cube = a³= (5*5*5) cm³= 125cm³

Q 6 - Three solid shapes of iron whose edge are 6 cm, 8cm and 10 cm are dissolved and framed into a solitary 3D shape. The Edge of the new solid shape framed is:

Answer : A

Explanation

Volume of new cube= [(6) ³+ (8) ³+ (10) ³] cm³
= (216+512+1000) cm³
= (1728) cm³= (2³*6³) cm³
Edge of this cube = (2*6) cm = 12 cm

Q 7 - The measurement of the base of a tube shaped drum is 35dm and its tallness is 24 dm. It is brimming with lamp oil. What number of tins each of size 25cm *22cm* 35 cm can be loaded with lamp fuel from the drum?

Answer : D

Explanation

r= 35/2 dm=(35/2*10)cm= 175 cm , h=24 dm = 240cm
Volume of drum = (22/7*175*175*240) cm³
=(22*25*175*240) cm³
Volume of a tin = (25*22*35) cm³
Number of tin = (22*25*175*240)/ (25*22*35) = 1200

Q 8 - The proportion of the radii of two barrels is 2:3 and the proportion of their statures is 5:3. The proportion of their volumes will be:

Answer : C

Explanation

Let the radii be 2r and 3rand the heights be 5h and 3h.
Ratio of their volume = {π*(2r) ²*5h/ π*(3r) ²*3h=   20/27 = 20:27

Q 9 - The aggregate surface territory of a strong barrel is 231 cm². On the off chance that its bended surface zone is two ?third of its aggregate surface zone, then its Volume is:

Answer : A

Explanation

(2πrh+2πr²) =231 and 2πrh= 2/3*231= 154
∴154+ 2πr² =231 ⇒2*22/7*r²= (231-154) =77
⇒r² = (77*7/44)= 49/4 ⇒ r =7/2 cm
∴2*22/7*7/2*h= 154   ⇒ h= 7cm
∴ Volume = πr²h = (22/7 *7/2 * 7/2 * 7) cm³ = 539/2 =269.5 cm³

Q 10 - If the sweep of circle is 6cm, then its volume is:

Answer : A

Explanation

Volume = {4/3π*(6)³} cm³ = (4/3π*6*6*6) cm³= (288π) cm³

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