Java.util.Arrays.sort(long[]) Method

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Description

The java.util.Arrays.sort(long[]) method sorts the specified array of longs into ascending numerical order.

Declaration

Following is the declaration for java.util.Arrays.sort() method

public static void sort(long[] a)

Parameters

  • a -- This is the array to be sorted.

Return Value

This method does not return any value.

Exception

  • NA

Example

The following example shows the usage of java.util.Arrays.sort() method.

package com.tutorialspoint;

import java.util.Arrays;

public class ArrayDemo {

   public static void main(String[] args) {

    // initializing unsorted long array
    long lArr[] = {22, 10, 91, 62, 46};

    // let us print all the elements available in list
    for (long number : lArr) {
      System.out.println("Number = " + number);
    }

    // sorting array
    Arrays.sort(lArr);

    // let us print all the elements available in list
    System.out.println("The sorted long array is:");
    for (long number : lArr) {
      System.out.println("Number = " + number);
    }
  }
}

Let us compile and run the above program, this will produce the following result:

Number = 22
Number = 10
Number = 91
Number = 62
Number = 46
The sorted long array is:
Number = 10
Number = 22
Number = 46
Number = 62
Number = 91



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