Decimal Equivalents of 1/2, 1/3, . . . ,1/10 in Python

In this article, we will learn a python program that prints out the decimal equivalents of 1/2, 1/3, 1/4, . . . ,1/10.

Methods Used

The following are the various methods to accomplish this task −

• Printing Decimal Equivalent of 1/2

• Using the range() function

• Using the decimal module

Method 1: Printing Decimal Equivalent of 1/2

We can easily use this code to find the decimal equivalents of 1/2. In this code, we just display the output after storing the result of 1/2 in a variable, inputNumber.

Example

The following program returns the decimal equivalents of 1/2 −

# input number 
inputNumber = 1/2

# printing the decimal equivalent of the input number 
print(inputNumber)

Output

On executing, the above program will generate the following output −

0.5

Method 2: Using the range() Function

The range() function returns a sequence of numbers that starts at 0 and increments by 1 (default) and stops before a given number.

Algorithm (Steps)

Following are the Algorithm/steps to be followed to perform the desired task. −

• Initialize a variable with value 1.

• Use the for loop to traverse in a range from 2 to 10 with the help of the range() function.

• Print 1 (here p) divided by the current number and format it using fstrings.

Example

The following program returns the decimal equivalents of 1/2, 1/3,….,1/10 using the range() function −

# initializing a variable with 1
p = 1

# iterating the for loop in a range from 2 to 10
for q in range(2, 11):
   # printing 1 (here p) divided by the current number and formatting it
	   print(f"{p}/{q} :", p/q)

Output

On executing, the above program will generate the following output −

1/2 : 0.5
1/3 : 0.3333333333333333
1/4 : 0.25
1/5 : 0.2
1/6 : 0.16666666666666666
1/7 : 0.14285714285714285
1/8 : 0.125
1/9 : 0.1111111111111111
1/10 : 0.1

Method 3: Using the Decimal Module

When working with decimal numbers in Python, one can utilize the decimal module to get more precise/accurate results because it supports arbitrary-precision decimal arithmetic.

Algorithm (Steps)

Following are the Algorithm/steps to be followed to perform the desired task. −

• Use the import keyword to import the decimal module.

• Use the for loop to traverse in a range from 2 to 10 with the help of the range() function.

• The range() function returns a sequence of numbers that starts at 0 and increments by 1 (default) and stops before a given number.

• Use the Decimal() function of the decimal module to get the decimal equivalent of 1 by the current number.

• Print the resultant decimal equivalent of the number by formatting it using fstrings.

Example

The following program returns the decimal equivalents of 1/2, 1/3, 1/4,….,1/10 using the decimal module −

# importing decimal module
import decimal

# iterating the for loop in a range from 2 to 10
for p in range(2, 11):
   # getting the decimal equivalent of 1 by the current number
	outputNum = decimal.Decimal(1) / decimal.Decimal(p)
   # printing the resultant decimal number by formatting it 
	print(f"1/{p}: {outputNum}")

Output

On executing, the above program will generate the following output −

1/2: 0.5
1/3: 0.3333333333333333333333333333
1/4: 0.25
1/5: 0.2
1/6: 0.1666666666666666666666666667
1/7: 0.1428571428571428571428571429
1/8: 0.125
1/9: 0.1111111111111111111111111111
1/10: 0.1

In the above example, the Decimal class represents decimal numbers that are imported from the decimal module. Division can be performed with arbitrary precision using the / operator, which belongs to the Decimal class.

In scenarios when a high level of precision is required, utilizing the decimal module may be more computationally expensive than using the built-in float type.

Conclusion

We learned three distinct techniques in this article for printing out the decimal equivalents of 1/2, 1/3, 1/4,..., and 1/10. We also learned how to iterate through the provided ranges using the range() method. Additionally, we learned how to use the Decimal function to obtain results in floating-point numbers with higher precision and accuracy.