Java.util.Scanner.findWithinHorizon() Method


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Description

The java.util.Scanner.findWithinHorizon(String pattern,int horizon) method attempts to find the next occurrence of a pattern constructed from the specified string, ignoring delimiters.An invocation of this method of the form findWithinHorizon(pattern) behaves in exactly the same way as the invocation findWithinHorizon(Pattern.compile(pattern, horizon)).

Declaration

Following is the declaration for java.util.Scanner.findWithinHorizon() method

public String findWithinHorizon(String pattern,int horizon)

Parameters

  • pattern -- a string specifying the pattern to search for

Return Value

This method returns the text that matched the specified pattern.

Exception

  • IllegalStateException -- if this scanner is closed

  • IllegalArgumentException -- if horizon is negative

Example

The following example shows the usage of java.util.Scanner.findWithinHorizon() method.

package com.tutorialspoint;

import java.util.*;
import java.util.regex.Pattern;

public class ScannerDemo {

   public static void main(String[] args) {

   String s = "Hello World! 3+3.0=6";

   // create a new scanner with the specified String Object
   Scanner scanner = new Scanner(s);

   // find a string of world, with horizon of 10
   System.out.println(""
   + scanner.findWithinHorizon("World", 10));

   // find a string of world, with horizon of 20
   System.out.println(""
   + scanner.findWithinHorizon("World", 20));

   // print the rest of the string
   System.out.println("" + scanner.nextLine());

   // close the scanner
   scanner.close();
   }
}

Let us compile and run the above program, this will produce the following result:

null
World
! 3+3.0=6

java_util_scanner.htm

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