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Microcontroller Articles
Page 32 of 33
8085 program to count total even numbers in series of 10 numbers
In this program we will see how to count number of even numbers in a block of elements.Problem StatementWrite 8085 Assembly language program to count number of even numbers in a block of data, where the block size is 10D. The block is starting from location8000H.DiscussionThe Odd Even checking is very simple. we can determine one number is odd or even by checking only the LSb. When LSb is 1, the number is odd, otherwise it is even. In this program we are taking a number from memory and then ANDing01H with it. if the result is nonzero, then the ...
Read More8085 program to find 1's and 2's complement of 8-bit number
In this program we will see how to find 1's complement and 2's complement of an 8-bit number.Problem StatementWrite 8085 Assembly language program to find 1's complement and 2's complement of a number stored in 8000H.Discussion8085 has an instruction CMA. This instruction complements the content of Accumulator. For 1's complement CMA instruction is sufficient, and for 2's complement we have to increase the number by 1 after complementing.We are taking the number from 8000H and storing the 1's complement at location 8050H, and 2's complement to 8051H.InputAddressData......8000AB......Flow DiagramProgramAddressHEX CodesMnemonicsCommentsF0003A, 00, 80LDA 8000HLoad the number from memoryF0032FCMAComplement the accumulatorF00432, 50, 80STA ...
Read More8085 program to find 1's and 2's complement of 16-bit number
In this program we will see how to find 1's complement and 2's complement of a 16-bit number.Problem StatementWrite 8085 Assembly language program to find 1's complement and 2's complement of a16-bit number stored in 8000H and 8001H.Discussion8085 has an instruction CMA. This instruction complements the content of Accumulator. For 1's complement CMA instruction is sufficient, and for 2's complement we have to increase the number by 1 after complementing.For 16-bit number, we are taking the number into HL pair, but for complementing we have to copy the numbers to Accumulator from H and L one by one. Then by ...
Read More8085 program to find 2's complement of the contents of Flag Register
In this program we will see how to find 2's complement of the content of flag register.Problem StatementWrite 8085 Assembly language program to find 2's complement of the content of flag register.DiscussionWe cannot access the total flag register directly. To use them we have to push the PSW(Accumulator-Flag) into stack, and then pop it to another register pair, then after complementing the LS byte of that register pair, we have to push it again into the stack, and then pop it to PSW to get it into Flag bits.InputHere we are not putting any input directly. If the flag bits ...
Read More8085 program to check whether the given number is even or odd
In this program we will see how to check whether a number is odd or even.Problem StatementWrite 8085 Assembly language program to check whether a number is odd or even.DiscussionThe Odd Even checking is very simple. we can determine one number is odd or even by checking only the LSb. When LSb is 1, the number is odd, otherwise it is even.In this program we are taking a number from memory and then ANDing 01H with it. if the result is nonzero, then the number is odd, otherwise it is even.Inputfirst inputAddressData......800015......second inputAddressData......80002C......Flow DiagramProgramAddressHEX CodesLabelMnemonicsCommentsF0003A, 00, 80LDA 8000HLoad the number ...
Read More8085 program to find larger of two 8 bit numbers
In this program we will see how to find the larger of two numbers.Problem StatementWrite 8085 Assembly language program to find the larger number of two 8-bit number store dat location 8000H and 8001H.DiscussionThis checking is done by using the CMP instruction. This instruction is very similar to the SUB instruction. The only difference is that it does not update the value of Accumulator after executing. So after comparing, if the CY flag is set, it means that the first number is smaller, and the second one is largerInputFirst inputAddressData......8000FD800123......second inputAddressData......800059800175......Flow DiagramProgramAddressHEX CodesLabelMnemonicsCommentsF00021, 00, 80LXI H, 8000HPoint to the first ...
Read More8085 program to find smallest number between two numbers
In this program we will see how to find the smallest of two numbers.Problem StatementWrite 8085 Assembly language program to find the smallest number of two 8-bit number stored at location 8000H and 8001H.DiscussionThis checking is done by using the CMP instruction. This instruction is very similar to the SUB instruction. The only difference is that it does not update the value of Accumulator after executing. So after comparing, if the CY flag is set, it means that the first number is smaller, and the second one is largerInputFirst inputAddressData......8000FD800123......second inputAddressData......800059800175......Flow DiagramProgramAddressHEX CodesLabelMnemonicsCommentsF00021, 00, 80LXI H, 8000HPoint to the first ...
Read More8085 program to find maximum of two 8 bit numbers
In this program we will see how to find the maximum of two numbers.Problem StatementWrite 8085 Assembly language program to find the maximum number of two 8-bit number stored at location 8000H and 8001H.DiscussionThis checking is done by using the CMP instruction. This instruction is very similar to the SUB instruction. The only difference is that it does not update the value of Accumulator after executing. So after comparing, if the CY flag is set, it means that the first number is smaller, and the second one is largerInputFirst inputAddressData......8000FD800123......second inputAddressData......800059800175......Flow DiagramProgramAddressHEX CodesLabelMnemonicsCommentsF00021, 00, 80LXI H, 8000HPoint to the first ...
Read More8085 program to swap two 8-bit numbers
In this program we will see how to swap two numbers.Problem StatementWrite 8085 Assembly language program to swap two 8-bit number stored at location 8000Hand 8001H.DiscussionIn 8085, there is an instruction XCHG. Using this we can swap the contents of DE and HL values. We are taking the numbers and storing them into H and D, then using XCHG the contents are swapped.InputAddressData......8000CD800134......Flow DiagramProgramAddressHEX CodesMnemonicsCommentsF0003A, 00, 80LDA 8000HLoad the first number into AF00367MOV H, AStore the number into HF0043A, 01, 80LDA 8001HLoad the second number into AF00757MOV D, AStore the number into DF008EBXCHGExchange DE and HLF0097CMOV A, HTake H content ...
Read More8085 program to swap two 16-bit numbers using Direct addressing mode
In this program we will see how to swap two 16-bit numbers in direct addressing mode.Problem StatementWrite 8085 Assembly language program to swap two 16-bit number stored at location 8000H – 8001H and 8002H – 8003H using direct addressing mode.DiscussionHere we are swapping the values using XCHG instruction. This instruction swaps the contents of DE and HL pair contents. We are taking the first number into DE register pair, then the second number into HL pair, then by XCHG we are swapping them.InputAddressData......8000CD8001AB800234800312......Flow DiagramProgramAddressHEX CodesMnemonicsCommentsF0002A, 00, 80LHLD 8000HLoad the first number into HLF003EBXCHGExchange DE and HLF0042A, 02, 80LHLD 8002HLoad the ...
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