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Aptitude - Averages Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to Averages. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Q 1 - What is the average of first 9 multiples of 3?

Answer : A

Explanation

Average = (3+6+9+12+15+18+21+24+27)/ 9= 135/9 = 15

Q 2 - 45 kg weight is the average of A, B and C. if the given condition of weight is 40 kg is the average of A and B while B and C have the average weight is 43 kg. Find out the weight of B?

Answer : C

Explanation

A, B and C have total weight = 45*3 = 135 kg
A and B  have total weight =    40*2 = 80 kg
B and C have total weight = 43*2 = 86 kg
∴ weight of B = (80+86- 135) = 31 kg.

Q 3 - 38°C is the average temperature of 4 day Monday , Tuesday , Wednesday and Thursday while 40°C is the average temperature of Tuesday, Wednesday , Thursday and Friday. On Monday 30° C temperature recorded. Find out the temperature on Friday?

Answer : D

Explanation

 M+T+W+Th = (38*4)= 152 ...(i)
T+W+Th+F = (40*4) =160 ...(ii)
After subtracting  (ii)-(i)  we find that f-M =8 ⇒ F-30 =8 ⇒ F =38.
∴ 38° C is the temperature on Friday.

Q 4 - 84 kg is the average weight of 3 people A, B and C. 80 kg is the average if D joins the group. A new man E replaces who have 3kg more weight than D. At that time 79 kg is the average weight of B, C, D and E. What should be the weight of A?

Answer : A

Explanation

A+B+C= (3*84)= 252 kg.     A+B+C+D= (4*80)= 320 kg
weight of D =( 320- 252) =68 kg.   weight of E = (68+3)= 71 kg.
sum of the weight of B+C+D+E= (79*4)= 316 kg ,
sum of the weight of B+C+D = (316-71)=245kg.
Total weight of A = (320- 245 )= 75 kg.

Q 5 - With the average of 12.4 takes 5 wickets by use of 26 run. A player has 0.4 downfalls in his average. What should be the number of wicket taken by him before the last match played?

Answer : A

Explanation

x is the number of wickets taken a player  before the last match played.
Then, (12.4x+26)/(x+5) =12 ⇒ 12.4x+26 =12x+60 ⇒ 0.4x =34
⇒ 0.4x =34 ⇒ x= 34/0.4 ⇒ x =340/4 = 85.
Wickets required = 85.

Q 6 - 7 is the average of 15 numbers. 6.5 is the average of first 8 numbers and 9.5 is the average of last 8 numbers. What should be the value of middle number?

Answer : A

Explanation

middle number = (8* 6.5) +(8*9.5)-(15*7)
= (52+76- 105) = 23

Q 7 - A company produces on an average 4000 items per month for the first 3 months. How many items it must produce on an average per month over the next 9 months, to average 4375 items per month over the whole?

Answer - A

Explanation

Required average = ^{(4375 x 12) - (4000 x 3)}⁄₉ = ^{52500 - 12000}⁄₉ = ⁴⁰⁵⁰⁰⁄₉ = 4500.

Q 8 - In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?

Answer - B

Explanation

Required run rate = ^{282 - (3.2 x 10)}⁄₄₀ = ²⁵⁰⁄₄₀ = 6.25.

Q 9 - The average age of 8 men is increased by 2 years when two of them whose ages are 21years and 23 years are replaced by two new men. The average age of the two new men is?

Answer - C

Explanation

Total age increased = (8 x 2) years = 16 years. 
Sum of ages of two new men = (21 + 23 + 16) years = 60 years 

Therefore age of two new men = ⁶⁰⁄₂ = 30 years.

Q 10 - The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is?

Answer - A

Explanation

Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years. 
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years 
Therefore Husbands present age = (90 - 50) years = 40 years

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