# Solve $7\frac{1}{3}\div \frac{2}{3}$ of $2\frac{1}{5}+1\frac{3}{8}\div 2\frac{3}{4}-1 \frac{1}{2}$.

Given:

$7\frac{1}{3}\div \frac{2}{3}$ of $2\frac{1}{5}+1\frac{3}{8}\div 2\frac{3}{4}-1 \frac{1}{2}$

To do:

We have to solve the given expression.

Solution:

$7\frac{1}{3}\div \frac{2}{3}$ of $2\frac{1}{5}+1\frac{3}{8}\div 2\frac{3}{4}-1 \frac{1}{2}=\frac{7\times3+1}{3}\div \frac{2}{3}$ of $\frac{2\times5+1}{5}+\frac{1\times8+3}{8}\div \frac{2\times4+3}{4}-\frac{1\times2+1}{2}$

$=\frac{22}{3}\div\frac{2}{3}$ of $\frac{11}{5}+\frac{11}{8}\div \frac{11}{4}-\frac{3}{2}$

$=\frac{22}{3}\div\frac{2}{3}\times\frac{11}{5}+\frac{11}{8}\div\frac{11}{4}-\frac{3}{2}$

$=\frac{22}{3}\div\frac{22}{15}+\frac{11}{8}\div\frac{11}{4}-\frac{3}{2}$

$=\frac{22}{3}\times\frac{15}{22}+\frac{11}{8}\times\frac{4}{11}-\frac{3}{2}$

$=5+\frac{1}{2}-\frac{3}{2}$

$=5+\frac{1-3}{2}$

$=5+(\frac{-2}{2})$

$=5-1$

$=4$

Therefore, $7\frac{1}{3}\div \frac{2}{3}$ of $2\frac{1}{5}+1\frac{3}{8}\div 2\frac{3}{4}-1 \frac{1}{2}=4$.

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Updated on: 10-Oct-2022

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