Java.util.Arrays.sort(long[]) Method
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Description
The java.util.Arrays.sort(long[]) method sorts the specified array of longs into ascending numerical order.
Declaration
Following is the declaration for java.util.Arrays.sort() method
public static void sort(long[] a)
Parameters
a -- This is the array to be sorted.
Return Value
This method does not return any value.
Exception
- NA
Example
The following example shows the usage of java.util.Arrays.sort() method.
package com.tutorialspoint;
import java.util.Arrays;
public class ArrayDemo {
public static void main(String[] args) {
// initializing unsorted long array
long lArr[] = {22, 10, 91, 62, 46};
// let us print all the elements available in list
for (long number : lArr) {
System.out.println("Number = " + number);
}
// sorting array
Arrays.sort(lArr);
// let us print all the elements available in list
System.out.println("The sorted long array is:");
for (long number : lArr) {
System.out.println("Number = " + number);
}
}
}
Let us compile and run the above program, this will produce the following result:
Number = 22 Number = 10 Number = 91 Number = 62 Number = 46 The sorted long array is: Number = 10 Number = 22 Number = 46 Number = 62 Number = 91