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Microcontroller Articles
Page 31 of 33
8085 Program to multiply two 16-bit binary numbers
Now let us see a program of Intel 8085 Microprocessor. This program will calculate the multiplication of two 16-bit numbers.Problem StatementWrite 8085 Assembly language program to multiply two 16-bit numbers stored at 8000H -8001H and 8002H - 8003H.DiscussionThis program takes the 16 bit data from memory location 8000H – 8001Hand 8002H – 8003H. The 32 bit results are stored at location 8050H– 8053H.Here we have tested with two 16 bit numbers. The results are as follows 1111H × 1111H = 01234321H 1C24H × 0752H = 00CDFF88HInputfirst inputAddressData......800011800111800211800311......second input AddressData......80002480011C800252800307......Flow DiagramProgramAddressHEXCodesLabelsMnemonicsCommentsF00031, 00, 20LXI SP, 2000H InitializeStack pointerF0032A, 00, ...
Read MoreProgramming the 8253
According to the microprocessor point of view, the 8253 is designed and has some specialty port chip I/O. We don't use it for interfering the I/O devices. For performing the application of time it is used. 8253 has the addressed A1 and A0 input pins.The counters have width of 16 bits. If they were 8-bits wide, the delay in time that would be generated is very small. The Least Significant Byte and the Most Significant Byte of a counter is selected by using the same address of the port.The processor here writes to the control port to configure the working of ...
Read MoreNon-Programmable 8-Bit I/O Port
There are two types of Input Output ports. They are Programmable Input Output ports and Non-Programmable Input Output ports. Since the functions of Programmable Input Output ports changed by software they became more popular. We don't need to change the wiring rather the hardware of the I/O port to change the function. Intel 8255 is a popular Input Output chip based on port. Whereas the I/O ports which are non-programmable needs to change the wiring or the hardware to change its complete function. We will see in later that the connection needs to be changed when 8212 works like an ...
Read MoreProgram to Find the largest number in an array of data in 8085 Microprocessor
In this program we will see how to find the largest number from a block of bytes using 8085.Problem StatementWrite 8085 Assembly language program to find the largest number from a block of bytes.DiscussionIn this program the data are stored at location 8001H onwards. The 8000H is containing the size of the block. After executing this program, it will return the largest number and store it at location 9000H.Logic is simple, we are taking the first number at register B to start the job. In each iteration we are getting the number from memory and storing it into register A. ...
Read MoreProgram to Find the smallest number in an array of data in 8085 Microprocessor
In this program we will see how to find the smallest number from a block of bytes using 8085.Problem StatementWrite 8085 Assembly language program to find the smallest number from a block of bytes.DiscussionIn this program the data are stored at location 8001H onwards. The 8000H is containing the size of the block. After executing this program, it will return the smallest number and store it at location 9000H.Logic is simple, we are taking the first number at register B to start the job. In each iteration we are getting the number from memory and storing it into register A. ...
Read More8085 program to add two 16 bit numbers
In this program we will see how to add two 16-bit numbers.Problem StatementWrite8085 Assembly language program to add two 16-bit number stored in memory location 8000H – 8001H and 8002H – 8003H.DiscussionIn this program we are pointing the operand addresses using HL and DE register pair. Then adding LSBytes by ADD operator, and after that adding MSBytes using ADC operator to consider the carry flag result. The 16-bit result will be stored at BC register, and by checking the carry bit after addition we can simply put 1 into memory.We are taking two numbersBCAD + FE2D = 1BADAInputAddressData......8000AD8001BC80022D8003FE......Flow DiagramProgramAddressHEX CodesLabelsMnemonicsCommentsF00021, ...
Read More8085 program to add 2-BCD numbers
In this program we will see how to add two 8-bit BCD numbers.Problem StatementWrite 8085 Assembly language program to add two 8-bit BCD number stored in memory location 8000H – 8001H.DiscussionThis task is too simple. Here we are taking the numbers from memory and after adding we need to put DAA instruction to adjust the accumulator content to decimal form. The DAA will check the AC and CY flags to adjust a number to its decimal form.InputAddressData......800099800125......Flow DiagramProgramAddressHEX CodesLabelsMnemonicsCommentsF00021, 00, 80LXI H, 8000HPoint to first operandF0037EMOV A, MLoad A with first operandF00423INX HPoint to next operandF00586ADD MAdd Acc and memory ...
Read MoreWorking of 8212
There are two types of Input Output ports. They are Programmable Input Output ports and Non-Programmable Input Output ports. Since the functions of Programmable Input Output ports changed by software they became more popular. We don't need to change the wiring rather the hardware of the I/O port to change the function. Intel 8255 is a popular Input Output chip based on port. Whereas the I/O ports which are non-programmable needs to change the wiring or the hardware to change its complete function. We will see in later that the connection needs to be changed when 8212 works like an ...
Read More8085 program to find the sum of first n natural numbers
In this program we will see how to add first n natural numbers.Problem StatementWrite 8085 Assembly language program to add first N natural numbers. The value of N is provided.DiscussionWe are getting the value of N from memory location 8000H. We are using the number N as count variable, in each step we are calculating (A + Count) value, and store them into A. After adding them, the count value is decreased, thus the total series is completed.If the number is 23H(35D), then the sum will be (35*36)/2 = 630 (276H)InputAddressData......800023......Flow DiagramProgramAddressHEX CodesLabelsMnemonicsCommentsF00021, 00, 80LXI H, 8000HPoint to get the ...
Read More8085 program to count number of once in the given 8-bit number
In this program we will see how to count number of 1's in an 8-bit number.Problem StatementWrite 8085 Assembly language program to count number of 1s in 8-bit number stored atlocation 8000H.DiscussionIn this program we areusing the rotate operation to count the number of 1's. As there are8 different bits in 8-bit number, then we are rotating the numbereight times. we can use RRC or RLC. Here we have used the RRCinstruction. This instruction sends the LSb to MSb also to carryflag. So after each iteration we can check the carry status to getthe count of 1s.If the number is ...
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