
- Mean, Median, and Mode
- Home
- Mode of a Data Set
- Finding the Mode and Range of a Data Set
- Finding the Mode and Range from a Line Plot
- Mean of a Data Set
- Understanding the Mean Graphically: Two bars
- Understanding the Mean Graphically: Four or more bars
- Finding the Mean of a Symmetric Distribution
- Computations Involving the Mean, Sample Size, and Sum of a Data Set
- Finding the Value for a New Score that will yield a Given Mean
- Mean and Median of a Data Set
- How Changing a Value Affects the Mean and Median
- Finding Outliers in a Data Set
- Choosing the Best Measure to Describe Data
Computations Involving the Mean, Sample Size, and Sum of a Data Set Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Computations Involving the Mean, Sample Size, and Sum of a Data Set. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Answer : D
Explanation
Step 1:
Let the last number be = x
Average = $ \frac{(7 + 9 + 15 + x)}{4}$ = 12.
Step 2:
Solving for x;
31 + x = 48; x = 48 – 31 = 17
Answer : C
Explanation
Step 1:
Given a + b + c = 26 and a + 2c = 28
Step 2:
Subtracting the first from second we get c – b = 28 -26 = 2; c = 2 + b
Step 3:
Plugging value of c in first equation we get a + 2b = 24
Answer : B
Explanation
Step 1:
Average of x and 3 = $\frac{(x + 3)}{2}$; Average of x, 6, and 9 = $\frac{(x + 6 + 9)}{3}$
Step 2:
Given $\frac{(x + 3)}{2} = \frac{(x + 15)}{3}$
Solving we get 3x + 9 = 2x + 30 or 3x – 2x = x = 30 – 9 = 21
Step 3:
So x = 21.
Answer : A
Explanation
Step 1:
Let the consecutive integers be a -2, a -1, a, a + 1 and a + 2
Average $\frac{(a -2 + a -1 + a + a + 1 + a + 2)}{5} = \frac{5a}{5}$ = 123
Step 2:
The numbers are 121, 122, 123, 124 and 125
Average of first three numbers = 122
Answer : C
Explanation
Step 1:
- Let the consecutive odd integers be a - 4, a -2, a, a + 2 and a + 4
Average $\frac{(a - 4 + a - 2 + a + a + 2 + a + 4)}{5} = \frac{5a}{5}$ = 101
Step 2:
The numbers are 97, 99, 101, 103 and 105
Average of first three numbers = 99
Answer : D
Explanation
Step 1:
Let there be n numbers x1, x2, ….xn in set P. Their mean = 10.
Total in set P = (x1 + x2 + …xn) = 10n
Step 2:
In set Q, n numbers x1+2, x2+2 ….xn+2.
Their total (x1+2, x2+2 ….xn+2) = (x1 + x2 + …xn) + 2n = 10n + 2n = 12n
Step 3
Mean of set Q = $\frac{Total}{n}= \frac{12n}{n}$ = 12
Answer : B
Explanation
Step 1:
Total degrees over 10 day period = 10 × 85 = 850
Step 2:
Let average temperature over 4 days = x
87 × 6 + 4 x = 850
Solving for x, 4x = 850 – 522 = 328
So x = $\frac{328}{4}$ = 82 degrees.
Answer : A
Explanation
Step 1:
Average of 14, 18 and 19 = $\frac{(14 + 18 + 19)}{3} = \frac{51}{3}$ = 17
Step 2:
Let required number by x
Average of x and 8 = $\frac{(8 + x)}{2}$
Given $\frac{(8 + x)}{2}$ + 10 = 17
So $\frac{(8 + x)}{2}$ = 17 – 10 = 7
8 + x = 14; x = 14 – 8 = 6.
Step 3
So required number = 6
Answer : C
Explanation
Step 1:
Let the consecutive even integers be x – 6, x – 4, x – 2, x, x + 2, x + 4, x + 6
Their average = $\frac{(x – 6 + x – 4 + x – 2 + x + x + 2 + x + 4 + x + 6)}{7} = \frac{7x}{7}$ = 48. So x = 48.
Step 2:
So the numbers are 42, 44, 46, 48, 50, 52, 54
The average of the two greatest of these integers 52 and 54 is $\frac{(52 + 54)}{2}=$ = 53
Answer : D
Explanation
Step 1:
Let the average height of the boys = x Then total height of 180 boys = 180x
Total height of 200 girls = 200 × $5\frac{4}{12} = \frac{3200}{3}$
Step 2:
Total height of boys and girls = 180x + $\frac{3200}{3}$
= Average x number of boys and girls = 5$\frac{6}{12}$ × 380
180x + $\frac{3200}{3}$ = 2090; 180x = $\frac{(6270 − 3200)}{3} = \frac{3070}{3}$; x = $\frac{3070}{540}$ = 5.69 feet.