C++ program to find the sum of the series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n

In this tutorial, we will be discussing a program to find the sum of the given series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n.

For this, we will be given with the value of n and our task is to add up every term starting from the first one to find the sum of the given series.

Example

#include <iostream>
#include <math.h>
using namespace std;
//calculating the sum of the series
double calc_sum(int n) {
   int i;
   double sum = 0.0, ser;
   for (i = 1; i <= n; i++)
   ser = 1/ pow(i, i);
   sum += ser;
   return sum;
}
int main() {
   int n = 5;
   double res = calc_sum(n);
   cout << res << endl;
   return 0;
}

Output

0.00032

Updated on: 09-Jul-2020

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