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An Inductor when connected in a circuit, that connection can be either series or parallel. Let us now know what will happen to the total current, voltage and resistance values if they are connected in series as well, when connected in parallel.

Let us observe what happens, when few inductors are connected in Series. Let us consider three resistors with different values, as shown in the figure below.

The total inductance of a circuit having series inductors is equal to the sum of the individual inductances. Total inductance value of the network given above is

$$L_{T}\:\:=\:\:L_{1}\:\:+\:\:L_{2}\:\:+\:\:L_{3}$$

Where L_{1} is the inductance of 1^{st} resistor, L_{2} is the inductance of 2^{nd} resistor and L_{3} is the inductance of 3^{rd} resistor in the above network.

The total voltage that appears across a series inductors network is the addition of voltage drops at each individual inductances.

Total voltage that appears across the circuit

$$V\:\:=\:\:V_{1}\:\:+\:\:V_{2}\:\:+\:\:V_{3}$$

Where V_{1} is the voltage drop across 1^{st} inductor, V_{2} is the voltage drop across 2^{nd} inductor and V_{3} is the voltage drop across 3^{rd} inductor in the above network.

The total amount of Current that flows through a set of inductors connected in series is the same at all the points throughout the network.

The Current through the network

$$I\:\:=\:\:I_{1}\:\:=\:\:I_{2}\:\:=\:\:I_{3}$$

Where I_{1} is the current through the 1^{st} inductor, I_{2} is the current through the 2^{nd} inductor and I_{3} is the current through the 3^{rd} inductor in the above network.

Let us observe what happens, when few resistors are connected in Parallel. Let us consider three resistors with different values, as shown in the figure below.

The total inductance of a circuit having Parallel resistors is calculated differently from the series inductor network method. Here, the reciprocal (1/R) value of individual inductances are added with the inverse of algebraic sum to get the total inductance value.

Total inductance value of the network is

$$\frac{1}{L_{T}}\:\:=\:\:\frac{1}{L_{1}}\:\:+\:\:\frac{1}{L_{2}}\:\:+\:\:\frac{1}{L_{3}}$$

Where L_{1} is the inductance of 1^{st} inductor, L_{2} is the inductance of 2^{nd} inductor and L_{3} is the inductance of 3^{rd} inductor in the above network.

From the method we have for calculating parallel inductance, we can derive a simple equation for two-inductor parallel network. It is

$$L_{T}\:\:=\:\:\frac{L_{1}\:\:\times\:\: L_{2}}{L_{1}\:\:+\:\: L_{2}}$$

The total voltage that appears across a Parallel inductors network is same as the voltage drops at each individual inductances.

The Voltage that appears across the circuit

$$V\:\:=\:\:V_{1}\:\:=\:\:V_{2}\:\:=\:\:V_{3}$$

Where V_{1} is the voltage drop across 1^{st} inductor, V_{2} is the voltage drop across 2^{nd} inductor and V_{3} is the voltage drop across 3^{rd} inductor in the above network. Hence the voltage is same at all the points of a parallel inductor network.

The total amount of current entering a Parallel inductive network is the sum of all individual currents flowing in all the Parallel branches. The inductance value of each branch determines the value of current that flows through it.

The total Current through the network is

$$I\:\:=\:\:I_{1}\:\:+\:\:I_{2}\:\:+\:\:I_{3}$$

Where I_{1} is the current through the 1^{st} inductor, I_{2} is the current through the 2^{nd} inductor and I_{3} is the current through the 3^{rd} inductor in the above network.

Hence the sum of individual currents in different branches obtain the total current in a parallel network.

Inductive Reactance is the opposition offered by an inductor to the alternating current flow, or simply AC current. An inductor has the property of resisting the change in the flow of current and hence it shows some opposition which can be termed as **reactance**, as the frequency of the input current should also be considered along with the resistance it offers.

Indication −

**XL**Units −

**Ohms**Symbol −

**Ω**

In a purely inductive circuit, the current **I _{L} lags** the applied voltage by 90°. Inductive reactance is calculated by,

$$X_{L}\:\:=\:\:2\pi fL$$

Where f is the frequency of the signal. Hence inductive reactance is a function of frequency and inductance.

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