# Writing a ratio as a percentage without a calculator Online Quiz

Following quiz provides Multiple Choice Questions (MCQs) related to **Writing a ratio as a percentage without a calculator**. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using **Show Answer** button. You can use **Next Quiz** button to check new set of questions in the quiz.

**Q 1 - While completing a 60-minute race, Joe spent 42 minutes walking and the rest jogging. What percentage of the time did he spend jogging in the race?**

### Answer : D

### Explanation

**Step 1:**

Duration of race = 60 minutes

Time spent in jogging = 60 – 42 = 18 minutes

**Step 2:**

Percentage time spent in jogging = $\frac{18}{60} \times 100 = 30\%$

**Q 2 - One day a DVD store rented out 40 movies of which 16 were comedies and rest were action movies. What is the percentage of action movies that were rented?**

### Answer : A

### Explanation

**Step 1:**

Total number of movies = 40

Number of comedies = 16

**Step 2:**

Number of action movies = 40 – 16 = 24

Percentage of action movies = $\frac{24}{40} \times 100 = 60\%$

**Q 3 - At a bakery a total of 80 items were sold. If 56 of the items sold were cookies and the rest were brownies what is the percentage of brownies that were sold?**

### Answer : B

### Explanation

**Step 1:**

Number of items that were sold = 80

Number of cookies sold = 56

**Step 2:**

Number of brownies sold = 80 – 56 = 24

Percentage of brownies sold = $\frac{24}{80} \times 100 = 30\%$

**Q 4 - A vendor sold a total of 90 snack items during a football game. If he sold 54 hotdogs and rest hamburgers, what is the percentage of hamburgers that he sold?**

### Answer : C

### Explanation

**Step 1:**

Total number of snacks sold = 90

Number of hotdogs sold = 54

**Step 2:**

Number of hamburgers sold = 90 – 54 = 36

Percentage of hamburgers sold = $\frac{36}{90} \times 100 = 40\%$

**Q 5 - A restaurant sold 50 burritos in a day of which 22 were bean burritos and the rest were beef burritos. What is the percentage of beef burritos that were sold?**

### Answer : A

### Explanation

**Step 1:**

Number of burritos sold = 50

Number of bean burritos sold = 22

**Step 2:**

Number of beef burritos sold = 50 – 22 = 28

Percentage of beef burritos sold = $\frac{28}{50} \times 100 = 56\%$

**Q 6 - A box of candy has 25 pieces in all. If 13 of the pieces are cherry flavored, what is the percentage of cherry flavored candies?**

### Answer : C

### Explanation

**Step 1:**

Total number of candy pieces = 25

Number of cherry flavored pieces = 13

**Step 2:**

The percentage of cherry flavored candy pieces = $\frac{13}{25} \times 100 = 52\%$

**Q 7 - At a summer camp there were a total of 90 boys and girls. If there were 72 boys, what is the percentage of girls that were there?**

### Answer : B

### Explanation

**Step 1:**

Total number of boys and girls = 90

Number of girls = 90 – 72 = 18

**Step 2:**

Percentage of girls = $\frac{18}{90} \times 100 = 20\%$

**Q 8 - In a bag of 120 candies, the number of yellow candies is 48 and the rest are blue candies. What is the percentage of blue candles in the bag?**

### Answer : D

### Explanation

**Step 1:**

Total number of candies = 120

Number of yellow candies = 48

**Step 2:**

Number of blue candies = 120 – 48 =72

Percentage of blue candies = $\frac{72}{120} \times 100 = 60\%$

**Q 9 - Sixteen people voted for candidate**

*A*during a class election. If there were a total of 50 votes, what is the percentage of votes polled by candidate*A*?### Answer : B

### Explanation

**Step 1:**

Total number of votes = 50

Number votes polled for candidate *A* = 16

**Step 2:**

Percentage of votes polled by A = $\frac{16}{50} \times 100 = 32\%$

**Q 10 - The length and width of a room measure 60 feet. If the length of the room is 39 feet, what is the percentage of the length of the room?**

### Answer : A

### Explanation

**Step 1:**

Length of the room = 39 feet

Total length and width = 60 feet

**Step 2:**

Percentage of the length = $\frac{39}{60} \times 100 = 65\%$