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Java.util.Scanner.findWithinHorizon() Method
Description
The java.util.Scanner.findWithinHorizon(String pattern,int horizon) method attempts to find the next occurrence of a pattern constructed from the specified string, ignoring delimiters.An invocation of this method of the form findWithinHorizon(pattern) behaves in exactly the same way as the invocation findWithinHorizon(Pattern.compile(pattern, horizon)).
Declaration
Following is the declaration for java.util.Scanner.findWithinHorizon() method
public String findWithinHorizon(String pattern,int horizon)
Parameters
pattern − a string specifying the pattern to search for
Return Value
This method returns the text that matched the specified pattern.
Exception
IllegalStateException − if this scanner is closed
IllegalArgumentException − if horizon is negative
Example
The following example shows the usage of java.util.Scanner.findWithinHorizon() method.
package com.tutorialspoint; import java.util.*; import java.util.regex.Pattern; public class ScannerDemo { public static void main(String[] args) { String s = "Hello World! 3 + 3.0 = 6"; // create a new scanner with the specified String Object Scanner scanner = new Scanner(s); // find a string of world, with horizon of 10 System.out.println("" + scanner.findWithinHorizon("World", 10)); // find a string of world, with horizon of 20 System.out.println("" + scanner.findWithinHorizon("World", 20)); // print the rest of the string System.out.println("" + scanner.nextLine()); // close the scanner scanner.close(); } }
Let us compile and run the above program, this will produce the following result −
null World ! 3 + 3.0 = 6