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The width of a rectangle is two-third of its length. If the perimeter is 180cm, find the dimension of the rectangle.
Given:
The width of a rectangle is two-third of its length.
The perimeter is 180cm
To Do: Find the dimension of rectangle
Solution:
Let Length of rectangle = $x$;
Width = $\frac{2}{3}$ of length = $\frac{2x}{3}$
Perimeter of rectangle = $2(l + b)$
= $2(x + \frac{2x}{3})$
= $2\frac{(3x+2x)}{3}$
= $\frac{10x}{3} = 180$ m
Solving $x = 180 \times \frac{3}{10} = 54$ m
width $\frac{2x}{3} = \frac{2}{3} \times 54$ = 36 m
So length of rectangle = 54 m and
width of rectangle = 36 m
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