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Microcontroller Articles
Page 11 of 33
8085 program to determine if the number is prime or not
In this program we will see how to check a number is prime or not using 8085.Problem StatementWrite 8085 Assembly language program to check whether a given number is prime or not.DiscussionHere the approach is little bit different. We are actually counting the number of unique factors. For prime numbers the factors are only two. The 1 and the number itself. So if the result is 02H, then it is prime, otherwise not a prime number. As there is no division operation, we have to perform division by subtracting repeatedly.InputAddressDataF10007 AddressDataF100FF AddressDataF1002F Flow Diagram ProgramAddressHEX CodesLabelsMnemonicsCommentsF00021, 00, F1 LXI H, F100Point to F100 to take ...
Read More8085 program to divide two 16 bit numbers
Here we will see how to divide two 16 bit numbers using 8085.Problem StatementWrite 8085 Assembly language program to divide two 16-bit numbers.Discussion8085 has no division operation. To perform division, we have to use repetitive subtraction. To perform 16-bit division, we have to do the same but for the register pairs. As the register pairs are used to hold 16-bit data.The Divisor is stored at location FC00 and FC01, the dividend is stored at FC02 and FC03. After division, the quotient will be stored at FC04 and FC05, and the remainder will be stored at FC06 and FC07.InputAddressDataFC008AFC015CFC025AFC031D Flow Diagram ProgramAddressHEX CodesLabelsMnemonicsCommentsF00001, ...
Read More8085 program to find the element that appears once
In this program we will see how to find a number who appears only once in an array of elements.Problem StatementWrite 8085 Assembly language program to find a number who appears only once in an array of elements. The size of the array is stored at location F100; the numbers are stored from memory location F101 onwards. The result will be stored at F150.DiscussionThe logic behind this problem is simple. Though it may find some wrong results in some cases. It can find the number if there is only one number which is appeared once, and rest of the numbers ...
Read More8085 program for Binary search
Here we will see how to perform binary search in 8085.Problem Statement:Write 8085 Assembly language program to perform binary search on a set of data stored at location F110 to F119. The key is located at F100.DiscussionTo perform binary search, the array must be sorted. We are taking the lower limit into L and upper limit into H. The array location is stored at DE register pair. The mid is calculated using (H + L)/2. To perform this division, we are just shifting it to the right one time. Then put the mid value into D and check the item ...
Read More8085 program to subtract two BCD numbers
Here we will see how to perform BCD subtractions using 8085.Problem StatementWrite 8085 Assembly language program to perform BCD subtractions of tow numbers stored at location 8001 and 8002. The result will be stored at 8050 and 8051.DiscussionTo subtract two BCD numbers, we are going to use the 10s complement method. Taking the first number and storing into B, Load 99 into A then subtract the number to get the 9’s complement. After that add 1 with the result to get 10’s complement. We cannot increase using INR instruction. This does not effect on CY flag. So we have to ...
Read More8254 Control Word and Operating modes
Here we will see the control words and the operation modes of the 8254 programmable interval timer chip.Before discussing its operating modes and control word properties, we should know about some important facts of this chip.When the chip is powering up, the state is undefined. The mode, count value, and outputs are undefined in that time.Each counter must be programmed before it is used. We do not need to program some unused counters.Counters are programmed by writing the control words and then one initial count.The structure of the counter is like this -76543210SC1SC0RW1RW2M2M1M0BCD/Binary We can select the counter by the SC1 ...
Read More8085 program to find bit differences between two binary patterns.
Here we will see how to find the bit differences of two binary patterns using 8085.Problem StatementTwo binary patterns are stored in locations 8030H and 8031H. Load them in registers A and B. Find out the bit positions where bits are differing and put these location numbers at locations starting from 8050H on words. (Bits are differing at those locations where 0 in A and 1 in B)DiscussionTo solve this problem, we are taking the numbers into A and B. Then initialize the C as counter with 08H, and the register L will keep tract the bit position, where A ...
Read More8085 program with a subroutine to add ten packed BCD numbers.
Here we will see how to add ten packed BCD numbers using 8085.Problem StatementA set of ten packed BCD numbers is stored in the memory location starting from 8040H to 8049H.Write a program with a subroutine to add these numbers in BCD. If a carry is generated save it to register B, and adjust it to BCD. The final sum will be less than 9999BCD. Store the sum at locations 8060H and 8061H.Write a second subroutine to unpack the BCD sum stored in registers A and B, and store them in the OutputBuffer memory starting at 8062H. The most significant ...
Read More8085 program to add even parity to a string of 7 bit ASCII characters.
Here we will see how to add even parity to 7-bit ASCII string using 8085.Problem StatementWrite a program to add even parity to a string of 7 bit ASCII characters. The length of the string is in memory location 8040 H and the string itself begins at memory location 8041 H. Place even parity in the most significant bit of each character.Discussion8085 has parity flat. that flag will be used to check and assign parity with each ASCII character. At first we will clear the most significant bit by masking the number with 7FH. Then use OR instruction, as this ...
Read More8085 program to implement the following function (a*b) + (c*d)
Here we will see how to implement mathematical function using 8085.Problem StatementWrite a program to implement the following function (a*b) + (c*d) and store the result in memory locations 8204 and 8205. Perform multiplication by using a subroutine. Here a, b, c and d numbers are stored at memory locations 8200H, 8201H, 8202H and 8203 respectively.DiscussionMultiplication instruction is not present in the 8085. So we have to use subroutine to perform multiplication. In this subroutine, it takes number from memory pointed by HL pair, and return result into DE register pair. After multiplying two parts, the intermediate results are stored, ...
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