The length of rectangle is $25\ m$ and width of rectangle is $56\ cm$ find the perimeter of rectangle.

Given: The length of rectangle is $25\ m$ and width of rectangle is $56\ cm$.

To do: To find the perimeter of rectangle.

Solution:
 

As given, The length of the rectangle $l=25\ m$

The width of the rectangle $b=56\ m$

Therefore, the perimeter of the rectangle$=2( l+b)$

$=2( 25+56)$

$=2( 81)$

$=162\ m^2$

Thus, the perimeter of the rectangle is $162\ m^2$.

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Updated on: 10-Oct-2022

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