- Multiply and Divide Fractions
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- Product of a Unit Fraction and a Whole Number
- Product of a Fraction and a Whole Number: Problem Type 1
- Introduction to Fraction Multiplication
- Fraction Multiplication
- Product of a Fraction and a Whole Number Problem Type 2
- Determining if a Quantity is Increased or Decreased When Multiplied by a Fraction
- Modeling Multiplication of Proper Fractions
- Multiplication of 3 Fractions
- Word Problem Involving Fractions and Multiplication
- The Reciprocal of a Number
- Division Involving a Whole Number and a Fraction
- Fraction Division
- Fact Families for Multiplication and Division of Fractions
- Modeling Division of a Whole Number by a Fraction
- Word Problem Involving Fractions and Division
- Selected Reading
- UPSC IAS Exams Notes
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Fraction Division Online Quiz
Following quiz provides multiplication Choice Questions (MCQs) related to Fraction Division. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : A
Explanation
Step 1:
Rewriting division as a multiplication operation
$\frac{5}{7}$ ÷ $\frac{9}{7}$ = $\frac{5}{7}$ × $\frac{7}{9}$ = $\frac{(5×7)}{(7×9)}$ = $\frac{35}{63}$
Step 2:
$\frac{5}{7}$ ÷ $\frac{9}{7}$ = $\frac{35}{63}$
Step 3:
Reducing to lowest terms
$\frac{35}{63}$ = $\frac{5}{9}$
Answer : B
Explanation
Step 1:
Rewriting division as a multiplication operation
$\frac{4}{9}$ ÷ $\frac{6}{15}$ = $\frac{4}{9}$ × $\frac{15}{6}$ = $\frac{(4×15)}{(9×6)}$ = $\frac{60}{54}$
Step 2:
$\frac{4}{9}$ ÷ $\frac{6}{15}$ = $\frac{60}{54}$
Step 3:
Reducing to lowest terms
$\frac{60}{54}$ = $\frac{10}{9}$
Answer : C
Explanation
Step 1:
Rewriting division as a multiplication operation
$\frac{5}{7}$ ÷ $\frac{5}{9}$ = $\frac{5}{7}$ × $\frac{9}{5}$ = $\frac{(5×9)}{(7×5)}$ = $\frac{45}{35}$
Step 2:
$\frac{5}{7}$ ÷ $\frac{5}{9}$ = $\frac{45}{35}$
Step 3:
Reducing to lowest terms
$\frac{45}{35}$ = $\frac{9}{7}$
Answer : D
Explanation
Step 1:
Rewriting division as a multiplication operation
$\frac{3}{5}$ ÷ $\frac{8}{10}$ = $\frac{3}{5}$ × $\frac{10}{8}$ = $\frac{(3×10)}{(5×8)}$ = $\frac{30}{40}$
Step 2:
$\frac{3}{5}$ ÷ $\frac{8}{10}$ $\frac{30}{40}$
Step 3:
Reducing to lowest terms
$\frac{30}{40}$ = $\frac{3}{4}$
Answer : B
Explanation
Step 1:
Rewriting division as a multiplication operation
$\frac{5}{9}$ ÷ $\frac{7}{9}$ = $\frac{5}{9}$ × $\frac{9}{7}$ = $\frac{(5×9)}{(9×7)}$ = $\frac{45}{63}$
Step 2:
$\frac{5}{9}$ ÷ $\frac{7}{9}$ = $\frac{45}{63}$
Step 3:
Reducing to lowest terms
$\frac{45}{63}$ = $\frac{5}{7}$
Answer : C
Explanation
Step 1:
Rewriting division as a multiplication operation
$\frac{4}{7}$ ÷ $\frac{5}{14}$ = $\frac{4}{7}$ × $\frac{14}{5}$ = $\frac{(4×14)}{(7×5)}$ = $\frac{56}{35}$
Step 2:
$\frac{4}{7}$ ÷ $\frac{5}{14}$ = $\frac{56}{35}$
Step 3:
Reducing to lowest terms
$\frac{56}{35}$ = $\frac{8}{5}$
Answer : D
Explanation
Step 1:
Rewriting division as a multiplication operation
$\frac{4}{6}$ ÷ $\frac{7}{12}$ = $\frac{4}{6}$ × $\frac{12}{7}$ = $\frac{(4×12)}{(6×7)}$ = $\frac{48}{42}$
Step 2:
$\frac{4}{6}$ ÷ $\frac{7}{12}$ = $\frac{48}{42}$
Step 3:
Reducing to lowest terms
$\frac{48}{42}$ = $\frac{8}{7}$
Answer : A
Explanation
Step 1:
Rewriting division as a multiplication operation
$\frac{3}{5}$ ÷ $\frac{7}{15}$ = $\frac{3}{5}$ × $\frac{15}{7}$ = $\frac{(3×15)}{(5×7)}$ = $\frac{45}{35}$
Step 2:
$\frac{3}{5}$ ÷ $\frac{7}{15}$ = $\frac{45}{35}$
Step 3:
Reducing to lowest terms
$\frac{45}{35}$ = $\frac{9}{7}$
Answer : C
Explanation
Step 1:
$\frac{5}{7}$ ÷ $\frac{8}{7}$
Rewriting division as a multiplication operation
$\frac{5}{7}$ ÷ $\frac{8}{7}$ = $\frac{5}{7}$ × $\frac{7}{8}$ = $\frac{(5×7)}{(7×8)}$ = $\frac{35}{56}$
Step 2:
$\frac{5}{7}$ ÷ $\frac{8}{7}$ = $\frac{35}{56}$
Step 3:
Reducing to lowest terms
$\frac{35}{56}$ = $\frac{5}{8}$
Answer : D
Explanation
Step 1:
Rewriting division as a multiplication operation
$\frac{5}{9}$ ÷ $\frac{7}{12}$ = $\frac{5}{9}$ × $\frac{12}{7}$ = $\frac{(5×12)}{(9×7)}$ = $\frac{60}{63}$
Step 2:
$\frac{5}{9}$ ÷ $\frac{7}{12}$ = $\frac{60}{63}$
Step 3:
Reducing to lowest terms
$\frac{60}{63}$ = $\frac{20}{21}$