The width of a rectangle is two-third of its length. If the perimeter is 180cm, find the dimension of the rectangle.

Given:

The width of a rectangle is two-third of its length.

The perimeter is 180cm

To Do:  Find the dimension of rectangle

Solution:

Let Length of rectangle = $x$; 

Width = $\frac{2}{3}$ of length = $\frac{2x}{3}$

Perimeter of rectangle = $2(l + b)$

                                          = $2(x + \frac{2x}{3})$

                                          = $2\frac{(3x+2x)}{3}$

                                          = $\frac{10x}{3} = 180$ m

Solving $x = 180 \times \frac{3}{10} = 54$ m   

                    width $\frac{2x}{3} = \frac{2}{3} \times 54$ = 36 m

So length of rectangle = 54 m and

width of rectangle = 36 m