- Trending Categories
- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Program to find sum of series 1 + 1/2 + 1/3 + 1/4 + .. + 1/n in C++
In this problem, we are given a number n. Our task is to create a program to find sum of series 1 + 1/2 + 1/3 + 1/4 + .. + 1/n in C++.
Code description − Here, we will find the sum of the series 1 + 1/2 + 1/3 + 1/4 + .. + 1/n till nth term. The series is a harmonic progression series.
Harmonic progression is a series whose inverse will be an arithmetic progression. I.e. if for a harmonic progression A1, A2, A3... An, there is an arithmetic progression 1/A1, 1/A2, 1/A3.
First, let’s take an example to understand the problem,
Input
n = 5
Output
2.59286
Explanation
Sum = 1 + ½ + ⅓ + ¼ + ⅕ + ⅙ + 1/7 = 2.59286
Solution Approach
To solve the problem, we will simply use the loops as there is no specif formula for the sum of HP.
Algorithm
Initialize − sumVal = 0;
- Step 1 − Loop for i -> 1 to n.
- Step 1.1 − Update sumVal, sumVal += 1/i.
- Step 2 − Print sumVal.
Program to illustrate the working of our solution
Example
#include <iostream> using namespace std; float calcSeriesSum(int n){ float sumVar = 0.00; for(float i = 1; i <= n; i++){ sumVar += (1/i); } return sumVar; } int main(){ int n = 7; cout<<"The sum of series till "<<n<<" is "<<calcSeriesSum(n); return 0; }
Output
The sum of series till 7 is 2.59286
Advertisements