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Find the perimeter of the rectangle. The length of the rectangle is 11 cm and the breadth of the rectangle is 3 cm.
Given :
The length of the rectangle (l) $= 11 cm$.
The breadth of the rectangle (b) $=3 cm$.
To do :
We have to find the perimeter of the rectangle.
Solution :
The perimeter of the rectangle with length 'l' and breadth 'b' is given by, $2(l+b)$
Perimeter$= 2(11+3)$
$=2(14)$
$ = 28 cm$
Therefore, the perimeter of the rectangle is 28 cm.
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