
- Power Electronics Tutorial
- Power Electronics - Home
- Power Electronics - Introduction
- Power Electronics - Switching Devices
- Linear Circuit Elements
- Power Semiconductor Devices
- Silicon Controlled Rectifier
- Power Electronics - TRIAC
- Power Electronics - BJT
- Power Electronics - IGBT
- Power Electronics - MOSFET
- Solved Example
- Phase Controlled Converters
- Power Electronics - Pulse Converters
- Effect of Source Inductance
- Performance Parameters
- Reactive Power Control of Converters
- Power Electronics - Dual Converters
- Solved Example
- DC to DC Converters
- Power Electronics - Choppers
- Power Electronics - Control Methods
- Resonant Switching
- DC Converters Solved Example
- AC to DC Converters
- Single Phase AC Voltage Controllers
- Power Electronics - Cycloconverters
- Integral Cycle Control
- Power Electronics - Matrix Converters
- Solved Example
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Power Electronics - Performance Parameters
It is important to determine the performance parameters for different converters whose topologies can be single phase or multi-phase.
Assumptions
- The devices used are ideal, that is, they do not have any losses
- The devices have resistive loads

DC Voltage on Load
$$V_{DC}=\frac{1}{T} \int_{0}^{T}V_{L}\left ( t \right )dt$$RMS Voltage on Load
$$V_{L}=\sqrt{\frac{1}{T}}\int_{0}^{T}V_{L}^{2}\left ( t \right )dt$$Form Factor
$$FF=\frac{V_{L}}{V_{DC}}$$Ripple Factor
$$RF=\frac{\sqrt{V_{L}^{2}-V_{DC}^{2}}}{V_{DC}}=\sqrt{FF^{2}-1}$$Efficiency(Rectification Factor)
$$\eta =\frac{P_{DC}}{P_{L}+P_{D}}$$Where the above are defined as −
$P_{DC}=V_{DC}\times I_{DC}$
$P_{L}=V_{L}\times I_{L}$
$P_{D}=R_{D}\times I_{L}^{2}$($P_{D}$ is the rectifier losses and $R_{D}$ the resistance)
$$\eta =\frac{V_{DC}I_{DC}}{\left ( V_{L}I_{L} \right )+\left ( R_{D}I_{L}^{2} \right )}=\frac{V_{DC}^{2}}{V_{L}^{2}}\times \frac{1}{1+\frac{R_{D}}{R_{L}}}$$But $R_{D}=0$
Therefore,
$$\eta =\left ( \frac{V_{DC}}{V_{L}} \right )^{2}=\left ( \frac{1}{FF}\right )^{2}$$Transformer Utilization Factor
$$TUF=\frac{P_{DC}}{VA \:Rating \:of \:the \:Transformer }=\frac{P_{DC}}{\frac{VA_{p}+VA_{s}}{2}}$$VAp and VAs are the primary and secondary power ratings of the transformer.
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